Imibuzo yesibonelo sokushayisana

Izibonelo eziyi-8 zemibuzo yokushayisana

Ukushayisana okunwebeka ngokuphelele

1. Izinto ezimbili u-A (3 kg) no-B (5 kg) zihamba ngendlela efanayo ngesivinini esingu-8 m/s ngasinye.^-1 kanye ne-4 ms^-1 Uma into A ishaya into B ngokuguquguquka okuphelele, khona-ke ijubane lento ngayinye ngemva kokushayisana...

A. 3 ms ^-1 kanye ne-7 ms ^-1

B. 6 ms ^-1 kanye ne-10 ms ^-1

C. 4,25 ms ^-1 kanye ne-10 ms ^-1

D. 5,5 ms ^-1 kanye ne-5,5 ms ^-1

E. 8 ms ^-1 kanye ne-4 ms ^-1

Ingxoxo

Kuyaziwa ukuthi:

Isisindo sento A (m₁) = 3 kg

Isisindo sento B (m₂) = 5 kg

Isivinini sento A (v)₁) = 8 ms^-1

Isivinini sento B (v)₂) = 4 ms^-1

Ukushayisana okunwebeka ngokuphelele

Kubuziwe: v₁' kanye no-v₂'

Impendulo:

Uma izinto ezishayisana ngokunwebeka zinesisindo esihlukene futhi ijubane lezinto ezimbili ngemva kokushayisana lingaziwa, khona-ke ijubane ngemva kokushayisana libalwa kusetshenziswa i-equation elandelayo:

Uma zombili izinto zihamba ngendlela efanayo, ijubane lazo lihle. Uma zombili izinto zihamba ngezindlela eziphambene, ijubane lento eyodwa lihle kanti ijubane lenye into lihle.

Ngakho ijubane lento A (v)₁') ngemva kokushayisana kungu-3 m/s futhi ijubane lento B (v₂') ngemva kokushayisana kuba yi-7 m/s.

Impendulo efanele ngu-A.

2. Ibhola elinomfutho u-P lishaya udonga bese liyagxuma. Ukushayisana kuyanwebeka ngokuphelele futhi isiqondiso siqondile. Ushintsho kumfutho webhola...

A. u-zero

B. p/4

C. p/4

D.P

E. 2P

Ingxoxo

Kuyaziwa ukuthi:

Isisindo sebhola = m

Isivinini sebhola ngaphambi kokushaya = v

Isivinini sebhola ngemva kokushaya = -v (ibhola liyagxuma liye kwesobunxele)

Umfutho webhola ngaphambi kokushayisana (p_o) = mv

Umfutho webhola ngemva kokushayisana (p_t) = m (-v) = – mv

Kubuziwe: Ubukhulu boshintsho emgudwini webhola

Impendulo:

Ushintsho emgudwini:

Δp = p_t - k_o

Δp = – mv – mv

Δp = – 2 mv

Δp = -2p

Ubukhulu boshintsho kumfutho webhola buyi-2p. Uphawu olubi lubonisa isiqondiso.

Impendulo efanele ngu-E.

3. Izinto ezimbili u-A no-B ezinobunzima obulinganayo ziyadlulana. U-A uhamba empumalanga kanti u-B uhamba entshonalanga, ngesivinini u-V no-2V, ngokulandelana. Uma izinto zithola ukushayisana okunwebeka ngokuphelele, khona-ke ngokushesha ngemva kokushayisana,...

A. V_A = V ukuya eNtshonalanga, V_B = V eMpumalanga

B. V_A = 2V ukuya eNtshonalanga, V_B = 2V eMpumalanga

C. V_A = 2V ukuya eNtshonalanga, V_B = V eMpumalanga

D.V_A = V ukuya eNtshonalanga, V_B = 2V eMpumalanga

E.V_A = 2V eMpumalanga, V_B = V ukuya eNtshonalanga

Ingxoxo

Kuyaziwa ukuthi:

Zombili izinto zinesisindo esifanayo.

