Makamashin Kinetic - Matsaloli da mafita

Makamashin Kinetic - Matsaloli da mafita

1. Motoci biyu suna da nauyin iri ɗaya , suna motsawa tare da kuzarin motsi daban-daban. Ƙarfin motsi na motar farko ya ninka ƙarfin motsi na motar ta biyu sau 9. Kwatancen saurin mota na farko da mota ta biyu shine…..

An sani:

Nauyin mota A (m _A ) = m

Nauyin mota B (m _B ) = m

Ƙarfin motsi na mota B (K E _B ) = K E

Ƙarfin motsi na mota A (K E _A ) = 9 K E

Ana so: Kwatanta saurin mota na farko da na biyu

Magani:

Daidaiton kuzarin motsi:

KE = 1/2 mv ²

2 K E = mv ²

v ² = 2 K E / m

Saurin mota A:

v ² = 2 K E _A / m _A = 2 (9 K E ) / m = 18 K E / m

Saurin mota B :

v ² = 2 K E _B / m _B = 2 K E / m = 2 K E / m

Kwatanta saurin mota A da motar B:

18 K E / m: 2 K E / m

18: 2

9: 1 = 3 ² : 1 ²

[irp]

2. Ƙarfin motsi na abu a wurin B = 100 J. Idan nauyin abu ya kai kilogiram 2.5 , to a tantance ƙarfin motsi na abu lokacin da ya bugi ƙasa a wurin C. Hanzarta saboda nauyi shine 10 m/s ².

Magani

Ƙarfin motsi na abu idan ya isa wurin B:

PE = mgh = (2.5)(10)(4) = Joules 100

Ƙarfin motsi na abu idan ya isa wurin C:

PE = mgh

PE = (2.5)(10)(4 + 6)

PE = (2.5)(10)(10)

PE = 250 Joule

[irp]