Izinkinga Ezixazululiwe ku-Basic Physics

1. Amandla P asetshenziswa ekugcineni kogongolo olunobude obungamamitha amabili. Ungakanani ubukhulu be- torque ? I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla (F) = 10 N

Ubude be-AB (r _AB ) = 2 m

I-Force F iqonde ngqo emsebeni.

Ingalo ye-lever (l ) = r _AB sin 90 ^o = (2 m)(1) = 2 m

Okufunwayo: I-torque ezungeze i-axis yokujikeleza

Isixazululo:

I-torque:

τ = F l = (10 N)(2 m) = 20 N m

Uphawu lokuhlanganisa ngoba umsebe ujikeleza ujikeleza ngokuphambene newashi.

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2. Ubude bomsebe u -AB bungama-2 m kanti ubukhulu bamandla u-F bungama-10 N. Bungakanani ubukhulu be-torque? I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla (F) = 10 N

Ubude be-AB (r _AB ) = 2 m

Ingalo yesibambo (l ) = r _AB sin 60 ^o = (2 m)(0.5 √3 ) = √3 m

Okufunwayo: I-torque ezungeze i-axis yokujikeleza

Isixazululo:

I-torque:

τ = F l = (10 N)( √3 m) = 10 √3 N m

Uphawu lokuhlanganisa ngoba amandla u-F abangela ukuthi umsebe ujikeleze ukujikeleza okuphikisana newashi.

[irp]

3. Ubude bomsebe bungama-2 m. Ubukhulu be-F ₁ bungama-10 N kanti ubukhulu be-F ₂ bungama-15 N. Thola i-torque ephelele phakathi nendawo yomsebe.

I-axis yokujikeleza enkabeni yomsebe.

Kwaziwa:

Amandla 1 (F ₁ ) = 10 N

Ibanga eliphakathi kuka-F ₁ kanye nesikhungo somsebe (r ₁ ) = 1 m

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 90 ^o = (1 m)(1) = 1 m

I-Force F ₁ iqonde ngqo emsebeni.

Amandla 2 (F ₂ ) = 15 N

Ibanga eliphakathi kuka-F ₂ kanye nesikhungo somsebe (r ₂ ) = 1 m

I-Force F ₂ iqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₁ sin 90 ^o = (1 m)(1) = 1 m

Okufunwayo: I -torque engenalutho ezungeze i-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 1 m) = 10 N m

Uphawu lokuhlanganisa ngoba amandla ka-F ₁ abangela ukuthi umsebe ujikeleze ukujikeleza okuphikisana newashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (15 N)( 1 m) = -15 N

Uphawu lokususa ngoba amandla u-F ₂ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ – τ ₂ = 10 – 15 = – 5 N m

Uphawu lokususa luwukuthi umsebe ujikeleza ngokwewashi.

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4. Ubude bomsebe u-AB bungama -2 m, ubukhulu be-F ₁ bungama-10 N kanti ubukhulu be-F ₂ bungama- 10 N. Thola i-torque ephelele phakathi nendawo yomsebe.

I-axis yokujikeleza enkabeni yomsebe.

Kwaziwa:

Amandla 1 (F ₁ ) = 10 Nn

Ibanga eliphakathi kuka-F ₁ kanye nesikhungo somsebe (r ₁ ) = 1 m

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 60 ^o = (1 m)(0.5 √3 ) = 0.5 √3 m

Amandla 2 (F ₂ ) = 10 N

Ibanga eliphakathi kuka-F ₂ kanye nesikhungo somsebe (r ₂ ) = 1 m

I-Force F ₂ iqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₂ sin 90 ^o = (1 m)(1) = 1 m

Okufunwayo: I-torque ephelele mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 0.5 √3 m) = 5 √3 = 8.7 Nm

Uphawu lokuhlanganisa ngoba amandla u-F ₁ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (10 N)( 1 m) = -10 N m

Uphawu lokususa ngoba amandla u-F ₂ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ – τ ₂ = 8.7 – 10 = – 1.3 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ujikeleze ngokwewashi.

[irp]

5. Ubude bomsebe buyi-10 m, ubukhulu be-F ₁ buyi-10 N, ubukhulu be-F ₂ buyi-10 N kanti ubukhulu be-F ₃ buyi-15 N. Ibanga eliphakathi kwephuzu A nephuzu C liyi-7.5 m. I-Force F ₂ itholakala enkabeni yomsebe. Thola i-torque ehlanzekile mayelana nephuzu C elitholakala ku-2.5 m ukusuka ephuzu B.

I-axis yokujikeleza itholakala endaweni C

Kwaziwa:

Amandla 1 (F ₁ ) = 10 N

Ibanga eliphakathi kuka-F ₁ nephuzu C (r ₁ ) = 2.5 m

I-Force F ₁ iqonde ngqo emsebeni.

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 90 ^o = ( 2.5 m)( 1 ) = 2.5 m

Amandla 2 (F ₂ ) = 10 N

Ibanga eliphakathi kuka-F ₂ nephuzu C (r ₂ ) = 2.5 m

Amandla F ₂ aqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₂ sin 90 ^o = ( 2.5 m)(1) = 2.5 m

Amandla 3 (F ₃ ) = 15 N

Ibanga eliphakathi kuka-F ₃ nephuzu C (r ₃ ) = 7.5 m

Amandla F ₃ aqonde ngqo emsebeni.

Ingalo yesibambo 3 (l ₃ ) = r ₃ sin 90 ^o = (7.5 m)(1) = 7.5 m

Okufunwayo: I-torque ephelele mayelana ne-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 2.5 m) = 25 N m

Uphawu lokuhlanganisa ngoba amandla u-F ₁ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (10 N)( 2.5 m) = 25 N m

Uphawu lwe -plus ngoba amandla u-F ₂ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 3:

τ ₃ = F ₃ l ₃ = (15 N)( 7.5 m) = -112..5 N m

Uphawu lokususa ngoba amandla u-F ₃ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ + τ ₂ – τ ₃ = 25 + 25 – 112.5 = – 62.5 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ujikeleze ngokwewashi.

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6. Ubude bomsebe buyi-10 m, ubukhulu buyi-F₁ ingu-10 N, ubukhulu buka-F₂ ingu-10 N kanye nobukhulu buka-F₃ ingu-10 N. Thola i-torque enetha mayelana nephuzu A, elitholakala ngamamitha angu-5 ukusuka endaweni ephakemeukusetshenziswa kwamandla F₁.

I-axis yokujikeleza endaweni A.

Kwaziwa:

Amandla 1 (F ₁ ) = 10 N

Ibanga eliphakathi kuka-F ₁ nephuzu A (r ₁ ) = 5 m

Ingalo yesibambo 1 (l ₁ ) = r ₁ sin 60 ^o = (5 m)(0.5 √3 ) = 2.5 √3 m

Amandla 2 (F ₂ ) = 10 N

Ibanga eliphakathi kuka-F ₂ nephuzu A (r ₂ ) = 0

Amandla F ₂ aqonde ngqo emsebeni.

Ingalo yesibambo 2 (l ₂ ) = r ₂ sin 90 ^o = (0)(1) = 0

Amandla 3 (F ₃ ) = 10 N

Ibanga eliphakathi kuka-F ₃ nephuzu A (r ₃ ) = 10 m

Ingalo yesibambo 3 (l ₃ ) = r ₃ sin 30 ^o = (10 m)(0.5) = 5 m

Okufunwayo: i-torque ehlanzekile ezungeze i-axis yokujikeleza

Isixazululo:

I-torque 1:

τ ₁ = F ₁ l ₁ = (10 N)( 2.5 √3 m ) = 25√3 = 43.3 N m

Uphawu lokuhlanganisa ngoba amandla u-F ₁ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque 2:

τ ₂ = F ₂ l ₂ = (10 N)(0) = 0

I-torque 3:

τ ₃ = F ₃ l ₃ = (10 N)( 5 m) = -50 N m

Uphawu lokususa ngoba amandla u-F ₃ abangela ukuthi umsebe ujikeleze ngokwewashi.

I-torque ephelele:

Σ τ = τ ₁ + τ ₂ – τ ₃ = 43.3 + 0 – 50 = – 6.7 N m

Uphawu lokususa ngoba amandla anetha abangela ukuthi umsebe ujikeleze ngokwewashi.

Funda kabanzi

1. Into engamagremu angu -500 , u-A, ehamba ngesivinini esingu- 10 m/s kanye nento engamagremu angu-200, u-B, ehamba ngesivinini esingu-12 m/s. Izinto ziyasondelana bese zishayisana. Uma ijubane lento A ngemva kokushayisana lingu -6 m/s, liyini ijubane lento B ngemva kokushayisana?

Kwaziwa:

Isisindo sento 1 (m ₁ ) = 500 amagremu = 0.5 kg

Isisindo sento 2 (m ₂ ) = 200 amagremu = 0.2 kg

Ijubane lokuqala lento 1 (v ₁ ) = -10 m/s

Ijubane lokuqala lento 2 (v ₂ ) = 12 m/s

Ijubane lokugcina lento 1 (v ₁ ') = 6 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

Okufunwayo : ijubane lokugcina lento 2 (v ₂ ')

Isixazululo:

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

(0.5)(-10) + (0.2)(12) = (0.5)(6) + (0.2)(v ₂ ')

-5 + 2.4 = 3 + 0.2 v ₂ '

-2.6 = 3 + 0.2 v ₂ '

-2.6 – 3 = 0.2 v ₂ '

-5.6 = 0.2 v ₂ '

v ₂ ' = -5.6 / 0.2

v ₂ ' = -28 m/s

Ijubane lento 2 ngemva kokushayisana lingama-28 m/s.

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

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2. Izinto ezimbili ezilingana ngobuningi ziyasondelana bese zishayisana. Ijubane lento 1 lingu-6 m/s kanti ijubane lento 2 lingu-8 m/s. Ngemva kokushayisana, into 2 iya ngakwesobunxele ngejubane elingu-5 m/s. Iyini ubukhulu kanye nesiqondiso sejubane lento 1 ngemva kokushayisana?

Yazi:

Isisindo sento 1 (m ₁ ) = m

Isisindo sento 2 (m ₂ ) = m

Isivinini sokuqala sento 1 (v ₁ ) = -6 m/s

isivinini sokuqala sento 2 (v ₂ ) = 8 m/s

Isivinini sokugcina sento 2 (v ₂ ') = -5 m/s

Okufunwayo : ubukhulu kanye nesiqondiso sento 1 ngemva kokushayisana

Isixazululo:

Ifomula yokulondolozwa komfutho oqondile :

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

mv ₁ + m v ₂ = m v ₁ ' + m v ₂ '

m (v ₁ + v ₂ ) = m (v ₁ ' + v ₂ ')

v ₁ + v ₂ = v ₁ ' + v ₂ '

-6 + 8 = v ₁ ' – 5

2 = v ₁ ' – 5

2 + 5 = v ₁ '

v ₁ ' = 7 m/s

Ijubane lento 1 ngemva kokushayisana (v ₁ ') lingu- 3 m/s.

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

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3. Ibhola elingu-1 kg eliyi-1 kanye nebhola elingu-2 kg lihamba ngendlela efanayo futhi lishayisana ngendlela engaguquki. Ngaphambi kokushayisana, ibhola elingu-1 lihamba ngesivinini esingu-10 m/s kanti ibhola elingu-2 lihamba ngesivinini esingu-5 m/s. Isivinini sebhola elingu-2 ngemva kokushayisana singama-4 m/s. Thola isivinini sebhola elingu-1 ngemva kokushayisana.

Kwaziwa:

Ibhola elisindayo 1 (m1 ₎ = 1 kg

Ibhola elisindayo 2 (m2 ₎ = 2 kg

Isivinini sebhola 1 (v ₁ ) = 10 m/s

Isivinini sebhola 2 (v ₂ ) = 5 m/s

Isivinini sokugcina sebhola 2 (v ₂ ') = 4 m/s

Isibonakaliso sokuhlanganiswa kwejubane sibonisa ukuthi amabhola aqonde ohlangothini olufanayo.

Okufunwayo : ijubane lokugcina lebhola 1 (v ₁ ')

Isixazululo:

m₁ v₁ +m₂ v₂ = m₁ v₁' + m₂ v₂'

(1)(10) + (2)(5) = (1)(v ₁ ') + (2)(4)

10 + 10 = v ₁ ' + 8

20 – 8 = v ₁ '

v ₁ ' = 12 m/s

Ijubane lebhola 1 ngemva kokushayisana liyi- 12 m/s.

[wpdm_package id='1190′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Inhlamvu engamagremu angu-30 ehamba ngesivinini esingama-30 m/s ishayisana nebhulokhi elingu-1 kg lapho iphumule. Thola isivinini sebhulokhi uma inhlamvu nebhulokhi kuxhumene ngenxa yokushayisana.

Kwaziwa:

Isisindo senhlamvu (m ₁ ) = amagremu angu-30 = 0.03 kg

Isisindo sebhulokhi (m2 ₎ = 1 kg

Isivinini sokuqala senhlamvu ( v ₁ ) = 30 m/s

isivinini sokuqala sebhulokhi (v ₂ ) = 0 ( ibhulokhi lapho iphumule )

Okufunwayo : isivinini senhlamvu kanye nebhulokhi ngemva kokushayisana (v')

Isixazululo:

m ₁ v ₁ + m ₂ v ₂ = (m ₁ + m ₂ ) v'

(0.03)(30) + (1)(0) = (0.03 + 1) v'

0.9 + 0 = 1.03 v'

0.9 = 1,03 v'

v' = 0.9 / 1,03

v' = 0.87 m/s

[irp]

2. Ibhola lebhiliyadi A elinobunzima obungu-2 kg lihamba ngesivinini v _A = 6 ms ⁻¹ lishayisana ngqo nebhola B elinobunzima obulinganayo. Uma ukushayisana kungaqini ngokuphelele, zingakanani izivinini zamabhola amabili ngemva kokushayisana.

Kwaziwa:

Isisindo A (m _A ) = 2 kg

Isisindo B (m _B ) = 2 kg

Isivinini sokuqala sebhola A (v _A ) = -6 m/s

Isivinini sokuqala sebhola B (v _B ) = 4 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

Okufunwayo : isivinini samabhola amabili ngemva kokushayisana. (v')

Isixazululo:

m _A v _A + m _B v _B = (m _A ' + m _B ) v'

(2)(-6) + (2)(4) = (2 + 2) v'

-12 + 8 = 4 v'

-4 = 4 v'

v' = -4 / 4

v' = -1 m/s

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3. m₁ = 3kg futhi m₂ = 4kg basondelane ngendlela ephambene ngesivinini v₁ = 10m/s futhi v₂ = 12 m/s. Uma ukushayisana kunganambitheki ngokuphelele, zingakanani ijubane lamabhola amabili ngemva kokushayisana?

Kwaziwa:

Into enesisindo 1 (m1 ₎ = 3 kg

Into enesisindo 2 (m2 ₎ = 4 kg

Isivinini sento 1 (v ₁ ) = -10 m/s

Isivinini sento 2 (v ₂ ) = 12 m/s

Okufunwayo : isivinini ngemva kokushayisana (v')

Isixazululo:

m ₁ v ₁ + m ₂ v ₂ = (m ₁ ' + m ₂ ) v'

(3)(-10) + (4)(12) = (3 + 4) v'

-30 + 48 = 7 v'

18 = 7 v'

v' = 18 / 7

v' = 2.6 m/s

[wpdm_package id='1157′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Ibhola elingamagremu angu-200, u-A, elihamba ngesivinini esingama-10 m/s lishaya ibhola elingamagremu angu-200, u-B, lapho liphumule. Liyini ijubane lebhola u-A nebhola u-B ngemva kokushayisana?