I-A iya empumalanga ngesivinini esingu-V

I-B iya entshonalanga ngesivinini esingu-2V

Kubuziwe: Isivinini sika-A no-B ngemva kokushayisana

Impendulo:

Uma ubuningi bezinto zombili bufana futhi ukushayisana kunwebeka ngokuphelele, khona-ke izinto ezimbili ziyashintshana ngesivinini ngemva kokushayisana.

Ngakho-ke ngemva kokushayisana, u-A uya entshonalanga ngesivinini esingu-2V kanti u-B uya empumalanga ngesivinini esingu-V.

Impendulo efanele ngu-C.

Ukushayisana Okuncane Okunwebekayo

4. Izinto ezimbili ezinobunzima obufanayo zihamba ziqonde komunye nomunye njengoba kuboniswe esithombeni!

Uma v₂' ijubane lento (2) ngemva kokushayisana ngakwesokudla ngesivinini esingu-5 ms^-1, bese kuba ubukhulu bejubane v₁ ' (1) ngemva kokushayisana…..

A. 7 ms^-1

B. 9 ms^-1

C. 13 ms^-1

D. 15 ms^-1

E. 17 ms^-1

Ingxoxo

Kuyaziwa ukuthi:

Ubunzima bezinto zombili bufana = m

Ijubane lento 1 ngaphambi kokushayisana (v₁) = 8 m/s

Ijubane lento 2 ngaphambi kokushayisana (v₂) = 10 m/s

Ijubane lento 2 ngemva kokushayisana (v₂') = 5 m/s

Kubuziwe: Ijubane lento 1 ngemva kokushayisana (v₁')

Impendulo:

Lokhu ukushayisana okungaphelele kokunwebeka. v₁' ibalwa kusetshenziswa umthetho wokulondolozwa komfutho:

m₁ v₁+m₂ v₂ = m₁ v₁' + m₂ v₂'

m (v₁ +v₂) = m (v₁' + v₂')

v₁ +v₂ =v₁' + v₂'

8 + 10 = v₁' + 5

18 = v₁' + 5

v₁' = 18-5

v₁' = 13 m/s

Impendulo efanele ngu-C.

Ukungqubuzana Okunganwebeki

5. Inhlamvu engamagremu ayi-10 ikhishwa ngesivinini esingu-100 m/s.^-1 , ishayisana nebhulokhi yokhuni engashintshi bese ingena ngaphakathi kwayo. Uma isisindo sebhulokhi yokhuni singamagremu angu-490, ijubane lebhulokhi yokhuni kanye nenhlamvu ngokushesha ngemva kokushayisana...

A. 1,0 ms^-1

B. 2,0 ms^-1

C. 2,5 ms^-1

D. 4,0 ms^-1

I-E. 5,0 ms^-1

Ingxoxo

Kuyaziwa ukuthi:

Isisindo senhlamvu (m₁) = amagremu ayi-10

Isivinini senhlamvu (v)₁) = 100 ms^-1

Isisindo sebhulokhi (m₂) = amagremu ayi-490

Isivinini sebhulokhi (v)₂) = 0 m/s (ibhulokhi lapho uphumule)

Kubuziwe: Isivinini sebhloko lokhuni kanye nenhlamvu ngokushesha ngemva kokushayisana

Impendulo:

Inhlamvu ishaya ibhlogo lokhuni elingashintshi bese lihlala kulo, ngakho-ke lokhu kuwukushayisana okungaqini. Ifomula yokushayisana okungaqini yile:

Umfutho ngaphambi kokushayisana = umfutho ngemva kokushayisana

m₁ v₁ +m₂ v₂ = (m₁ +m₂) v'

(10)(100) + (490)(0) = (10 + 490) v'

1000 + 0 = 500 v'

1000 = 500 v'

v' = 1000 / 500

v' = 2 m/s = 2 ms^-1

Impendulo efanele ingu-B.

6. Iloli lihamba ngesivinini esingama-10 m/s^-1 ukushayiswa yimoto ehamba ngesivinini esingama-20 ms^-1Ngemva kokushayisana, izimoto ezimbili zashayisana. Uma isisindo seloli singama-1400 kg kanti isisindo semoto singama-600 kg, isivinini sezimoto ezimbili ngemva kokushayisana...

A. 6 ms^-1

B. 9 ms^-1

C. 11 ms^-1

D. 13 ms^-1

E. 17 ms^-1

Ingxoxo

Ngemva kwengozi izimoto ezimbili zanamathelana, okwaholela ekushayisaneni okungenasici.

Kuyaziwa ukuthi:

Isivinini seloli (v)₁) = 10 m/s

Isivinini semoto (v)₂) = 20 m/s

Isisindo seloli (m₁) = 1400 kg

Isisindo semoto (m₂) = 600 kg

Kubuziwe: isivinini sezimoto zombili ngemva kokushayisana (v)

Impendulo:

Ifomula yokushayisana kwe-Inelastic:

m₁ v₁ +m₂ v₂ = (m₁ +m₂) v

(1400)(10) + (600)(20) = (1400 + 600) v

14000 + 12000 = 2000 v

26000 = 2000 v

v = 13 m/s

Impendulo efanele ngu-D.

I-7 Sinhlamvu engamagremu angu-20 ihamba ngesivinini esingu-10 ms^-1 isiqondiso esivundlile sishaya ibhlogo elinesisindo esingamagremu angu-60 elilele phansi. Uma inhlamvu inamathele ebhlokini, khona-ke isivinini samanje sebhlokhi….

A. 1,0 ms^-1

B. 1,5 ms^-1

C. 2,0 ms^-1

D. 2,5 ms^-1

E. 3,0 ms^-1

Ingxoxo

I-Diketahui :

Isisindo senhlamvu (m_P) = amagremu angu-20 = 0,02 kg

Isisindo sebhulokhi (m_B) = amagremu angu-60 = 0,06 kg

Ijubane lokuqala lenhlamvu (v)_P) = 10 m/s

Ijubane lokuqala lebhulokhi (v)_B= = 0

Kubuziwe : isivinini senhlamvu kanye nebhulokhi ngemva kokushayisana (v')

Jawab :

Ifomula umthetho wokulondolozwa komfutho uma izinto ezimbili zinamathelana ngemva kokushayisana:

m_P v_P +m_B v_B = (m_P +m_B) v'

(0,02)(10) + (0,06)(0) = (0,02 + 0,06) v'

0,2 + 0 = 0,08 v'

0,2 = 0,08 v'

v' = 0,2 / 0,08

v' = 2,5 m/s

Impendulo efanele ngu-D.

8. Amatroli amabili u-A no-B, ngalinye linesisindo esingu-1,5 kg, ayasondelana ngesivinini u-v._A = 4 ms^-1 kanye no-v_B = 5 ms^-1 njengoba kusesithombeni. Uma ama-trolley amabili eshayisana ngendlela enganwebeki, khona-ke ijubane lama-trolley amabili ngemva kokushayisana...

A. 4,5 ms^-1 Ngakwesokudla

B. 4,5 ms^-1 Ngakwesokunxele

C. 1,0 ms^-1 Ngakwesokunxele

D. 0,5 ms^-1 Ngakwesokunxele

E. 0,5 ms^-1 Ngakwesokudla

Ingxoxo

Kuyaziwa ukuthi:

Isisindo setroli A (m)_A) = 1,5 kg

Isisindo setroli B (m)_B) = 1,5 kg

Isivinini setroli A ngaphambi kokushayisana (v)_A) = 4 m/s (okuqondile ngakwesokudla)

Isivinini setroli B ngaphambi kokushayisana (v)_B) = -5 m/s (i-negative ngakwesobunxele)

Kubuziwe: Uma ukushayisana kungaqini, nquma ijubane lama-trolley womabili ngemva kokushayisana.

Impendulo:

Umthetho wokulondolozwa komfutho:

m_Av_A +m_Bv_B = (m_A +m_B) v'

(1,5)(4) + (1,5)(-5) = (1,5 + 1,5) v'

6 – 7,5 = (3) v'

-1,5 = (3) v'

v' = -1,5 / 3

v' = -0,5 m/s

Uphawu olunegethivu lusho ukuthi ngemva kokushayisana kokubili kuya ngakwesobunxele, ngendlela efanayo netroli B. Lokhu kunengqondo ngoba umfutho wetroli B mkhulu kunomfutho wetroli A.

Umthombo wombuzo:

Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi