Matsalolin da aka Magance a fannin Fizik na Asali

1. Kwallon kafa da aka harba ta bar ƙasa a kusurwa θ = 30^o zuwa kwance tare da saurin farko na m14/s. Lissafa saurin ƙarshe kafin ƙwallon ta faɗi ƙasa.

An sani:

Kusurwa (θ) = 30^o

Saurin farko (v_o) = 14 m/s

Haɓaka nauyi (g) = 10 m / s²

Ana so: Saurin ƙarshe kafin ƙwallon ta faɗi ƙasa

Magani:

Sashen kwance na saurin farko:

v_ox = v_o cos θ = (14 m/s)(cos 30^o) = (14 m/s)(0.5√3) = 7√3 m / s

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (14 m/s)(zunubi 30^o) = (14 m/s)(0.5) = 7 m/s

Saurin ƙarshe a tsaye a alkibla

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 7 m/s (tabbatacce zuwa sama)

Saurin nauyi (g) = –10 m / s² (mara kyau zuwa ƙasa)

Tsawo (h) = 0 (abin da aka mayar zuwa matsayin farko)

Ana so: Saurin ƙarshe (v)_t)

Magani:

v_t² = v_o² + 2 gh = 7² + 2(-10)(0) = 49 – 0 = 49

v_t = √49 = 7 m/s

Saurin ƙarshe a kwance a alkibla

Saurin farko a kwance shine 7√3 m/s. Saurin yana da daidaito don haka saurin ƙarshe yayi daidai da saurin farko.

Saurin ƙarshe kafin abu ya faɗi ƙasa

2. An haska jiki sama a kusurwar 30^o tare da kwance daga gini mai tsayin mita 5. Saurinsa na farko shine m10/s. Lissafa saurin ƙarshe kafin abin ya faɗo ƙasa! Saurin nauyi shine m10/s².

An sani:

Kusurwa (θ) = 30^o

Tsawon farko (h)_o) = mita 5

Saurin farko (v)_o) = 10 m/s

Saurin nauyi (g) = 10 m/s²

Ana so: Saurin ƙarshe

Magani:

Sashen kwance na saurin farko:

v_ox = v_o cos θ = (10 m/s)(cos 30^o) = (10 m/s)(0.5√3) = 5√3 m / s

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (10 m/s)(zunubi 30^o) = (10 m/s)(0.5) = 5 m/s

Saurin ƙarshe a tsaye a alkibla

An sani:

Saurin farko (v)_o) = 5 m/s (tabbatacce zuwa sama)

hanzari na nauyi (g) = –10 m / s² (mara kyau zuwa ƙasa)

Tsawo (h) = -5 m (korau saboda ƙasa tana ƙasa da tsayin farko)

Ana so: Saurin ƙarshe (v)_t)

Magani:

v_t² = v_o² + 2 gh = 5² + 2(-10)(-5) = 25 + 100 = 125

v_t = √125 m/s

Saurin ƙarshe a kwance a alkibla

Saurin ƙarshe a kwance shine 5.3 m/s.

Saurin ƙarshe

3. Ƙaramin ƙwallon da aka zana a kwance tare da saurin farko v_o = 8 m/s daga gini mai tsayin mita 12. Lissafa saurin ƙarshe kafin ƙwallon ta faɗi ƙasaSaurin nauyi shine 10 m/s²

An sani:

Tsawo (h) = mita 12

Saurin farko (v)_o) = 8 m/s

Saurin nauyi (g) = 10 m/s²

Ana so: Saurin ƙarshe (v)_t)

Magani:

Sashen kwance na saurin farko:

v_ox = v_o = 8m/s

Bangaren tsaye na saurin farko:

v_oy = 0m/s

Saurin ƙarshe a tsaye a alkibla

an ƙididdige ta amfani da lissafin motsi na faɗuwa kyauta.

An sani:

Saurin nauyi (g) = 10 m / s²

Tsawo (h) = mita 12

Ana so: Saurin ƙarshe (v)_t)

Magani:

v_t² = 2 gh = 2(10)(12) = 240

v_t = √240 m/s

Saurin ƙarshe a kwance a alkibla

Gudun farko a alkiblar kwance shine 8 m/s. Gudun yana nan akai-akai don haka saurin farko yayi daidai da saurin ƙarshe. Don haka saurin ƙarshe a alkiblar kwance shine 8 m/s.

Saurin ƙarshe

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1. Warware saurin farko zuwa sassan kwance da a tsaye
2. Ƙayyade ƙaura a kwance
3. Ƙayyade matsakaicin tsayi
4. Ƙayyade tazarar lokaci
5. Ƙayyade matsayin abin
6. Ƙayyade saurin ƙarshe

Karin bayani

An warware matsalolin motsi na harsashi - tantance matsayin wani abu

1. An haska jiki sama a kusurwar 60^o to kwance tare da saurin farko na m12/s. Kayyade matsayin abin bayan motsi na daƙiƙa 1! Haɓaka nauyi shine 10 m/s².

An sani:

Kusurwa (θ) = 60^o

Da farko gudu (v_o) = 12 m/s

Tazarar lokaci (t) = daƙiƙa 1

Saurin nauyi (g) = 10 m / s²

Ana so: Matsayin abu bayan motsi na daƙiƙa 1

Magani:

Sashen kwance na saurin farko:

v_ox = v_o cos θ = (12 m/s)(cos 60^o) = (12 m/s)(0.5) = 6 m/s

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (12 m/s)(zunubi 60^o) = (12 m/s)(0.5√3) = 6√3 m / s

Matsayin abu a kwance:

An sani:

Sashen kwance na saurin gudu (v)_x) = 6 m/s

Tazarar lokaci (t) = daƙiƙa 1

Ana so: zangon kwance (x)

Magani:

Mita 6 / daƙiƙa yana nufin ƙwallon yana motsawa har zuwa mita 6 a kowace daƙiƙa 1. Nisa da ƙwallon bayan ya motsa na daƙiƙa 1 shine mita 6. Don haka matsayin ƙwallon a kwance shine mita 6.

Matsayin abu a tsaye:

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 6√3 m/s (tabbatacce zuwa sama)

Tazarar lokaci (t) = daƙiƙa 1

Saurin nauyi (g) = -10 m/s² (mara kyau zuwa ƙasa)

Ana so: tsayi bayan motsi na daƙiƙa 1

Magani:

h = v_o t + 1/2 gt² = (6√3)(1) + 1/2 (-10)(1)²) = 6√3 + (-5)(1) = 6√3 – 5 = 6(1.7) – 5 = 10.2 – 5 = mita 5.2.

Matsayin abu bayan motsi na daƙiƙa 1:

Matsar da aka yi a kwance (x) = mita 6

Matsar tsaye (y) = mita 5.2

2. An haska jiki sama a kusurwar 30^o to kwance daga gini mai tsayin mita 20. Saurinsa na farko shine m50/s. Lissafa motsi a tsaye bayan jikin ya motsa na daƙiƙa 1! Saurin nauyi shine m10/s².

An sani:

Kusurwa (θ) = 30^o

Tsawon farko (h)_o) = mita 20

Saurin farko (v)_o) = 50 m / s

Tazarar lokaci (t) = daƙiƙa 1

Saurin nauyi (g) = 10 m / s²

Ana so: Tsayi (h)

Magani:

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (50 m/s)(zunubi 30^o) = (50 m/s)(0.5) = 25 m / s

Height:

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 25 m/s (tabbatacce zuwa sama)

Tazarar lokaci (t) = daƙiƙa 1

Saurin nauyi (g) = -10 m / s² (mara kyau zuwa ƙasa)

Ana so: Tsayi (h)

Magani:

h = v_o t + 1/2 gt² = (25)(1) + 1/2 (-10)(1)²) = 25 + (-5)(1) = 25 – 5 = mita 20.

Tsayin jiki bayan ya motsa na daƙiƙa 1 yana da mita 20 sama da inda jikin yake shirin ko kuma mita 40 sama da ƙasa.

3. Ƙaramin ƙwallon da aka zana a kwance tare da saurin farko v_o = 10 m/s daga gini mai tsayin mita 10. Lissafa matsugunin ƙwallon bayan an motsa daƙiƙa 1Saurin nauyi shine 10 m/s²

An sani:

Tsawon farko (h) = mita 10

Saurin farko (v)_o) = 10 m/s

Tazarar lokaci (t) = daƙiƙa 1

Saurin nauyi (g) = 10 m/s²

SE busca: Matsayin ƙwallon bayan motsi na daƙiƙa 1!

Magani:

Matsar da aka yi a kwance:

An sani:

Sashen kwance na saurin gudu (v)_x) = 10 m/s

Tazarar lokaci (t) = daƙiƙa 1

SE busca: Matsayin abin

Magani:

Mita 10/daƙiƙa yana nufin abin yana motsawa har zuwa mita 10 a kowace daƙiƙa 1. Hijira Bayan motsi na daƙiƙa 1, mita 10 ne. Don haka ƙaura a kwance mita 10 ne.

Matsar tsaye:

An ƙididdige shi azaman motsi na faɗuwa kyauta.

An sani:

Tazarar lokaci (t) = daƙiƙa 1

Saurin nauyi (g) = 10 m/s²

Ana so: Tsawo bayan motsi na daƙiƙa 1 (h)

Magani:

h = 1/2 gt² = 1/2 (10)(1)²) = (5)(1) = mita 5.

Bayan daƙiƙa 1, abin zai faɗi har zuwa mita 5. Tsayin da ke sama da matakin ƙasa = mita 10 – mita 5 = mita 5.

Matsayin abin bayan motsi na daƙiƙa 1:

Matsayin abin a alkiblar kwance (x) = mita 10

Matsayin abin a tsaye (y) = mita 5

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1. Warware saurin farko zuwa sassan kwance da a tsaye
2. Ƙayyade ƙaura a kwance
3. Ƙayyade matsakaicin tsayi
4. Ƙayyade tazarar lokaci
5. Ƙayyade matsayin abin
6. Ƙayyade saurin ƙarshe

Karin bayani

An warware matsalolin motsi na harsashi - ƙayyade tazara tsakanin lokaci

1. Kwallon kafa da aka harba ta bar ƙasa a kusurwa θ = 30^o zuwa kwance tare da saurin farko na m 10/s. Lissafa tazarar lokaci don isa ga matsakaicin tsayi! Haɓaka nauyi shine 10 m/s².

An sani:

Kusurwoyi (θ) = 30^o

Saurin farko (v)_o) = 10 m/s

Saurin nauyi (g) = 10 m/s²

Ana so: Lokaci don zuwa ga ƙarshe matsakaicin tsayi

Magani:

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (10 m/s)(zunubi 30^o) = (10 m/s)(0.5) = 5 m / s

Ana ƙayyade tazarar lokaci don isa ga mafi girman tsayi ta hanyar motsi a tsaye Daidaito. Zaɓi hanyar sama a matsayin mai kyau da kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 5 m / s (tabbatacce sama)

Saurin nauyi (g) = –10 m / s² (mara kyau zuwa ƙasa)

Saurin ƙarshe a matsakaicin tsayi (v)_t) = 0

Ana so: tazara ta lokaci (t)

Magani:

v_t = v_o + gt

0 = 5 + (-10)t

0 = 5 – 10 t

5 = 10t

t = 5/10 = 0.5 s

2. An haska jiki sama a kusurwar 30^o to a kwance tare da saurin farko na m30/s. Lissafa lokacin tashi! Saurin nauyi shine m10/s².

An sani:

Kusurwoyi (θ) = 30^o

Saurin farko (v)_o) = 8 m/s

Saurin nauyi (g) = 10 m / s²

Ana so: Tsawon lokaci kafin jiki ya faɗi ƙasa

Magani:

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (8 m/s)(zunubi 30^o) = (8 m/s)(0.5) = 4 m / s

Da farko za mu ƙididdige tazarar lokaci don isa ga matsakaicin tsayi ta amfani da lissafin motsi na tsaye.

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 4 m / s (tabbatacce sama)

Saurin nauyi (g) = –10 m / s² (mara kyau zuwa ƙasa)

Saurin ƙarshe a matsakaicin tsayi (v)_t) = 0

Ana so: Tazarar lokaci (t)

Magani:

v_t = v_o + gt

0 = 4 + (-10)t

0 = 4 – 10 t

4 = 10t

t = 4/10 = 0,4 s

Tazarar lokaci don isa ga matsakaicin tsayi shine 0.4 s.

Lokacin da ake amfani da shi a iska shine 2 x 0.4 s = 0.8 s.

3. An haska jiki sama a kusurwar 30^o tare da kwance daga gini mai tsayin mita 10. Saurinsa na farko shine m 40/s. Har yaushe yake ɗaukar gawar don isa ƙasa? Saurin nauyi shine m 10/s².

An sani:

Kusurwoyi (θ) = 30^o

Tsawon farko (h)_o) = mita 10

Saurin farko (v)_o) = 40 m/s

Saurin nauyi (g) = 10 m / s²

Ana so: Lokacin da ake cikin iska (t)

Magani:

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (40 m/s)(zunubi 30^o) = (40 m/s)(0.5) = 20 m / s

Da farko za mu ƙididdige tazarar lokaci don isa ga matsakaicin tsayi ta amfani da lissafin motsi na tsaye.

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 20 m / s (tabbatacce sama)

Saurin nauyi (g) = –10 m / s² (mara kyau zuwa ƙasa)

Saurin ƙarshe a lokacin kololuwa (v)_t) = 0

Ana so: Tazarar lokaci (t)

Magani:

v_t = v_o + gt

0 = 20 + (-10)t

0 = 20 – 10 t

20 = 10t

t = 20/10 = daƙiƙa 2

Lokacin da ake amfani da shi a iska = daƙiƙa 2 x 2 = daƙiƙa 4.

Abin yana da nisan mita 10 daga ƙasa. Daƙiƙa 4 shine tazara tsakanin lokacin da za a isa wurin da yake daidai da matsayin farko. Har yanzu ƙwallon tana tafiya ƙasa.

Ana ƙididdige tazarar lokacin da za a isa ƙasa ta amfani da lissafin motsi na faɗuwa kyauta. 

An sani:

Saurin nauyi (g) = 10 m / s²

Tsawo (h) = mita 10

Ana so: Tazarar lokaci (t)

Magani:

h = 1/2 gt²

10 = 1/2 (10) t²

10 = 5t²

t² = 10/5 = 2

t = √2 = daƙiƙa 1.4

Tazarar lokaci = daƙiƙa 1.4.

Jimlar tazara tsakanin lokaci = daƙiƙa 4 + daƙiƙa 1.4 = daƙiƙa 5.4.

4. Ƙaramin ƙwallon da aka zana a kwance tare da saurin farko v_o = 15 m/s daga gini mai tsayin mita 5. Lissafa lokacin da ake cikin iskaSaurin nauyi shine 10 m/s²

An sani:

Tsawo (h) = mita 5

Saurin farko (v)_o) = 15 m/s

Saurin nauyi (g) = 10 m/s²

SE busca: Lokacin da ake cikin iska (t)

Magani:

Ana ƙididdige lokaci a cikin iska ta amfani da lissafin motsi na faɗuwa cikin 'yanci.

An sani:

Tsawo (h) = mita 5

Saurin nauyi (g) = 10 m/s²

Ana so: Tazarar lokaci (t)

Magani:

h = 1/2 gt²

5 = 1/2 (10) t²

5 = 5t²

t² = 5/5 = 1

t = √1 = daƙiƙa 1

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1. Warware saurin farko zuwa sassan kwance da a tsaye
2. Ƙayyade ƙaura a kwance
3. Ƙayyade matsakaicin tsayi
4. Ƙayyade tazarar lokaci
5. Ƙayyade matsayin abubuwa
6. Ƙayyade saurin ƙarshe

Karin bayani

An warware matsalolin motsi na harsashi - ƙayyade matsakaicin tsayi

1. Kwallon kafa da aka harba ta bar ƙasa a kusurwa θ = 60^o tare da kwance yana da saurin farko na m 10/s. Lissafa matsakaicin tsayi! Haɓaka nauyi shine 10 m/s².

An sani:

Kusurwoyi (θ) = 60^o

Saurin farko (v)_o) = 10 m/s

Ana so: Tsawon mafi girma (h)

Magani:

Bangaren tsaye na saurin farko:

ba 60^o = v_oy /v_o

v_oy = v_o ba 60^o = (10)(zunubi 60^o) = (10)(0.5)√3) = 5√3 m / s

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin nauyi (g) = -10 m/s² (mara kyau zuwa ƙasa)

Bangaren tsaye na saurin farko (v)_oy) = +5√3 m / s (tabbatacce sama)

Saurin ƙarshe a matsakaicin tsayi (v)_ty) = 0

Ana so: Tsawon mafi girma (h)

Magani:

v_t² = v_o² + 2 gh

0² = (5√3)² + 2 (-10) h

0 = 25(3) – awanni 20

0 = 75 – awanni 20

75 = 20 pm

h = 75/20

h = mita 3.75

Tsawon mafi girma shine mita 3.75.

2. An haska jiki sama a kusurwar 30^o tare da kwance daga gini mai tsayin mita 20. Saurin farko shine m4/s. Lissafa matsakaicin tsayi! Saurin nauyi shine m10/s².

An sani:

Kusurwoyi (θ) = 30^o

Tsawon farko (h) = mita 20

Saurin farko (v_o) = 4 m/s

Saurin nauyi (g) = 10 m/s²

Ana so: Matsakaicin tsayi (h)

Magani:

Bangaren tsaye na saurin farko:

ba 30^o = v_oy /v_o

v_oy = v_o ba 30^o = (4)(zunubi 30^o) = (4)(0.5) = 2 m / s

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin nauyi (g) = -10 m/s² (mara kyau zuwa ƙasa)

Bangaren tsaye na saurin farko (v)_oy) = +2 m / s (tabbatacce sama)

Saurin ƙarshe a matsakaicin tsayi (v)_ty) = 0

Ana so: Matsakaicin tsayi

Magani:

Matsakaicin tsayi:

v_t² = v_o² + 2 gh

0² = 2² + 2 (-10) h

0 = 4 – awanni 20

4 = 20 pm

h = 4/20

h = mita 0.2

Tsawonsa mafi girma shine mita 0.2 + mita 20 = mita 20.2.

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1. Warware saurin farko zuwa sassan kwance da a tsaye
2. Ƙayyade ƙaura a kwance
3. Ƙayyade matsakaicin tsayi
4. Ƙayyade tazarar lokaci
5. Ƙayyade matsayin abubuwa
6. Ƙayyade saurin ƙarshe

Karin bayani

An warware matsalolin motsi na harsashi - ƙayyade canjin kwance

1. Kwallon kafa da aka harba ta bar ƙasa a kusurwa θ = 60^o Idan aka yi la'akari da cewa ƙwallon a kwance tana da saurin farko na m16/s. Har yaushe zai ɗauka kafin ƙwallon ta faɗi ƙasa?

An sani:

Kusurwa (θ) = 60^o

Saurin farko (v)_o) = 16 m / s

Saurin nauyi (g) = 10 m/s²

Ana so: Matsar da aka yi a kwance (x)

Magani:

Sashen kwance na saurin farko:

v_ox = v_o cos θ = (16 m/s)(cos 60^o) = (16 m/s)(0.5) = 8 m / s

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (16 m/s)(zunubi 60^o) = (16 m/s)(0.5√3) = 8√3 m / s

projectile-motsi za a iya fahimtar ta hanyar nazarin sassan motsi na kwance da tsaye daban-daban. Motsin x yana faruwa ne a saurin da ba ya canzawa kuma motsin y yana faruwa ne a saurin nauyi akai-akai.

Lokaci a sararin samaniya

Lokacin da yake tsayawa a cikin iska ana ƙaddara shi ta hanyar motsi na y. Da farko mun sami lokacin ta amfani da motsi na y sannan muka yi amfani da wannan ƙimar lokaci a cikin lissafin x (saurin da ya dace lissafi).

Zaɓi hanyar sama a matsayin mai kyau, kuma hanyar ƙasa a matsayin mara kyau.

An sani:

Saurin farko (v)_o) = 8√3 m / s (v_o sama)

Saurin nauyi (g) = -10 m/s² (g ƙasa)

Tsawo (h) = 0 (ƙwallon ta koma matsayi ɗaya)

Ana so: Lokacin da ake cikin iska

Magani:

h = v_o t + 1/2 gt²

0 = (8√3) t + 1/2 (-10) t²

0 = 8√3 t – t 5²

8√3 t = t 5²

8 (1.7) = 5 t

14 = 5 t

t = 14 / 5 = daƙiƙa 2.8

Matsar da aka kwance

An sani:

gudu (v) = 8 m/s

Tazarar lokaci (t) = daƙiƙa 2.8

Ana so: Hijira

Magani:

x = vt = (8 m/s)(2.8 s) = mita 22.4

Matsakaicin tsayin jirgin ƙasa shine mita 22.4.

2. An haska jiki sama a kusurwar 60^o tare da tsayin daka daga gini mai tsayin mita 50. Saurin farko shine m30/s. Lissafa gudun da ake yi a kwance! Saurin nauyi shine m10/s².

An sani:

Kusurwa (θ) = 60^o

Tsawo (h) = mita 15

Saurin farko (v)_o) = 30 m / s

Saurin nauyi (g) = 10 m/s²

Ana so: x

Magani:

Sashen kwance na saurin farko ::

v_ox = v_o cos θ = (30 m/s)(cos 60^o) = (30 m/s)(0.5) = 15 m/s

Bangaren tsaye na saurin farko:

v_oy = v_o zunubi θ = (30 m/s)(zunubi 60^o) = (30 m/s)(0.5√3) = 15√3 m / s

Lokaci a sararin samaniya

Da farko mun gano lokacin ta amfani da motsin y sannan muka yi amfani da wannan ƙimar lokaci a cikin lissafin x (daidaitaccen lissafin saurin gudu). Zaɓi sama a matsayin mai kyau da ƙasa kamar mara kyau.

An sani:

Saurin farko (v)_o) = 15√3 m / s (tabbatacce sama)

Saurin nauyi (g) = -10 m/s² (mara kyau zuwa ƙasa)

Babba (h) = -50 (Ƙasa mita 50 ƙasa da wurin farko)

Ana so: t

Magani:

h = v_o t + 1/2 gt²

-50 = (15√3) t + 1/2 (-10) t²

-50 = 15√3 t – t 5²

5 t² - 15√3 t – 50 = 0

Lissafa lokaci ta amfani da wannan dabarar:

a = 5, b = –15√3, c = –50

Lokacin da ake buƙata shine daƙiƙa 6.7.

Matsar da aka yi a kwance:

An sani:

Gudun (v) = 15 m/s

Tazarar lokaci (t) = daƙiƙa 6.7

Ana so: sauyawa

Magani:

s = vt = (15 m/s)(6.7 s) = mita 100.5

Matsakaicin tsayin jirgin ƙasa shine mita 100.5.

3. Ƙaramin ƙwallon da aka zana a kwance tare da saurin farko v_o = 10 m/s daga gini mai tsayin mita 10. Lissafa wurin da aka ajiye a kwanceSaurin nauyi shine 10 m/s²

An sani:

Tsawo (h) = mita 10

Saurin farko (v)_o) = 10 m / s

Haɓaka nauyi (g) = 10 m/s²

Ana so: x

Magani:

Sashen kwance na saurin farko = saurin farko = 10 m/s.

Lokaci a sararin samaniya

An ƙididdige lokacin da ake amfani da shi a cikin iska ta amfani da motsi na faɗuwa kyauta daidaituwa

An sani:

Saurin nauyi (g) = 10 m/s²

Tsawo (h) = mita 10

Ana so: t

Magani:

h = 1/2 gt²

10 = 1/2 (10) t²

10 = 5t²

t² = 10/5 = 2

t = √2 = daƙiƙa 1.4

Matsar da aka kwance

Matsar da aka ƙididdige ta hanyar amfani da lissafi na motsi a madaidaicin gudu.

An sani:

Gudun (v) = 10 m/s

Tazarar lokaci (t) = daƙiƙa 1.4

Ana so: x

Magani:

s = vt = (10 m/s)(1.4 s) = mita 14

Matsakaicin tsayin jirgin ƙasa shine mita 14.

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[wpdm_package id='536′]

1. Warware saurin farko zuwa sassan kwance da a tsaye
2. Ƙayyade ƙaura a kwance
3. Ƙayyade matsakaicin tsayi
4. Ƙayyade tazarar lokaci
5. Ƙayyade matsayin abubuwa
6. Ƙayyade saurin ƙarshe

Karin bayani

An warware matsalolin motsi na harsashi - warware saurin farko zuwa sassan kwance da a tsaye

1. Ƙwallon ƙafa da aka harba ta bar ƙasa a kusurwa θ = 60^o da saurin mita 10/s. Lissafa abubuwan da suka fara saurin gudu!
An sani:
Kusurwoyi (θ) = 60^o
Saurin farko (v)_o) = 10 m/s
Ana so: v_ox kuma v_oy
Magani:
Warware saurin farko zuwa ɓangaren x (a kwance) da kuma ɓangaren y (a tsaye).
zunubi θ = v_oy /v_o —–> v_oy = v_o zunubi θ
cos θ = v_ox /v_o —–> v_ox = v_o kowa

x bangaren (a kwance):
v_ox = v_o cos θ = (10 m/s)(cos 60^o) = (10 m/s)(0.5) = 5 m/s

bangaren y (a tsaye):
v_oy = v_o zunubi θ = (10 m/s)(zunubi 60^o) = (10 m/s)(0.5√3) = 5√3 m/s

2. Abu yana barin ƙasa a kusurwa θ = 30^o tare da ɓangaren y na saurin 10 m/s. Lissafa saurin farko!
An sani:
Kusurwoyi (θ) = 30^o
bangaren y (v)_oy) = 10 m/s
Ana so: Saurin farko (v)_o)
Magani:
v_oy = v_o zunubi θ
10 = (v_o) (zunubi 30^o)
10 = (v_o(0.5)
v_o = 10/0.5
v_o = 20m/s

3. Sashen kwance na saurin farko shine m30/s kuma sashin tsaye na saurin farko shine m40/s. Lissafa saurin farko.
An sani:
Sashen kwance na saurin farko (v)_ox) = 30 m/s
Bangaren tsaye na saurin farko (v)_oy) = 40 m/s
Ana so: Saurin farko (v)_o)
Magani:
v_o² = v_ox² +v_oy² = 30² + 40² = 900 + 1600 = 2500
v_o = √2500
v_o = 50m/s

4. Ana hango ƙaramin ƙwallo a kwance tare da saurin farko v_o = 6m/s. Lissafa x bangaren da y bangaren saurin farko.
An sani:
Saurin farko (v)_o) = 6 m/s
Ana so: vox da v_oy
Magani:
Kwallo yana motsawa a kwance don haka ɓangaren gudu a kwance (v)_ox) = saurin farko (v_o) = 6 m/s. Tsarin tsaye na saurin (v_oy) = 0 ba.

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[wpdm_package id='536′]

1. Warware saurin farko zuwa sassan kwance da a tsaye
2. Ƙayyade ƙaura a kwance
3. Ƙayyade matsakaicin tsayi
4. Ƙayyade tazarar lokaci
5. Ƙayyade matsayin abubuwa
6. Ƙayyade saurin ƙarshe

Karin bayani