Kwaziwa:

Isisindo sebhola A (m _A ) = 200 amagremu = 0.2 kg

Isisindo sebhola B (m _B ) = 200 amagremu = 0.2 kg

Isivinini sebhola A ngaphambi kokushayisana (v _A ) = 10 m/s

Isivinini sebhola B ngaphambi kokushayisana (v _B ) = 0

Okufunwayo: isivinini sebhola A (v _A ') kanye nesivinini sebhola B (v _B ') ngemva kokushayisana

Isixazululo:

v _A ' = v _B = 0

v _B ' = v _A = 10 m/s

[irp]

2. Izinto ezimbili ezilingana ngobuningi ziyasondelana, zishayisane bese zigxumagxuma. Ijubane lesisindo u-A ngaphambi kokushayisana lingu-8 m/s kanti ijubane lesisindo u-B ngaphambi kokushayisana lingu-12 m/s. Ubukhulu kanye nesiqondiso sejubane lesisindo u-A kanye nesisindo u-B ngemva kokushayisana kuyini!

Kwaziwa:

Isisindo A (m _A ) = m

Isisindo B (m _B ) = m

Isivinini sesisindo A ngaphambi kokushayisana (v _A ) = -8 m/s

Isivinini sesisindo B ngaphambi kokushayisana (v _B ) = 12 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

Okufunwayo: ubukhulu kanye nesiqondiso sejubane lesisindo u-A (v _A ') kanye nesisindo u-B (v _B ') ngemva kokushayisana

Isixazululo:

Ekushayisaneni okunwebeka ngokuphelele, uma izinto zinobunzima obulinganayo khona-ke ijubane lika-A ngemva kokushayisana (v _A ') = ijubane lika-B ngaphambi kokushayisana (v _B ) kanye nejubane lika-B ngemva kokushayisana (v _B ') = ijubane lika-A ngaphambi kokushayisana (v _A ).

Uma ngaphambi kokushayisana, u-A uya kwesokudla kanti u-B uya ngakwesobunxele, khona-ke, ngemva kokushayisana, u-A uya ngakwesobunxele kanti u-B uya kwesokudla.

Izinto zinesisindo esilinganayo futhi ukushayisana kunwebeka ngokuphelele ngakho zombili izinto zishintshana ngesivinini.

v _A ' = -v _B = -12 m/s

v _B ' = v _A = 8 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

[irp]

3. Into engamakhilogremu amabili, u-A, ehamba ngesivinini esingama-10 m/s ishaya ibhola elingamakhilogremu angu-4, u-B, ihamba ngesivinini esingama-20 m/s. Uma ukushayisana kunwebeka ngokuphelele, liyini ijubane lento u-A kanye nento u-B ngemva kokushayisana?

Kwaziwa:

Isisindo A (m _A ) = 2 kg

Isisindo B (m _B ) = 4 kg

Isivinini sento A ngaphambi kokushayisana (v _A ) = 10 m/s

Isivinini sento B ngaphambi kokushayisana (v _B ) = 20 m/s

Okufunwayo : isivinini sento A (v _A ') kanye nesivinini sento B (v _B ') ngemva kokushayisana

Isixazululo :

Ekushayiseni okunwebeka ngokuphelele , uma izinto zinesisindo esilinganayo futhi zisondelana, ijubane lento ngemva kokushayisana libalwa kusetshenziswa le fomula:

Isivinini sento A ngemva kokushayisana:

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4. Ukuhamba ngesivinini esingamagremu ayi-100 ngesivinini esingama-20 m/s kushaya ukushayisana kodonga okunwebeka ngokuphelele. Kuyini ubukhulu kanye nesiqondiso sejubane lento ngemva kokushayisana.

Kwaziwa:

Isisindo (m _A ) = amagremu ayi-100 = 0.1 kg

Isisindo sodonga (m _B ) = okungapheli

Isivinini sobunzima ngaphambi kokushayisana (v _A ) = 20 m/s

Isivinini sobunzima ngemva kokushayisana (v _B ) = 0

Okufunwayo : ubukhulu kanye nesiqondiso sejubane ngemva kokushayisana

Isixazululo:

Uma u-v _B = 0, u-m _A omncane kakhulu futhi u-m ₂ mkhulu kakhulu khona-ke u-v _A ' = -v _A kanye no-v ₂ ' = 0.

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

5. Amabhola amabili, u-A onesisindo esingu- 2-kg kanye nebhola u-B onesisindo esingu- 5-kg, ngaphambi nangemva kokushayisana aboniswe esithombeni esingezansi. Uma ukushayisana kunwebeka ngokuphelele, lingakanani ijubane lebhola u-A ngaphambi kokushayisana?

Kwaziwa:

Isisindo sebhola A (m_A) = 2 kg

Isisindo sebhola B (m _B ) = 5 kg

Isivinini sebhola B ngaphambi kokushayisana (v _B ) = 2 m/s

Isivinini sebhola A ngemva kokushayisana (v _A ') = 5 m/s

Isivinini sebhola B ngemva kokushayisana (v _B ') = 4 m/s

Womabili amabhola aya ngakwesokudla ngakho ijubane lawo lisayinwe lihle.

Okufunwayo: Isivinini sebhola A ngaphambi kokushayisana (v _A )

Isixazululo:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

2(v _A ) + (5)(2) = (2)(5) + (5)(4)

2(v _A ) + 10 = 10 + 20

2(v _A ) + 10 = 30

2(v _A ) = 30 – 10

2(v _A ) = 20

v _A = 20/2

v _A = 10 m/s

[irp]

6. Izinto A no-B zihamba ngendiza evundlile, njengoba kuboniswe esithombeni esingezansi. Uma ukushayisana kunwebeka ngokuphelele futhi ijubane lento B ngemva kokushayisana lingu- 15 m/s ¹ , liyini ijubane lento A ngemva kokushayisana.

Kwaziwa:

Isisindo sento A (m_A) = 5 kg

Isisindo sento B (m _B ) = 2 kg

Isivinini sento A ngaphambi kokushayisana (v _A ) = 12 m/s

Isivinini sento B ngaphambi kokushayisana (v _B ) = 10 m/s

Isivinini sento B ngemva kokushayisana (v _B ') = 15 m/s

Zombili izinto, ngaphambi nangemva kokushayisana, ziya kwesokudla ukuze ijubane lazo libonakale lihle.

Okufunwayo: Isivinini sento A ngemva kokushayisana (v _A ')

Isixazululo:

m_A v_A +m_B v_B = m_A v_A' + m_B v_B'

(5)(12) + (2)(10) = (5)v _A ' + (2) (15)

60 + 20 = (5)v _A ' + 30

80 = (5)v _A ' + 30

80 – 30 = (5)v _A '

50 = (5)v _A '

v _A ' = 50/5

v _A ' = 10 m/s

[wpdm_package id='1156′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Ibhola elincane liphonswa ngokuvundlile ngesivinini esingaguquki esingu-10 m/s. Ibhola lishaya udonga futhi liphinde libonakale ngesivinini esifanayo. Luyini ushintsho ku- linear momentum yebhola?

Kwaziwa:

Isisindo (m) = 0.2 kg

Isivinini sokuqala (v _o ) = -10 m/s

Isivinini sokugcina (v _t ) = 10 m/s

Izimpawu zokuhlanganisa kanye nokususa zibonisa ukuthi izinto zihamba ngendlela ehlukile.

Okufunwayo : ushintsho ku-momentum eqondile (Δp)

Isixazululo:

Ifomula yoshintsho ku-momentum eqondile :

Δp = mv _t – mv _o = m (v _t – v _o )

Ushintsho ku-momentum eqondile:

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

Δp = 4 kg m/s

[irp]

2. Ibhola elingamagremu ayi-10 liwela ngokukhululeka lisuka endaweni ephakeme, lishaye phansi ngesivinini esingu-15 m/s, bese libuyela phezulu ngesivinini esingu-10 m/s. Thola ukuthi i-pulse ingakanani!

Kwaziwa:

Isisindo (m) = 10 amagremu = 0.01 kg

Ijubane lokuqala (v _o ) = -15 m/s

Ijubane lokugcina (v _t ) = 10 m/s

Okufunwayo: Impulse (I)

Isixazululo:

I-impulse (I) ilingana noshintsho ku-momentum (Δp)

I = mv _t – mv _o = m (v _t – v _o )

Umfutho:

I = 0.01 (10 – (-15)) = 0.01 (10 + 15)

I = 0.01 (25)

I = 0.25 kg m/s

[irp]

3. Ibhola elingamagremu angu-200 laphonswa ngokuvundlile ngesivinini esingu-4 m/s, bese ibhola lishaywa ngendlela efanayo. Ubude bebhola uma lithintana nebhethi buyimizuzwana engu-2 mil l kanti isivinini sebhola ngemva kokushiya ibhethi singu-12 m/s. Ubukhulu bamandla asetshenziswa ngumshayi ebholeni bungu …

Kwaziwa:

Isisindo (m) = 200 amagremu = 0.2 kg

Ijubane lokuqala (v _o ) = 4 m/s

Ijubane lokugcina (v _t ) = 12 m/s

Isikhawu sesikhathi (t) = 2 milliseconds = (2/1000) imizuzwana = 0.002 imizuzwana

Okufunwayo : Ubukhulu bamandla (F)

Isixazululo:

Ifomula ye-impulse:

I = F t

Ifomula yokushintsha komfutho:

mv _t – mv _o = m (v _t – v _o )

I-impulse (I) ilingana noshintsho ku-momentum (Δp)

I = Δp

F t = m (v _t – vo _o )

F (0.002) = (0.2)(12 – 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Newton

[wpdm_package id='1155′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

1. Into ihamba ngesivinini esingaguquki esingu-10 m/s. Bala umfutho oqondile wento.

Kwaziwa :

Isisindo (m) = 1 kg

Ijubane (v) = 10 m/s

Okufunwayo: umfutho oqondile (p)

Isixazululo:

Ifomula yomfutho oqondile:

p = mv

p = umfutho oqondile, m = isisindo, v = ijubane

Umfutho oqondile:

p = mv = (1)(10) = 10 kg m/s ²

[irp]

2. Ibhulokhi engu-2 kg kanye nebhulokhi engu-4 kg lihamba ngesivinini esingaguquki esingu-20 m/s. Iyini ijubane eliqondile lamabhulokhi.

Kwaziwa:

Isisindo sebhulokhi A (m _A ) = 2 kg

Isisindo sebhulokhi B (m _B ) = 4 kg

Ijubane lebhulokhi A (v _A ) = 20 m/s

Ijubane lebhulokhi B (v _B ) = 20 m/s

Okufunwayo: Umfutho oqondile webhulokhi A (p _A ) kanye nomfutho oqondile webhulokhi B (p _B )

Isixazululo:

Umfutho oqondile webhulokhi A :

p _A = m _A v _A = (2)(20) = 40 kg m/s

Umfutho oqondile webhulokhi B :

p _B = m _B v _B = (4)(20) = 80 kg m/s

[irp]

3. Ibhulokhi elingamakhilogremu angu-2 lihamba ngesivinini esingaguquki esingu-2 m/s kanye nebhulokhi elingamakhilogremu angu-2 lihamba ngesivinini esingaguquki esingu-4 m/s. Thola umfutho oqondile wamabhulokhi.

Kwaziwa:

Isisindo sebhulokhi A (m _A ) = 2 kg

Isisindo sebhulokhi B (m _B ) = 2 kg

Ijubane lebhulokhi A (v _A ) = 2 m/s

Ijubane lebhulokhi B (v _B ) = 4 m/s

Okufunwayo: umfutho oqondile wamabhulokhi

Isixazululo:

Umfutho oqondile webhulokhi A :

p _A = m _A v _A = (2)(2) = 4 kg m/s

Umfutho oqondile webhulokhi B:

p _B = m _B v _B = (2)(4) = 8 kg m/s

[irp]

4. Into engamakhilogremu angu-5 iphumule. Iyini ijubane eliqondile lejubane.

Kwaziwa:

Isisindo (m) = 5 kg

Ijubane lento (v) = 0

Okufunwayo : umfutho oqondile (p)

Isixazululo:

p = mv = (5)(0) = 0

[wpdm_package id='1155′]

1. Izinkinga zomugqa wejubane kanye nezixazululo
2. Izinkinga zejubane kanye nezixazululo zomfutho
3. Ukushayisana okunwebeka ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
4. Ukushayisana okune-elastic ngokuphelele ezinkingeni nezixazululo zobukhulu obubodwa
5. Ukushayisana kwe-inelastic ezinkingeni nezixazululo zobukhulu obubodwa

Funda kabanzi

Amandla yisilinganiso lapho umsebenzi wenziwa khona esikhathini esithile. Ngokwezibalo, amandla yisilinganiso somsebenzi/sesikhathi.

P = W/t

Incazelo: P = amandla (iJoule/isekhondi = iWatt), W = umsebenzi (iJoule), t = isikhawu sesikhathi (isekhondi)

Ngokusekelwe kulesi sibalo, kungaphethwa ngokuthi uma izinga lomsebenzi likhulu, amandla aba maningi. Ngakolunye uhlangothi, uma izinga lomsebenzi lincane, amandla aba mancane. Izinga lomsebenzi libhekisela esilinganisweni lapho umsebenzi wenziwa khona.

[irp]

Amandla ayi-scalar. Iyunithi yamandla ye-SI yi-Joule/yesibili. I-Joule/yesibili = Watt (efushanisiwe njengo-W), eqanjwe kanjalo ukuhlonipha uJames Watt. Iyunithi yamandla yaseBrithani ingama-foot-pounds ngomzuzwana.

Le yunithi incane kakhulu ngezinjongo ezisebenzayo, ngakho-ke kusetshenziswa iyunithi enkulu yamandla ehhashi (efingqiwe njenge-hp). Ihhashi elilodwa lamandla ehhashi = amakhilogremu angu-550 ngomzuzwana = ama-Watts angu-764 = ¾ kilowatt.

Inani lomsebenzi lingabonakaliswa ngamayunithi wamandla x isikhathi, isibonelo, ama-kilowatt-hours noma i-kWh. I-kWh eyodwa ibhekisela emsebenzini owenziwe ngesilinganiso esingaguquki se-kilowatt eli-1 ihora elilodwa.

1. Umuntu onesisindo esingama -50 kg ugijima ngezitebhisi ngamamitha ayi-10 ukuphakama ngemizuzu emi-2. Ukusheshisa ngenxa yamandla adonsela phansi (g) kungu-10 m/ s ^2. Thola amandla.

Kwaziwa:

Isisindo (m) = 50 kg

Ukuphakama (h) = amamitha ayi -10

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isikhawu sesikhathi (t) = imizuzu emi-2 = 2 (60) = imizuzwana eyi -120

Kufunwa : Amandla (P)

Isixazululo:

Ifomula yamandla:

P=W/t

P = amandla , W = umsebenzi , t = isikhathi

Ifomula Yomsebenzi:

W = F s = wh = mgh

W = umsebenzi , F = amandla , w = isisindo , d = ukufuduka , h = ukuphakama , m = isisindo, g = ukusheshisa ngenxa yamandla adonsela phansi

W = mgh = (50)(10)(10) = 5000 amaJoules.

P = W / t = 5000 / 120 = 41.7 AmaJoules/isekhondi c ku- d.

[irp]

2. Bala amandla adingekayo kumuntu onesisindo esingu-60 kg okhuphuka esihlahleni ngamamitha angu-5 ukuphakama ngemizuzwana eyi-10. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ².

Kwaziwa:

Isisindo (m) = 60 kg

Ukuphakama (h) = 5 amamitha s

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Kufunwa : Amandla

Isixazululo:

Umsebenzi:

W = mgh = (60)(10)(5) = 3000 amaJoules

Amandla:

P = W / t = 3000 / 10 = 300 Joules/se cond.

3. Ihlaya elijikelezayo elinamandla angama-watts angu-300 kanye nesikhathi semizuzu emi-5 lijikeleza imizuliswano emi-5. Amandla eliwasebenzisayo….

A. 15 kJ

B. 75 kJ

C. 90 kJ

D. 450 kJ

Kwaziwa:

Amandla (P) = 300 Watts = 300 Joules/isekhondi

Isikhathi (T) = imizuzu emi-5 = 5 (imizuzwana engama-60) = imizuzwana engama-300

Inani lokujikeleza = 5

Kufunwa: Amandla asetshenziswa yi-rotary comedy

Isixazululo:

Impendulo efanele ngu-D.

[wpdm_package id='1190′]

1. Umsebenzi wenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhulokhi liwela phansi endaweni ebushelelezi ethambekele ngaphandle kokungqubuzana . Iyini ijubane lebhulokhi uma lifika phansi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ²

Kwaziwa:

Ukuphakama (h) = 8 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo : ijubane (v)

Isixazululo :

Amandla okuqala omshini (ME _o ) = amandla adonsela phansi (PE)

ME _o = PE = mgh = m (10)(8) = 80 m

Amandla okugcina omshini (ME _t ) = amandla e-kinetic (KE)

ME _t = KE = ½ mv ²

Isimiso sokulondolozwa kwamandla omshini sithi amandla okuqala omshini = amandla okugcina omshini:

Mina ₌ Mina _t

80 m = ½ mv ²

80 = ½ v ²

160 = v ²

v = √160 = √(16)(10) = 4√10 m/s

[irp]

2. Into engu-1-kg ishelela phansi ngamamitha angu-8. Thola amandla e-kinetic ngemva kokuba into ihambe ngamamitha angu-5… Ukusheshisa ngenxa yamandla adonsela phansi g = 10 m/s ²

Kwaziwa:

Isisindo (m) = 0.2 kg

d = amamitha angu-5

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo : amandla e-kinetic (KE)

Isixazululo:

isono 30 ^o = h / d

0.5 = amahora / 5

h = (0.5)(5) = amamitha angu-2.5

Ushintsho ekuphakameni kwento lungamamitha angu-2.5.

Amandla okuqala omshini (ME _o ) = amandla adonsela phansi (PE)

ME _o = PE = mgh = (1)(10)(2.5) = 25 amaJoules

Amandla okugcina omshini (ME _t ) = amandla e-kinetic (KE)

ME _t = KE

Umgomo wokulondolozwa kwamandla omshini uthi amandla okuqala omshini = amandla okugcina omshini:

Mina ₌ Mina _t

25 = KE

Amandla e-kinetic = ama-Joules angu-25.

[wpdm_package id='1170′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhulokhi elingu-1-kg lishelela phansi endaweni ebushelelezi egobile. Thola amandla e-kinetic kanye nejubane lebhulokhi endaweni ephansi kakhulu. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ².

Kwaziwa:

Isisindo (m) = 1 kg

Ushintsho ekuphakameni (h) = 5 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Amandla e-Kinetic (KE) kanye nesivinini sebhlokhi.

Isixazululo:

(a) Amandla e-Kinetic

Amandla okuqala omshini = amandla adonsela phansi

ME _o = PE = mgh = (1)(10)(5) = 50 amaJoules

Amandla okugcina omshini = amandla e-kinetic

ME _t = KE = ½ mv _t ²

Isimiso sokulondolozwa kwamandla omshini sithi amandla okuqala omshini = amandla okugcina omshini:

Mina ₌ Mina _t

I-PE = KE

50 = KE

Amandla e-Kinetic (KE) = ama-Joules angu-50.

(b) Ijubane lebhulokhi

Umgomo wokonga amandla emishini:

Amandla okuqala omshini (ME _o ) = amandla okugcina omshini (ME _t )

Amandla adonsela phansi (PE) = amandla e-kinetic (KE)

50 = ½ mv ²

2(50) / m = v ²

100 / 1 = v ²

100 = v ²

v = √100

v = 10 m/s

[irp]

2. Into engamakhilogremu angu-2 iyashelela phansi ngaphandle kokungqubuzana. Iyini amandla e-kinetic kanye nejubane lento engamamitha amabili ngaphezu komhlabathi. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ²

Kwaziwa:

Isisindo (m) = 2 kg

Ushintsho ekuphakameni (h) = 10 – 2 = 8 m

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo : amandla e-kinetic (KE) kanye nesivinini (v) kumamitha ama-2 ngaphezu komhlabathi.

Isixazululo:

(a) Amandla e-kinetic amamitha amabili ngaphezu komhlabathi

Amandla okuqala omshini = amandla adonsela phansi

ME _o = PE = mgh = (2)(10)(8) = 160 amaJoules

Amandla okugcina omshini = amandla e-kinetic

ME _t = KE = ½ mv _t ²

Umgomo wokulondolozwa kwamandla omshini uthi amandla okuqala omshini = amandla okugcina omshini:

Mina ₌ Mina _t

I-PE = KE

160 = KE

Amandla e-kinetic (KE) amamitha ama-2 ngaphezu komhlabathi angama-160 Joules.

(b) Ijubane lento endaweni ephansi kakhulu

Isimiso sokulondolozwa kwamandla omshini:

Amandla okuqala omshini (ME _o ) = amandla okugcina omshini (EM _t )

Amandla adonsela phansi (PE) = amandla e-kinetic (KE)

160 = ½ mv ²

160 = ½ (2) v ²

160 = v ²

v = √160 = √(16)(10) = 4√10 m/s

[wpdm_package id='1167′]

1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

Funda kabanzi

1. Ibhola elikhahlelwayo lishiya phansi nge-engeli θ = 30 ^{o ngejubane lokuqala elingu-10 m/s.} Isisindo sebhola = 0.1 kg. Ukusheshisa ngenxa yamandla adonsela phansi kungu-1 0 m/s ² . Thola (a) Amandla adonsela phansi endaweni ephakeme kakhulu (b) Iphuzu eliphakeme kakhulu noma ukuphakama okuphezulu kakhulu

Kwaziwa:

Isisindo (m) = 0.1 kg

Ijubane lokuqala (v _o ) = 10 m/s

I-engeli = 30 ^o

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isixazululo:

(a) Amandla adonsela phansi

Bala ingxenye evundlile (v _ox ) kanye nengxenye evundlile (v _oy ) yejubane lokuqala.

v_ox =v_o cos θ = (10)(cos 30^o) = (10)(0.5√3) = 5√3 m/s

v _oy = v _o isono θ = (10)(isono 30 ^o ) = (10)( 0.5) = 5 m/s

Amandla okuqala omshini

Amandla okuqala omshini (ME _o ) = amandla e-kinetic (KE)

ME _o = KE = ½ mv _o ² = ½ (0.1) (10) ² = ½ (0.1) (100) = ½ (10) = 5 Joules

Amandla okugcina omshini

Amandla e-kinetic endaweni ephezulu kakhulu:

KE = ½ mv _inkabi ² = ½ (0.1) (5√3) ² = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Joules

Isimiso sokulondolozwa kwamandla okusebenza ngomshini

Amandla okuqala omshini (ME _o ) = amandla okugcina omshini (ME _t )

KE = PE + KE

5 = EP + 3.75

I-PE = 5 – 3.75 = 1.25 AmaJoule

Amandla adonsela phansi endaweni ephakeme kakhulu angama-1.25 Joules.

(b) Iphuzu eliphakeme kakhulu noma ukuphakama okuphezulu kakhulu

PE = mgh

1.25 = (0.1)(10) h

1.25 = ihora

Ukuphakama okuphezulu kungamamitha ama-1.25.

[irp]

2. Ibhola elingu-0.1-kg liphonswa ngokuvundlile ngesivinini sokuqala v _o = 10 m/s ukusuka esakhiweni esingamamitha ayi-10 ukuphakama. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s ^2. Thola amandla e-kinetic ebhola uma lishaya phansi.

Kwaziwa:

Isisindo (m) = 0.1 kg

Ijubane lokuqala (v _o ) = 10 m/s

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Ushintsho ekuphakameni (h) = 10 – 2 = 8 m

Kufunwa: amandla e-kinetic kumamitha amabili ngaphezu komhlabathi

Isixazululo:

Amandla adonsela phansi (PE) = mgh = (0.1)(10)(10) = 10 Joules

Amandla okuqala e-kinetic (KE)= ½ mv _o ² = ½ (0.1)(10) ² = ½ (0.1)(100) = ½ (10) = 5 Joules

Amandla okugcina e-kinetic = amandla okuqala adonsela phansi + amandla okuqala e-kinetic = 10 + 5 = 15 Joules

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1. Umsebenzi owenziwa ngezinkinga zamandla nezixazululo
2. Izinkinga zamandla e-kinetic kanye nezixazululo zomsebenzi
3. Izinkinga nezixazululo zesimiso samandla okusebenza-okusebenza ngomshini
4. Izinkinga zamandla adonsela phansi kanye nezixazululo ezingaba khona
5. Amandla angaba khona ezinkinga zentwasahlobo ezinwebekayo nezixazululo
6. Izinkinga zikagesi nezixazululo
7. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kuqhutshekwe nokuwa kwamahhala
8. Ukusetshenziswa kokulondolozwa kwamandla omshini wokunyakaza okuphezulu nokwehla ekunyakazeni kokuwa kwamahhala
9. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ukuze kushukunyiswe endaweni egobile
10. Ukusetshenziswa kokulondolozwa kwamandla omshini ukuze kushukunyiswe endizeni ethambekele
11. Ukusetshenziswa kokulondolozwa kwamandla okusebenza ngomshini wokunyakaza okubonakalayo

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