Imibuzo Eyisibonelo Ekhuluma Ngezinkundla ZikaMagnetic
Insimu yamagnetic ingumqondo oyisisekelo ku-physics ochaza indlela amandla kazibuthe asebenzisana ngayo nezinto ezisebenzisa amandla kazibuthe noma ukushaja kukagesi okuhambayo. Ukufunda ngamasimu kazibuthe kubaluleke kakhulu ngoba kunezinhlelo zokusebenza eziningi, kusukela kumadivayisi kagesi kuya kwezokwelapha kuya ezindizeni. Lesi sihloko sizoxoxa ngezibonelo eziningana zemibuzo yokufunda ngamasimu kazibuthe kanye nengxoxo yawo kanye nezixazululo, esithemba ukuthi zizokusiza ukuthi uwuqonde kangcono lo mqondo.
Ukuqonda Amasimu Kamagnetic
Ngokuvamile, insimu yamagnetic ingadalwa yimagnethi ehlala njalo noma ugesi ogeleza ocingweni. Amandla ensimu yamagnetic endaweni ethile abalwa kusetshenziswa umthetho we-Biot-Savart noma umthetho we-Ampère, kuye ngezimo ezithile. Insimu yamagnetic iboniswa yi-vector B futhi inamayunithi e-Tesla (T).
Imibuzo Eyisibonelo Nengxoxo
Umbuzo 1: Insimu Kamagnetic Ephakathi Kwendilinga Ethwala Ugesi
Umbuzo: Bala ubukhulu bensimu yamagnetic enkabeni yeluphu yentambo eyindilinga ene-radius R kanye nephethe ugesi I.
Ingxoxo:
Insimu yamagnetic enkabeni yeluphu yentambo eyindilinga ingabalwa kusetshenziswa umthetho we-Biot-Savart othi:
\[ B = \frac{\mu_0 I}{2R} \]
Kuphi:
– \( \mu_0 \) = ukuvuleka kwe-vacuum ( \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m/A} \) )
– I = ugesi ojikelezayo
– R = irediyasi yeluphu
Ake sithi u-R = 0,1 m kanye no-I = 5 A, khona-ke ubukhulu bensimu yamagnetic enkabeni yeluphu buyi:
\[ B = \frac{4\pi \times 10^{-7} \times 5}{2 \times 0,1} = \frac{2\pi \times 10^{-6}}{0,1} = 2\pi \times 10^{-5} \, \text{T} \]
Ngakho-ke, ubukhulu bensimu yamagnetic enkabeni yeluphu cishe bungu-\( 6,28 \times 10^{-5} \, \text{T} \).
Umbuzo 2: Insimu Kamagnetic Eceleni Kwentambo Eqondile Ethwala Ugesi
Umbuzo: Thola insimu yamagnetic kude no-d kusuka ku-wire ende eqondile ephethe ugesi u-I.
Ingxoxo:
Ukuze siqinisekise insimu yamagnetic ezungeze ucingo oluthwala ugesi oluqondile, sisebenzisa umthetho ka-Ampere, ochazwa kanje:
\[ B = \frac{\mu_0 I}{2\pi d} \]
Kuphi:
– \( \mu_0 \) = ukuvuleka kwe-vacuum
– I = ugesi ocingweni
– d = ibanga ukusuka kucingo
Ake sithi mina = 10 A kanye no-d = 0,02 m, bese kuthi:
\[ B = \frac{4\pi \times 10^{-7} \times 10}{2\pi \times 0,02} = \frac{4 \times 10^{-6} \times 10}{0,02} = 2 \times 10^{-4} \, \text{T} \]
Ngakho-ke, ubukhulu bensimu yamagnetic ebangeni elingamamitha angu-0,02 ukusuka entanjeni ngu-\( 2 \times 10^{-4} \, \text{T} \).
Umbuzo 3: Insimu Kamagnetic Phakathi Kwezintambo Ezimbili Ezithwala Ugesi Ezihambisanayo
Umbuzo: Izintambo ezimbili ezithwala ugesi ezifanayo zihlukaniswe ibanga elingu-d futhi ngayinye ithwala ugesi ongu-I1 no-I2. Thola insimu yamagnetic phakathi nendawo phakathi kwezintambo ezimbili.
Ingxoxo:
Ukuze sibale insimu yamagnetic phakathi nendawo phakathi kwezintambo ezimbili, kumelwe sicabangele isiqondiso kanye nobukhulu bensimu yamagnetic ekhiqizwa yintambo ngayinye.
Ake sithi u-I1 = 5 A no-I2 = 10 A, kanti ibanga eliphakathi kwezintambo ezimbili lingu-0,1 m. Bese ibanga elisuka endaweni ephakathi liye kuntambo ngayinye lingu-0,05 m. Ngokusekelwe emthethweni we-Ampere:
Insimu yamagnetic yentambo 1 (B1) endaweni ephakathi:
\[ B_1 = \frac{\mu_0 I_1}{2\pi (d/2)} = \frac{4\pi \times 10^{-7} \times 5}{2\pi \times 0,05} = 2 \times 10^{-5} \, \text{T} \]
Insimu yamagnetic yentambo 2 (B2) endaweni ephakathi:
\[ B_2 = \frac{\mu_0 I_2}{2\pi (d/2)} = \frac{4\pi \times 10^{-7} \times 10}{2\pi \times 0,05} = 4 \times 10^{-5} \, \text{T} \]
Njengoba amasimu amabili kazibuthe ehlukene endaweni ephakathi nendawo, ubukhulu bensimu kazibuthe iyonke endaweni ephakathi nendawo umehluko phakathi kwe-B2 ne-B1:
\[ B_{\text{total}} = B_2 – B_1 = 4 \times 10^{-5} – 2 \times 10^{-5} = 2 \times 10^{-5} \, \text{T} \]
Ngakho-ke, ubukhulu bensimu yamagnetic endaweni ephakathi kwezintambo ezimbili ngu-\( 2 \times 10^{-5} \, \text{T} \).
Umbuzo 4: Insimu Kamagnetic Enhliziyweni Ye-Solenoid
Umbuzo: Bala insimu yamagnetic ngaphakathi kwe-solenoid ende enama-n turns ngobude beyunithi futhi ephethe ugesi I.
Ingxoxo:
Kwi-solenoid ende, insimu yamagnetic ku-solenoid icishe ifane futhi ibalwa kusetshenziswa i-equation:
\[ B = \mu_0 n I \]
Kuphi:
– \( \mu_0 \) = ukuvuleka kwe-vacuum
– n = inani lokujika ngemitha
– I = ugesi wamanje
Ake sithi i-solenoid inamajika angu-1000 ngemitha kanye nomsinga wokugeleza okungu-2 A, khona-ke:
\[ B = 4\pi \izikhathi 10^{-7} \izikhathi 1000 \izikhathi 2 = 8\pi \izikhathi 10^{-4} \, \umbhalo{T} \]
\[ B = 8 \izikhathi 3.14 \izikhathi 10^{-4} = 25.12 \izikhathi 10^{-4} \, \umbhalo{T} \]
Ngakho-ke, insimu yamagnetic ngaphakathi kwe-solenoid icishe ibe ngu-\( 2.51 \times 10^{-3} \, \text{T} \).
Isiphetho
Ukuqonda amasimu kazibuthe kuyisihluthulelo sezinhlelo zokusebenza eziningi zobuchwepheshe besimanje. Ngalezi zibonelo, abafundi banethemba lokuthi bazothola ukuqonda okungcono kokuthi amasimu kazibuthe asebenza kanjani ezimweni ezahlukene, njengeluphu yentambo eyindilinga, intambo eqondile, izintambo ezimbili ezihambisanayo, kanye ne-solenoid. Ukuzijwayeza okuqhubekayo ngezinkinga nezimo ezahlukahlukene kuzoqinisa lo mqondo.
