Izibonelo ezingu-20 zemithetho kaNewton
Umthetho Wokuqala KaNewton
1. Uma amandla aphumelayo asebenza entweni elingana no-zero, khona-ke...
(1) into ngeke isheshise
(2) izinto zihlala ziphumule
(3) ushintsho kwijubane lento luyi-zero
(4) akunakwenzeka ukuthi into ihambe ngendlela eqondile ngesivinini esingaguquki
Iqiniso lithi…
A. (1), (2) kanye no-(3)
B. (1) kanye (3) kuphela
C. (2) kanye no-(4) kuphela
D. (4) kuphela
E. (1), (2), (3) kanye no (4)
Ingxoxo
Impendulo efanele ithi:
(1) Into ngeke isheshise
Amandla avelayo abangela into ukuthi isheshise. Uma amandla avelayo engu-zero, into ngeke isheshise.
(2) Izinto zihlala ziphumule
UMthetho Wokuqala KaNewton uthi uma amandla aphumayo asebenza entweni elingana no-zero, khona-ke into ephumule izohlala iphumule kanti into ehamba ngesivinini esingaguquki (ukunyakaza okuqondile okufanayo) izohlala ishukuma ngesivinini esingaguquki.
(3) Ushintsho ejubaneni lento luyi-zero
Ushintsho lwejubane = ukusheshisa. Ushintsho lwejubane lento luyi-zero, okusho ukuthi ukusheshisa kwento kuyi-zero. Uma ukusheshisa kuyi-zero, khona-ke amandla asebenzayo entweni ayi-zero.
Impendulo efanele ngu-A.
Izinto Ezise-Lifti
2. Uma uSandi esesiliftini esimile, isisindo sakhe singama-N angu-500. Ukusheshisa okubangelwa amandla adonsela phansi = 10 ms –2 . Uma isilifti sisheshisa, ukucindezeleka entanjeni kuba ngu-750 N. Ngakho-ke, ukusheshisa kwesilifti kuba…
A. 5,0 ms –2
B. 7,5 ms –2
C. 10,0 ms –2
D. 12,5 ms –2
E. 15,0 ms –2
Ingxoxo
Kuyaziwa ukuthi:
Isisindo sekhodi (w) = 500 Newton = 500 kg ms –2 (ilifti lapho iphumule)
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 ms –2
Isisindo Sephasiwedi (m) = 500 / 10 = 50 kg
Ukuqina kwentambo (T) = 750 N (i-lifti isheshisiwe)
Isisindo se-lift asinakwa.
Kubuziwe: Ukusheshisa kwe-lifti
Impendulo:
Ilifti iphumule, akukho ukusheshisa (a = 0). Amandla aphezulu amahle, amandla aphansi angemabi.
ΣF = ma
T – w = 0
T = w
T = 500 Newton
Uma i-lift ishesha iyehla, amandla okucindezela entanjeni aba ngaphansi kwama-Newton angu-500. Ngakolunye uhlangothi, uma i-lift isheshiswa iye phezulu, amandla okucindezela entanjeni aba ngaphezu kwama-Newton angu-500.
Ukucindezeleka entanjeni kuba ngu-750 N, okwenza ilifti isheshise iye phezulu. Amandla asohlangothini olufanayo nokunyakaza kwelifti alungile, kanti amandla asohlangothini oluphambene nawo angalungile.
T – w = ma
750 – 500 = 50 a
250 = 50 a
a = 250/50
a = 5,0 ms –2
Impendulo efanele ngu-A.
3. Umuntu onesisindo esingama-60 kg usesiliftini esihamba phansi ngesivinini esingu-3 ms -2 . Uma ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms -2 , khona-ke ubukhulu bamandla avamile asetshenziswa phansi kwesilifti kumuntu...
A. 180 N
B. 200 N
C. 340 N
D. 420 N
E. 600 N
Ingxoxo
Kuyaziwa ukuthi:
IMisa (m) = 60 kg
Ukusheshisa komuntu kanye ne-lifti (a) = 3 m/s 2
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Amandla adonsela phansi (w) = mg = (60)(10) = 600 amaNewton
Kubuziwe: amandla avamile (N)
Impendulo:
Kunamandla amabili asebenza kumuntu ose-lifti, okungukuthi amandla adonsela phansi (w) kanye namandla avamile asetshenziswa phansi kwe-lifti kumuntu (N). Kunezinhlobo ezintathu ze-vector, okungukuthi amandla adonsela phansi, amandla avamile, kanye nokusheshisa i-lifti, lapho amandla adonsela phansi eqondiswa phansi, amandla avamile eqondiswa phezulu, kanye nokusheshisa i-lifti kuqondiswa phansi. Inani le-vector eliqondiswe phansi likhethwa ukuthi libe nophawu oluhle kanti inani le-vector eliqondiswe phezulu likhethwa ukuthi libe nophawu olubi.
∑ F = ma
w – N = (60)(3)
600 – N = 180
N = 600 – 180
N = 420 Newton
Impendulo efanele ngu-D.
4. UReza, onesisindo esingama-40 kg, usesiliftini esikhuphukayo. Uma amandla ephansi lesilifti ezinyaweni zikaReza engama-520 N futhi ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms -2 , khona-ke ukusheshisa kwesilifti...
A. 1,0 ms -2
B. 1,5 ms -2
C. 2,0 ms -2
D. 2,5 ms -2
E. 3,0 ms -2
Ingxoxo
Kuyaziwa ukuthi:
IMisa (m) = 40 kg
Amandla ajwayelekile (N) = 520 N
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Amandla adonsela phansi (w) = mg = (40)(10) = 400 N
Kubuziwe: Ukusheshisa kwe-lifti
Impendulo:
∑ F = ma
400 – 520 = (40)(a)
-120 = (40)(a)
a = -120/40
a = -3 m/s 2
Ukusheshisa kwe-lifti kungu-3 m/s 2. Uphawu olunegethivu lusho ukuthi i-lifti iya phezulu.
5. Umuntu onesisindo esingama-60 kg usesiliftini esihamba phansi ngesivinini esingu-3 ms -2 . Ingakanani ingcindezi ekhishwa izinyawo zabantu phansi kwesilifti?
Ingxoxo
Kuyaziwa ukuthi:
Isisindo somuntu (m) = 60 kg
Isisindo somuntu (w) = mg = (60 kg)(10 m/s 2 ) = 600 kg m/s 2 = 600 Newtons
Ukusheshisa kwe-lifti (a) = 3 m/s 2 , phansi.
Ubuziwe: Ingakanani ingcindezi ekhishwa yizinyawo zomuntu phansi kwe-lifti?
Impendulo:
I-lifti yehla ngesivinini (a) esingu-3 m/s 2. Amandla aqondene nokunyakaza kwe-lifti alungile, amandla aqondene nokunyakaza kwe-lifti alungile.
w – N = ma
N = w – ma
N = 600 – (60)(3)
N = 600 – 180
N = 420 Newton
Lawa amandla avamile asetshenziswa yiphansi le-lifti kumuntu. Umuntu umile e-lifti ukuze ubukhulu bamandla avamile bulingane nesisindo esibonakalayo somuntu. Isisindo esibonakalayo silingana nokucindezela kwezinyawo zomuntu phansi.
Uhlelo Lomthwalo Wezintambo Ze-Pulley
6. Izinto ezimbili u-A no-B, ngayinye enesisindo esingu-6 kg kanye no-2 kg, ziboshwe ngentambo phezu kwe-pulley njengoba kuboniswe esithombeni. Uma ukungqubuzana phakathi kwentambo ne-pulley kunganakwa futhi u-g = 10 ms -2 , khona-ke ukucindezeleka entanjeni...
A. 20 N
B. 24 N
C. 27 N
D. 30 N
E. 50 N
Ingxoxo
Kuyaziwa ukuthi:
m A = 6 kg, m B = 2 kg, g = 10 m/s 2
w A = m A g = (6 kg)(10 m/s 2 ) = 60 kg m/s 2
w B = m B g = (2 kg)(10 m/s 2 ) = 20 kg m/s 2
Umbuzo: Iyini amandla okucindezela entambo (T)?
Impendulo:
w A > w B ngakho-ke uhlelo luhamba ngokuphambene newashi (m A wehla, m B wenyuka).
Ukusheshisa
ΣF = ma
w A – w B = (m A + m B ) a
60 – 20 = (6 + 2) a
40 = (8) a
a = 40 / 8 = 5 m/s 2
Ukuqina kwentambo
m A uyehla
w A – T A = m A a
60 – T A = (6)(5)
60 – TA = 30
TA = 60 – 30
I-T 2 = 30 Newton
u-m B uya phezulu
T B – w B = m B a
I-T B – 20 = (2)(5)
I-T B – 20 = 10
I-T B = 10 + 20
I-T 1 = 30 Newton
Ukuqina kwentambo (T) = 30 amaNewton.
Impendulo efanele ngu-D.
7. Bheka isithombe ohlangothini! Ukungqubuzana kwentambo kanye ne-pulley akunakwa. Uma isisindo A = 5 kg, g = 10 ms —2 kanye no-A kwehlela phansi ngokusheshisa okungu-2,5 ms —2 , khona-ke siyini isisindo sika-B?
