Imibuzo yesibonelo ye-Thermodynamics

Izibonelo ezingu-20 zemibuzo ye-Thermodynamics

Inqubo ye-Thermodynamic

1. Ku-thermodynamics, igesi efanelekile idlula enkambisweni ye-isothermal uma…

A. izinguquko esimweni segesi, izinga lokushisa lihlala lingaguquki

B. wonke ama-molecule ahamba ngesivinini esihlukile

C. Zonke izimo zegesi zihlala zishintsha izinga lokushisa

D. emazingeni okushisa aphezulu ijubane lama-molecule liphakeme

Umfutho wegesi kanye nomthamo akushintshi

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I-Isothermal noma i-isothermic kusho izinga lokushisa elingaguquki.

Impendulo efanele ngu-A.

2. Wonke amagesi afanele adlula enkambisweni ye-isochoric ngakho...

A. wonke ama-molecule anejubane elifanayo

B. emazingeni okushisa aphezulu isivinini esimaphakathi sama-molecule sikhulu

C. umfutho wegesi uhlala ungaguquki

D. igesi izosebenza

I-E. ayinawo amandla angaphakathi

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Isochoric = ivolumu engaguquki.

Impendulo efanele ingu-B.

3. Isitatimende esifanele mayelana nezinqubo ze-thermodynamic sithi…

A. I-Isobaric inqubo yokushintsha igesi ngokucindezela okungaguquki.

B. I-Isobaric inqubo yokushintsha igesi ekushiseni okungaguquki.

C. I-Isochoric inqubo yokushintsha igesi ngokucindezela okungaguquki.

I-D. isotherm inqubo yokushintsha igesi ngevolumu engaguquki.

E. I-Isochoric inqubo yokushintsha igesi ekushiseni okungaguquki.

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Isobaric = ukucindezela okuqhubekayo

Isochoric = ivolumu engaguquki

Isothermal = izinga lokushisa elingaguquki

Impendulo efanele ngu-A.

Umthetho Wokuqala We-Thermodynamics

4. Kusukela kugrafu ye-PV engezansi, inani lomsebenzi wegesi ezinqubweni I kanye ne-II lilingana njengoba...

A. 4: 3Isibonelo se-Thermodynamics Umbuzo 1

B. 3: 4

C. 2: 3

D. 1: 2

Isahluko 1: 1

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Kuyaziwa ukuthi:

Inqubo 1:

Ingcindezi (P) = 20 N/m2

Ivolumu yokuqala (V)1) = amalitha ama-10 = ama-dm ama-103 = 10 x10-3 m3

Umqulu wokugcina (V)2) = amalitha ama-40 = ama-dm ama-403 = 40 x10-3 m3

Inqubo 2:

Ingcindezi (P) = 15 N/m2

Ivolumu yokuqala (V)1) = amalitha ama-20 = ama-dm ama-203 = 20 x10-3 m3

Umqulu wokugcina (V)2) = amalitha ama-60 = ama-dm ama-603 = 60 x10-3 m3

Kubuziwe:

Impendulo:

Umsebenzi wegesi uyaqhubeka I:

W = P ΔV = P (V)2-V1) = (20)(40-10)(10-3 m3) = (20)(30)(10-3 m3) = (600)(10-3 m3= 0,6m3

Umsebenzi wegesi uyaqhubeka II:

W = P ΔV = P (V)2-V1) = (15)(60-20)(10-3 m3) = (15)(40)(10-3 m3) = (600)(10-3 m3= 0,6m3

Ukuqhathaniswa komsebenzi wegesi ezinqubweni I kanye ne-II:

0,6 m3 : 0,6 m3

1: 1

Impendulo efanele ngu-E.

5. Kusukela kugrafu ye-P kuya ku-V, inani lomsebenzi wegesi ezinqubweni I kanye ne-II lilingana njengoba...

A. 4: 3Isibonelo se-Thermodynamics Umbuzo 2

B. 3: 4

C. 2: 3

D. 1: 2

Isahluko 1: 1

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Kuyaziwa ukuthi:

Inqubo I:

Ingcindezi (P) = 20 Pascal

Umqulu 1 (V)1) = amalitha ayi-10

Umqulu 2 (V)2) = amalitha ayi-40

Inqubo II:

Ingcindezi (P) = 15 Pascal

Umqulu 1 (V)1) = amalitha ayi-20

Umqulu 2 (V)2) = amalitha ayi-60

Kubuziwe: Ukuqhathaniswa komsebenzi wegesi ezinqubweni I kanye ne-II

Impendulo:

Inqubo ye-thermodynamic esekelwe kugrafu engenhla iyinqubo ye-isobaric (ukucindezela okuqhubekayo).

Umsebenzi owenziwe yigesi enqubweni yokuqala:

W = P (V)2 - V1)

W = (20)(40 – 10)

W = (20)(30)

W=600

Umsebenzi owenziwe yigesi enqubweni II:

W = P (V)2 - V1)

W = (15)(60 – 20)

W = (15)(40)

W=600

Ukuqhathaniswa komsebenzi wegesi ezinqubweni I kanye ne-II:

600: 600

1: 1

Impendulo efanele ngu-E.

6. Igesi ye-helium iyashiswa ngokwegrafu ye-PV engezansi. Umsebenzi owenziwe yigesi ye-helium enqubweni ye-AB...

A. 15 joule Isibonelo se-Thermodynamics Umbuzo 3

B. ama-joule ayi-10

C. 8 ama-joule

D. 4 ama-joule

E. 2 ama-joule

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I-Diketahui :

Ukucindezela (P) = 2 x 105 N / m2 = 2 x105 Easter

Ivolumu yokuqala (V)1= 5cm3 = 5 x10-6 m3

Umqulu wokugcina (V)2= 15cm3 = 15 x10-6 m3

Kubuziwe Umsebenzi owenziwe yigesi enqubweni AB

Jawab :

W = ∆P ∆V

W = P (V)2 - V1)

W = (2 x 105)(15 x 10-6 - 5 x 10-6)

W = (2 x 105)(10 x 10-6) = (2 x 105)(1 x 10-5)

W = 2 Joule

Impendulo efanele ngu-E.

7. Bheka isithombe! Igesi efanelekile idlula enkambisweni yokushintsha kwengcindezi (P) uma kuqhathaniswa nevolumu (V). Umsebenzi owenziwa yigesi kule nqubo…

A. 20 JouleIsibonelo se-Thermodynamics Umbuzo 5

B. 15 Joule

C. 10 Joule

FUNDA FUTHI  Percobaan Hukum II Newton

D. 5 Joule

E. 4 AmaJoule

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I-Diketahui :

Ingcindezi yokuqala (P)1) = 4 Pa ​​​​= 4 N/m2

Ingcindezi yokugcina (P)2) = 6 Pa ​​​​= 6 N/m2

Ivolumu yokuqala (V)1= 2m3

Umqulu wokugcina (V)2= 4m3

Kubuziwe Umsebenzi owenziwe yigesi (W)

Jawab :

Umsebenzi owenziwe ngegesi = indawo engaphansi kwejika ab.

W = indawo kanxantathu + indawo yesikwele

W = ½ (6-4)(4-2) + 4(4-2)

W = ½ (2)(2) + 4(2)

W = 2 + 8

W = 10 Joule

Impendulo efanele ngu-E.

8. Igesi efanelekile idlula enqubweni evaliwe A → B → C → A. Emjikelezweni, igesi isebenza cishe….

A. -2,0 x 103 JIsibonelo se-Thermodynamics Umbuzo 6

B. -5,5 x 103 J

C. -8,0 x 105 J

D. 2,0 x 106 J

E. 4,0 x 106 J

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Umsebenzi (W) = indawo yejika (indawo yenxantathu ngaphakathi komugqa ophawulwe ngomcibisholo).

W = ½ (20-10)(6 x 105 - 2 x 105)

W = ½ (10)(4 x 105)

W = (5)(4 x 105)

W = 20 x 105 = 2 x106 Joule

Impendulo efanele ngu-D.

Injini Yokushisa

9. Injini imunca amaJoules angu-2.000 okushisa avela endaweni yokugcina ukushisa okuphezulu bese yenqaba amaJoules angu-1.200 aye endaweni yokugcina ukushisa okuphansi. Ukusebenza kahle kwenjini ku ....

A. 80%

B. 75%

C. 60%

D. 50%

E. 40%

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Kuyaziwa ukuthi:

Ukushisa kuthathwe (Q)H) = amaJoules ayi-2000

Ukushisa kukhishwe (Q)L) = amaJoules ayi-1200

Umsebenzi owenziwe umshini (W) = 2000 – 1200 = 800 Joules

Kubuziwe : Ukusebenza kahle kwenjini yokushisa (e)

Jawab :

Ifomula yokusebenza kahle kwenjini yokushisa:

e = W / QH = 800/2000 = 0,4 x 100% = 40%

Impendulo efanele ngu-E.

Injini ye-Carnot

10. Ukusebenza kahle kwenjini yeCarnot enomjikelezo omunca ukushisa ekushiseni okungu-960 K futhi wenqabe ukushisa ekushiseni okungu-576 K...

A. 40%

B. 50%

C. 56%

D. 60%

E. 80%

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I-Diketahui :

Izinga lokushisa eliphezulu (T)H) = 960 K

Izinga lokushisa eliphansi (T)L) = 576 K

Kubuziwe Ukusebenza kahle kwenjini ye-Carnot (e)

Jawab :

Isibonelo se-Thermodynamics Umbuzo 7

Ukusebenza kahle kwenjini yeCarnot kungu-0,4 x 100% = 40%

Impendulo efanele ngu-A.

11. Kugrafu ye-PV yenjini yeCarnot engezansi, i-W = ama-Joules angu-6.000. Inani lokushisa elikhishwa yinjini ngomjikelezo ngamunye…

A. Ama-joule angu-2.250Isibonelo se-Thermodynamics Umbuzo 9

B. ama-joule ayi-3.000

C. 3.750 ama-joule

D. 6.000 ama-joule

E. 9.600 ama-joule

Ingxoxo

Kuyaziwa ukuthi:

Umsebenzi (W) = ama-Joules angu-6000

Izinga lokushisa eliphezulu (T)H) = 800 Kelvin

Izinga lokushisa eliphansi (T)L) = 300 Kelvin

Kubuziwe: Q

Impendulo:

Ukusebenza kahle kwenjini yokushisa efanele (injini yeCarnot):

Isibonelo se-Thermodynamics Umbuzo 10

Ukushisa okumuncwa yinjini yeCarnot:

W = e Q1

6000 = (0,625) Q1

Q1 = 6000/0,625

Q1 = 9600

Ukushisa okukhishwa yinjini yeCarnot:

Q2 =Q1 - W

Q2 = 9600 - 6000

Q2 = 3600 amaJoule

Ayikho impendulo efanele.

12. Injini yeCarnot esebenza kahle ngo-40% isebenzisa idamu elishisayo ku-727°C. Thola izinga lokushisa ledamu elibandayo!

A. 327°C

B. 357°C

C. 400°C

D. 600°C

E. 627°C

Ingxoxo

Kuyaziwa ukuthi:

Ukusebenza kahle (e) = 40% = 40/100 = 0,4

Izinga lokushisa eliphezulu (T)H= = 727oC + 273 = 1000 K

Kubuziwe: Nquma izinga lokushisa ledamu elibandayo

Impendulo:

Isibonelo se-Thermodynamics Umbuzo 11

Izinga lokushisa ledamu lingu-600–273 = 327oC

Impendulo efanele ngu-A.

13. Igrafu ye-P-V yenjini yeCarnot ibukeka njengesithombe esilandelayo! Uma injini imunca ukushisa okungu-800 J, khona-ke umsebenzi owenziwe…

A. 105,5 JIsibonelo se-Thermodynamics Umbuzo 13

B. 252,6 J

C. 336,6 J

D. 466,7 J

E. 636,7 J

Ingxoxo

Kuyaziwa ukuthi:

Izinga lokushisa eliphezulu (T)H) = 600 Kelvin

Izinga lokushisa eliphansi (T)L) = 250 Kelvin

Ukushisa kuthathwe (Q)1) = amaJoules ayi-800

Kubuziwe: Ibhizinisi (W)

Impendulo:

Ukusebenza kahle kwenjini yokushisa efanele (injini yeCarnot):

Isibonelo se-Thermodynamics Umbuzo 16

Imizamo eyenziwe yile:

W = e Q1

W = (7/12)(800 amaJoules)

W = 466,7 Joule

Impendulo efanele ngu-D.

14. Injini yeCarnot isebenza ekushiseni okuphezulu okungu-600 K ukuze ikhiqize umsebenzi womshini. Uma injini imunca ukushisa okungu-600 J ekushiseni okuphansi okungu-400 K, khona-ke umsebenzi okhiqizwayo….

A. 120 J

B. 124 J

C. 135 J

D. 148 J

E. 200 J

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I-Diketahui :

Izinga lokushisa eliphansi (T)L) = 400 K

FUNDA FUTHI  Imibuzo Eyisibonelo Ekhuluma Ngokusabalala Kwamagagasi E-Electromagnetic

Izinga lokushisa eliphezulu (T)H) = 600 K

Ukushisa kuthathwe (Q)1) = amaJoules ayi-600

Kubuziwe Umsebenzi owenziwe yinjini yeCarnot (W)

Jawab :

Ukusebenza kahle kwenjini yokushisa efanele (injini yeCarnot):

Isibonelo se-Thermodynamics Umbuzo 17

Umsebenzi owenziwe yinjini yeCarnot:

W = e Q1

W = (1/3)(600) = 200 amaJoules

Impendulo efanele ngu-E.

I-Kinetic Theory yamagesi kanye ne-Thermodynamics

15. Ethangini kukhona igesi efanelekile enomthamo wamalitha ama-4, izinga lokushisa lingama-27oC kanye nokucindezela okungu-3 atm (1 atm = 105 I-Nm-2Igesi idlula enkambisweni yokushisa ngokucindezela okungaguquki kuze kufike ekushiseni okungu-87.oC. Umthamo wokushisa wegesi ungama-9 JK-1 . Umthamo wokugcina wegesi kanye noshintsho lwamandla angaphakathi egesi ngokulandelana…

A. 4,2 amalitha, ΔU = 200 amaJoule

B. 4,4 amalitha, ΔU = 240 amaJoule

C. 4,6 amalitha, ΔU = 280 amaJoule

D. 4,8 amalitha, ΔU = 300 amaJoule

E. 4,8 amalitha, ΔU = 360 amaJoule

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Inqubo ye-Isobaric (ingcindezi eqhubekayo)

Kuyaziwa ukuthi:

Umthamo wokuqala wegesi efanele (V)1) = amalitha ayi-4

Izinga lokushisa lokuqala legesi elifanele (T)1= = 27oC + 273 = 300 K

Izinga lokushisa lokugcina legesi elifanele (T)2= = 87oC + 273 = 360 K

Umfutho wegesi ofanele (P) = 3 atm = 3 x 105 I-Nm-2

Umthamo wokushisa wegesi (C) = 9 JK-1

Kubuziwe: Umthamo wokugcina wegesi (V)2) kanye noshintsho lwamandla kugesi (ΔU)

Impendulo:

Bala ivolumu yokugcina usebenzisa ifomula yomthethoum Charles (inqubo ye-isobaric noma yengcindezi engaguquki):

Isibonelo se-Thermodynamics Umbuzo 18

Ukushintsha kwevolumu:

Ilitha eli-1 = 0,001 m3

Ivolumu yokuqala (V)1) = 4 (0,001 m3= 0,004m3

Umqulu wokugcina (V)2) = 4,8 (0,001 m3= 0,0048m3

Shintsha vume (ΔV) = V2 - V1 = 0,0048 m3 - 0,004 m3 = 0,008m3.

Izinguquko Zokushisa:

Izinguquko zokushisa (ΔT) = T2 - T1 = 360 K – 300 K = 60 K

Bala ushintsho lwamandla angaphakathi (ΔU) wegesi efanelekile usebenzisa ifomula yoMthetho Wokuqala We-Thermodynamics:

ΔU = Q - W

Incazelo: ΔU = ushintsho emandleni angaphakathi, Q = ukushisa, W = umsebenzi.

Bala umsebenzi (W) ngokucindezela okungaguquki:

W = P ΔV = (3 x 105)(0,0008) = (3x101)(8) = (30)(8) = 240 amaJoule

Bala ukushisa (Q) usebenzisa ifomula yamandla okushisa (C):

C = Q / ΔT

Q = (C)(ΔT) = (9)(60) = 540 Joules

Bala ushintsho lwamandla angaphakathi:

ΔU = Q – W = 540 Joules – AmaJoules angu-240 = amaJoules angu-300.

Impendulo efanele ngu-D.

16. Ethangini kukhona amalitha ayi-6 egesi elifanele ngokucindezela okungu-2 atm (1 atm = 105 I-Nm-2), izinga lokushisa 27oC. Igesi ishiswa kufikela ku-77 degreesoC ngengcindezi engaguquki. Uma amandla okushisa egesi angama-5 JK-1, ivolumu yokugcina kanye noshintsho lwamandla angaphakathi egesi ngokulandelana….

A. amalitha angu-8; ΔU = 250 amaJoule

B. amalitha angu-8; ΔU = 200 amaJoule

C. amalitha angu-7; ΔU = 100 amaJoule

D. 7 amalitha; ΔU = 50 amaJoule

E. amalitha angu-7; ΔU = 20 amaJoule

Ingxoxo

Inqubo ye-Isobaric (ingcindezi eqhubekayo)

Kuyaziwa ukuthi:

Umthamo wokuqala wegesi efanele (V)1) = amalitha ayi-6

Izinga lokushisa lokuqala legesi elifanele (T)1= = 27oC + 273 = 300 K

Izinga lokushisa lokugcina legesi elifanele (T)2= = 77oC + 273 = 350 K

Umfutho wegesi ofanele (P) = 2 atm = 2 x 105 I-Nm-2

Umthamo wokushisa wegesi (C) = 5 JK-1

Kubuziwe: Umthamo wokugcina wegesi (V)2) kanye noshintsho lwamandla kugesi (ΔU)

Impendulo:

Bala ivolumu yokugcina usebenzisa ifomula yomthethoum Charles (inqubo ye-isobaric noma yengcindezi engaguquki):

Isibonelo se-Thermodynamics Umbuzo 19

Ukushintsha kwevolumu:

Ilitha eli-1 = 0,001 m3

Ivolumu yokuqala (V)1) = 6 (0,001 m3= 0,006m3

Vivolumu yokugcina (V)2) = 7 (0,001 m3= 0,007m3

Ukushintsha kwevolumu (ΔV) = V2 - V1 = 0,007m3 - 0,006 m3 = 0,001m3.

Izinguquko Zokushisa:

Izinguquko zokushisa (ΔT) = T2 - T1 = 350 K – 300 K = 50 K

Bala ushintsho lwamandla angaphakathi (ΔU) wegesi efanelekile usebenzisa ifomula yoMthetho Wokuqala We-Thermodynamics:

ΔU = Q - W

Incazelo: ΔU = ushintsho emandleni angaphakathi, Q = ukushisa, W = umsebenzi.

Bala umsebenzi (W) ngokucindezela okungaguquki:

W = P ΔV = (2 x 105)(0,001) = (2x102)(1) = (200)(1) = 200 amaJoules

Bala ukushisa (Q) usebenzisa ifomula yamandla okushisa (C):

C = Q / ΔT

Q = (C)(ΔT) = (5)(50) = 250 Joules

Bala ushintsho lwamandla angaphakathi:

ΔU = Q – W = 250 Joules – AmaJoules angu-200 = amaJoules angu-50.

Impendulo efanele ngu-D.

Inqubo ye-Thermodynamic

17. Naka igrafu eseceleni kanye nezitatimende ezilandelayo!

FUNDA FUTHI  Imibuzo Eyisibonelo Ekhuluma Ngokusebenza Kwe-Inductance Nama-Transformers

(1) Inqubo ye-AB iyi-isobaric kanti i-W = P (V)2 - V1)Isibonelo se-Thermodynamics Umbuzo 20

(2) Inqubo i-BC i-adiabatic, kanti i-ΔU = Q

(3) Inqubo i-BC ayifani ne-isochoric, kanti i-ΔU = Q

(4) Inqubo ye-CA ayishisi kakhulu, futhi uhlelo lumunca ukushisa.

Isitatimende esinembile sithi…

A. (1) kanye no-(3)

B. (1) kanye no-(4)

C. (2) kanye no-(3)

D. (2) kanye (4)

E. (3) kanye no-(4)

Ingxoxo

(1) Inqubo ye-AB iyi-isobaric kanti i-W = P (V)2 - V1)

Isobaric = ukucindezeleka okungaguquki. Ukucindezela okuqhubekayo kuboniswa umugqa oqondile eceleni kuka-P1 kusuka ku-A kuya ku-B. Kule nqubo, ingcindezi ihlala ingaguquki kodwa kukhona ushintsho kuvolumu lapho ivolumu ikhuphuka khona. Uma ivolumu ikhuphuka khona-ke uhlelo lusebenza endaweni ezungezile, lapho inani lomsebenzi (W) liwumphumela wokuphindaphinda ingcindezi (P) kanye noshintsho kuvolumu (ΔU).

(3) Inqubo i-BC ayifani ne-isochoric, kanti i-ΔU = Q

Isochoric = ivolumu engaguquki. Ivolumu engaguquki iboniswa umugqa oqondile eceleni kuka-V.2 kusuka ku-B kuya ku-C. Kule nqubo, ivolumu ihlala ingaguquki kodwa kukhona ushintsho ekucindezelweni lapho ingcindezi ikhuphuka khona. Ivolumu ayiguquki ngakho akukho msebenzi owenziwayo, lapho u-W = 0. Ifomula yoMthetho Wokuqala We-Thermodynamics ithi ΔU = Q – W, ​​​​lapho u-ΔU = ushintsho emandleni angaphakathi, u-Q = ukushisa kanye no-W = umsebenzi. Uma kungekho msebenzi khona-ke u-W = 0, ngakho-ke u-ΔU = Q.

Impendulo efanele ngu-A.

18. Bheka igrafu elandelayo yomjikelezo we-thermodynamic!Isibonelo se-Thermodynamics Umbuzo 24

Kusukela kulesi sitatimende esilandelayo:

(1) A – B = isochoric, umsebenzi uncike ekushintsheni kwezinga lokushisa

(2) B – C = adiabatic, akukho ukushintsha kokushisa

(3) B – C = isobaric, umsebenzi uncike ekushintsheni kwevolumu

(4) C – A = inqubo yenzeka ngomzamo ovela ngaphandle kohlelo

Iqiniso liwukuthi…

A. (1) kanye no-(2)

B. (1) kanye no-(3)

C. (2) kanye no-(3)

D. (2) kanye (4)

E. (3) kanye no-(4)

Ingxoxo

(1) A – B = isochoric, umsebenzi uncike ekushintsheni kwezinga lokushisa

Yebo, le nqubo i-isochoric (ivolumu eqhubekayo). Kodwa-ke, ivolumu ihlala ingaguquki, ngakho-ke akukho msebenzi owenziwayo. Umsebenzi uyenzeka uma kukhona ushintsho lwevolumu. Ngakho-ke, lesi sitatimende asilungile.

(3) B – C = isobaric, umsebenzi uncike ekushintsheni kwevolumu

I-Isobaric = ingcindezi engaguquki. Ingcindezi engaguquki iboniswa umugqa oqondile ukusuka ku-B kuya ku-C. Kule nqubo, kuba noshintsho kuvolumu yesistimu, lapho ivolumu yesistimu ikhuphuka khona. Ukwanda kwevolumu yesistimu kusho ukuthi uhlelo lusebenza endaweni ezungezile.

(4) C – A = inqubo yenzeka ngomzamo ovela ngaphandle kohlelo

Kule nqubo, ivolumu yesistimu iyancipha futhi ingcindezi yesistimu iyancipha. Ukwehla kwevolumu yesistimu kusho ukuthi indawo iyasebenza ohlelweni. Ngamanye amazwi, umsebenzi wenziwa ngaphandle.

Impendulo efanele ngu-E.

Imithetho yeThermodynamics

19. Bheka isithombe! Igesi efanelekile idlula enkambisweni yokushintsha ingcindezi (P) ibe yivolumu (V). Umsebenzi owenziwa yigesi kule nqubo…
A. 20 JouleIsibonelo se-Thermodynamics Umbuzo 27
B. 15 Joule
C. 10 Joule
D. 5 Joule
E. 4 AmaJoule
Ingxoxo
I-Diketahui :
Ingcindezi yokuqala (P)1) = 4 Pa ​​​​= 4 N/m2
Ingcindezi yokugcina (P)2) = 6 Pa ​​​​= 6 N/m2
Ivolumu yokuqala (V)1= 2m3
Umqulu wokugcina (V)2= 4m3
Kubuziwe Umsebenzi owenziwe yigesi (W)
Jawab :
Umsebenzi owenziwe ngegesi = indawo engaphansi kwejika ab.
W = indawo kanxantathu + indawo yesikwele
W = ½ (6-4)(4-2) + 4(4-2)
W = ½ (2)(2) + 4(2)
W = 2 + 8
W = 10 Joule
Impendulo efanele ngu-E.

20. Igesi efanelekile idlula enqubweni evaliwe A → B → C → A. Emjikelezweni, igesi isebenza cishe….
A. −2,0 x 103 JIsibonelo se-Thermodynamics Umbuzo 29
B. −5,5 x 103 J
C. −8,0 x 105 J
D. 2,0 x 106 J
E. 4,0 x 106 J
Ingxoxo
Umsebenzi (W) = indawo yejika (indawo yenxantathu ngaphakathi komugqa ophawulwe ngomcibisholo).
W = ½ (20-10)(6 x 105 - 2 x 105)
W = ½ (10)(4 x 105)
W = (5)(4 x 105)
W = 20 x 105 = 2 x106 Joule
Impendulo efanele ngu-D.

Umthombo wombuzo:

Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi

Shiya amazwana