I-physics

1. Umzimba onesisindo esingu-1 kg uwela ngokukhululeka ekuphumuleni, kusukela ekuphakameni kwamamitha angu-80. Ukusheshisa ngenxa yamandla adonsela phansi kungu- 10 m/s ^2. Iyini amandla e-kinetic lapho umzimba ushaya phansi.

Kwaziwa:

Isisindo (m) = 1 kg

Ukuphakama (h) = 80 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: amandla e-kinetic lapho umzimba ushaya phansi

Isixazululo:

Amandla okuqala omshini (ME _o ) = amandla adonsela phansi (PE)

M E _o = P E = mgh = (1)(10)(80) = ama-Joules angu-800

Amandla okugcina omshini (M E _t ) = amandla e-kinetic (K E )

Umgomo wokonga amandla emishini :

M E _o = M E _t

P E = K E

800 = K E

Amandla okugcina e-kinetic angama- 800 Joules.

2. Umzimba onesisindo esingamakhilogremu angu-4 uwela ngokukhululeka ekuphumuleni, kusukela ekuphakameni kwamamitha ayi-10. Ukusheshisa ngenxa yamandla adonsela phansi kungu- 10 ms ^–2 . Iyini amandla e-kinetic kanye nesivinini esingamamitha ama-5 ngaphezu komhlabathi.

Kwaziwa:

Ushintsho lokuphakama (h) = 10 – 5 = 5 amamitha s

Isisindo (m) = 4 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Amandla e-kinetic amamitha ama-5 ngaphezu komhlabathi kanye nesivinini samamitha ama-5 ngaphezu komhlabathi

Isixazululo:

(a) Amandla e-kinetic amamitha ama-5 ngaphezu komhlabathi

Amandla okuqala omshini (M E _o ) = amandla adonsela phansi (P E )

M E _o = P E = mgh = (4)(10)(5) = ama-Joules angu-200

Amandla okugcina omshini (EM _t ) = amandla e-kinetic (EK)

M E _t = K E

Isimiso sokulondolozwa kwamandla omshini sithi amandla okuqala omshini = amandla okugcina omshini.

M E _o = M E _t

200 = K E

Amandla e-kinetic amamitha angu-5 ngaphezu komhlabathi angama- Joules angu-200.

(b) isivinini samamitha ama-5 ngaphezu komhlabathi

Amandla okuqala omshini (M E _o ) = amandla okugcina omshini (M E _t )

P E = K E

200 = ½ mv ²

2(200) / 4 = v ²

100 = v ²

v = √100

v = 10 m/s

Ijubane lomzimba ngamamitha ama-5 ngaphezu komhlabathi liyi-10 m/s.

3. Umango uwela ngokukhululeka ekuphumuleni, usuka ekuphakameni kwamamitha amabili. Ukusheshisa ngenxa yamandla adonsela phansi kungu- 10 ms ^–2 . Thola ijubane lomango uma ushaya phansi.

Kwaziwa:

Ukuphakama (h) = 2 amamitha s

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: ijubane likamango uma lishaya phansi.

Isixazululo:

Amandla okuqala omshini (M E _o ) = amandla adonsela phansi (P E )

ME = PE = mgh = m (10)(2) = 20 m

Amandla okugcina omshini (M E _t ) = amandla okunyakaza (K E )

I - M _Et = KE = ½ mv ²

Isimiso sokulondolozwa kwamandla omshini sithi amandla okuqala omshini = amandla okugcina omshini.

M E _o = M E _t

20 m = ½ mv ²

20 = ½ v ²

2(20) = ^v2

40 = v ²

v = √40 = √(4)(10) = 2√10 m/ s

[wpdm_package id='1166′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Umuntu uphonsa itshe elingamakhilogremu angu-1 phezulu ngesivinini esingu-2 m/s ngenkathi emi onqenqemeni lwedwala ukuze itshe liwele phansi kwedwala elingamamitha angu-40 ngaphansi. Iyini amandla e-kinetic etshe elingamamitha ayi-10 ngaphezu komhlabathi? Ukusheshisa ngenxa yamandla adonsela phansi g = 10 m/s ².

Kwaziwa:

Isisindo (m) = 1 kg

Ijubane lokuqala (v _o ) = 2 m/s

Ushintsho lokuphakama = 40 – 10 = amamitha angu-30

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Kufunwa: amandla e-kinetic etshe ngamamitha ayi-10 ngaphezu komhlabathi

Isixazululo:

Amandla okuqala omshini

Amandla okuqala adonsela phansi (EP) = mgh = (1)(10)(30) = 300 Joules

Amandla okuqala e-kinetic (KE) = ½ mv _o ² = ½ (1)(2) ² = ½ (4) = 2 Joules

Amandla okuqala omshini = amandla okuqala adonsela phansi + amandla okuqala e-kinetic = 300 + 2 = 302 Joules.

Amandla okugcina omshini

Amandla okugcina okusebenza ngomshini = amandla okugcina e-kinetic = amandla okuqala adonsela phansi + amandla okuqala e-kinetic = 300 + 2 = 302 Joules.

2. Umuntu uphonsa into engu-1 kg phezulu emoyeni ngesivinini sokuqala esingu-10 m/s. Thola (a) amandla adonsela phansi ekuphakameni okuphezulu (b) ukuphakama okuphezulu.

Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ²

Kwaziwa:

Isisindo (m) = 1 kg

Ijubane lokuqala (v _o ) = 10 m/s

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo : amandla adonsela phansi ekuphakameni okuphezulu kanye nokuphakama okuphezulu

Isixazululo:

(a) amandla adonsela phansi ekuphakameni okuphezulu

Amandla okuqala omshini:

Amandla okuqala omshini (ME) = amandla okuqala omshini (KE) = ½ mv _o ² = ½ (1)(10) ² = ½ (100) = 50 Joules.

Amandla okugcina okusebenza ngomshini:

Amandla okugcina omshini (ME) = amandla adonsela phansi (PE)

Umgomo wokonga amandla emishini:

Amandla okuqala omshini = amandla okugcina omshini

KE = PE

50 = PE

Amandla adonsela phansi angama-Joules angu-50.

(b) Ukuphakama okuphezulu

PE = mgh

50 = (1)(10) h

50 = amahora angu-10

h = 50 / 10 = amamitha angu-5

Ukuphakama okuphezulu kungamamitha ama-5 ngaphezu komhlabathi.

[wpdm_package id='1174′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe ebusweni obugobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Isisindo esingamakhilogremu angu-2 sinamathiselwe esiphethwini. Uma ukunwebeka kwentwasahlobo kungu-4 cm, thola amandla angaba khona esiphethwini esinwebekayo . Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ².

Kwaziwa:

Isisindo (m) = 2 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isisindo (w) = mg = (2)(10) = 20 N

Ubude (x) = 4 cm = 0.04 m

Okufunwayo: Amandla angaba khona entwasahlobo enwebekayo

Isixazululo:

Ifomula yomthetho kaHooke :

F = kx

F = amandla, k = ukungaguquguquki kwentwasahlobo, x = ushintsho lobude bentwasahlobo

I-constant yasentwasahlobo:

k = w / x = 20 / 0.04 = 500 N/m

Amandla angaba khona entwasahlobo enwebekayo:

I-PE = ½ kx ² = ½ (500) (0.04) ² = (250) (0.0016) = 0.4 Joules

Isixazululo esihlukile:

I-PE = ½ kx ² = ½ (w / x) x ² = ½ wx = ½ mgx

w = isisindo, m ​​= isisindo, x = ushintsho lobude bentwasahlobo

I-PE = ½ (2) (10) (0.04) = (10) (0.04) = 0.4 Joules.

2. Ukwelulwa kwentwasahlobo okwelulwe ngamandla u-F = 50 N kungu-10 cm. Yimaphi amandla angaba khona entwasahlobo enwebekayo uma ukwelulwa kwentwasahlobo kungu-12 cm.

Kwaziwa:

Ubude (x) = 10 cm = 0.1 m

Amandla (F) = 50 N

Okufunwayo : Amandla angaba khona entwasahlobo enwebekayo

Isixazululo:

I-constant yasentwasahlobo:

k = F / x = 50 / 0.1 = 500 N/m

Amandla angaba khona entwasahlobo enwebekayo uma ukunwebeka kwentwasahlobo kungu-12 cm. :

I-PE = ½ kx ² = ½ (500) (0.12) ² = (250) (0.0144) = 3.6 Joules.

3. Igrafu ka-F vs x eboniswe esithombeni esingezansi. Iyini amandla angaba khona entwasahlobo enwebekayo, uma ukunwebeka kwentwasahlobo kungu-10 cm.

Kwaziwa:

Amandla (F) = 5 N

Ukwandiswa kwentwasahlobo (x) = 2 cm = 0.02 m

Okufunwayo: Amandla angaba khona entwasahlobo enwebekayo uma ukunwebeka kwentwasahlobo kungu-0.1 m.

Isixazululo:

I-constant yasentwasahlobo:

k = F / x = 5 / 0.02 = 250 N/m

Amandla angaba khona entwasahlobo enwebekayo uma ukunwebeka kwentwasahlobo kungu-0.1 m:

I-PE = ½ kx ² = ½ (250) (0.1) ² = (125) (0.01) = 1.25 Joules.

4. Umsubathi ugxumela ensimbini yesipilingi enesisindo esingu-500 N, intwasahlobo ifinyeza ngo-4 cm. Thola inani lamandla angase asetshenziswe ukuphoqa umsubathi.

A. 20 Joule

B. 10 Joule

C. 5 Joule

D. 2 Joule

Kwaziwa:

Amandla (F) = 500 N

Ushintsho lobude bentwasahlobo (Δx) = 4 cm = 0.04 m

Okufunwayo: Amandla angaba khona entwasahlobo

Isixazululo:

Bala i-elastic constant yesipringi usebenzisa i-equation yomthetho kaHooke:

k = F / Δx = 500 N / 0.04 m = 12500 N/m

Amandla anamandla okunwebeka entwasahlobo:

PE = ½ k Δx ² = ½ (12500) (0.04) ² = (6250) (0.0016)

PE = 10 amaJoule

Impendulo efanele ngu-B.

5. Isipilingi uma silenga ngobunzima obungamagremu angu- 500, ubude baso buyanda ngo-5 cm. Thola amandla aso angaguquki kanye namandla aso angase abe khona.

Kwaziwa:

Isisindo sento (m) = 500 amagremu = (500/1000) kg = 5/10 kg = 0.5 kg

Ukusheshisa (g) = 10 m/s ²

Isisindo sento (w) = mg = (0.5 kg)(10 m/s ² ) = 5 kg m/s ² = 5 AmaNewton

Ushintsho lobude bentwasahlobo (Δx) = 5 cm = 0.05 m

Okufunwayo: amandla angaguquki entwasahlobo (k) kanye namandla angase abe khona (PE)

Isixazululo:

Okokuqala, bala i-constant yasentwasahlobo usebenzisa i-equation yomthetho kaHooke:

k = w / Δx = 5 N / 0.05 m = 100 N/m

Ukunwebeka okungenzeka kwentwasahlobo:

PE = ½ k Δx ² = ½ (100) (0.05) ² = (50) (0.0025)

PE = 0.125 amaJoule

[wpdm_package id='1179′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini ukuze kushukunyiswe ezindaweni ezigobile
10. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Umzimba onesisindo esingu-1 kg uwela uphumule, kusukela ekuphakameni okungamamitha ayi-10.

Nquma:

(a) Umsebenzi owenziwe ngamandla adonsela phansi

(b) Ushintsho emandleni adonsela phansi

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Kwaziwa:

Isisindo (m) = 1 kg

Ukuphakama (h) = 10 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isisindo (w) = mg = (1 kg)(10 m/s ² ) = 10 N

Isixazululo:

(a) Umsebenzi owenziwe ngamandla adonsela phansi

W = wh = mgh

W = (1)(10)(10) = 100 amaJoule

(b) Ushintsho emandleni adonsela phansi

Ushintsho emandleni adonsela phansi lulingana nomsebenzi owenziwa amandla adonsela phansi.

Δ EP = 100 Joule

2. Into engu-10 N ishelela phansi endaweni ebushelelezi ethambekele ngamamitha amabili. Thola umsebenzi owenziwe ngamandla esisindo!

Kwaziwa:

isisindo (w) = 10 N

w _x = w isono θ = (10)(isono 30 ^o ) = (10)(0.5) = 5 N

d = 2 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: umsebenzi owenziwe ngamandla esisindo

Isixazululo:

W = F d = w _x d = (5)(2) = 10 amaJoules

Isixazululo esihlukile:

Isono 30 ^o = h / d

0.5 = amahora / 2

h = (0.5)(2)

h = 1 m

Umsebenzi owenziwe ngamandla esisindo;

W = F d = wh = (10 N)(1 m) = 10 N m = 10 Joules

3. Into engamagremu angu-1,500 ebangeni elingamamitha angu-20 ngaphezu komhlabathi , ukuwa kwayo phansi ngokukhululeka. Iyini amandla adonsela phansi ale nto. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ².

Kwaziwa:

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isisindo (m) = 1500 amagremu = 1500/1000 amakhilogremu = 1.5 amakhilogremu

Ukuphakama (h) = amamitha angu-20

Okufunwayo: Amandla adonsela phansi

Isixazululo:

PE = mgh = (1.5 kg)(10 m/s ² )(20 m) = 300 kg m ² /s ² = 300 Joules

4. Ngokusekelwe esithombeni esingezansi, uma isisindo sento 1 singama-2 kg kanti isisindo sento 2 singama-4 kg, ukuqhathanisa amandla angaba khona ento 1 kanye nento 2 kungu …..

Kwaziwa:

Isisindo sento 1 (m₁) = 2 kg

Isisindo sento 2 (m ₂ ) = 4 kg

Ukuphakama 1 (h ₁ ) = amamitha angu-12

Ukuphakama 2 (h ₂ ) = amamitha angu-9

Okufunwayo: Ukuqhathaniswa kwamandla angaba khona ento 1 kanye nento 2

Isixazululo:

PE = mgh

m = isisindo (iyunithi yayo yamazwe ngamazwe yi-kilogram, i-kilogram efingqiwe)

g = ukusheshisa ngenxa yamandla adonsela phansi (iyunithi yayo yamazwe ngamazwe ingamamitha ngomzuzwana isikwele, isifinyezo m/s ² )

h = ukuphakama (iyunithi yayo yamazwe ngamazwe iyimitha, efingqiwe m)

I-PE = amandla adonsela phansi (iyunithi yayo yamazwe ngamazwe yi-kg m2 ^/ s ² noma i-Joule)

Amandla adonsela phansi ento 1:

EP ₁ = m ₁ gh ₁ = (2)(g)(12) = 24 g

Amandla adonsela phansi ento 2:

EP ₂ = m ₂ gh ₂ = (4)(g)(9) = 36 g

Ukuqhathaniswa kwamandla angase abe khona ento 1 kanye nento 2:

I-PE ₁ : I-PE ₂

24 g : 36 g

24: 36

24/12: 36/12

2: 3

[wpdm_package id='1175′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhokisi elingamakhilogremu angu-2 liyehla ngesivinini kusuka ku-10 m/s liye ekuphumuleni. I-coefficient ye -kinetic friction ingu-0.2. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ^2. Ubukhulu bokufuduka buyini?

Kwaziwa;

Isisindo (m) = 2 kg

Ijubane lokuqala (v _o ) = 10 m/s

Ijubane lokugcina (v _t ) = 0 m/s

I-coefficient ye-kinetic friction ( _μk ) = 0.2

Isisindo (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Okufunwayo: Ubukhulu bokufuduka (d)

Isixazululo:

Umgomo wamandla okusebenza nowokusebenza :

W _nc = ΔEM

W _nc = ΔEK + ΔEP

I-W _nc = ½ m (v _t ² – vo ₂ ⁾ + mgh

W _nc = umsebenzi owenziwe ngamandla angewona awokugcina imithetho asebenza entweni

ΔEK = ushintsho lwamandla e-kinetic

ΔEP = ushintsho emandleni angase abe khona

m = isisindo

v = ijubane

g = ukusheshisa ngenxa yamandla adonsela phansi

h = ushintsho ekuphakameni

Ushintsho ekuphakameni h = 0 ngakho-ke ΔEP = 0

W _nc = ΔEK

Umsebenzi owenziwe ngamandla angewona awokugcina imithetho:

W _nc = -F _c d = – μ _k N d = – μ _k wd = – μ _k mgd

I-W _nc = -(0.2)(2)(10)(s)

W _nc = – (4)(2)

Uphawu lokususa lubonisa ukuthi isiqondiso samandla okungqubuzana kwe-kinetic siphambene nesiqondiso sokufuduka.

Ushintsho kumandla e-kinetic:

ΔEK = ½ m (v _t ² – v _o ² ) = ½ (2)(0 – 10 ² ) = 0 – 100 = -100

Ubukhulu bokufuduka:

W _nc = ΔEK

– 4 s = – 100

s = -100/-4

s = 25 m

2. Ibhlokhi liyashelela phansi endizeni ethambekele. I-coefficient ye-kinetic friction ingu-0.4. Ukusheshisa ngenxa yamandla adonsela phansi kungu -g = 10 ms ^-2 . Thola ijubane lokugcina lapho ibhlokhi lishaya phansi.

Kwaziwa:

Ukuphakama kokuqala (h₂o₂ ₎ = 6 m

Ukuphakama kokugcina (h _t ) = 0 m

Ijubane lokuqala (v _o ) = 0

I-coefficient ye-kinetic friction ( _μk ) = 0.4

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 ms ^-2

cos θ = 8/10

Ingxenye eqondile yesisindo = w _y = w cos θ = mg cos θ = m (10) (8/10) = m (10)(4/5) = m (40/5) = 8 m

Amandla ajwayelekile = N = w _y = 8 m

Amandla okungqubuzana kwe-kinetic = f _k = μ _k N = μ _k w _y = (0.4)(8 m) = 3.2 m

Okufunwayo: Ijubane lokugcina (v _t )

Isixazululo:

Umgomo wamandla okusebenza nowokusebenza:

W _nc = Δ EM

W _nc = Δ EK + Δ EP

Ushintsho kumandla e-kinetic:

ΔEK = 1/2 m (v_t² - v_o²) = 1/2 m (v_t² - 0) = 1/2 mv_t²

Ushintsho emandleni angaba khona:

Δ EP = mg (h _t – ho ₎ = m (10)(0-6) = m (10)(-6) = – 60 m

Umsebenzi owenziwe ngamandla okungqubuzana kwe-kinetic:

Ukuphakama _nc = – f _ks = – ( 3.2 m)(10) = – 32 m

Uphawu lokususa lubonisa ukuthi isiqondiso samandla okungqubuzana kwe-kinetic siphambene nesiqondiso sokufuduka.

Ijubane lokugcina (v _t ):

W _nc = Δ EK + Δ EP

– 32 m = 1/2 mv _t ² – 60 m

– 32 m = m (1/2 v _t ² – 60)

– 32 = 1/2 v _t ² – 60

– 32 + 60 = 1/2 v _t ²

28 = 1/2 v _t ²

2 (28) = v _t ²

56 = v _t ²

v _t = √4.14

v _t = 2 √14 ms ^-1

3. Ibhulokhi liwela phansi endizeni ethambekele phansi. Ijubane lokuqala lingu-0 m/s kanti ijubane lokugcina lingu- 10 ms ^-1 . Uma amandla okungqubuzana kwe-kinetic engu-2 N kanye nokusheshisa ngenxa yamandla adonsela phansi u-g = 10 ms ^-2 , kuyini ukuphakama (h)?

Kwaziwa:

Isisindo (m) = 1 kg

Ijubane lokuqala (v _o ) = 0 (ukuphumula kwebhulokhi)

Ijubane lokugcina (v _t ) = 10 ms ^-1

Ukuphakama kokuqala (h _o ) = h

Ukuphakama kokugcina (h _t ) = 0

Amandla okungqubuzana kwe-kinetic (f _k ) = 2 N

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 ms ^-2

Okufunwayo: Ukuphakama (h)

Isixazululo:

Umsebenzi owenziwe ngamandla okungqubuzana kwe-kinetic:

W _nc = – f _ks = – (2 )(15) = – 30

Uphawu lokususa lubonisa ukuthi isiqondiso samandla okungqubuzana kwe-kinetic siphambene nesiqondiso sokufuduka.

Ushintsho kumandla e-kinetic:

ΔEK = 1/2 m (v_t² - v_o²) = 1/2 (1)(10² - 0) = 1/2 (10²) = 1/2 (100= = 50

Ushintsho emandleni angaba khona:

Δ EP = mg (h _t – ho ₎ = (1)(10)(0-h) = (10)(-h) = -10 h

Umgomo wamandla okusebenza nowokusebenza:

W _nc = Δ EK + Δ EP

– 30 = 50 – 10 amahora

Amahora ayi-10 = 50 + 30

Amahora ayi-10 = 80

h = 80/10

h = 8 m

4Uma ibhlogo lihamba phansi endaweni ethambekele kakhulu, khona-ke….
A. Umsebenzi owenziwa ngamandla adonsela phansi ebhulokini mkhulu kunoshintsho lwamandla angaba khona ebhulokini.
B. Amandla omshini ayanda
C. Inani lamandla e-kinetic kanye namandla akhona ancishisiwe
D. Umsebenzi wenziwa ngamandla okungqubuzana alingana noshintsho lwamandla e-kinetic ebhulokhi
Isixazululo

U-A unephutha

Umsebenzi owenziwa ngamandla adonsela phansi ebhulokini ulingana noshintsho emandleni adonsela phansi ebhulokini.

U-B unephutha

Uma indiza efakwe ngaphakathi ibushelelezi khona-ke amandla omshini webhloko ahlala njalo. Uma iphezulu kwendiza ethambekele futhi ingakahambi, amandla omshini webhloko alingana namandla okudonsa amandla adonsela phansi. Ibhloko lisaphumule ngakho amandla alo e-kinetic ayi-zero. Uma lihamba phansi kwendiza ethambekele, ukuphakama kwebhloko kuyancishiswa ngakho amandla okudonsa amandla adonsela phansi nawo ayancishiswa. Amandla okudonsa amandla adonsela phansi ayancipha ngoba ashintsha abe amandla e-kinetic. Nakuba amandla okudonsa amandla aguquka abe amandla e-kinetic, amandla omshini ahlala njalo.

Uma indiza ethambekele ilukhuni khona-ke amandla omshini ebhulokhi ayancipha ngenxa yomsebenzi ongemuhle owenziwa amandla omshini. Amandla omshini angamandla angalondolozi. Umsebenzi owenziwa amandla angalondolozi entweni ubangela ukuba amandla omshini ento anciphe.

U-C ulungile

Indiza ethambekele ilukhuni ngakho-ke kukhona amandla okungqubuzana aphonsela inselelo ukunyakaza kwebhlokhi. Amandla okungqubuzana angamandla angaguquki. Amandla okusebenza-omshini we-theorem athi umsebenzi owenziwa amandla angaguquki (isibonelo amandla okungqubuzana) ulingana noshintsho lwamandla omshini. Kulokhu kuphishekela, amandla omshini ayancipha.

Amandla omshini ebhulokhi = amandla adonsela phansi + amandla e-kinetic.

U-D unephutha.

Umsebenzi owenziwa amandla okungqubuzana ebhulokini ulingana noshintsho lwamandla omshini webhulokhi, hhayi ushintsho lwamandla okungqubuzana ebhulokhi. Kuyiqiniso ukuthi amandla okungqubuzana aphonsela inselelo ukunyakaza kwebhulokhi ngakho-ke anciphisa ijubane lebhulokhi futhi anciphise amandla okungqubuzana ebhulokhi. Kodwa qaphela ukuthi amandla okungqubuzana ebhulokhi avela emandleni anamandla adonsela phansi. Ngakho-ke kuyiqiniso ukuthi umsebenzi wenziwa amandla okungqubuzana alingana noshintsho lwamandla omshini (amandla omshini ayancipha).

Impendulo efanele ithi C.

5. Into ephansi eliqinile iyashaywa ukuze inyakaze imizuzwana emi-3 bese iyama. Uma isisindo esaziwayo sale nto singamagremu ayi-10, amandla okungqubuzana phakathi kwento nephansi angamakhiloyne ama-2. Thola umsebenzi owenziwe amandla okungqubuzana.

A. 0.18 J

B. -0.18 J

C. 0.36 J

D. -0.36 J

Kwaziwa:

Isikhawu sesikhathi (t) = imizuzwana eyi-3

Isivinini sokugcina (v _t ) = 0 m/s (ukuphumula kwezinto)

Isisindo sento (m) = 10 amagremu = 10/1000 kg = 1/100 kg = 0.01 kg

I-Friction force (F) = 2 kilodynes = 2 x 10 ^{3 ama} -dynes

Okufunwayo: Umsebenzi (W) owenziwe ngamandla okungqubuzana

Isixazululo:

Ukuguqulwa kwamayunithi amandla:

1 Newton = 1 x 10 ⁵ dyne

I-dyne eyi-1 = 1 / 10 ⁵ AmaNewton = 1 x 10 ^-5 AmaNewton = 10 ^-5 AmaNewton

Amandla okungqubuzana (F) = 2 x 10 ³ dyne = 2 x 10 ³ x 10 ^-5 Newton = 2 x 10 ^-2 Newton = 2/100 Newton = 0.02 Newton

I-Theorem work-mechanical energy ithi umsebenzi wenziwa ngamandla angewona awokugcina entweni elingana noshintsho emandleni okusebenza ento.

Uma into ihamba endizeni ethambekele khona-ke amandla omshini (ME) = amandla adonsela phansi (PE) + amandla omshini (KE). Kodwa uma into ihamba endizeni evundlile ukuze kungabikho ushintsho ekuphakameni, amandla omshini = amandla omshini. Endizeni evundlile, amandla adonsela phansi ayi-zero ngoba akukho ushintsho ekuphakameni.

Amandla okungqubuzana angamandla angaguquki. Amandla okungqubuzana avame ukunciphisa ijubane lento kanye namandla okuhambahamba kwento. Angaphetha ngokuthi umsebenzi owenziwa amandla okungqubuzana entweni ulingana nokwehla kwamandla omshini.

Ngokwezibalo:

Umsebenzi (W) = Ushintsho lwamandla omshini (ΔEM)

F s = ΔEP + ΔEK

F s = mg Δh + ½ m (v _t ² – _vo ² )

F s = mg (0) + ½ m (0 ² – _vo ² )

Fs = 0 + ½ m (– (v _o ² ))

F s = – ½ mv _o ² ———— Isibalo 1

Incazelo: F = amandla okungqubuzana, d = ukufuduka, m = isisindo, v _o = isivinini sokuqala

Ukufuduka (d) kanye nesivinini sokuqala (vo _o ) akukaziwa okwamanje ngoba kuqala bala u-v _o noma u-d. Umsebenzi owenziwe ngamandla okungqubuzana ubalwe kusetshenziswa esinye sezibalo ngemuva kuka-v _o noma u-d owaziwayo.

Isibalo sokufuduka (d) ekuhambeni okuqondile okungalingani:

v _t ² = vo ₂ ⁺ 2 (-a) s

Isivinini sokugcina (v _t ) = 0 kanye nokusheshisa (a) kusayinwe ngokuthi kuphambene ngoba into yehlisiwe (isivinini sento sinciphile).

0 = v_o² – izikhangiso ezi-2

v_o² = isikhangiso esingu-2

d = v _o ^2/2 a———— Isibalo 2

Shintsha u-d ku-equation 2 no-d ku-equation 1:

F d = – ½ mv _o ²

F (v _o ² /2a) = – ½ mv _o ²

(F/2a) v _o ² = – ½ mv _o ²

F/2a = – ½ m

F = (2)(a)(-1/2)(m)

F = – (a)(m)

a = – (F / m)

a = – 0.02 Newtons / 0.01 kg

a = – 2 Newton/kg

a = – 2 m/s ²

Isibalo sokubala isivinini sokuqala (v _o ) ekuhambeni okuqondile okungalingani:

v _t = vo _o + at —–> Isivinini sokugcina (v _t ) = 0, Ukusheshisa (a) = 2 m/s ² , isikhawu sesikhathi (t) = imizuzwana emi-3

0 = vo ₊ (-2)(3)

0 = v _o – 6

v _o = amamitha ayi-6/umzuzwana

Umsebenzi (W) owenziwe ngamandla okungqubuzana:

W = – ½ mv _o ² = -1/2 (0.01)(6 ² ) = -1/2 (0.01)(36)

W = -1/2 (0.36)

W = – 0.18 Joule

Umsebenzi owenziwe amandla okungqubuzana usayinwe ungemuhle okusho ukuthi umsebenzi wehlisa amandla okusebenza ento.

Uma kwaziwa ukuthi u-d umsebenzi ungabalwa kusetshenziswa i-equation ka- W = F d.

Impendulo efanele ngu-B.

[wpdm_package id='1178′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

Amandla e-Work-Kinetic :

1. Imoto enesisindo esingama-5000 kg isheshiswe ukusuka ekuphumuleni iye kuma-20 m/s. Nquma umsebenzi ophelele owenziwe emotweni.

Kwaziwa:

Isisindo (m) = 5000 kg

Isivinini sokuqala (v _o ) = 0 m/s ( ukuphumula kwemoto )

Isivinini sokugcina (v _t ) = 20 m/s

Okufunwayo : inethiwekhi

Isixazululo:

Umgomo wamandla okusebenza-kinetic :

I-W _inethi = Δ EK

W _inetha = ½ m (v _t ² – v _o ² )

I-W _inethi = umsebenzi wenethi

Δ EK = ushintsho lwamandla e-kinetic

m = isisindo (kg),

v _t = isivinini sokugcina (m/s),

v _o = isivinini sokuqala (m/s).

Inethiwekhi:

W _inetha = ½ m (v _t ² – v _o ² )

W _inetha = ½ (5000)(20 ² – 0 ² )

I-W _inethi = (2500)(400 - 0)

I-W _inethi = (2500)(400)

I-W _inethi = 1000,000 Joule

2. Into enesisindo esingu-10 kg isheshiswe kusuka ku-5 m/s kuya ku-10 m/s. Nquma umsebenzi wenethi owenziwe entweni!

Kwaziwa:

Isisindo (m) = 10 kg

Isivinini sokuqala (v _o ) = 5 m/s

Isivinini sokugcina (v _t ) = 10 m/s

Okufunwayo : inethiwekhi

Isixazululo:

Inethiwekhi:

I-W _inethi = Δ EK

W _inetha = ½ m (v _t ² – v _o ² )

W _inetha = ½ (10)(10 ² – 5 ² )

I-W _inethi = (5)(100 - 25)

I-W _inethi = (5)(75)

I-W _inethi = 375 Joule

3. Imoto enesisindo esingama-2000 kg yehla ngesivinini kusuka ku-10 m/s kuya ku-5 m/s. Yimuphi umsebenzi owenziwayo emotweni?

Kwaziwa:

Isisindo semoto (m) = 2000 kg

Isivinini sokuqala (v _o ) = 10 m/s

Isivinini sokugcina (v _t ) = 5 m/s

Okufunwayo: inethiwekhi

Isixazululo:

Inethiwekhi:

I-W _inethi = Δ EK

W _inetha = ½ m (v _t ² – v _o ² )

W _inetha = ½ (2000)(5 ² – 10 ² )

I-W _inethi = (1000)(25 - 100)

I-W _inethi = (1000)(-75)

I-W _inetha = -75,000 amaJoule

Uphawu lokususa lubonisa ukuthi indlela yokufuduka iphambene nendlela yamandla e-net.

4. Amandla angaguquki angu-60-N asetshenziswa entweni engu-10-kg imizuzwana eyi-12. Ijubane lokuqala lento lingu-6 m/s futhi isiqondiso sento sifana nesiqondiso samandla.

(1) Umsebenzi owenziwe kule nto ungama-Joules angu-30,240

(2) Amandla okugcina e-kinetic angama-30,240 joules

(3) Amandla angama-2,520 Watt

(4) Ukwanda kwamandla e-kinetic ento kungama-Joules ayi-180

Izitatimende eziqondile zithi…

Kwaziwa:

Amandla (F) = 60 N

Isikhawu sesikhathi (t) = imizuzwana eyi-12

Isisindo sento (m) = 10 kg

Ijubane lokuqala (v _o ) = 6 m/s

Okufunwayo: Izitatimende ezifanele

Isixazululo:

Ukusheshisa kwento:

∑F = ma

60 = 10 a

a = 60 / 10 = 6 m/s ²

Ijubane lokugcina:

v _t = vo _o + at

v _t = 6 + (6)(12)

v _t = 6 + 72

v _t = 78 m/s

Ibanga elihanjiwe ngemizuzwana eyi-12 :

s = vot ₊ 1/2 ku- ²

s = (6)(12) + 1/2 (6)(12) ²

s = 72 + (3)(144)

s = 72 + 432

s = amamitha ayi-504

(1) Umsebenzi owenziwe ngenkani

W = F s = (60)(504) = 30,240 amaJoules

(2) Amandla okugcina e-kinetic

KE = 1/2 mv _t ² = 1/2 (10) (78) ² = (5) (6084) = 30,420 Joules

(3) Amandla

P = W / t = 30,240 / 12 = 2,520 amaJoules/isekhondi

(4) Ukwanda kwamandla e-kinetic

ΔKE = 1/2 mv _t ² – 1/2 mv _o ² = 1/2 m (v _t ² – v _o ² ) = 1/2 (10)(78 ² – 6 ² ) = 5 (6084 –36) = 5 (6048)

I-ΔKE = 30,240 amaJoule

5. Umsebenzi omkhulu wenziwa ngenombolo yento…

Isixazululo:

Umsebenzi we-Net = ushintsho lwamandla e-kinetic

W _inetha = ½ m (v _t ² – v _o ² )

Umsebenzi omkhulu:

W ₁ = ½ (8)(4 ² – 2 ² ) = (4)(16 – 4) = (4)(12) = 48 Ama-Joules

W ₂ = ½ (8)(5 ² –3 ² ) = (4)(25 – 9) = (4)(16) = 64 Ama-Joules

W ₃ = ½ (10)(6 ² – 5 ² ) = (5)(36 – 25) = (5)(11) = 55 Ama-Joules

W ₄ = ½ (10)(4 ² – 0 ² ) = (5)(16 – 0) = (5)(16) = 80 Ama-Joules

W ₅ = ½ (20)(3 ² – 3 ² ) = (10)(9 – 9) = (10)(0) = 0 Ama-Joules

6. Imoto enesisindo esingamakhilogremu angu-4000 ihamba ngomugqa oqondile ngesivinini esingama-25 m/s. Imoto yehliswa ukuze ijubane lokugcina lemoto libe ngu-15 m/s. Uyini umsebenzi owenziwe emotweni?

Kwaziwa:

Isisindo (m) = 4000 kg

Ijubane lokuqala (v _o ) = 25 m/s

Ijubane lokugcina (v _t ) = 15 m/s

Okufunwayo : Umsebenzi owenziwe emotweni

Isixazululo:

I-W _inethi = ½ m (v _t ² – vo ₂ ⁾ = ½(4000)(15 ² -25 ² ) = (2000)(225-625) = (2000)(-400) = -800,000 Ama-Joules = -800 kJ

7. I-0.1-kg ephonswe ngokuvundlile ku-6 m/s ukusuka ekuphakameni kwamamitha ama-5. Uma ukusheshisa kwamandla adonsela phansi kungu-10 m/s ² , khona-ke iyini amandla e-kinetic ebhola ekuphakameni kwamamitha ama-2.

Kwaziwa:

Isisindo (m) = 0.1 kg

Ushintsho lokuphakama (h) = 5 m – 2 m = 3 amamitha

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Amandla e-kinetic ekuphakameni kwamamitha amabili.

Isixazululo:

Ukunyakaza okubonakalayo kungaqondwa ngokuhlaziya izingxenye ezivundlile neziqondile zokunyakaza ngokwehlukana. Ukunyakaza okuvundlile kuhlaziywe njengokunyakaza kwejubane okungaguquki kanye nokunyakaza okuvundlile kuhlaziywe njengokunyakaza kokuwa kwamahhala noma ukunyakaza okuvundlile.

Amandla okuqala omshini = amandla adonsela phansi anamandla adonsela phansi.

I-PE = mgh = (0.1)(10)(3) = 3 amaJoules.

Amandla okugcina omshini = amandla e-kinetic.

KE = 3 amaJoules.

8. Imoto enesisindo esingamakhilogremu ayi-1000 ishesha kakhulu uma iphumula futhi ihamba ngesivinini esingama-5 m/s. Uyini umsebenzi owenziwa yimoto?

Kwaziwa:

Isisindo (m) = 1000 kg

Ijubane lokuqala (v _o ) = 0

Ijubane lokugcina (v _t ) = 5 m/s

Okufunwayo: Umsebenzi (W) owenziwa ngemoto

Isixazululo:

W _inetha = ½ m (v _t ² – v _o ² )

Umsebenzi owenziwe ngemoto:

I-W _inethi = ½ (1000)(5 ² – 0 ² ) = (500)(25 – 0) = (500)(25) = 12,500 amaJoules

9. Ibhola elingamagremu angu-500 liphonswa phezulu phezulu lisuka ebusweni bomhlaba ngesivinini sokuqala esingu-10 m/s ² . Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms ^-2 . Uyini umsebenzi owenziwa amandla esisindo lapho ibhola lifinyelela ukuphakama okuphezulu.

Kwaziwa :

Isisindo sebhola (m) = amagremu angu-500 = 0.5 kg

Ijubane lokuqala (v _o ) = 10 m/s ²

Ijubane lokugcina (v _t ) = 0 (ijubane endaweni ephezulu kakhulu)

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Umsebenzi (W) don ngesisindo

Isixazululo:

Umsebenzi we-net owenziwe ngamandla e-net entweni = ushintsho kumandla e-kinetic.

I-W _inethi = ΔEK = EK _t – EK _o

I-Wnet = ½ mv _t ² – ½ mv _o ² = ½ m (v _t ² – v _o ² )

I-KE _t = amandla okugcina e-kinetic, i-KE _o = amandla okuqala e-kinetic, m = isisindo sento, v _t = ijubane lokugcina lento, v _o = ijubane lokuqala lento.

Inethiwekhi:

W _inetha = ½ m (v _t ² – v _o ² ) = ½ (0.5)(0 ² – 10 ² )

I-W _inethi = (0.25)(-100) = -25 Ama-Joule

Uphawu lokususa lubonisa ukuthi indlela yokugudluka iphambene nesisindo sebhola. Indlela ibhola elibheke ngayo iqondile kanti indlela yesisindo iqondile.

10. Into enesisindo esingu-1 kg iyawa ngomehluko wokuphakama = amamitha angu-2.5. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms ^-2 . Uyini umsebenzi owenziwayo entweni?

Kwaziwa:

Isisindo sebhola (m) = 1 kg

Ijubane lokuqala (v _o ) = 0 m/s

Ukuphakama (h) = amamitha angu-2.5

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Umsebenzi we-inthanethi ngesikhathi sokufuduka

Isixazululo:

Ijubane lokugcina lebhola (v _t )

Kubalwa kusetshenziswa i-equation yokunyakaza kokuwa okukhululekile. Okuyaziwayo: Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ² , Ushintsho ekuphakameni kwebhola (h) = amamitha angu-2.5. Okufunwayo: Ijubane lokugcina.

v _t ² = 2 gh = 2(10)(2.5) = 2(25)

v _t = √2(25)

v _t = 5√2

Umsebenzi we-Net = ushintsho lwamandla e-kinetic

W _inetha = ΔEK = ½ m (v _t ² – v _o ² ) = ½ (1){(5√2) ² – 0 ² }

I-W _inethi = ½ (25)(2) = 25 amaJoule

11. Into engamakhilogremu angu-2 ihamba ngesivinini esingamakhilomitha angu-72 ngehora. Ngemva kokuhamba amamitha angu-400, ijubane lokugcina lento lingu-144 km ngehora. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms ^-2 . Thola umsebenzi wenethi.

Kwaziwa:

Isisindo sento (m) = 2 kg

Ijubane lokuqala (v _o ) = 72 km/ihora = 20 m/s

Ijubane lokugcina (v _t ) = 144 km/h = 40 m/s

Ibanga (ama) = amamitha angu-400

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Inethiwekhi

Isixazululo:

Umsebenzi we-net = izinguquko zamandla e-kinetic

W _inetha = ΔEK = ½ m (v _t ² – v _o ² ) = ½ (2)(40 ² – 20 ² }

I-W _inetha = ½ (2)(1600 - 400) = 1200 amaJoules

12. Into engamakhilogremu angu-2 ihamba ngesivinini esingu-2 ms ^–1 . Umsebenzi owenziwe entweni ungama-Joules angu-21. Iyini ijubane lokugcina lento.

Kwaziwa:

Isisindo (m) = 2 kg

Ijubane lokuqala (v _o ) = 2 m/s

Umsebenzi (W) = 21 Joule

Okufunwayo: ijubane lokugcina (v _t )

Isixazululo:

I-W _inethi = ΔEK

I-W _inethi = 1/2 mv _t ² -1/2 mv _o ²

I-W _inetha = 1/2 m (v _t ² – v _o ² )

21 = 1/2 (2) (v _t ² – 2 ² )

21 = (v _t ² – 2 ² )

21 = v _t ² – 4

v _t ² = 21 + 4 = 25

v _t = √25

v _t = 5 m/s

1 3. Amandla angaguquki angu-8 N asebenza entweni enesisindo esingu-16 kg. Uma into iqale iphumule, khona-ke nquma ijubane lento ngemva kokuba amandla esebenza entweni imizuzwana emi-4.

Kwaziwa:

Amandla angaguquki (F) = 8 Newton

Isisindo sento (m) = 16 kg

Isivinini sokuqala sento (v _o ) = 0 m/s

Isikhawu sesikhathi amandla asebenza entweni (t) = imizuzwana emi-4

Okufunwayo: Isivinini sokugcina (v _t )

Isixazululo:

Umsebenzi = Ushintsho emandleni e-kinetic

W = KE final – KE initial

W = ½ mv _t ² – ½ mv _o ²

W = ½ mv _t ² – 0

W = ½ mv _t ² —— Isibalo 1

Umsebenzi = Amandla x Ukufuduka

W = F d

W = 8 d

Sebenzisa i-equation yokunyakaza okuqondile okungalingani ngezansi ukuze ubale ukufuduka (d):

d = vot ₊ ½ ku- ²

d = ukufuduka, v _o = ijubane lokuqala, t = isikhawu sesikhathi, a = ukusheshisa

d = 0 + ½ ku- ² = ½ ku- ² —-> a = (v _t – vo _o ) / t = v _t / t

d = ½ (v _t / t) t ²

^d = ½ (v _t ) t

Shintsha ukufuduka (d) ku-equation ethi Umsebenzi ngokufuduka (d) kulesi sibalo:

W = 8 d

W = 8(1/2)(v _t )(t)

W = (4)(v _t )(t) —— isibalo 2

Isibalo 1 = Isibalo 2

W = W

½ mv _t ² = (4)(v _t )(t)

½ mv _t = (4)(t)

½ (16)(v _t ) = 4(4)

8 v _t = 16

v _t = 16/8

v _t = 2 amamitha/umzuzwana

14. Ukuze wandise ijubane lento ibe izikhathi ezimbili zejubane lokuqala, nquma umsebenzi odingekayo enkambisweni…

Kwaziwa:

Isisindo sento (m) = 1 kg

Isivinini sokuqala (v _o ) = 1 m/s

Isivinini sokugcina (v _t ) = 2 x isivinini sokuqala = 2 x 1 = 2 m/s

Okufunwayo: Umsebenzi

Isixazululo:

Amandla okuqala e-kinetic:

KE isiqalo = ½ mv _o ² = ½ (1)(1) ² = ½ (1)(1) = ½ (1) = 0.5

Amandla okugcina e-kinetic lapho ijubane lento liba kabili kunejubane layo lokuqala:

KUYA kokugcina = ½ mv _t ² = ½ (1)(2) ² = ½ (4) = 2

Ithiyori yamandla okusebenza-kinetic:

Umsebenzi = Ushintsho lwamandla e-kinetic

Umsebenzi = Amandla okugcina e-kinetic – amandla okuqala e-kinetic

Umsebenzi = 2 – 0.5

Umsebenzi = 1.5

Amandla okuqala e-kinetic = 0.5

Umsebenzi = 3 x 0.5 = 1.5

Umsebenzi odingekayo izikhathi ezintathu zamandla ayo okuqala e-kinetic.

15. Imoto enesisindo esingu-1500 kg ihamba ngesivinini esingu-36 km/ihora emgwaqweni oqondile nobushelelezi ovundlile. Imoto isheshise yafika ku-72 km/ihora. Thola umsebenzi odingekayo ukuze imoto isheshise.

Kwaziwa:

Isisindo semoto (m) = 1500 kg

Isivinini sokuqala semoto (v _o ) = 36 km/ihora = 36,000 amamitha / 3600 isekhondi = 10 amamitha/isekhondi

Isivinini sokugcina semoto (v _t ) = 72 km/ihora = 72,000 amamitha / 3600 imizuzwana = 20 amamitha/isekhondi

Kufunwa: Kudingeka umsebenzi ukuze kusheshiswe imoto

Isixazululo:

Ithiyori yamandla okusebenza-kinetic:

W = EK final – isiqalo se-EK

W = ½ mv _t ² – ½ mv _o ² = ½ m (v _t ² –v _o ² )

W = ½ (1500)(20 ² – 10 ² )

W = ½ (1500)(400 - 100)

W = ½ (1500)(300)

W = (1500)(150)

W = amaJoules angu-225,000

16. Into enesisindo esingu-2 kg iqala ukuhamba ngesivinini esingu-72 km. ihora ^-1 . Ngemva kokuhamba emgwaqweni oqondile ovundlile kuze kufike ku-400 m, ijubane lento lingu-144 km . ihora ^-1 . Thola umsebenzi ophelele entweni.

Kwaziwa:

Isisindo sento (m) = 2 kg

Isivinini sokuqala (v _o ) = 72 km/ihora = 72,000 amamitha / 3600 imizuzwana = 20 m/s

Isivinini sokugcina (v _t ) = 144 km/ihora = 144,000 amamitha / 3600 imizuzwana = 40 m/s

Ukufuduka kwento = amamitha angu-400

Okufunwayo: Umsebenzi we-inthanethi entweni

Isixazululo:

Ithiyori yamandla okusebenza-kinetic ithi umsebenzi wenethi usebenza entweni ngendlela efanayo nokushintsha kwamandla okusebenza kwento.

I-W inethi = IYA kokugcina – IYA kokuqala

I-W inethi = ½ mv _t ² – ½ mv _o ²

W inetha = ½ m (v _t ² – v _o ² )

W inetha = ½ (2)(40 ² – 20 ² )

I-W inethi = 1600 – 400

I-W inethi = 1200 Joule

incazelo:

W = Umsebenzi, KE = amandla e-kinetic

Amandla weKinetic

17. Inhlamvu engamagremu ayi-10 ehamba ngesivinini esingaguquki esingu-100 m/s. Iyini amandla e-kinetic enhlamvu.

Kwaziwa:

Isisindo senhlamvu (m) = amagremu ayi-10 = 10/1000 amakhilogremu = 1/100 amakhilogremu = 0.01 amakhilogremu

Isivinini senhlamvu (v) = amamitha ayi-100/umzuzwana

Okufunwayo: Amandla e-Kinetic

Isixazululo:

I-KE = 1/2 mv ²

I-KE = 1/2 (0,01 kg)(100 m/s) ²

KE = 1/2 (0,01 kg)(10.000 m ² /s ² )

KE = (0,01 kg)(5000 m ² /s ² )

KE = 50 kg m ² /s ²

KE = 50 amaJoule

[wpdm_package id='1191′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe ebusweni obugobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Umuntu udonsa ibhlogo elingamamitha amabili endaweni evundlile ngamandla angaguquki F = 20 N. Thola umsebenzi owenziwe ngamandla F osebenza kubhlogo.

Kwaziwa:

Amandla (F) = 20 N

Ukufuduka (s) = 2 m

I-engeli (θ ) = 0

Okufunwayo : Umsebenzi (W)

Isixazululo:

W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joule

2. Amandla F = 10 N asebenza ebhokisini eliyi-1 m eduze kwendawo evundlile. Amandla asebenza nge-engeli engama-30 ^o njengoba kuboniswe esithombeni esingezansi. Thola umsebenzi owenziwe ngamandla F!

Kwaziwa :

Amandla (F) = 10 N

Amandla avundlile (F _x ) = F cos 30 ^o = (10)(0.5√3) = 5√3 N

Ukufuduka (d) = 1 imitha

Ufunwa : Umsebenzi (W)?

Isixazululo :

W = F _x d = (5√3)(1) = 5√3 AmaJoules

3. Umzimba uwela ngokukhululeka ekuphumuleni, kusukela ekuphakameni kwamamitha amabili. Uma ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ² , nquma umsebenzi owenziwe ngamandla adonsela phansi!

Kwaziwa:

Isisindo sento (m) = 1 kg

Ukuphakama (h) = 2 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Umsebenzi owenziwe ngamandla adonsela phansi (W)

Isixazululo:

W = F d = wh = mgh

W = (1)(10)(2) = 20 amaJoule

W = umsebenzi, F = amandla, d = ibanga, w = isisindo , h = ukuphakama, m ​​= isisindo, g = ukusheshisa ngenxa yamandla adonsela phansi.

4. Into enesisindo esingu-1 kg inamathele esiphethwini ukuze inwetshwe ngo-2 cm. Uma ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ² , nquma (a) i-spring constant (b) umsebenzi owenziwe ngamandla esiphethwini entweni

Kwaziwa:

Isisindo (m) = 1 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Ubude (x) = 2 cm = 0.02 m

Isisindo (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Okufunwayo: I-Spring constant kanye nomsebenzi owenziwe yi-spring force

Isixazululo:

(a) I-constant yasentwasahlobo

Ifomula yomthetho kaHooke :

F = k x.

k = F / x = w / x = mg / x

k = (1)(10) / 0.02 = 10 / 0.02

k = 500 N/m

(b) umsebenzi owenziwe ngamandla entwasahlobo

W = – ½ kx ²

W = – ½ (500)(0.02) ²

W = – (250)(0.0004)

W = -0.1 Joule

Uphawu lokususa lubonisa ukuthi isiqondiso samandla entwasahlobo siphambene nesiqondiso sokufuduka kwento.

5. Amandla F = 10 N asheshisa ibhokisi phezu kokuhamba okungu-2 m. Iphansi liqinile futhi linamandla okungqubuzana F _k = 2 N. Thola umsebenzi wenethi owenziwe ebhokisini.

Kwaziwa:

Amandla (F) = 10 N

Amandla okungqubuzana kwe-kinetic (F _k ) = 2 N

Ukufuduka (d) = 2 m

Okufunwayo: Inethiwekhi (i-W _net )

Isixazululo:

Umsebenzi owenziwe ngenkani F:

W ₁ = F d cos 0 = (10)(2)(1) = 20 amaJoules

Umsebenzi owenziwe ngamandla okungqubuzana kwe-kinetic (F _k ):

W ₂ = F _k d = (2)(2)(cos 180) = (2)(2)(-1) = -4 AmaJoules

Inethiwekhi:

I-W _inethi = W ₁ – W ₂

I-W _inethi = 20 – 4

I-W _inethi = 16 Joule

6. Uyini umsebenzi owenziwe ngenkani u-F ebhlokini?

Kwaziwa:

Amandla (F) = 12 Newton

Ukufuduka (d) = amamitha angu-4

Okufunwayo: Umsebenzi (W)

Isixazululo:

W = F d = (12 Newton)(amamitha angu-4) = 48 N m = 48 Joules

7. Ibhlokhi licindezelwa ngamandla angu-200 N. Ukuhamba kwebhlokhi kungamamitha ama-2. Uyini umsebenzi owenziwayo ebhlokhini?

Kwaziwa:

Amandla (F) = 200 Newton

Ukufuduka (d) = amamitha angu-2

Okufunwayo: Umsebenzi (W)

Isixazululo:

Umsebenzi:

W = F s

W = (200 Newton)(amamitha ama-2)

W = 400 N m

W = 400 Joule

8. Umshayeli we-sedan ufuna ukupaka imoto yakhe ngqo phambi kweloli elingamamitha ayi-0.5, okuyimitha eyi-10 ukusuka endaweni ye-sedan. Yimuphi umsebenzi odingwa yi-sedan?

Kwaziwa:

Ukufuduka (d) = amamitha ayi-10 – amamitha angu-0.5 = amamitha angu-9.5

Amandla (F) = 50 Newton

Okufunwayo: Umsebenzi (W)

Isixazululo:

W = F s

W = (50 Newton)(amamitha ama-9.5)

W = 475 N m

W = 475 Joule

9.

Umsebenzi owenziwe nguTom noJerry ukuze imoto ikwazi ukuhamba ibanga elingafika kumamitha angu-4. Amandla asetshenziswa nguTom noJerry angama-50 N kanye nama-70 N.

Kwaziwa:

Ukufuduka (ama) = amamitha angu-4

Amandla aphelele (F) = 50 Newtons + 70 Newtons = 120 Newtons

Okufunwayo: Umsebenzi (W)

Isixazululo:

W = F s = (120 Newton)(4 amamitha) = 480 N m = 480 Joules

10. Umshayeli udonsa imoto ukuze imoto ihambe ibanga elingafika ku-1000 cm. Yini eyenziwayo emotweni?

Kwaziwa:

Amandla (F) = 250 Newton

Ukufuduka (ama) = 1000 cm = 1000/100 amamitha = 10 amamitha

Okufunwayo: Umsebenzi (W)

Isixazululo:

W = F s = (250 Newton)(10 amamitha) = 2500 N m = 2500 Joules

11. Ngokusekelwe esithombeni esingezansi, uma umsebenzi owenziwe ngamandla e-net ungama- Joules angu-375, nquma ukufuduka kwento.

Kwaziwa:

Umsebenzi (W) = 375 Joule

Amandla engqikithi ( ΣF) = 40 N + 10 N – 25 N = 25 Newtons ( kwesokudla )

Kufunwa: Ukufuduka ( d )

Isixazululo:

Isilinganiso somsebenzi:

W = F s

Ukufuduka kwento:

d = W / F = 375 Joules / 25 Newtons

d = amamitha ayi-15 s

12. Imisebenzi engezansi engasebenzi yilena …

A. Cindezela into kuze kufike kumamitha ayi-10

B. Cindezela imoto ize ihambe

C. Cindezela udonga

D. Wadonsa ibhokisi

Isixazululo:

Isilinganiso somsebenzi:

W = ΣF s

W = umsebenzi , F = amandla , d = ukufuduka

Ngokusekelwe kufomula engenhla, umsebenzi wenziwa ngenkani futhi kukhona ukufuduka.

Impendulo efanele ithi C.

1 3. U-Andrew usunduza into ngamandla angu-20 N ukuze into ihambe ngokunyakaza okujikelezayo okunerediyasi yamamitha angu-7. Thola umsebenzi owenziwe ngu-Andrew wokunyakaza okujikelezayo okuphindwe kabili.

A. 0 Joule

B. 1400 Joule

C. 1540 Joule

D. 1760 Joule

Isixazululo:

Uma umuntu esunduza isihlalo sabakhubazekile ukunyakaza okuphindwe kabili, umuntu kanye nesihlalo sabakhubazekile babuyela endaweni yokuqala, ngakho-ke ukugudluzwa komuntu kungu-zero.

Ukufuduka = ​​0 ngakho-ke umsebenzi = 0.

Impendulo eyiyo ngu-A.

14. Othile usunduza into phansi ngamandla angu-350 N. Iphansi linamandla okungqubuzana angu-70 N. Thola umsebenzi owenziwe ngamandla ukuze uhambise into kude kufike kumamitha ayi-6.

A. 45 J

B. 72 J

C. 1680 J

D. 2580 J

Kwaziwa:

Amandla okusunduza (F) = 350 Newtons

Amandla okungqubuzana (F _fric ) = 70 Newtons

Ukufuduka kwento (izinto) = amamitha ayi-6

Okufunwayo: Umsebenzi (W)

Isixazululo:

Kunamandla amabili asebenza entweni, amandla okusunduza (F) kanye namandla okusunduza (F _fric ). Amandla okusunduza anesiqondiso esifanayo nokusunduza kwento ngoba amandla okusunduza enza umsebenzi omuhle. Ngakolunye uhlangothi, amandla okusunduza anesiqondiso esiphambene nokusunduza kwento ukuze amandla okusunduza enze umsebenzi omubi.

Umsebenzi owenziwe ngamandla okusunduza:

W = F d = (350 Newton)(amamitha ayi-6) = 2100 Newton-meters = 2100 Joules

Umsebenzi owenziwe ngamandla okungqubuzana:

W = – (F _fric )(s) = – (70 Newton)(6 amamitha) = – 420 Newton-amamitha = – 420 Joules

Inethiwekhi:

I-W inetha = amaJowule angu-2100 – amaJowule angu-420

I-W inethi = 1680 Joule

Impendulo efanele ithi C.

15. Into icindezelwa ngamandla avundlile angama-Newton angu-14 phansi okuqinile ngamandla okungqubuzana angama-Newton angu-10. Thola umsebenzi wenethi wokuhambisa into kuze kufike kumamitha angu-8.

A. 0.5 Joule

B. 3 Joule

C. 32 Joule

D. 192 Joule

Kwaziwa:

Amandla okusunduza (F) = 14 Newton

Amandla okungqubuzana (F _fric ) = 10 Newtons

Ukufuduka kwento (d) = amamitha angu-8

Okufunwayo: Umsebenzi (W)

Isixazululo:

Kunamandla amabili asebenza entweni, amandla okusunduza (F) kanye namandla okungqubuzana (F _fric ).

Amandla okusunduza anesiqondiso esifanayo nokusunduza kwento ukuze amandla okusunduza enze umsebenzi omuhle. Ngakolunye uhlangothi, amandla okusunduza anesiqondiso esiphambene nokusunduza kwento ukuze amandla okusunduza enze umsebenzi omubi.

Umsebenzi owenziwe ngamandla okusunduza:

W = F s = (14 Newton)(amamitha angu-8) = 112 Newton amamitha = 112 Joules

Umsebenzi owenziwe ngamandla okungqubuzana:

W = – (F _fric )(s) = – (10 Newton)(amamitha angu-8) = – 80 Newton amamitha = – 80 Joules

Inethiwekhi:

I-W inetha = amaJowule angu-112 – amaJowule angu-80

I-W inethi = 32 Joule

Impendulo efanele ithi C.

16. Thola umsebenzi we-net ngokusekelwe kumfanekiso ongezansi.

A. 360 Joule

B. 450 Joule

C. 600 Joule

D. 750 Joule

Isixazululo:

Umsebenzi = Amandla (F) x ukufuduka (d)

Umsebenzi = Indawo kanxantathu 1 + indawo kanxantathu + indawo kanxantathu 2

Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)

Umsebenzi = 1/2(40)(3) + (40)(6) + 1/2(40)(3)

Umsebenzi = (20)(3) + 240 + (20)(3)

Umsebenzi = 60 + 240 + 60

Umsebenzi = ama-Joule angu-360

Impendulo eyiyo ngu-A.

17. Ucezu lokhuni olunobude obungu-60 cm luxhunywe phansi. Ukhuni lushaywa ngesando esingamakhilogremu angu-10 ukusuka ekuphakameni okungama-40 cm ngaphezu kwengaphezulu kokhuni. Uma amandla okumelana ajwayelekile omhlabathi engu-2 x 10 3 ^N futhi ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ² , khona-ke ukhuni luzongena ngokuphelele emhlabathini ngemva kokushaya….

A. 4

B. 16

C. 28

D. 30

Kwaziwa:

Isisindo sesando (m) = 10 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/ s ²

Isisindo sesando (w) = mg = (10)(10) = 100 kg m/s ²

Ukususwa kwesando ngaphambi kokushaya ukhuni (d) = 40 cm = 0.4 amamitha

Ukumelana kokhuni (F) = 2 x 10 ³ N = 2000 N

Ubude bokhuni = 60 cm = 0.6 amamitha

Okufunwayo: Ukhuni luzongena ngokuphelele emhlabathini ngemva… kokushaya.

Isixazululo:

Umsebenzi owenziwe ngesando lapho isando sihamba ibanga elingamamitha angu-0.4 uwukuthi:

W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joules

Umsebenzi owenziwe ngamandla okumelana nomhlabathi:

W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joules

Ukhuni luzongena ngokuphelele emhlabathini ngemva… kokushaya.

AmaJoules angu-1200 / amaJoules angu-40 = 30

Impendulo efanele ngu-D.

[wpdm_package id='1192′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe ebusweni obugobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibanga loMhlaba ukusuka eLangeni lingu-149.6 x 10 ⁶ km kanti isikhathi sokuguquka koMhlaba singunyaka owodwa. Bala u-T ² / r ³

Kwaziwa:

T = unyaka ongu-1, r = 149.6 x 10 ⁶ km

Okufunwayo : T ² / r ³ = … ?

Isixazululo :

k = T² /r³ = 1² / (149.6x10⁶)³ = 1 / (3348071.9 x 10¹⁸) = 2.98 x 10^-25 Ngonyaka²/km³

2. I-Universal constant (G) = 6.67 x 10 ^-11 Nm ² /kg ² kanye ne-Sun's 1.99 x 10 ³⁰ kg.

3. Ibanga eliphakathi loMhlaba ukusuka eLangeni lingu-149.6 x 10 ⁶ km kanti ibanga eliphakathi leMercury ukusuka eLangeni lingu-57.9 x 10 ⁶ km. Isikhathi sokuguquka koMhlaba singunyaka owodwa, siyini isikhathi sokuguquka kukaMercury?

Kwaziwa:

r yoMhlaba = 149.6 x 10 ⁶ km

r ye-mercury = 57.9 x 10 ⁶ km

Unyaka ongu-1

Ufunwa: T ye-mercury?

Isixazululo:

[wpdm_package id='953′]

1. Umthetho kaNewton wezinkinga zamandla adonsela phansi kanye nezixazululo
2. Amandla adonsela phansi, izinkinga zesisindo, kanye nezixazululo
3. Ukusheshisa ngenxa yezinkinga zamandla adonsela phansi kanye nezixazululo
4. Izinkinga zesathelayithi ze-geosynchronous kanye nezixazululo
5. Izinkinga zomthetho kaKepler kanye nezixazululo izinkinga kanye nezixazululo

Funda kabanzi

1. Kungakanani ukuphakama kwesathelayithi esihambisana ne-geosynchronous ngaphezu kobuso boMhlaba?

G = okungaguquki okujwayelekile = 6.67 x 10 ^-11 N m ² /kg ²

M = Isisindo somhlaba = 5.97 x 10 ²⁴ kg

T = amahora angama-24 = 24 (imizuzwana engama-3600) = imizuzwana engama-86,400 = 8.64 x 10 ⁴ imizuzwana

Isixazululo

Ukuphakama kwesathelayithi ngaphezu kobuso boMhlaba = 4.22 x 10 ⁷ m = 4.22 x 10 ⁴ km = 42,200 km

Ukuphakama kwesathelayithi ngaphezu kobuso boMhlaba = 6.38 x 10 ⁶ m = 6.38 x 10 ³ km = 6380 km

Ukuphakama kwesathelayithi ngaphezu kobuso boMhlaba = ibanga lesathelayithi ukusuka enkabeni yoMhlaba - irediyasi yoMhlaba

Ukuphakama kwesathelayithi ngaphezu kobuso boMhlaba = 42,200 km – 6380 km

Ukuphakama kwesathelayithi ngaphezu kobuso boMhlaba = 35,820 km

2. Ingakanani ijubane lesathelayithi esishintshashintshayo?

I-Universal constant (G) = 6.67 x 10 ^-11 N m ² /kg ²

Isisindo somhlaba (m _E ) = 5.97 x 10 ²⁴ kg

Ibanga eliphakathi kwesathelayithi nesikhungo soMhlaba (r) = 4.22 x 10 ⁷ m

Isixazululo

noma sebenzisa lesi sibalo

[wpdm_package id='949′]

1. Umthetho kaNewton wezinkinga zamandla adonsela phansi kanye nezixazululo
2. Amandla adonsela phansi, izinkinga zesisindo, kanye nezixazululo
3. Ukusheshisa ngenxa yezinkinga zamandla adonsela phansi kanye nezixazululo
4. Izinkinga zesathelayithi ze-geosynchronous kanye nezixazululo
5. Izinkinga zomthetho kaKepler kanye nezixazululo izinkinga kanye nezixazululo

Funda kabanzi

1. Ibanga phakathi komuntu ongama-40 kg nomuntu ongama-30 kg lingama-2 m. Ubukhulu bamandla adonsela phansi ngalinye liwasebenzisa kwelinye. I-Universal constant = 6.67 x 10 ^-11 N m ² / kg ²

Kwaziwa:

m ₁ = 40 kg, m ₂ = 30 kg, r = 2 m, G = 6.67 x 10 ^-11 N m ² / kg ²

Okufunwayo: ubukhulu bamandla adonsela phansi (F)?

Isixazululo:

2. Ibanga eliphakathi koMhlaba neNyanga (r) lingu-3.84 x 10 ⁸ m. Ubukhulu bamandla adonsela phansi ngalinye liwasebenzisa kwelinye?

Kwaziwa:

Isisindo somhlaba (m _E ) = 5.97 x 10 ²⁴ kg

Isisindo seNyanga (m _M ) = 7.35 x 10 ²² kg

Ibanga eliphakathi kwesikhungo soMhlaba nesikhungo seNyanga (r) = 3.84 x 10 ⁸ m

I-Universal constant (G) = 6.67 x 10 ^-11 N m ² / kg ²

Okufunwayo: Ubukhulu bamandla adonsela phansi (F)

Isixazululo:

3. Lingakanani ibanga ukusuka eMhlabeni, ubukhulu bamandla adonsela phansi omhlaba kanye nenyanga buyi-zero?

Kwaziwa:

Isisindo somhlaba = 5.97 x 10 ²⁴ kg

Isisindo seNyanga = 7.35 x ¹⁰²² kg

Ibanga eliphakathi kwesikhungo soMhlaba nesikhungo seNyanga (r) = 3.84 x 10 ⁸ m.

I-Universal constant ( G) = 6.67 x 10 ^-11 N m ² / kg ²

Kufunwa: ibanga ukusuka eMhlabeni

Isixazululo:

Amandla adonsela phansi aphelele ayi-zero.

Sebenzisa ifomula ye-quadratic:

A = – 6.35

B = – 7.68 x 10 ⁸

C = 87.76 x 10 ^-14

 

[wpdm_package id='955′]

1. Umthetho kaNewton wezinkinga zamandla adonsela phansi kanye nezixazululo
2. Amandla adonsela phansi, izinkinga zesisindo, kanye nezixazululo
3. Ukusheshisa ngenxa yezinkinga zamandla adonsela phansi kanye nezixazululo
4. Izinkinga zesathelayithi ze-geosynchronous kanye nezixazululo
5. Izinkinga zomthetho kaKepler kanye nezixazululo izinkinga kanye nezixazululo

 

Funda kabanzi