Isibonelo sokusebenzisa imithetho kaNewton endaweni ebushelelezi (akukho ukungqubuzana)

Izibonelo ezimbili zokusebenzisa imithetho kaNewton endaweni ebushelelezi (akukho ukungqubuzana)

1. Isisindo sebhulokhi singama-2 kg, ukusheshisa ngenxa yamandla adonsela phansi = 10 m/s². Nquma (a) amandla aphumela ekusheshiseni ibhloko (b) ubukhulu bokusheshisa kwebhloko.
Ingxoxo
I-Diketahui :
Isisindo sebhulokhi (m) = 2 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²
Isisindo sebhulokhi (w) = mg = (2)(10) = 20 Newton
w_x = w isono 30 = (20)(0,5) = 10 amaNewton
w_y = w cos 30 = (20)(0,5√3) = 10√3 AmaNewton
Impendulo:
(A) amandla aphumela ekusheshiseni ibhlogo
Indiza ethambekele ngokushelela lapho kucatshangwa ukuthi akukho ukungqubuzana. Ngakho-ke amandla athinta ukunyakaza kwebhulokhi kuphela_x
(B) ukusheshisa okukhulu kwebhulokhi
Ubukhulu bokusheshisa kwebhulokhi buyi-5 m/s², isiqondiso sokusheshisa kwebhulokhi siphansi.

2. Ibhloko lisendizeni ebushelelezi, engenakho ukungqubuzana. Isisindo sebhloko singama-3 kg, kanti ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s.²Thola ubukhulu bamandla F uma (a) ibhloko lisesekhona (b) ibhloko lihamba liye phansi ngesivinini esingu-2 m/s² (c) ibhloko lihamba liye phezulu ngokusheshisa okungaguquki okungu-2 m/s².
Ingxoxo
I-Diketahui :
Isisindo sebhulokhi (m) = 3 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²
Isisindo sebhulokhi (w) = mg = (3)(10) = 30 Newton
w_x = w isono 30 = (30)(0,5) = 15 amaNewton
w_y = w cos 30 = (30)(0,5√3) = 15√3 AmaNewton
Impendulo:
(a) Thola u-F ukuthi ibhloko liphumulile yini.
Umthetho wokuqala kaNewton uthi into iphumula uma amandla aphumayo engu-zero.
(b) Thola u-F uma ibhulokhi lihamba liyehla ngesivinini esingu-2 m/s²
(c) Nquma u-F uma ibhlogo lihamba liye phezulu ngokusheshisa okungaguquki okungu-2 m/s²

[IsiNgisi: Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana]