Imibuzo Yezibonelo kanye Nengxoxo Yezilinganiso Zezinga Lokusabela kanye Nohlelo Lokusabela
Ukuqonda nokufunda amazinga okusabela kanye nemiyalelo yokusabela kuyingxenye ebalulekile yokutadisha i-kinetics yamakhemikhali. Kulesi sihloko, sizoxoxa ngemibono eyisisekelo, sethula izinkinga zezibonelo, futhi sethula ingxoxo yezilinganiso zezinga lokusabela kanye nemiyalelo yokusabela.
Isingeniso Sezinga Lokusabela kanye Nokulandelana Kokusabela
Izinga lokusabela
Izinga lokusabela liyizinga lokushintsha kokuhlushwa kwe-reactant noma umkhiqizo ngesikhathi ngasinye. Kuzilinganiso zezinga, sivame ukubona ifomu elijwayelekile elilandelayo:
\[ \text{rate} = k \cdot [A]^m \cdot [B]^n \]
Di mana:
– \(\text{rate}\) izinga lokusabela.
– \(k\) yizinga lokusabela elingaguquki.
– \([A]\) kanye \([B]\) yizingxube ze-reactants A kanye ne-B.
– \(m\) kanye \(n\) yiziqondiso zokusabela maqondana no-A no-B.
Ukulandelana Kwempendulo
I-oda lokusabela lichaza ukuthi ukuhlushwa kwe-reactant kunathonya elingakanani esilinganisweni sokusabela. I-oda lokusabela eliphelele liyisamba sama-oda e-reactant ngayinye.
Imibuzo Yezibonelo kanye Nengxoxo Yezinga Lokusabela kanye Nokulandelana Kokusabela
Isibonelo Umbuzo 1
Umbuzo:
Ukusabela phakathi kwento A kanye nento B kunikezwa yi-chemical equation:
\[ A + 2B \umcibisholo ongakwesokudla C \]
Kuyaziwa ukuthi izinga lokusabela kwalokhu kusabela yileli:
\[ \text{rate} = k \cdot [A]^2 \cdot [B] \]
1. Thola indlela yokusabela maqondana no-A no-B.
2. Thola i-oda eliphelele lokusabela.
Ingxoxo:
1. Kusukela ku-rate equation \( \text{rate} = k \cdot [A]^2 \cdot [B] \), singabona ukuthi:
– Ukuhleleka kokusabela maqondana no-A kungu-2 (ngoba i-exponent ka-\([A]\) ingu-2).
– Ukuhleleka kokusabela maqondana no-B kungu-1 (ngoba i-exponent ka-\([B]\) ingu-1).
2. I-oda eliphelele lokusabela liyisamba sama-oda e-reactant ngayinye:
– I-oda eliphelele = I-oda A + I-oda B = 2 + 1 = 3.
Isibonelo Umbuzo 2
Umbuzo:
Kusukela ekuhlolweni, idatha elandelayo yesilinganiso sokusabela itholiwe:
| [A] (mol/L) | [B] (mol/L) | Izinga lokusabela (mol/L s) |
|———-|——————————————–|
| 0.1 | 0.1 | 0.01 |
| 0.1 | 0.2 | 0.02 |
| 0.2 | 0.2 | 0.08 |
1. Thola ukulandelana kokusabela kwama-reactants u-A no-B.
2. Bala izinga lokusabela elingaguquki (k).
Ingxoxo:
1. Ukuze sithole ukuhleleka kokusabela, sidinga ukubheka ukuthi izinga lokusabela lishintsha kanjani lapho ukuhlushwa kwama-reactants kushintsha:
– Thola indlela yokusabela maqondana no-A:
Qhathanisa ukuhlolwa 2 no-3:
– \([A]\) iyanda kusuka ku-0.1 M kuya ku-0.2 M (okuphindwe kabili), kuyilapho \([B]\) ihlala ingu-0.2 M.
– Izinga lokusabela liyanda kusuka ku-0.02 mol/L s kuya ku-0.08 mol/L s (ngokuphindwe kane).
Ukuhleleka kokusabela maqondana no-A kunganqunywa yi-equation:
\[ \left(\frac{0.2}{0.1}\right)^m = \frac{0.08}{0.02} \]
\[ 2^m = 4 \]
\[ m = 2 \]
– Thola indlela yokusabela maqondana no-B:
Qhathanisa ukuhlolwa 1 no-2:
– \([B]\) iyanda kusuka ku-0.1 M kuya ku-0.2 M (okuphindwe kabili), kuyilapho \([A]\) ihlala ingu-0.1 M.
– Izinga lokusabela liyanda kusuka ku-0.01 mol/L s kuya ku-0.02 mol/L s (okuphindwe kabili).
Ukuhleleka kokusabela maqondana no-B kunganqunywa yi-equation:
\[ \left(\frac{0.2}{0.1}\right)^n = \frac{0.02}{0.01} \]
\[ 2^n = 2 \]
\[ n = 1 \]
2. Nquma izinga lokusabela elingaguquki (k):
Sebenzisa idatha evela kwenye yezivivinyo (isibonelo, isivivinyo 1):
\[ \text{rate} = k \cdot [A]^2 \cdot [B] \]
\[ 0.01 = k \cdot (0.1)^2 \cdot 0.1 \]
\[ 0.01 = k \cdot 0.001 \]
\[ k = \frac{0.01}{0.001} = 10 \, \text{L}^2/(\text{mol}^2 \cdot \text{s}) \]
Isibonelo Umbuzo 3
Umbuzo:
Ukusabela kulandela i-equation yesilinganiso esilandelayo:
\[ \text{rate} = k \cdot [A]^{1/2} \cdot [B]^2 \]
Uma amazinga okuqala ka-A no-B engu-0.36 M no-0.2 M, ngokulandelana, liyini izinga lokusabela kuleli qophelo uma \( k = 5 \, \text{L}^{5/2} / (\text{mol}^{5/2} \cdot \text{s}) \)?
Ingxoxo:
Sebenzisa i-equation yesilinganiso enikeziwe:
\[ \text{rate} = k \cdot [A]^{1/2} \cdot [B]^2 \]
Faka amanani anikeziwe:
\[ \izinga lombhalo} = 5 \cdot (0.36)^{1/2} \cdot (0.2)^2 \]
Bala inani lokuhlushwa:
\[ (0.36)^{1/2} = 0.6 \]
\[ (0.2)^2 = 0.04 \]
Manje, xhuma lawo manani ku-equation:
\[ \izinga lombhalo} = 5 \cdot 0.6 \cdot 0.04 \]
\[ \izinga lombhalo} = 5 \cdot 0.024 \]
\[ \izinga lombhalo} = 0.12 \, \umbhalo{mol/L\s} \]
Izinga lokusabela kulokhu kuhlushwa lingu-0.12 mol/L s.
Isiphetho
Isilinganiso sezinga lokusabela kanye nokuhlelwa kokusabela kuyimiqondo eyisisekelo ku-kinetics yamakhemikhali. Ngokuqonda ukuthi ukugxila kwe-reactant kuthinta kanjani amazinga okusabela, singabala izinga lokusabela bese sinquma izinga elihlala njalo. Lesi sihloko sinikeza izibonelo zezinkinga nezixazululo zokusiza ukuqonda le miqondo. Ukuqonda kahle lezi zihloko kubalulekile ekusetshenzisweni okusebenzayo elabhorethri yamakhemikhali kanye nezinqubo zezimboni.
Ngokuzijwayeza njalo kanye nokuhlaziya ngokucophelela, singaqonda kangcono ukuthi singanquma kanjani ama-oda okusabela futhi sisebenzise izilinganiso zesilinganiso ezimweni ezahlukahlukene. Ukufunda okuhle!
