Isibonelo sombuzo wokuthola izingxenye zejubane lokuqala lokunyakaza kwe-parabolic

Izibonelo ezi-4 zemibuzo yokunquma izingxenye zejubane lokuqala lokunyakaza kwe-parabolic

1. Ibhola likhahlelwa nge-engeli engama-60^o ebusweni bensimu. Uma ijubane lokuqala (v)_o) 10 m/s, nquma izingxenye eziqondile nezivundlile isivinini ibhola lasekuqaleni!
Ingxoxo
Kuyaziwa ukuthi:
I-engeli (θ) = 60^o
Ijubane lokuqala (v)_o) = 10 m/s
Kubuziwe: v_ox kanye no-v_oy
Impendulo:

isono θ = v_oy /v_o —–> v_oy =v_o isono θ
cos θ = v_ox /v_o —–> v_ox =v_o cosθ

Ingxenye evundlile yejubane lokuqala lebhola:
v_ox =v_o cos θ = (10 m/s)(cos 60^o) = (10 m/s)(0,5) = 5 m/s

Ingxenye eqondile yejubane lokuqala lebhola:
v_oy =v_o isono θ = (10 m/s)(isono 60^o) = (10 m/s)(0,5√3) = 5√3 m/s

2. Into iphonswa phezulu nge-engeli engu-30°^o kuya endaweni evundlile. Uma ingxenye eqondile yejubane lento (v)_oy) ingu-10 m/s, bala ijubane lokuqala lento (v_o)!
Ingxoxo
Kuyaziwa ukuthi:
I-engeli (θ) = 30^o
Ingxenye eqondile yejubane lokuqala (v)_oy) = 10 m/s
Kubuziwe: Ijubane lokuqala lento (v)_o)
Impendulo:
Ifomula yengxenye eqondile yejubane lokuqala:
v_oy =v_o isono θ
10 = (v_o)(isono 30^o)
10 = (v_o)(0,5)
v_o = 10/0,5
v_o = 20m/s
Ijubane lokuqala lento lingu-20 m/s.

3. Ingxenye evundlile yejubane lenhlamvu ingu-30 m/s kanti ingxenye evundlile yejubane lenhlamvu ingu-40 m/s. Iyini ijubane lokuqala lenhlamvu?
Ingxoxo
Kuyaziwa ukuthi:
Ingxenye evundlile yejubane lenhlamvu (v)_ox) = 30 m/s
Ingxenye eqondile yejubane lenhlamvu (v)_oy) = 40 m/s
Kubuziwe: Ijubane lokuqala lenhlamvu (v)_o)
Impendulo:
Ijubane lokuqala lenhlamvu libalwa kusetshenziswa ifomula yePythagorean:
v_o² =v_ox² +v_oy² = 30² 40 +² = 900 + 1600 = 2500
v_o = √2500
v_o = 50m/s
Ijubane lokuqala lenhlamvu lingu-50 m/s.

4. Imabula iphonswa ngokuvundlile ngakwesokudla kusukela esakhiweni esinezitezi eziningi. Uma ijubane lokuqala lemabula lingu-6 m/s, lingakanani ijubane lokuqala lemabula eziqondisweni ezivundlile neziqondile?
Ingxoxo
Kuyaziwa ukuthi:
Ijubane lokuqala lemabula (v)_o) = 6 m/s
Kubuziwe: Ijubane lokuqala lemabula ohlangothini oluvundlile (v_ox) kanye nokuma (v_oy)
Impendulo:
Indlela yemabula ifana nesithombe.
Ekuqaleni imabula ihamba ngendlela evundlile ukuze ijubane lokuqala lemabula libe ngendlela evundlile (v)._ox) = ijubane lokuqala lemabula (v_o) = 6 m/s.
Okwamanje, ijubane lokuqala lemabula ohlangothini oluqondile lingu-zero.

[IsiNgisi: Ukuxazulula izinkinga zokunyakaza okuqoshwe phansi – Ukuxazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile ]