Umthetho wokulondolozwa komfutho we-angular wathi uma umzuzu wamandla ophumela entweni eqinile ejikelezayo inani lingu-zero bese kuba umfutho we-angular Into eqinile ekunyakazeni okujikelezayo njalo. Ifomula yomthetho wokulondolozwa komfutho we-angular ingatholakala ngokwezibalo ngokushintsha ifomula yomthetho wesibili kaNewton wokunyakaza komfutho we-angular.
Le nguqulo ye-angular momentum yomthetho wesibili kaNewton iyisifaniso sokujikeleza sefomula Inguqulo yesibili yomfutho womthetho kaNewton.
Uma umzuzu wamandla ophumelayo ungu-zero, ifomula engenhla ishintsha ibe yi:
Imininingwane:
Isibonelo sezinkinga:
1. Inhlayiya ejikelezayo inomzuzu wokungahlali kahle ongu-4 kg m2 kanye nejubane le-angular elingu-2 rad/s. Uma ijubane le-angular le-particle lishintsha libe ngu-4 rad/s khona-ke umzuzu we-inertia ye-particle ushintsha ube…
Ingxoxo
I-Diketahui :
Isikhathi sokuqala sokungalali kahle = 4 kg m2
Ijubane lokuqala le-angular = 2 rad/s
Isivinini sokugcina se-angular = 4 rad/s
Kubuziwe : umzuzu wokugcina wokungabi naso isikhathi?
Jawab :
Umthetho wokulondolozwa komfutho we-angular uthi:
Umfutho wokuqala we-angular (L)o) = umfutho wokugcina we-angular (Lt)
(umzuzu wokuqala we-inertia) (isivinini sokuqala se-angular) = (umzuzu wokugcina we-inertia) (isivinini sokugcina se-angular)
(4 kg m2)(2 rad/s) = (umzuzu wokugcina we-inertia)(4 rad/s)
Isikhathi sokugcina sokungakhathali = 2 kg m2
2. Inhlayiya enesisindo esingu-2 kg ijikeleza i-axis yokujikeleza isuka ebangeni elingamamitha amabili ngesivinini se-angle esingu-2 rad/s. Uma ibanga lenhlayiya lisuka ku-axis yokujikeleza lishintsha libe yimitha eli-1, thola ijubane le-angle lenhlayiya!
Ingxoxo
I-Diketahui :
Isisindo sezinhlayiya = 2 kg
Ibanga lezinhlayiya ukusuka ku-axis yokujikeleza (1) = 2 imitha
Ijubane lokuqala le-angular = 2 rad/s
Ibanga lezinhlayiya ukusuka ku-axis yokujikeleza (2) = 1 imitha
Kubuziwe : ijubane lokugcina le-angular?
Jawab :
Bala umzuzu we-inertia (I) we-particle
Isikhathi sokuqala sokungalali kahle (I) awu) :
I awu = uMnu.2 = (2 kg)(2 m)2 = (2 kg)(4 m2) = 8 kg m2
Isikhathi sokugcina sokungakhathali (I ukuphela) :
I ukuphela = uMnu.2 = (2 kg)(1 m)2 = (2 kg)(1 m2) = 2 kg m2
Bala ijubane lokugcina le-angular
Umthetho wokulondolozwa komfutho we-angular :
Umfutho wokuqala we-angular = umfutho wokugcina we-angular
(umzuzu wokuqala we-inertia) (isivinini sokuqala se-angular) = (umzuzu wokugcina we-inertia) (isivinini sokugcina se-angular)
(8 kg m2)(2 rad/s) = (2 kg m2)(isivinini sokugcina se-angular)
Isivinini sokugcina se-angular = 8 rad/s
3. Idiski eqinile eyisilinda elinganayo iqala ijikeleza ku-axis yayo ngesivinini se-angular esingu-4 rad/s. Ubunzima kanye nerediyasi yediski kungu-1 kg kanye no-0,5 wamamitha. Uma idiski ijikeleza, indandatho enesisindo kanye nerediyasi engu-0,2 kg kanye no-0,1 wamamitha ibekwa phezu kwediski ukuze idiski kanye neringi kuzungeze ndawonye. Isikhungo seringi singaphezu ngqo kwesikhungo sediski. Thola isivinini se-angular sediski kanye neringi!
Ingxoxo
I-Diketahui :
Isivinini sokuqala se-angular = isivinini se-angular sesilinda esiqinile = 4 rad/s
Isisindo sesilinda esiqinile = 1 kg
Irediyasi yesilinda esiqinile = amamitha angu-0,5
Isisindo sendandatho = 0,2 kg
Irediyasi yendandatho = amamitha angu-0,1
Kubuziwe : isivinini sokugcina se-angular = isivinini se-angular sendandatho nesilinda esiqinile?
Jawab :
Ifomula yesikhathi sokungabi namandla kwesilinda esiqinile esilinganayo = I = ½ mr2
Ifomula yesikhathi sokungabi namandla kwendandatho = I = mr2
Isikhathi sokuqala sokungakhathali = isikhathi sokungakhathali kwesilinda esiqinile:
Mina = ½ uMnu.2 = ½ (1 kg)(0,5 m)2 = (0,5 kg)(0,25 m2) = 0,125 kg m2
Umzuzu wokugcina we-inertia = umzuzu we-inertia wesilinda esiqinile + umzuzu we-inertia wendandatho:
Isikhathi sokungakhathali kwendandatho = Mina = uMnu.2 = (0,2 kg)(0,1 m)2 = (0,2 kg)(0,01 m2) = 0,002 kg m2
Isikhathi sokugcina sokungakhathali = 0,125 kg m2 + 0,002 kg m2 = 0,127 kg m2
Umthetho wokulondolozwa komfutho we-angular :
Umfutho wokuqala we-angular (L)o) = umfutho wokugcina we-angular (Lt)
(umzuzu wokuqala we-inertia) (isivinini sokuqala se-angular) = (umzuzu wokugcina we-inertia) (isivinini sokugcina se-angular)
(0,125 kg m2)(4 rad/s) = (0,127 kg m2)(isivinini sokugcina se-angular)
0,5 kg m2/s = (0,127 kg m2)(isivinini sokugcina se-angular)
Isivinini sokugcina se-angular = 0,5 / 0,127
Isivinini sokugcina se-angular = 4 rad/s
