Izinkinga Ezixazululiwe ku-Basic Physics

1. Amandla P asetshenziswa kolunye uhlangothi lomshayo onobude obungamamitha amabili. Ubukhulu bawo buyini itorqueI-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla (F) = 10 N

Ubude be-AB (r)_AB= 2m

I-Force F iqonde ngqo emsebeni.

Ingalo ye-lever (l)) =r_AB ngaphandle 90^o = (2 m)(1) = 2 m

Okufunayo: I-torque ezungeze i-axis yokujikeleza

Isixazululo:

I-torque:

τ = F l = (10 N)(2 m) = 20 N m

Uphawu lokuhlanganisa ngenxa yokukhanya ijikeleza ukujikeleza okuphikisana newashi.

2. Ubude bomsebe I-AB ingu-2 m kanti ubukhulu bamandla u-F bungu-10 N. Iyini ubukhulu be-torque? I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla (F) = 10 N

Ubude be-AB (r)_AB= 2m

Ingalo ye-lever (l)) =r_AB ngaphandle 60^o = (2 m)(0.5.3) = .3 m

Okufunayo: I-torque ezungeze i-axis yokujikeleza

Isixazululo:

I-torque:

τ = F l = (10 N)(.3 m) = 10.3 N m

Uphawu lokuhlanganisa ngoba amandla u-F abangela umsebe ijikeleza ukujikeleza okuphikisana newashi.

3. Ubude bomsebe buyi-2 m. Ubukhulu be-F₁ ingu-10 N kanye nobukhulu buka-F₂ ingu-15 N. Thola i-torque eqondile ezungeze isikhungo somsebe.

I-axis yokujikeleza enkabeni yomsebe.

Kwaziwa:

Amandla 1 (F)₁) = 10 N

The ibanga phakathi kuka-F₁ kanye nesikhungo somsebe (r₁= 1m

Ingalo ye-lever 1 (l)₁) =r₁ ngaphandle 90^o = (1 m)(1) = 1 m

Amandla F₁ iqonde ngqo emshayweni.

Amandla 2 (F)₂) = 15 N

Ibanga eliphakathi kuka-F₂ kanye nesikhungo somsebe (r₂= 1m

Amandla F₂ iqonde ngqo emshayweni.

Ingalo ye-lever 2 (l)₂) =r₁ ngaphandle 90^o = (1 m)(1) = 1 m

Kufunwa: Ti-torque yayo ezungeze i-axis yokujikeleza

Isixazululo:

I-torque 1:

τ₁ =F₁ l₁ = (10 N)(1 m) = 10 N m

Uphawu lokuhlanganisa ngenxa yamandla ka-F₁ kubangela umsebe ijikeleza ukujikeleza okuphikisana newashi.

I-torque 2:

τ₂ =F₂ l₂ = (15 N)(1 m) = -15 N

Uphawu lokususa ngoba amandla u-F₂ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque ephelele:

Στ = τ₁ – τ₂ = 10 – 15 = – 5 N m

Uphawu lokususa ngoba umsebe uya ijikeleza ngokwewashi.

4. Ubude be-AB be-beam buyi 2 m, Ubukhulu be-F₁ ingu-10 N kanye nobukhulu buka-F₂ is 10 N. Thola i-torque eqondile ezungeze isikhungo somsebe.

I-axis yokujikeleza enkabeni yomsebe.

Kwaziwa:

Amandla 1 (F)₁) = 10 Nn

Ibanga eliphakathi kuka-F₁ kanye nesikhungo somsebe (r₁= 1m

Ingalo ye-lever 1 (l)₁) =r₁ ngaphandle 60^o = (1 m)(0.5.3= = 0.5.3 m

Amandla 2 (F)₂) = 10 N

Ibanga eliphakathi kuka-F₂ kanye nesikhungo somsebe (r₂= 1m

Amandla F₂ iqonde ngqo emshayweni.

Ingalo ye-lever 2 (l)₂) =r₂ ngaphandle 90^o = (1 m)(1) = 1 m

Kufunwa: I-torque ephelele mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ₁ =F₁ l₁ = (10 N)(0.5.3 m) = 5√3 = 8.7 Nm

Uphawu lokuhlanganisa ngoba amandla u-F₁ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque 2:

τ₂ =F₂ l₂ = (10 N)(1 m) = -10 N m

Uphawu lokususa ngoba amandla u-F₂ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque ephelele:

Στ = τ₁ – τ₂ = 8.7 – 10 = – 1.3 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ijikeleza ngokwewashi.

5. Ubude bomsebe buyi-10 m, ubukhulu buyi-F₁ ingu-10 N, ubukhulu buka-F₂ ingu-10 N kanye nobukhulu buka-F₃ ingu-15 N. Ibanga eliphakathi kwephuzu A nephuzu C lingu-7.5 m. Amandla F₂ etholakala maphakathi nogongolo. Thola i-torque eqondile mayelana nephuzu C elitholakala ku-2.5 m ukusuka ephuzu B.

I-axis yokujikeleza itholakala endaweni C

Kwaziwa:

Amandla 1 (F)₁) = 10 N

Ibanga eliphakathi kuka-F₁ kanye nephuzu C (r₁) = 2.5 m

Amandla F₁ iqonde ngqo emshayweni.

Ingalo ye-lever 1 (l)₁) =r₁ ngaphandle 90^o = ((2.5 m)(1) = 2.5 m

Amandla 2 (F)₂) = 10 N

Ibanga eliphakathi kuka-F₂ kanye nephuzu C (r₂) = 2.5 m

Amandla F₂ iqonde ngqo emshayweni.

Ingalo ye-lever 2 (l)₂) =r₂ ngaphandle 90^o = ((2.5 m(1) = 2.5 m

Amandla 3 (F)₃) = 15 N

Ibanga eliphakathi kuka-F₃ futhi iphuzu C (r)₃= 7.5m

Amandla F₃ iqonde ngqo emshayweni.

Ingalo ye-lever 3 (l)₃) =r₃ ngaphandle 90^o = (7.5 m)(1) = 7.5 m

Kufunwa: I-torque ephelele mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ₁ =F₁ l₁ = (10 N)(2.5 m) = 25 N m

Uphawu lokuhlanganisa ngoba amandla u-F₁ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque 2:

τ₂ =F₂ l₂ = (10 N)(2.5 m) = 25 n m

Tuphawu lwe-plus ngoba amandla F₂ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque 3:

τ₃ =F₃ l₃ = (15 N)(7.5 m) = -112..5 N m

Uphawu lokususa ngoba amandla u-F₃ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque ephelele:

Στ = τ₁ + τ₂ – τ₃ = 25 + 25 - 112.5 = – 62.5 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ijikeleza ngokwewashi.

6. Ubude bomsebe buyi-10 m, ubukhulu buyi-F₁ ingu-10 N, ubukhulu buka-F₂ ingu-10 N kanye nobukhulu buka-F₃ ingu-10 N. Thola i-torque enetha mayelana nephuzu A, elitholakala ngamamitha angu-5 ukusuka endaweni ephakemeukusetshenziswa kwamandla F₁.

I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla 1 (F)₁) = 10 N

Ibanga eliphakathi kuka-F₁ kanye nephuzu A (r)₁= 5m

Ingalo ye-lever 1 (l)₁) =r₁ ngaphandle 60^o = (5 m)(0.5.3= = 2.5.3 m

Force 2 (F)₂) = 10 N

Ibanga eliphakathi kuka-F₂ kanye nephuzu A (r)₂= = 0

Amandla F₂ iqonde ngqo emshayweni.

Ingalo ye-lever 2 (l)₂) =r₂ ngaphandle 90^o = (0)(1) = 0

Amandla 3 (F)₃) = 10 N

Ibanga eliphakathi kuka-F₃ kanye nephuzu A (r)₃= 10m

Ingalo ye-lever 3 (l)₃) =r₃ ngaphandle 30^o = (10 m)(0.5) = 5 m

Kufunwa: i-torque enetha mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ₁ =F₁ l₁ = (10 N)(2.5√3 m) = 25√3 = 43.3 N m

Uphawu lokuhlanganisa ngoba amandla u-F₁ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque 2:

τ₂ =F₂ l₂ = (10 N)(0) = 0

I-torque 3:

τ₃ =F₃ l₃ = (10 N)(5 m) = -50 N m

Uphawu lokususa ngoba amandla u-F₃ kubangela ukuthi umsebe ijikeleza ngokwewashi.

I-torque ephelele:

Στ = τ₁ + τ₂ – τ₃ = 43.3 0 + - 50 = – 6.7 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ijikeleza ngokwewashi.

Funda kabanzi

1. A 500-grinto, u-A, ngihamba ku- 10 m / s kanye nento engamagremu angu-200, B, ehamba ngesivinini esingu-12 m/s. Izinto ziyasondelana bese zishayisana. Uma ijubane lento A lilandela ukushayisana ingu-6 m/s, ingakanani ijubane lento B ngemva kokushayisana?

Kwaziwa:

Imisa kwento 1 (m₁) = amagremu angu-500 = 0.5 kg

Imisa kwento 2 (m₂) = amagremu angu-200 = 0.2 kg

Okokuqala velocity kwento 1 (v₁) = -10 m/s

Ijubane lokuqala lento 2 (v₂) = 12 m/s

Ijubane lokugcina lento 1 (v₁') = 6 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

wayefuna : ijubane lokugcina lento 2 (v₂')

Isixazululo:

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

(0.5)(-10) + (0.2)(12) = (0.5)(6) + (0.2)(v₂')

-5 + 2.4 = 3 + 0.2 v₂'

-2.6 = 3 + 0.2 v₂'

-2.6 – 3 = 0.2 v₂'

-5.6 = 0.2 v₂'

v₂' = -5.6 / 0.2

v₂' = -28 m/s

Ijubane lento 2 ngemva kokushayisana lingama-28 m/s.

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

2. Izinto ezimbili ezilinganayo ziyasondelana bese ziyashayisana. Ijubane lento 1 lingu-6 m/s kanti ijubane lento 2 lingu-8 m/s. Ngemva kokushayisana, into 2 iya ngakwesobunxele ngejubane elingu-5 m/s. Iyini ubukhulu kanye nesiqondiso sejubane lento 1 ngemva ukushayisana?

Yazi:

Imisa kwento 1 (m₁) = m

Imisa kwento 2 (m₂) = m

Isivinini sokuqala sento 1 (v₁) = -6 m/s

isivinini sokuqala sento 2 (v₂) = 8 m/s

Isivinini sokugcina sento 2 (v₂') = -5 m/s

wayefuna : ubukhulu kanye nesiqondiso sento 1 ngemva kokushayisana

Isixazululo:

Ifomula ye ukulondolozwa komfutho oqondile :

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

mv₁ +m v₂ = m v₁' + m v₂'

m (v₁ +v₂) = m (v₁' + v₂')

v₁ +v₂ =v₁' + v₂'

-6 + 8 = v₁' – 5

2 = v₁' – 5

2 + 5 = v₁'

v₁' = 7 m/s

Isivinini sento 1 ngemva kokushayisana (v₁') is 3m/s.

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

3. Ibhola elingu-1 kg eliyi-1 kanye nebhola elingu-2 kg lihamba ngendlela efanayo futhi lishayisana ngendlela engaguquki. Ngaphambi kokushayisana, ibhola elingu-1 lihamba ngesivinini esingu-10 m/s kanti ibhola elingu-2 lihamba ngesivinini esingu-5 m/s. Isivinini sebhola elingu-2 ngemva kokushayisana singama-4 m/s. Thola isivinini sebhola elingu-1 ngemva kokushayisana.

Kwaziwa:

Imisa ibhola 1 (m₁) = 1 kg

Imisa ibhola 2 (m₂) = 2 kg

Isivinini sebhola 1 (nge₁) = 10 m/s

Isivinini sebhola 2 (v₂) = 5 m/s

Isivinini sokugcina sebhola 2 (v₂') = 4 m/s

Isibonakaliso sokuhlanganiswa kwejubane sibonisa ukuthi amabhola aqonde ohlangothini olufanayo.

wayefuna : ijubane lokugcina lebhola 1 (v₁')

Isixazululo:

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

(1)(10) + (2)(5) = (1)(v)₁') + (2)(4)

10 + 10 = v₁' + 8

20 – 8 = v₁'

v₁' = 12 m/s

Isivinini sebhola 1 ngemva kokushayisana singu 12m/s.

[wpdm_package id='1190′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Inhlamvu engamagremu angu-30 ehamba ngesivinini esingama-30 m/s ishayisana nebhulokhi elingu-1 kg lapho iphumule. Thola isivinini sebhulokhi uma inhlamvu nebhulokhi kuxhumene ngenxa ye- ukushayisana.

Kwaziwa:

Imisa yenhlamvu (m₁) = amagremu angu-30 = 0.03 kg

Imisa kwebhulokhi (m₂) = 1 kg

Isivinini sokuqala senhlamvu (v₁) = 30 m/s

isivinini sokuqala sebhulokhi (v₂) = 0 (ibhulokhi ekuphumuleni)

wayefuna : isivinini senhlamvu kanye nebhulokhi ngemva kokushayisana (v')

Isixazululo:

m₁ v₁ +m₂ v₂ = (m₁ +m₂) v'

(0.03)(30) + (1)(0) = (0.03 + 1) v'

0.9 + 0 = 1.03 v'

0.9 = 1,03 v'

v' = 0.9 / 1,03

v' = 0.87 m/s

2. Ibhola lebhiliyadi A elinobunzima obungu-2 kg lihamba ngesivinini v_A = 6 ms^-1 ishayisana ngqo nebhola B elinobunzima obulinganayo. Uma ukushayisana kungaqini ngokuphelele, zingakanani izivinini zamabhola amabili ngemva kokushayisana.

Kwaziwa:

Isisindo A (m_A) = 2 kg

Isisindo B (m_B) = 2 kg

Isivinini sokuqala sebhola A (v_A) = -6 m/s

Isivinini sokuqala sebhola B (v_B) = 4 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

wayefuna: isivinini samabhola amabili ngemva kokushayisana. (v')

Isixazululo:

m_A v_A +m_B v_B = (m_A' + m_B) v'

(2)(-6) + (2)(4) = (2 + 2) v'

-12 + 8 = 4 v'

-4 = 4 v'

v' = -4 / 4

v' = -1 m/s

3. m₁ = 3kg futhi m₂ = 4kg basondelane ngendlela ephambene ngesivinini v₁ = 10m/s futhi v₂ = 12 m/s. Uma ukushayisana kunganambitheki ngokuphelele, zingakanani ijubane lamabhola amabili ngemva kokushayisana?

Kwaziwa:

Imisa into 1 (m₁) = 3 kg

Imisa into 2 (m₂) = 4 kg

Isivinini sento 1 (v₁) = -10 m/s

Isivinini sento 2 (v₂) = 12 m/s

wayefuna : isivinini ngemva kokushayisana (v')

Isixazululo:

m₁ v₁ +m₂ v₂ = (m₁' + m₂) v'

(3)(-10) + (4)(12) = (3 + 4) v'

-30 + 48 = 7 v'

18 = 7 v'

v' = 18 / 7

v' = 2.6 m/s

[wpdm_package id='1157′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Ibhola elingamagremu angu-200, u-A, elihamba ngesivinini esingu-10 m/s lishaya ibhola elingamagremu angu-200, u-B, lapho liphumule. Liyini ijubane lebhola u-A kanye nebhola u-B ngemva kwe- ukushayisana?

Kwaziwa:

Imisa ibhola A (m_A) = amagremu angu-200 = 0.2 kg

Isisindo sebhola B (m_B) = amagremu angu-200 = 0.2 kg

Isivinini sebhola A ngaphambi kokushayisana (v)_A) = 10 m/s

Isivinini sebhola B ngaphambi kokushayisana (v)_B= = 0

Okufunayo: isivinini sebhola A (v)_A') kanye nesivinini sebhola B (v_B') ngemva kokushayisana

Isixazululo:

v_A' = v_B = 0

v_B' = v_A = 10m/s

2. Izinto ezimbili ezilingana ngobuningi ziyasondelana, zishayisane bese zigxumagxuma. Isivinini sesisindo u-A ngaphambi kokushayisana singama-8 m/s kanti isivinini sesisindo u-B ngaphambi kokushayisana singama-12 m/s. Ubukhulu kanye nesiqondiso salo mgwaqo velocity yesisindo A kanye nesisindo B ngemva kokushayisana!

Kwaziwa:

Isisindo A (m_A) = m

Isisindo B (m_B) = m

Isivinini sesisindo A ngaphambi kokushayisana (v)_A) = -8 m/s

Isivinini sesisindo B ngaphambi kokushayisana (v)_B) = 12 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

Okufunayo: ubukhulu kanye nesiqondiso sejubane lesisindo A (v)_A') kanye nesisindo B (v_B') ngemva kokushayisana

Isixazululo:

Ekushayisaneni okunwebeka ngokuphelele, uma izinto zinobunzima obulinganayo khona-ke ijubane lika-A ngemva kokushayisana (v_A') = isivinini sika-B ngaphambi kokushayisana (v_B) kanye nesivinini sika-B ngemva kokushayisana (v_B') = isivinini sika-A ngaphambi kokushayisana (v_A).

Uma ngaphambi kokushayisana, u-A uya kwesokudla kanti u-B uya ngakwesobunxele, khona-ke, ngemva kokushayisana, u-A uya ngakwesobunxele kanti u-B uya kwesokudla.

Izinto zinesisindo esilinganayo futhi Ukushayisana kuyanwebeka ngokuphelele ngakho izinto zombili zishintshana ngesivinini.

v_A' = -v_B = -12 m/s

v_B' = v_A = 8m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

3. Into engamakhilogremu amabili, u-A, ehamba ngesivinini esingama-10 m/s ishaya ibhola elingamakhilogremu angu-4, u-B, ihamba ngesivinini esingama-20 m/s. Uma ukushayisana kunwebeka ngokuphelele, liyini ijubane lento u-A kanye nento u-B ngemva kokushayisana?

Kwaziwa:

Isisindo A (m_A) = 2 kg

Isisindo B (m_B) = 4 kg

Isivinini sento A ngaphambi kokushayisana (v)_A) = 10 m/s

Isivinini sento B ngaphambi kokushayisana (v)_B) = 20 m/s

wayefuna : isivinini sento A (v)_A') kanye nesivinini sento B (v_B') ngemva kokushayisana

Isixazululo :

In ukushayisana okunwebeka ngokuphelele, uma izinto zinesisindo esilinganayo futhi zisondelana, ijubane lento ngemva kokushayisana libalwa kusetshenziswa le fomula :

Isivinini sento A ngemva kokushayisana:

4. Ukuhamba ngesivinini esingamagremu ayi-100 ngesivinini esingama-20 m/s kushaya ukushayisana kodonga okunwebeka ngokuphelele. Kuyini ubukhulu kanye nesiqondiso sejubane lento ngemva kokushayisana.

Kwaziwa:

Isisindo (m_A) = amagremu angu-100 = 0.1 kg

Isisindo sodonga (m_B) = okungapheli

Isivinini sobunzima ngaphambi kokushayisana (v)_A) = 20 m/s

Isivinini sesisindo ngemva kokushayisana (v)_B= = 0

wayefuna : ubukhulu kanye nesiqondiso sejubane ngemva kokushayisana

Isixazululo:

Uma v_B = 0, m_A encane kakhulu futhi m₂ mkhulu kakhulu kune-v_A' = -v_A kanye v₂' = 0.

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

5. Amabhola amabili, A ngesisindo se 2 kg kanye nebhola B elinesisindo 5-kg, Ngaphambi nangemva kokushayisana kuboniswe esithombeni esingezansi. Uma ukushayisana kunwebeka ngokuphelele, lingakanani ijubane lebhola u-A ngaphambi kokushayisana?

Kwaziwa:

Isisindo sebhola A (m_A) = 2 kg

Isisindo sebhola B (m)_B) = 5 kg

Isivinini sebhola B ngaphambi kokushayisana (v_B) = 2 m/s

Isivinini sebhola A ngemuva kokushayisana (v_A') = 5 m/s

Isivinini sebhola B ngemva kokushayisana (v_B') = 4 m/s

Womabili amabhola aya ngakwesokudla ngakho ijubane lawo lisayinwe lihle.

Kufunwa: Isivinini sebhola A ngaphambi kokushayisana (v_A)

Isixazululo:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

2(v)_A) + (5)(2) = (2)(5) + (5)(4)

2(v)_A) + 10 = 10 + 20

2(v)_A) + 10 = 30

2(v)_A) = 30 – 10

2(v)_A= = 20

v_A = 20 / 2

v_A = 10m/s

6. Izinto A no-B zihamba ngendiza evundlile, njengoba kuboniswe esithombeni esingezansi. Uma ukushayisana kunwebeka ngokuphelele futhi ijubane lento B ngemva kokushayisana liyi 15 m / s¹, Iyini ijubane lento A ngemva kokushayisana.

Kwaziwa:

Isisindo sento A (m_A) = 5 kg

Isisindo sento B (m)_B) = 2 kg

Isivinini sento A ngaphambi kokushayisana (v_A) = 12 m/s

Isivinini sento B ngaphambi kokushayisana (v_B) = 10 m/s

Isivinini sento B ngemva kokushayisana (v_B') = 15 m/s

Zombili izinto, ngaphambi nangemva kokushayisana, ziya kwesokudla ukuze ijubane lazo libonakale lihle.

Kufunwa: Isivinini sento A ngemva kokushayisana (v_A')

Isixazululo:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

(5)(12) + (2)(10) = (5)v_A' + (2)(15)

60 + 20 = (5)v_A' + 30

80 = (5)v_A' + 30

80 – 30 = (5)v_A'

50 = (5)v_A'

v_A' = 50/5

v_A' = 10 m/s

[wpdm_package id='1156′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Ibhola elincane liphonswa ngokuvundlile ngesivinini esingaguquki esingu-10 m/s. Ibhola lishaya odongeni futhi liphinde libonakale ngesivinini esifanayo. Luyini ushintsho ku- umfutho oqondile yebhola?

Kwaziwa:

Imisa (m) = 0.2 kg

Isivinini sokuqala (v)_o) = -10 m/s

Isivinini sokugcina (v)_t) = 10 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

wayefuna : ushintsho ku-momentum eqondile (Δp)

Isixazululo:

Ifomula yoshintsho ku-momentum eqondile :

Δp = mv_t – mv_o = m (v_t - v_o)

Ushintsho ku-momentum eqondile:

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

Δp = 4 kg m/s

2. Ibhola elingamagremu ayi-10 ukuwa ngokukhululeka kusukela ekuphakameni, ishaya phansi ngesivinini esingu-15 m/s, bese ibuyela phezulu ngesivinini esingu-10 m/s. Thola ukuthi i-pulse ingakanani!

Kwaziwa:

Isisindo (m) = 10 amagremu = 0.01 kg

Ijubane lokuqala (v)_o) = -15 m/s

Ijubane lokugcina (v)_t) = 10 m/s

Kufunwa: Isisusa (I)

Isixazululo:

I-impulse (I) ilingana noshintsho ku-momentum (Δp)

I = mv_t – mv_o = m (v_t - v_o)

Umfutho:

I = 0.01 (10 – (-15)) = 0.01 (10 + 15)

I = 0.01 (25)

I = 0.25 kg m/s

3. Ibhola elingamagremu angu-200 laphonswa ngokuvundlile ngesivinini esingu-4 m/s, bese ibhola lishaywa ngendlela efanayo. Isikhathi sebhola uma lithintana nebhethi singamakhilomitha amabili.lamasekhondi ambalwa futhi isivinini sebhola ngemva kokushiya ibhethi singama-12 m/s. ubukhulu be qinisa ukuzikhandla ngomshayi osebholeni …

Kwaziwa:

Isisindo (m) = 200 amagremu = 0.2 kg

Ijubane lokuqala (v)_o) = 4 m/s

Ijubane lokugcina (v)_t) = 12 m/s

Isikhawu sesikhathi (t) = 2 milliseconds = (2/1000) imizuzwana = 0.002 imizuzwana

wayefuna : Ubukhulu bamandla (F)

Isixazululo:

Ifomula ye-impulse:

I = F t

Ifomula yokushintsha komfutho:

mv_t – mv_o = m (v_t - v_o)

I-impulse (I) ilingana noshintsho ku-momentum (Δp)

I = Δp

F t = m (v_t - v_o)

F (0.002) = (0.2)(12 – 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Newton

[wpdm_package id='1155′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Into ihamba ngesivinini esingaguquki esingu-10 m/s. Bala umfutho oqondile lento.

Kuyaziwa :

Imisa (m) = 1 kg

Velocity (v) = 10 m/s

Kufunwa: umfutho oqondile (p)

Isixazululo:

Ifomula yomfutho oqondile:

p = mv

p = umfutho oqondile, m = isisindo, v = ijubane

Umfutho oqondile:

p = mv = (1)(10) = 10 kg m/s²

2. Ibhulokhi engu-2 kg kanye nebhulokhi engu-4 kg lihamba ngesivinini esingaguquki esingu-20 m/s. Iyini ijubane eliqondile lamabhulokhi.

Kwaziwa:

Imisa kwebhulokhi A (m_A) = 2 kg

Imisa kwebhulokhi B (m)_B) = 4 kg

Isivinini sebhulokhi A (v)_A) = 20 m/s

Isivinini sebhulokhi B (v)_B) = 20 m/s

Kufunwa: Umfutho oqondile webhulokhi A (p)_A) kanye nomfutho oqondile webhulokhi B (p_B)

Isixazululo:

Umfutho oqondile webhulokhi A :

p_A = m_A v_A = (2)(20) = 40 kg m/s

Umfutho oqondile webhulokhi B :

p_B = m_B v_B = (4)(20) = 80 kg m/s

3. Ibhulokhi elingamakhilogremu ama-2 lihamba ngesivinini esingaguquki sama-2 m/s kanye nebhulokhi elingamakhilogremu ama-2 lihamba ngesivinini esingaguquki sama-4 m/s. Thola umfutho oqondile wamabhulokhi.

Kwaziwa:

Imisa kwebhulokhi A (m_A) = 2 kg

Isisindo sebhulokhi B (m_B) = 2 kg

Isivinini sebhulokhi A (v)_A) = 2 m/s

Isivinini sebhulokhi B (v_B) = 4 m/s

Kufunwa: umfutho oqondile wamabhulokhi

Isixazululo:

Umugqa ongu-mi-omentum kwebhulokhi A :

p_A = m_A v_A = (2)(2) = 4 kg m/s

Umfutho oqondile webhulokhi B:

p_B = m_B v_B = (2)(4) = 8 kg m/s

4. Into engamakhilogremu angu-5 iphumule. Iyini ijubane eliqondile lejubane.

Kwaziwa:

Isisindo (m) = 5 kg

Ijubane lento (v) = 0

wayefuna : umfutho oqondile (p)

Isixazululo:

p = mv = (5)(0) = 0

[wpdm_package id='1155′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

Amandla yisilinganiso lapho umsebenzi wenziwa khona esikhathini esithile. Ngokwezibalo, amandla yisilinganiso somsebenzi/sesikhathi.

P = W/t

Incazelo: P = amandla (iJoule/isekhondi = iWatt), W = umsebenzi (iJoule), t = isikhawu sesikhathi (isekhondi)

Ngokusekelwe kulesi sibalo, kungaphethwa ngokuthi uma izinga lomsebenzi likhulu, amandla aba maningi. Ngakolunye uhlangothi, uma izinga lomsebenzi lincane, amandla aba mancane. Izinga lomsebenzi libhekisela esilinganisweni lapho umsebenzi wenziwa khona.

Amandla ayi-scalar. Iyunithi yamandla ye-SI yi-Joule/yesibili. I-Joule/yesibili = Watt (efushanisiwe njengo-W), eqanjwe kanjalo ukuhlonipha uJames Watt. Iyunithi yamandla yaseBrithani ingama-foot-pounds ngomzuzwana.

Le yunithi incane kakhulu ngezinjongo ezisebenzayo, ngakho-ke kusetshenziswa iyunithi enkulu yamandla ehhashi (efingqiwe njenge-hp). Ihhashi elilodwa lamandla ehhashi = amakhilogremu angu-550 ngomzuzwana = ama-Watts angu-764 = ¾ kilowatt.

Inani lomsebenzi lingabonakaliswa ngamayunithi wamandla x isikhathi, isibonelo, ama-kilowatt-hours noma i-kWh. I-kWh eyodwa ibhekisela emsebenzini owenziwe ngesilinganiso esingaguquki se-kilowatt eli-1 ihora elilodwa.

1. Isisindo esingu-50 kg umuntu ugijima phezulu izitebhisi ngamamitha ayi-10 ukuphakama in Imizuzu ye-2. Aukusheshisa ngenxa ye amandla adonsela phansi (g) angu-10 m/s². Nquma i- amandla.

Kwaziwa:

Imisa (m) = 50 kg

Ukuphakama (h) = 10 mama-eter

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Isikhathi sokuphumula (t) = 2 iminithi = 2 (60) = 120 yesibilis

wayefuna : Power (P)

Isixazululo:

Ifomula yamandla:

P=W/t

P= amandla, W = umsebenzi, t = isikhathi

Ifomula Yomsebenzi:

W = F s = wh = mgh

W= umsebenzi, F = qinisa, w = isisindo, d = Ukuhambisa, h = ukuphakama, m = isisindo, g = ukusheshisa ngenxa yamandla adonsela phansi

W = mgh = (50)(10)(10) = 5000 amaJoules.

P = W / t = 5000 / 120 = 41.7 Joules/second.

2. Bala amandla adingekayo kumuntu onesisindo esingamakhilogremu angu-60 okhuphuka esihlahleni esingamamitha angu-5 ukuphakama ngemizuzwana eyi-10. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

Isisindo (m) = 60 kg

Ukuphakama (h) = amamitha ama-5s

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Isikhathi sokuphumula (t) = 10 imizuzwana

wayefuna : Power

Isixazululo:

Umsebenzi:

W = mgh = (60)(10)(5) = 3000 amaJoules

Amandla:

P = W / t = 3000 / 10 = 300 Joules/seisimo.

3. Ihlaya elijikelezayo elinamandla angama-watts angu-300 kanye nesikhathi semizuzu emi-5 lijikeleza imizuliswano emi-5. Amandla eliwasebenzisayo….

A. 15 kJ

B. 75 kJ

C. 90 kJ

D. 450 kJ

Kwaziwa:

Amandla (P) = 300 Watts = 300 Joules/isekhondi

Isikhathi (T) = imizuzu emi-5 = 5 (imizuzwana engama-60) = imizuzwana engama-300

Inani lokujikeleza = 5

Okufunayo: Amandla asetshenziswa yi-rotary comedy

Isixazululo:

Impendulo efanele ngu-D.

[wpdm_package id='1190′]

1. Umsebenzi wenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhulokhi lishelela phansi libushelelezi indiza ethambekele ngaphandle frictionKuyini i-block's velocity uma ishaya phansi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s²

Kwaziwa:

Ukuphakama (h) = 8 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

wayefuna ijubane (v)

Isixazululo :

Amandla okuqala omshini (ME)_o) = amandla adonsela phansi (PE)

ME_o = PE = mgh = m (10)(8) = 80 m

Amandla okugcina omshini (ME)_t) = amandla kinetic (KWENZA)

ME_t = KE = ½ mv²

Isimiso sokulondolozwa kwamandla omshini sithi okokuqala amandla emishini = amandla okugcina omshini:

ME_o = MINA_t

80 m = ½ mv²

80 = ½ v²

160 = v²

v = √160 = √(16)(10) = 4√10 m/s

2. Into enesisindo esingu-1 kg ishelela phansi ngamamitha angu-8. Thola amandla e-kinetic ngemva kokuba into ihambe ngamamitha angu-5… Ukusheshisa ngenxa yamandla adonsela phansi g = 10 m/s²

Kwaziwa:

Isisindo (m) = 0.2 kg

d = amamitha angu-5

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

wayefuna amandla e-kinetic (KE)

Isixazululo:

ngaphandle 30^o = h / d

0.5 = amahora / 5

h = (0.5)(5) = amamitha angu-2.5

Ushintsho ekuphakameni kwento lungamamitha angu-2.5.

Amandla okuqala omshini (ME)_o) = amandla adonsela phansi (PE)

ME_o = PE = mgh = (1)(10)(2.5) = ama-Joule angu-25

Amandla okugcina omshini (ME)_t) = amandla e-kinetic (KE)

ME_t = KUYA

Isimiso se ukulondolozwa kwamandla okusebenza ngomshini ithi amandla okuqala omshini = amandla okugcina omshini:

ME_o = MINA_t

25 = KE

Amandla weKinetic = AmaJoule angu-25.

[wpdm_package id='1170′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhulokhi elingu-1 kg liyashelela phansi endaweni ebushelelezi egobile. Thola ukuthi amandla kinetic kanye nesivinini sebhulokhi endaweni ephansi kakhulu. Ukusheshisa ngenxa yamandla adonsela phansi ingu-10 m/s².

Kwaziwa:

Imisa (m) = 1 kg

Ushintsho ekuphakameni (h) = 5 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Okufunayo: Amandla e-Kinetic (KE) kanye velocity kwebhulokhi.

Isixazululo:

(a) Amandla e-Kinetic

The initial amandla emishini = amandla adonsela phansi

ME_o = PE = mgh = (1)(10)(5) = ama-Joule angu-50

Amandla okugcina omshini = amandla e-kinetic

ME_t = KE = ½ mv_t²

Isimiso se ukulondolozwa kwamandla okusebenza ngomshini ithi amandla okuqala omshini = amandla okugcina omshini:

ME_o = MINA_t

I-PE = KE

50 = KE

Amandla weKinetic (KE) = ama-Joules angu-50.

(b) Ijubane lebhulokhi

Umgomo wokonga amandla emishini:

Amandla okuqala omshini (ME)_o) = amandla okugcina omshini (ME)_t)

Amandla adonsela phansi (PE) = amandla e-kinetic (KE)

50 = ½ mv²

2(50) / m = v²

100 / 1 = v²

100 = v²

v = √100

v = 10 m/s

2. Into engamakhilogremu angu-2 iyashelela phansi ngaphandle kokungqubuzana. Iyini amandla e-kinetic kanye nejubane lento engamamitha amabili ngaphezu komhlabathi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s²

Kwaziwa:

Isisindo (m) = 2 kg

Ushintsho ekuphakameni (h) = 10 – 2 = 8 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

wayefuna : amandla e-kinetic (KE) kanye nesivinini (v) kumamitha ama-2 ngaphezu komhlabathi.

Isixazululo:

(a) Amandla e-kinetic amamitha amabili ngaphezu komhlabathi

Amandla okuqala omshini = amandla adonsela phansi

ME_o = PE = mgh = (2)(10)(8) = ama-Joule angu-160

Amandla okugcina omshini = amandla e-kinetic

ME_t = KE = ½ mv_t²

Umgomo wokulondolozwa kwamandla omshini uthi amandla okuqala omshini = amandla okugcina omshini:

ME_o = MINA_t

I-PE = KE

160 = KE

Amandla e-kinetic (KE) amamitha ama-2 ngaphezu komhlabathi angama-160 Joules.

(b) Ijubane lento endaweni ephansi kakhulu

Isimiso sokulondolozwa kwamandla omshini:

Amandla okuqala omshini (ME)_o) = amandla okugcina omshini (EM)_t)

Amandla adonsela phansi (PE) = amandla e-kinetic (KE)

160 = ½ mv²

160 = ½ (2) v²

160 = v²

v = √160 = √(16)(10) = 4√10 m/s

[wpdm_package id='1167′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhola elikhahlelwe lishiya phansi nge-engeli θ = 30^o ngejubane lokuqala elingu-10 m/s. Amabhola Mass = 0.1 kg. Ukusheshisa ngenxa yamandla adonsela phansi yi-10 m / s². Nquma (a) I amandla adonsela phansi endaweni ephakeme kakhulu (b) Iphuzu eliphakeme kakhulu noma ukuphakama okuphezulu kakhulu

Kwaziwa:

Isisindo (m) = 0.1 kg

Ijubane lokuqala (v)_o) = 10 m/s

I-engeli = 30^o

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Isixazululo:

(a) Amandla adonsela phansi

Bala ingxenye evundlile (v)_ox) kanye nengxenye eqondile (v_oy) yejubane lokuqala.

v_ox =v_o cos θ = (10)(cos 30^o) = (10)(0.5√3) = 5√3 m/s

v_oy =v_o Isono θ = (10)(isono 30^o) = (10)(0.5) = 5 m/s

Amandla okuqala omshini

The initial amandla emishini (MINA_o) = amandla kinetic (KWENZA)

ME_o = KE = ½ mv_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 amaJoules

Amandla okugcina omshini

Amandla e-kinetic endaweni ephezulu kakhulu:

KE = ½ mv_ox² = ½ (0.1)(5√3)² = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Ama-Joule

Isimiso sokulondolozwa kwamandla okusebenza ngomshini

Amandla okuqala omshini (ME)_o) = amandla okugcina omshini (ME)_t)

KE = PE + KE

5 = EP + 3.75

I-PE = 5 – 3.75 = 1.25 AmaJoule

Amandla adonsela phansi endaweni ephakeme kakhulu angama-1.25 Joules.

(b) Iphuzu eliphakeme kakhulu noma ukuphakama okuphezulu kakhulu

PE = mgh

1.25 = (0.1)(10) h

1.25 = ihora

Ukuphakama okuphezulu kungamamitha ama-1.25.

2. Ibhola elingu-0.1 kg liphonswe ngokuvundlile ngejubane lokuqala v_o = 10 m/s ukusuka esakhiweni esingamamitha ayi-10 ukuphakama. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s²Thola amandla e-kinetic ebhola uma lishaya phansi.

Kwaziwa:

Isisindo (m) = 0.1 kg

Ijubane lokuqala (v)_o) = 10 m/s

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Ushintsho ekuphakameni (h) = 10 – 2 = 8 m

Okufunayo: amandla e-kinetic kumamitha amabili ngaphezu komhlabathi

Isixazululo:

Amandla adonsela phansi (PE) = mgh = (0.1)(10)(10) = 10 Joules

Amandla okuqala e-kinetic (KE) = ½ mv_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 amaJoules

Amandla okugcina e-kinetic = amandla okuqala adonsela phansi + amandla okuqala e-kinetic = 10 + 5 = 15 Joules

[wpdm_package id='1173′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi