1. Iphuzu A lisebangeni elingama-5 cm ukusuka ekushajweni okungu-+10 micro Coulombs. Ubukhulu kanye nesiqondiso sensimu kagesi ephuzu A… (k = 9 x 109 Nm2C-2, i-Coulomb encane eyi-1 = 10-6 C)
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I-Diketahui :
Kubuziwe Ubukhulu kanye nesiqondiso sensimu kagesi endaweni A
Jawab :
Isiqondiso sensimu kagesi endaweni A :
Ishaja kagesi ilungile, ngakho-ke isiqondiso sensimu kagesi sikude neshaja kagesi futhi sikude nephuzu A.
2. Ibanga eliphakathi kwephuzu P kanye nokushaja okungu--20 micro Coulombs lingu-10 cm. Thola amandla ensimu kagesi kanye nesiqondiso sensimu kagesi endaweni P.
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I-Diketahui :
Kubuziwe : Ubukhulu kanye nesiqondiso sensimu kagesi endaweni P
Jawab :
Isiqondiso sensimu kagesi endaweni A :
Ishaja kagesi ayilungile, ngakho-ke isiqondiso sensimu kagesi sibheke ishaja kagesi futhi siqhelelene nephuzu P.
3. Amashaja amabili kagesi ahlukaniswe ngebanga elingama-40 cm. Amandla ensimu kagesi kanye nesiqondiso sensimu kagesi endaweni ephakathi kwamashaja amabili…
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Ake sithi iphuzu eliphakathi kwamacala amabili liyiphuzu P.
I-Diketahui :
Kubuziwe : ubukhulu kanye nesiqondiso sensimu kagesi endaweni ephakathi kwamashaja amabili (iphuzu P)
Jawab :
Insimu kagesi ekhiqizwa yishaja u-A endaweni P :
Ishaja A ayilungile ngakho-ke isiqondiso sensimu kagesi sibheke kushaja A (ngakwesobunxele).
Insimu kagesi ekhiqizwa yishaja B endaweni P :
Ishaja B ilungile ngakho-ke isiqondiso sensimu kagesi sikude neshaja B (ngakwesobunxele).
Insimu kagesi ephumela endaweni A :
EA kanye no-EB ngendlela efanayo ngakho-ke zenezelwa ndawonye.
E = EA +EB
E = (4,5 x 105) + (9 x 105)
E = 13,5 x 105 Akunjalo
Indlela eya ensimini kagesi ibheke ekushajeni u-A futhi ikude ne-charge u-B (ngakwesobunxele).
4. Amandla ensimu kagesi ayi-zero endaweni ethile ebangeni eli-…
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Ishaja A ilungile kanti ishaja B ilungile, ngakho-ke amandla ensimu kagesi ayi-zero, atholakala phakathi kwamacala amabili. Ake sithi iphuzu lapho amandla ensimu kagesi eyi-zero khona liyi-point P.
I-Diketahui :
Kubuziwe : amandla ensimu kagesi awekho atholakala endaweni ethile ebangeni elingama-…
Jawab :
Insimu kagesi ekhiqizwa yishaja u-A endaweni P :
Ishaja A ilungile ngakho-ke isiqondiso sensimu kagesi edalwe yishaja A endaweni P sikude neshaja A (ngakwesokudla).
Insimu kagesi ekhiqizwa yishaja B endaweni P :
Ishaja B ilungile ngakho-ke isiqondiso sensimu kagesi edalwe yishaja B endaweni P sikude neshaja B (ngakwesobunxele).
Insimu kagesi ephumela endaweni P = 0 :
EA kanye no-EB uhlangothi oluphambene.
EA - EB = 0
EA =EB
Sebenzisa ifomula ye-ABC ukuthola inani lika-a.
Amandla kagesi angenalutho atholakala endaweni engama-8 cm ukusuka ekushajeni u-A noma ama-12 cm ukusuka ekushajeni u-B.
5. Ibanga eliphakathi kwamashaja amabili u-A no-B lingamamitha ama-3. Iphuzu u-O liphakathi kwamashaja amabili futhi lingamamitha ama-2 ukusuka kumashaja B. qA = –300 μC kanye no-qB = 600 μC. k = 9 × 109 N m2 C-2Amandla ensimu kagesi endaweni ethi O athonywa yi-chaji qA kanye no-qB kuyinto…
A. 9 × 105 Akunjalo
B. 18 × 105 Akunjalo
C. 52 × 105 Akunjalo
D. 60 × 105 Akunjalo
E. 81 × 105 Akunjalo
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I-Diketahui :
qA = –300 μC, qB = 600 μC, k = k = 9 × 109 N m2 C-2
Kubuziwe :
Iyini amandla kagesi (E) endaweni ethi O?
Jawab :
Amandla ensimu aphumela:
E = EA +EB
E = (2700 x 103 Akukho) + (5400 x 103 Akukho/C)
E = 8100 x 103 Akunjalo
E = 81 x 105 Akunjalo
Impendulo efanele ngu-E.
6. Izindleko ezimbili ngayinye ye-q1 = -20 μC kanye no-q2 = -40 μC. Uma kusendaweni ethi P engama-20 cm ukusuka ku-q2 amandla ensimu kagesi aphumelayo ayi-zero, bese inani x kuyinto…
A. 11 cm
B. 12 cm
C. 13 cm
D. 14 cm
E. 15 cm
Ingxoxo:
I-Diketahui :
q1 = -20 μC, q2 = -40 μC, r2 = 0,2 m, r1 =x
Kubuziwe :
Ibanga lephuzu P kusuka ku-q1 (x) ?
Jawab :
Amandla kagesi aphumelayo ayi-zero endaweni ethi P:
Impendulo efanele ngu-D.
7. Iphuzu A litholakala phakathi kwamashaja amabili anobukhulu obufanayo kodwa izinhlobo ezahlukene ezihlukaniswe yibanga. Ubukhulu bamandla ensimu kagesi endaweni A ngaleso sikhathi bungu-36 NC -1 . Uma iphuzu A lishintshwa ngo-¼ eduze nelinye lamashaja, khona-ke ubukhulu bamandla ensimu kagesi endaweni A ngemva koshintshwa bungu ….
A. 100 NC -1
B. 96 NC -1
C. 80 NC -1
D. 60 NC -1
E. 16 NC -1
Ingxoxo
Kuyaziwa ukuthi :
Ishaja 1 (q 1 ) = +Q
Ishaja 2 (q 2 ) = -Q
Ibanga phakathi kokushaja 1 kanye nephuzu A (r 1A ) = ½ a
Ibanga phakathi kokushaja 2 kanye nephuzu A (r 2A ) = ½ a
Amandla kagesi endaweni A (EA ) = 36 NC -1
Umbuzo : Uma iphuzu A lishintshwa ngo-¼ eduze kwelinye lamashaji, khona-ke amandla ensimu kagesi ephuzu A...
Impendulo :
Isigaba 1.
Ukuze ubale amandla ensimu kagesi endaweni A, ake sithi kukhona ishaja yokuhlola elungile kuleyo ndawo. Ukuba khona kweshaja yokuhlola elungile kuthinta indlela insimu kagesi elungile ngayo.
Insimu kagesi ekhiqizwa yi-charge +Q endaweni A :
Ishaja yokuhlola ilungile kanti ishaja 1 ilungile ngakho-ke isiqondiso sensimu kagesi sibheke ekushajeni 2.
Insimu kagesi ekhiqizwa yi-charge -Q endaweni A :
Ishaja yokuhlola ilungile kanti ishaja 2 imbi ngakho-ke isiqondiso sensimu kagesi sibheke ekushajeni 2.
Insimu kagesi ephumela endaweni A :
Isigaba sesi-2.
Uma iphuzu A lishintshelwa eduze kokushaja okungu-1 khona-ke:
Ibanga eliphakathi kokushaja 1 nephuzu A (r 1A ) = ¼ a
Ibanga phakathi kokushaja 2 kanye nephuzu A (r 2A ) = ¾ a
Insimu kagesi ekhiqizwa yi-charge +Q endaweni A :
Ishaja yokuhlola ilungile kanti ishaja 1 ilungile ngakho-ke isiqondiso sensimu kagesi sibheke ekushajeni 2.
Insimu kagesi ekhiqizwa yi-charge -Q endaweni A :
Ishaja yokuhlola ilungile kanti ishaja 2 imbi ngakho-ke isiqondiso sensimu kagesi sibheke ekushajeni 2.
Insimu kagesi ephumela endaweni A :
Impendulo efanele ngu-C.
8. Izinhlayiya ezimbili ngayinye enamashaja q A = 1 μC kanye q B = 4 μC zibekwe eceleni ngo-4 cm (k = 9 x 10 9 N m 2 C −2 ). Amandla ensimu kagesi phakathi kuka-q A kanye no-q B …
A. 6,75 x 10 7 NC −1
B. 4,50 x 10 7 NC −1
C. 4,20 x 10 7 NC −1
D. 3,60 x 10 7 NC −1
E. 2,25 x 10 7 NC −1
Ingxoxo
Kuyaziwa ukuthi :
Ishaja A (q A ) = 1 μC = 1 x 10 −6 C
Ishaja B (q B ) = 4 μC = 4 x 10 −6 C
k = 9 x 10 9 N m 2 C −2
Ibanga eliphakathi kwamanani A no-B (r AB ) = 4 cm = 0,04 amamitha
Ibanga eliphakathi kweshaja A kanye nephuzu eliphakathi (r A ) = 0,02 amamitha
Ibanga eliphakathi kweshaja B kanye nendawo ephakathi (r B ) = 0,02 amamitha
Umbuzo : Amandla kagesi phakathi kuka-q A no-q B …
Impendulo :
Ukuze ubale amandla ensimu kagesi phakathi kuka-q A no-q B , ake sithi ishaja yokuhlola enhle itholakala phakathi kwalawa mashaja amabili. Ukuba khona kweshaja yokuhlola enhle kuthinta indlela insimu kagesi eqondiswa ngayo.
Insimu kagesi ekhiqizwa yishaja u-A endaweni ephakathi nendawo :
Ishaja yokuhlola ilungile kanti ishaja u-A ilungile ngakho-ke isiqondiso sensimu kagesi sibheke ekushajeni u-B.
Insimu kagesi ekhiqizwa yishaja B endaweni ephakathi nendawo :
Ishaja yokuhlola ilungile kanti ishaja B ilungile ngakho-ke isiqondiso sensimu kagesi sibheke ekushajeni A.
Insimu kagesi ephumela endaweni ephakathi nendawo :
I-E A ne-E B zisezinhlangothini eziphambene.
E = E B – E A = 9 x 10 7 – 2,25 x 10 7 = 6,75 x 10 7 NC -1
Impendulo efanele ngu-A.
9. Bheka isithombe esilandelayo samaphuzu amabili okushaja! Iphi iphuzu P ukuze amandla ensimu kagesi endaweni P alingane no- zero? (k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
A. phakathi no-Q 1 no-Q 2
B. 6 cm ngakwesokudla kwe-Q 2
C. 6 cm ngakwesobunxele se-Q 1
D. 2 cm ngakwesokudla kwe-Q 2
E. 2 cm ngakwesobunxele se-Q 1
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Ukuze ubale amandla ensimu kagesi ephuzwini P, cabanga ukuthi kukhona ishaja yokuhlola enhle ephuzwini P. Q 1 inhle kanti Q 2 imbi, ngakho-ke iphuzu P kumele libe ngakwesokudla se-Q 2 noma ngakwesobunxele se-Q 1. Uma iphuzu P likwesobunxele se-Q 1 ; insimu kagesi ekhiqizwe yiphuzwi Q 1 ephuzwini P iqondiswe ngakwesobunxele (kude ne-Q 1 ) kanti insimu kagesi ekhiqizwe yi-Q 2 ephuzwini P iqondiswe kwesokudla (ebheke ku-Q 1 ). Ngenxa yokuthi isiqondiso sensimu kagesi siphambene, lezi ezimbili ziyakhiphana ukuze amandla ensimu kagesi ephuzwini P abe yi-zero.
Kuyaziwa ukuthi :
Q 1 = +9 μC = +9 x 10 −6 C
Q 2 = -4 μC = -4 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Ibanga eliphakathi kweshaja 1 neshaja 2 = 3 cm
Ibanga eliphakathi kuka-Q 1 nephuzu P (r 1P ) = a
Ibanga eliphakathi kuka-Q 2 nephuzu P (r 2P ) = 3 cm + a
Umbuzo : Iphi iphoyinti P ukuze amandla ensimu kagesi ephoyinti P alingane no-zero?
Impendulo :
Iphuzu P lingakwesobunxele se-Q 1.
Insimu kagesi ephumela endaweni A :
Sebenzisa ifomula ye-ABC ukuthola inani lika-a.
10. Bheka isithombe esilandelayo! Ishaja q 3 ibekwe ebangeni elingama-5 cm ukusuka ku-q 2 , bese kuthi amandla kagesi ashaja q 3 abe… (1 µC = 10 -6 C)
A. 4,6 x 107 I-NC-1
B. 3,6 x 10 7 NC -1
C. 1,6 x 10 7 NC -1
D. 1,4 x 10 7 NC -1
E. 1,3 x 10 7 NC -1
Ingxoxo
Ishaja q 3 ibekwe ebangeni elingama-5 cm ukusuka ku-q 2 , okusho ukuthi hhayi ngakwesobunxele se-q 2 kodwa ngakwesokudla se-q 2. Uma ingakwesobunxele se-q 2 khona-ke insimu kagesi ephumelayo ingu-zero. Lokhu kungenxa yokuthi ibanga eliphakathi kweshaja q 3 neshaja q 1 kanye ne-q 2 lingu-5 cm kanti ubukhulu beshaja q 1 bufana neshaja q 2.
Ngenxa yokuthi ishaja q 3 ilungile, isiqondiso sensimu kagesi eshaja q 3 sibheke ekushajeni okungekuhle q 2 (E 2 ) futhi siqhele ekushajeni okuhle q 1 (E 1 ). Insimu kagesi ephumelayo iyisamba samandla ensimu kagesi E 1 kanye no-E 2.
Kuyaziwa ukuthi :
Ishaja q 1 = 5 µC = 5 x 10 -6 Coulomb
Ishaja q 2 = 5 µC = -5 x 10 -6 Coulomb
Ibanga phakathi kweshaja q 1 kanye neshaja q 3 (r 1 ) = 15 cm = 0,15 m = 15 x 10 -2 amamitha
Ibanga phakathi kweshaja q 2 kanye neshaja q 3 (r 2 ) = 5 cm = 0,05 m = 5 x 10 -2 amamitha
k = 9 x 10 9 N m 2 C -2
Umbuzo : Amandla kagesi ashajayo q 3
Impendulo :
Amandla kagesi 1
E 1 = kq 1 / r 1 2
E 1 = (9 x 10 9 )(5 x 10 -6 ) / (15 x 10 -2 ) 2
E 1 = (45 x 10 3 ) / (225 x 10 -4 )
E 1 = 0,2 x 10 7 N/C
Amandla kagesi 2
E 2 = kq 2 / r 2 2
E 2 = (9 x 10 9 )(5 x 10 -6 ) / (5 x 10 -2 ) 2
E 2 = (45 x 10 3 ) / (25 x 10 -4 )
E 2 = 1,8 x 10 7 N/C
Amandla kagesi aphumelayo
Amandla kagesi atholakalayo ekushajeni q 3 yilawa:
E = E 2 – E 1 = (1,8 x 10 7 ) – (0,2 x 10 7 ) = 1,6 x 10 7 N/C
Isiqondiso sensimu kagesi singakwesobunxele noma sibheke ku- E2.
Impendulo efanele ngu-C.
11. Kuhlukaniswe amashaja amabili kagesi njengoba kuboniswe esithombeni. Amandla ensimu endaweni P angu… (k = 9 x 10 9 N m 2 C -2 )
A. 9,0 x 109 I-NC-1
B. 4,5 x 10 9 NC -1
C. 3,6 x 10 9 NC -1
D. 5,4 x 10 9 NC -1
E. 4,5 x 10 9 NC -1
Ingxoxo
Kuyaziwa ukuthi :
Ishaja q A = +2,5 C
Ishaja q B = -2 C
Ibanga phakathi kokushaja q A kanye nephuzu P (r A ) = 5 m
Ibanga phakathi kokushaja q B kanye nephuzu P (r B ) = 2 m
k = 9 x 10 9 N m 2 C -2
Umbuzo : Amandla ensimu kagesi endaweni P
Impendulo :
Amandla kagesi ensimu A
E A = kq A / r A 2
E A = (9 x 10 9 )(2,5) / (5) 2
E A = (22,5 x 10 9 ) / 25
I-EA = 0,9 x 10 9 N / C
Amandla kagesi ensimu B
E B = kq B / r B 2
E B = (9 x 10 9 )(2) / (2) 2
E B = (18 x 10 9 ) / 4
I-E B = 4,5 x 10 9 N/C
Amandla kagesi aphumelayo
Amandla kagesi aphumela endaweni ethi P yilawa:
E = E B – E A = (4,5 – 0,9) x 10 9 = 3,6 x 10 9 N/C
Isiqondiso sensimu kagesi singakwesobunxele noma sibheke ku- E B.
Impendulo efanele ngu-C.
12. Amashaja amabili kagesi, ngalinye lineshaja Q 1 = -40 µC kanye Q 2 = +5 µC, atholakala endaweni njengoba kuboniswe esithombeni (k = 9 x 10 9 Nm 2 .C -2 kanye no-1 µC = 10 -6 C), amandla ensimu kagesi endaweni P...
A. 2,25 x 106 I-NC-1
B. 2,45 x 10 6 NC -1
C. 5,25 x 10 6 NC -1
D. 6,75 x 10 6 NC -1
E. 9,00 x 10 6 NC -1
Ingxoxo
Kuyaziwa ukuthi :
Ishaja q 1 = -40 µC = -40 x 10 -6 C
Ishaja q 2 = +5 µC = +5 x 10 -6 C
Ibanga phakathi kokushaja q 1 kanye nephuzu P (r 1 ) = 40 cm = 0,4 m = 4 x 10 -1 m
Ibanga phakathi kokushaja q 2 kanye nephuzu P (r 2 ) = 10 cm = 0,1 = 1 x 10 -1 m
k = 9 x 10 9 N m 2 C -2
Umbuzo : Amandla ensimu kagesi endaweni P
Impendulo :
Amandla kagesi 1
E 1 = kq 1 / r 1 2
E 1 = (9 x 10 9 )(40 x 10 -6 ) / (4 x 10 -1 ) 2
E 1 = (360 x 10 3 ) / (16 x 10 -2 )
E 1 = 22,5 x 10 5 N/C
Amandla kagesi 2
E 2 = kq 2 / r 2 2
E 2 = (9 x 10 9 )(5 x 10 -6 ) / (1 x 10 -1 ) 2
E 2 = (45 x 10 3 ) / 1 x 10 -2
E 2 = 45 x 10 5 N/C
Amandla kagesi aphumelayo
Amandla kagesi aphumela endaweni ethi P yilawa:
E = E 2 – E 1 = (45 – 22,5) x 10 5 = 22,5 x 10 5 N/C
E = 2,25 x 10 6 N/C
Isiqondiso sensimu kagesi singakwesokudla noma sibheke ku- E2.
13. Kusukela esithombeni esilandelayo sokushaja, esibonisa ukuthi imigqa yamandla kuma-charge amabili asondelene...
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Imigqa yamandla kagesi, noma imigqa yamandla, idonswa kusukela ekushajeni okuhle kuya ekushajeni okubi. Uma ukushaja okuhle nokubi kuhlanganiswa ndawonye, imigqa yamandla ivela njengasempendulweni A.
Impendulo efanele ngu-A.
8. Amashaja amabili kagesi asondezwana emgqeni wokuxhuma ukuze akhiqize imigqa kagesi. Isithombe esifanele sithi…
Ingxoxo
Impendulo efanele ngu-D.
9. Imigqa efanele yamandla phakathi kwamacala amabili…
Ingxoxo
Impendulo efanele ngu-D.
14. Bheka isithombe esilandelayo samaphuzu amabili!
Iphi indawo u-P ukuze amandla ensimu kagesi endaweni u-P alingane no-zero?
(k = 9.10 9 Nm 2 .C -2 , 1 µC = 10 -6 C)
A. 1 cm ngakwesokudla kwe-q 1
B. 1 cm ngakwesokudla kwe-q 2
C. ½ cm ngakwesokudla kwe-q 2
D. ½ cm ngakwesobunxele se-q 1
E. ½ cm ngakwesokudla kwe-q 1
Ingxoxo
Kuyaziwa ukuthi:
Ishaja 1 (q 1 ) = -9 µC = -9.10 -6 Coulomb
Ishaja 2 (q 2 ) = 1 µC = 1.10 -6 Coulomb
Ibanga eliphakathi kuka-q 1 no-q 2 (r 12 ) = 1 cm
k = 9.10 9 Nm 2 .C -2
Umbuzo: Iphi iphoyinti P ukuze amandla ensimu kagesi ephoyinti P alingane no-zero?
Impendulo:
E 1 = amandla ensimu kagesi akhiqizwa yi-q 1 endaweni P
Isiqondiso se-E 1 sibheke ku-q 1 ngoba u-q 1 ungemuhle.
E 2 = amandla ensimu kagesi akhiqizwa yi-q 2 endaweni P
Indlela u-E 2 aqondani ngayo no-q 2 ngoba u-q 2 ulungile.
r 1 = ibanga phakathi kuka-P no-q 1 = x + 1
r 2 = ibanga phakathi kuka-P no-q 2 = x
Amandla ensimu kagesi endaweni ethi P alingana no-zero:
Sebenzisa ifomula ye-ABC:
Ibanga eliphakathi kuka-P no-q 2 = x = 0,5 cm.
Iphuzu P lingu-0,5 cm ngakwesokudla kwe-q 2 noma u-0,25 cm ngakwesobunxele kwe-q 1.
Impendulo efanele ngu-C.
15. Naka amacala amabili atholakala kude ngezansi!
Uma amandla ensimu kagesi endaweni ethi P engu-k Q/x 2 , khona-ke inani lika-x lingu….
A. 1/3 a
B. 2/3 a
C. a
D. 3/2 a
E. 2a
Ingxoxo
Kuyaziwa ukuthi:
I-EP = k Q / x 2
Kubuziwe: inani lika-x
Impendulo:
Sebenzisa ifomula ye-ABC:
Impendulo efanele ngu-A.
16. Imibuzo Yokuhlolwa Kazwelonke ye-SMA/MA Physics U-ZC-2013/2014 No. 27
Bheka isithombe esilandelayo samaphuzu amabili ashajayo!
Iphi indawo u-P ukuze amandla ensimu kagesi endaweni u-P alingane no-zero?
(k = 9.109 Nm2.C-2, 1 µC = 10-6 C)
- 1 cm ngakwesokudla kwe-q1
- 1 cm ngakwesokudla kwe-q2
- ½ cm ngakwesokudla kwe-q2
- ½ cm ngakwesobunxele se-q1
- ½ cm ngakwesokudla kwe-q1
Ingxoxo
Kuyaziwa ukuthi:
Ishaja 1 (q)1) = -9 µC = -9.10-6 I-Coulomb
Ishaja 2 (q)2) = 1 µC = 1.10-6 I-Coulomb
Ibanga eliphakathi kuka-q1 kanye no-q2 (r12= 1cm
k =9.109 Nm2.C-2
Kubuziwe: Iphi indawo u-P ukuze amandla ensimu kagesi endaweni u-P alingane no-zero?
Impendulo:
E1 = amandla ensimu kagesi akhiqizwa yi-q1 endaweni P
Isiqondiso E1 ku-q1 ngoba u-q1 uphawu olungalungile
E2 = amandla ensimu kagesi akhiqizwa yi-q2 endaweni P
Isiqondiso E2 hlala kude no-q2 ngoba u-q2 uphawu oluhle
r1 = ibanga phakathi kuka-P no-q1 = x + 1
r2 = ibanga phakathi kuka-P no-q2 =x
Amandla kagesi 1:
Amandla kagesi 2:
Amandla ensimu kagesi endaweni ethi P alingana no-zero:
a = 8, b = -2, c = -1
Sebenzisa ifomula ye-ABC:
Ibanga phakathi kuka-P no-q2 = x = 0,5 cm.
Iphuzu P liyi-0,5 cm ngakwesokudla kwe-q2 noma ku-0,25 cm ngakwesobunxele se-q1.
Impendulo efanele ngu-C.
17. Imibuzo Yokuhlolwa Kazwelonke ye-SMA/MA Physics U-ZC-2013/2014 No. 27
Cabanga ngamacala amabili atholakala kude ngezansi!
Uma amandla ensimu kagesi endaweni P engu-k Q/x2, khona-ke inani lika-x lingu….
- 1 / 3 a
- 2 / 3 a
- a
- 3 / 2 a
- 2a
Ingxoxo
Kuyaziwa ukuthi:
EP = k Q / x2
Kubuziwe: inani le-x
Impendulo:
E1 = amandla ensimu kagesi endaweni P ngokushaja -Q
r1 = ibanga phakathi kokushaja –Q kanye nephuzu P = x
E2 = amandla ensimu kagesi endaweni P ngokushaja +32Q
r2 = ibanga phakathi kokushaja +32Q kanye nephuzu P = a + x
Sebenzisa ifomula ye-ABC:
Impendulo efanele ngu-A.
