Ifomula Engaba Khona Kagesi
I-Pendahuluan
Amandla kagesi ngumqondo oyisisekelo ku-physics kagesi ochaza amandla amandla kagesi ngeyunithi ngayinye yokushaja endaweni ethile ensimini kagesi. Udlala indima ebalulekile ezinhlobonhlobo zezicelo, okuhlanganisa ukuklama amasekethe kagesi, ukuqonda izimo zikagesi kanye nezama-magnetic, kanye nokuhlaziya ukuziphatha kwezinhlayiya ezishajiwe. Lesi sihloko sizoxoxa ngencazelo yamandla kagesi, amafomula ahlobene, umqondo wamasimu kagesi, ukusetshenziswa kwawo ekuphileni kwansuku zonke, kanye nezibonelo zokujulisa ukuqonda.
Incazelo Yamandla Kagesi
Amandla kagesi endaweni ethile ensimini kagesi achazwa njengomsebenzi owenziwayo ukuhambisa ishaja yeyunithi kusuka endaweni yokubhekisela (ngokuvamile engapheli) kuya kuleyo ndawo. Ngokwezibalo, amandla kagesi (\(V\)) abonakaliswa ngamayunithi ama-volts (V) futhi angakhiwa kanje:
\[ V = \frac{W}{q} \]
Kuphi:
– \(V\) amandla kagesi,
– \(W\) umsebenzi owenziwe ukuhambisa ishaja,
– \(q\) ubukhulu beshaja.
Ifomula Engaba Khona Kagesi Yemithombo Yamaphoyinti
Ukuze uthole ishaja yephoyinti \(Q\) ekhiqiza insimu kagesi, amandla kagesi \(V\) akude \(r\) kusukela ekushajeni anikezwa ngu:
\[ V = \frac{kQ}{r} \]
Kuphi:
– \(V\) amandla kagesi,
– \(k\) yi-Coulomb constant (\(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\)),
– \(Q\) ubukhulu benkokhelo,
– \(r\) ibanga elisuka ekushajweni kuya endaweni lapho amandla alinganiswa khona.
Insimu Kagesi kanye Nekhono Likagesi
Insimu kagesi (\(E\)) iyinani levektha elichaza amandla ngeyunithi yokushaja etholwa yishaja yokuhlola endaweni ethile esikhaleni. Ubudlelwano phakathi kwensimu kagesi kanye namandla kagesi bungabonakaliswa kanje:
\[ \vec{E} = -\nabla V \]
Kuphi:
– \(\vec{E}\) yinsimu kagesi,
– \(\nabla V\) i-gradient yamandla kagesi.
Amandla kagesi okukhokhisa eziningana
Uma kunezinkokhelo eziningana zamaphoyinti, amandla kagesi aphelele endaweni ethile ayisamba se-algebraic sama-powers kagesi akhiqizwa yinkokhelo ngayinye. Ngokwezibalo, ngama-charges \(Q_1, Q_2, \ldots, Q_n\) atholakala kude \(r_1, r_2, \ldots, r_n\) ukusuka endaweni, amandla kagesi aphelele \(V_{total}\) ngu:
\[ V_{total} = \sum_{i=1}^{n} \frac{kQ_i}{r_i} \]
Amandla kagesi kuma-Conductor
Kumqhubi kagesi, amashaja amahhala angahamba kalula. Ngenxa yalokho, insimu kagesi ngaphakathi komqhubi ingu-zero, futhi amandla kagesi ahlala njalo kuyo yonke i-conductor. Lokhu kusho ukuthi uma sixhuma amaphuzu amabili kumqhubi kagesi, akukho mehluko ongaba khona phakathi kwawo.
Ukusetshenziswa Kwamandla Kagesi Empilweni Yansuku Zonke
Amabhethri kanye nezifunda zikagesi
Ibhethri liwumthombo wamandla kagesi odala umehluko ongaba khona phakathi kwama-terminal ayo amahle nangalungile. Lo mehluko ongaba khona ubangela ukuthi ugesi ugeleze ku-closed circuit, okunikeza amandla kumadivayisi ahlukahlukene kagesi.
I-Kapastor
I-capacitor iyithuluzi eligcina amandla ngesimo sensimu kagesi phakathi kwamapuleti amabili aqhubayo ahlukaniswe yi-dielectric. Amandla kagesi phakathi kwamapuleti anquma inani lokushaja elingagcinwa.
Petir
Umbani uvela lapho ukuqongelela kwamacala kagesi emafwini kudala umehluko omkhulu phakathi kwefu kanye nobuso boMhlaba. Uma lo mehluko ongaba khona mkhulu ngokwanele, amandla kagesi akhishwa ngesimo sombani.
Imibuzo nezixazululo zezibonelo
Isibonelo Umbuzo 1
Ishaja yephuzu \(Q = 2 \, \mu \text{C}\) ibekwa endaweni ethile. Bala amandla kagesi ebangeni elingamamitha angu-0,5 ukusuka ekushajeni.
Isixazululo:
Ukusebenzisa ifomula yamandla kagesi ukuze uthole ishaja yephoyinti:
\[ V = \frac{kQ}{r} \]
Faka amanani anikeziwe:
\[ V = \frac{8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \times 2 \times 10^{-6} \, \text{C}}{0,5 \, \text{m}} \]
\[ V = \frac{17.98 \times 10^3 \, \text{N m/C}}{0,5} \]
\[ V = 35.96 \izikhathi ezingu-10^3 \, \umbhalo{V} \]
\[ V = 35.96 \, \umbhalo{kV} \]
Ngakho-ke, amandla kagesi ebangeni elingamamitha angu-0,5 ukusuka ekushajweni angama-35,96 kV.
Isibonelo Umbuzo 2
Izindleko ezimbili zamaphuzu \(Q_1 = 3 \, \mu \text{C}\) kanye \(Q_2 = -2 \, \mu \text{C}\) zibekwe ebangeni elingamamitha angu-1 kanye namamitha angu-0,5 ukusuka endaweni P. Bala inani eliphelele lamandla kagesi endaweni P.
Isixazululo:
Ukusebenzisa ifomula yamandla kagesi ngamashaji amaningana:
\[ V_{total} = \frac{kQ_1}{r_1} + \frac{kQ_2}{r_2} \]
Faka amanani anikeziwe:
\[ V_{total} = \frac{8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \times 3 \times 10^{-6} \, \text{C}}{1 \, \text{m}} + \frac{8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \times (-2) \times 10^{-6} \, \text{C}}{0,5 \, \text{m}} \]
\[ V_{isamba} = 26.97 \izikhathi 10^3 \, \umbhalo{V} – 35.96 \izikhathi 10^3 \, \umbhalo{V} \]
\[ V_{total} = -8.99 \izikhathi ezingu-10^3 \, \umbhalo{V} \]
Ngakho-ke, amandla kagesi aphelele endaweni P angama--8.99 kV.
Isiphetho
Amandla kagesi ngumqondo obalulekile ochaza amandla angase abe khona ngeyunithi ngayinye yokushaja endaweni ethile ensimini kagesi. Ngokuqonda amafomula ahlobene namandla kagesi, njenge-\( V = \frac{W}{q} \) kanye ne-\( V = \frac{kQ}{r} \), kanye nokusetshenziswa kwawo ezimweni ezahlukene, singaziqonda kangcono izimo zikagesi empilweni yansuku zonke. Amandla kagesi anezinhlelo eziningi ezisebenzayo, kusukela ekwakhiweni kwesekethe kagesi kuya ezenzakalweni zemvelo ezifana nombani. Ngezinkinga zezibonelo ezifakiwe, kunethemba lokuthi ukuqonda lo mqondo kuzoba ngokujulile futhi kusebenze.
