Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu (kukhona ukungqubuzana)

Izibonelo ezimbili zokusebenzisa imithetho kaNewton ezindizeni ezithambekele kabi (kukhona ukungqubuzana)

1. Isisindo sebhulokhi singama-2 kg, ukusheshisa ngenxa yamandla adonsela phansi = 10 m/s2, i-coefficient ye-static kanye ne-kinetic friction ingu-0,2 kanye no-0,1. Ingabe ibhloko isamile noma iyahamba? Uma ibhloko ihamba, nquma (a) amandla aphumela ekusheshiseni ibhloko (b) ubukhulu kanye nesiqondiso sokusheshisa kwebhloko!
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 1Ingxoxo
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 2I-Diketahui :
IMisa (m) = 2 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s2
I-coefficient yokungqubuzana okuqinile = 0,2
I-coefficient yokungqubuzana okuqinile = 0,1
Isisindo sebhulokhi (w) = mg = (2)(10) = 20 Newton
wx = isono 30o = (20)(0,5) = 10 Newton
wy = w cos 30o = (20)(0,5√3) = 10√3 AmaNewton
Amandla ajwayelekile (N) = wy = 10√3 uNewton
Amandla okungqubuzana aqinile (f)s) = (0,2)(10√3) = 2√3 AmaNewton
Amandla okungqubuzana kwe-kinetic (f)k) = (0,1)(10√3) = √3 AmaNewton
Kubuziwe : Ingabe ibhlokhi isamile noma iyahamba? Uma ihamba, thola amandla aphumayo asheshisa ibhlokhi kanye nokusheshisa kwebhlokhi!

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Jawab :
Ibhloko liphumule uma wx < fs, ibhulokhi lihamba uma u-wx > fsNgoba wx = 10 uNewton no-fs = 2√3 AmaNewton, ngakho-ke kuphethwa ngokuthi ibhloko liyehla liye phansi.
(a) amandla aphumela ekusheshiseni ibhulokhi
Uma ibhloko lihamba, amandla okungqubuzana asebenza kubhloko yiwona amandla okungqubuzana e-kinetic (f).k).
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 3(b) ubukhulu kanye nesiqondiso sokusheshisa kwebhulokhi
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 4Ubukhulu bokusheshisa kwebhulokhi buyi-4,15 m/s2 futhi isiqondiso sokusheshisa kwebhulokhi siphansi.

2. Isisindo sebhulokhi singama-4 kg, ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s2. Ama-coefficients okungqubuzana okungaguquki kanye nokujiya kwe-kinetic angama-0,4 kanye no-0,2. Uma ubukhulu bamandla u-F bungu-40 Newton, ingabe ibhloko limile noma liyahamba? Uma ibhloko lihamba, nquma (a) amandla aphumela ekusheshiseni ibhloko (b) ubukhulu kanye nesiqondiso sokusheshisa kwebhloko!
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 5Ingxoxo
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 6I-Diketahui :
IMisa (m) = 4 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s2
I-coefficient yokungqubuzana okuqinile = 0,4
I-coefficient yokungqubuzana okuqinile = 0,2
Isisindo sebhulokhi (w) = mg = (4)(10) = 40 Newton
wx = isono 30o = (40)(0,5) = 20 Newton
wy = w cos 30o = (40)(0,5√3) = 20√3 AmaNewton
Amandla ajwayelekile (N) = wy = 20√3 uNewton
Amandla okungqubuzana aqinile (f)s) = (0,4)(20√3) = 8√3 AmaNewton
Amandla okungqubuzana kwe-kinetic (f)k) = (0,2)(20√3) = 4√3 AmaNewton
F = 40 Newton
Kubuziwe : Ingabe ibhlokhi isamile noma iyahamba? Uma ihamba, thola amandla aphumayo asheshisa ibhlokhi kanye nokusheshisa kwebhlokhi!
Jawab :
Ibhulokhi ihlela phansi uma u-F < wx +fsIbhulokhi iqhubekela phezulu uma u-F > wx +fs. F = 40 Newton, wx = 20 uNewton no-fs = 8√3 = 13,6 AmaNewton, ngakho-ke kuphethwa ngokuthi ibhloko liya phezulu ngoba u-F mkhulu kuno-wx +fs.
(a) amandla aphumela ekusheshiseni ibhulokhi
Uma ibhloko lihamba, amandla okungqubuzana asebenza kubhloko yiwona amandla okungqubuzana e-kinetic (f).k).
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 7(b) ubukhulu kanye nesiqondiso sokusheshisa kwebhulokhi
Isibonelo sokusebenzisa imithetho kaNewton endaweni ethambekele kakhulu 8Ubukhulu bokusheshisa kwebhulokhi buyi-1,6 m/s2 futhi isiqondiso sokusheshisa kwebhulokhi siphezulu.

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[IsiNgisi: Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana]

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