Imiyalelo yokuhlolwa komthetho ka-Archimedes
Inhloso yokuhlolwa komthetho ka-Archimedes:
– Abafundi bangalinganisa umthamo kanye nesisindo samanzi asuswe yinto ecwiliswe emanzini.
– Abafundi bangazi futhi baqonde umthetho ka-Archimedes
Amathuluzi nezinto zokwakha:
– Isitsha esiphakathi nendawo (1)
– Isitsha esincane (1)
– I-Dynamometer (1)
– Layisha (1)
- Umoya
Izinyathelo zokuhlola:
(Ukuhlolwa ukuphenya ivolumu yomthwalo)
– Faka amanzi esitsheni esiphakathi nendawo kuze kube yilapho amanzi egcwala kakhulu.
– Sondeza isitsha esincane eduze kwesitsha esiphakathi nendawo.
– Faka kancane kancane isisindo esitsheni esiphakathi esigcwele amanzi.
– Ngemva kokufakwa komthwalo esitsheni esiphakathi nendawo, amanzi athile achitheka. Amanzi achithekile abe esekhishwa esitsheni esincane.
– Linganisa umthamo wamanzi achithekile. Uma usebenzisa ithubhu lokulinganisa noma isitsha sesikali khona-ke kukhona isikali odongeni lwethubhu. Umugqa ohambisana nomphezulu wamanzi = umthamo wamanzi achithekile. Umthamo (V) = …… amamitha-cubic (m)3)
– Uma ungasebenzisi isilinda esiphothuliwe, umthamo wamanzi unganqunywa kusetshenziswa indlela elandelayo. Kala umjikelezo wesitsha. Uma umjikelezo wesitsha uyindilinga, bala irediyasi usebenzisa ifomula yomjikelezo wesitsha. Uma umjikelezo wesitsha uyindilinga noma unxande, bala ubude nobubanzi usebenzisa umjikelezo wesikwele noma unxande wefomula yonxande. Bhala phansi imiphumela yakho yokubala. Irediyasi yesitsha (r) = …… amamitha noma ubude besitsha (p) = …….. amamitha. Ububanzi besitsha (l) = …… amamitha
– Kala ukuphakama kobuso bamanzi usebenzisa ithuluzi lokulinganisa. Ukuphakama (t) = …… amamitha
– Sebenzisa ifomula yevolumu ukuze ubale ivolumu yamanzi achithekile. Ifomula yevolumu ilungiswa ngesimo sesilinda. Ivolumu (V) = …… amamitha ayi-cubic (m3)
Zonke izingxenye kumele zichazwe ngamayunithi aphesheya kwezilwandle.
(Ukubalwa kobukhulu bamandla okuphaphazela)
Bala ubukhulu bamandla agelezayo usebenzisa ifomula yamandla agelezayo:
FA = g V = (1000)(9,8)(V) = (9800)(……..) = ……… Newton.
Imininingwane:
FA = amandla okuntanta, = ukuminyana kwamanzi = 1000 kg/m3, g = ukusheshisa ngenxa yamandla adonsela phansi = 9,8 m/s2.
(Zama ukuhlola isisindo samanzi achithekile)
– Faka amanzi esitsheni esiphakathi nendawo kuze kube yilapho amanzi egcwala kakhulu.
– Kala isisindo sesitsha esincane usebenzisa isikali (m = …… amakhilogremu)
– Sondeza isitsha esincane eduze kwesitsha esiphakathi nendawo.
– Faka kancane kancane isisindo esitsheni esiphakathi esigcwele amanzi.
– Ngemva kokufakwa komthwalo esitsheni esiphakathi nendawo, amanzi athile achitheka. Amanzi achithekile abe esekhishwa esitsheni esincane.
– Kala isisindo sesitsha esincane esinamanzi achithekile (m' = …….kilogram)
– Isisindo samanzi achithekile = m' – m = …… amakhilogremu
– Bala isisindo samanzi achithekile. Sebenzisa isilinganiso sokusheshisa amandla adonsela phansi = g = 9,8 m/s2.
w = (m' – m)(9,8) = ………….Newton
Isiphetho:
Phendula imibuzo elandelayo ngokusekelwe ezivivinyweni ozenzile.
– Amandla anamandla amakhulu kangakanani? FA = ……………………… uNewton
– Mangaki amanzi achithekile? w = …….. AmaNewton
– Ingabe ubukhulu bamandla okuphapha bufana noma bucishe bufane nesisindo samanzi achithekile?
Uma kunjalo, khona-ke usuwenze kahle umsebenzi wakho wokuhlola nokubala. Uma ubukhulu bamandla agelezayo buhluke kakhulu kunesisindo samanzi asusiwe, khona-ke umsebenzi wakho wokuhlola nokubala akwenziwanga kahle.
Ubukhulu bamandla okuphapha bulingana nesisindo samanzi achithekile = umthetho ka-Archimedes.
Imibuzo eyisibonelo ngomthetho ka-Archimedes dan Imibuzo yomthetho ka-Archimedes
