3 cheist faoi chothromóidí réimse leictreach
1. Tá muirear leictreach de 500 μC ag liathróid sheolta le ga 10 cm. Tá pointí A, B, agus C suite i líne le lár na liathróide ag achar 12 cm, 10 cm agus 8 cm faoi seach ó lár na liathróide. Ríomh neart an réimse leictrigh ag pointí A, B, agus C!
Aitheanta:
Ga an liathróid sheolta (R) = 10 cm = 0.1 m
Muirear leictreach (q) = 500 μC = 500 x 10-6 C
r A = 12 cm = 0,12 m
rB = 10 cm = 0,1 m
rC = 8 cm = 0,08 m
Tairiseach Coulomb (k) = 9 x 10⁶
Ag Teastáil: Neart an réimse leictrigh ag pointe A (EA ) , ag pointe B (EB ) agus ag pointe C ( EC )
réiteach:
a) Neart an réimse leictrigh ag pointe A
E A = kq / r A 2 = (9 x 10 9 )(500 x 10-6 ) / (0,12) 2 = (4500 x 10 3 ) / 0,0144 = 312500 x 10 3 = 3,125 x 10 8 N/C
b) Neart an réimse leictrigh ag pointe B
E B = kq / r B 2 = (9 x 10 9 )(500 x 10-6 ) / (0,1) 2 = (4500 x 10 3 ) / 0,01 = 450.000 x 10 3 = 4,5 x 10 8 N/C
c) Neart an réimse leictrigh ag pointe C
E C = 0 as a bheith sa liathróid.
2. Má chuirtear muirear tástála de 4 nC ag pointe áirithe, bíonn fórsa 5 × 10 – 4 N ag an muirear. Cad é méid an réimse leictrigh E ag an bpointe sin?
Aitheanta:
Tástáil muirir leictrigh (q) = 4 nC = 4 x 10-9 Coulomb
Fórsa leictreach (F) = 5 × 10⁻⁴ N
Ag Teastáil: Méid an réimse leictrigh (E)
réiteach:
E = F / q = (5 × 10⁻⁴ ) / (4 x 10⁻⁶ ) = 1,25 x 10⁻⁴ N /C
3. Cuirtear dhá mhuirear q, B = 12 μC agus q, C = 9 μC ag buaicphointí triantáin dhronuilleogaigh mar atá i bhFíor. Faigh amach neart an réimse leictrigh a bhraitheann tú ag pointe A!
Aitheanta:
Muirear ag pointe B (qB) = 12 μC = 12 x 10-6 C
Muirear ag pointe C (qC) = 9 μC = 9 x 10-6 C
Tairiseach Coulomb (k) = 9 x 10⁶
r AC = 4 cm = 0,04 m
r AB = 3 cm = 0,03 m
Teastaíonn: neart an réimse leictrigh ag pointe A
réiteach:
E AC = kq / r² = (9 x 10⁶ ) (9 x 10⁻⁶ ) / (0,04) ² = 81 x 10⁶ / 0,0016 = 5,0 x 10⁶ N/C
E AB = kq / r² = (9 x 10⁶ ) (9 x 10⁻⁶ ) / (0,03) ² = 81 x 10⁶ / 0,0009 = 9,0 x 10⁶ N/C