A. 0,5 kg
B. 1 kg
C. 1,5 kg
D. 2 kg
E. 3 kg
Ingxoxo
Kuyaziwa ukuthi:
Isisindo A (m A ) = 5 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Ukusheshisa A noma ukusheshisa kwesistimu (a) = 2,5 m/s 2
Isisindo A (w A ) = (m A )(g) = (5)(10) = 50 AmaNewton
Ubuziwe: buyini ubunzima buka-B (m B )?
Impendulo:
Ibhulokhi A liyehla ngakho-ke isisindo sika-A (w A ) sikhulu kunesisindo sika-B (w B ).
Sebenzisa umthetho wesibili kaNewton:
ΣF = ma
w A – w B = (m A + m B ) a
50 – (m B )(10) = (5 + m B ) (2,5)
50 – 10 m B = 12,5 + 2,5 m B
50 – 12,5 = 2,5 m B + 10 m B
37,5 = 12,5 m B
m B = 3 kg
Impendulo efanele ngu-E.
8. Izinto ezimbili ezinesisindo esingu-2 kg kanye no-3 kg ziboshwa ngentambo bese zinamathiselwa epulangweni elinobunzima obunganakwa njengoba kuboniswe esithombeni.
Uma ubukhulu bokusheshisa kwamandla adonsela phansi = 10 ms -2 , amandla okucindezela entambo abonwa uhlelo...
A. 20 N
B. 24 N
C. 27 N
D. 30 N
E. 50 N
Ingxoxo
Kuyaziwa ukuthi:
m 1 = 2 kg, m 2 = 3 kg, g = 10 m/s 2
w 1 = (m 1 )(g) = (2 kg)(10 m/s 2 ) = 20 kg m/s 2 noma 20 AmaNewton
w 2 = (m 2 )(g) = (3 kg)(10 m/s 2 ) = 30 kg m/s 2 noma 30 AmaNewton
Umbuzo: Iyini amandla okucindezela entambo (T)?
Impendulo:
w 2 > w 1 ngakho-ke uhlelo luhamba ngokwewashi (m 2 uya phansi, m 1 uya phezulu).
Ukusheshisa
ΣF = ma
w 2 – w 1 = (m 1 + m 2 ) a
30 – 20 = (2 + 3) a
10 = (5) a
a = 10 / 5 = 2 m/s 2.
Ukuqina kwentambo
m2 ihlela phansi
w 2 – T 2 = m 2 a
30 – T 2 = (3)(2)
30 – T 2 = 6
Isigaba 2 = 30 – 6
I-T 2 = 24 Newton
m 1 iya phezulu
I-T 1 – w 1 = m 1 a
I-T 1 – 20 = (2)(2)
Isigaba 1 – 20 = 4
I-T 1 = 20 + 4
I-T 1 = 24 Newton
Ukuqina kwentambo (T) = 24 amaNewton.
Impendulo efanele ingu-B.
9. Amabhulokhi amabili axhunywe nge-pulley ebushelelezi futhi isisindo se-pulley asinakwa njengoba kuboniswe esithombeni. Isisindo A = m A , isisindo B = m B kanye nebhulokhi B kwehla ngokusheshisa a. Uma ukusheshisa ngenxa yamandla adonsela phansi kungu-g, khona-ke ubukhulu bokucindezelwa kwentambo okwenzeka kubhulokhi B…
A. T = mB.a
B. T = m A (a – g)
C. T = m A (g – a)
D. T = m B (a – g)
E. T = m B (g – a)
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Ubuso obuyisicaba bubushelelezi ngakho-ke awekho amandla okungqubuzana avimbela ukunyakaza kwebhulokhi A. Amandla ashukumisa uhlelo lwebhulokhi isisindo sebhulokhi B.
Bala ukusheshisa kwesistimu:
Bala amandla okucindezela entambo (T):
Cabanga ngokunyakaza kwenye yezinto, isibonelo u-A. U-A uhamba ngakwesokudla.
Faka esikhundleni u-m A ku- equation 1 ku-m A ku- equation 2.
Impendulo efanele ngu-E.
10. Ibhulokhi enesisindo esingu-10 kg ibekwa phansi eliqinile bese idonswa ngamandla avundlile F. Uma i-coefficient of static friction ingu-μs = 0,5 kanye ne-coefficient ye-kinetic friction μk = 0,3. Thola ubukhulu bamandla okungqubuzana lapho ibhlogo selizohamba. (g = 10 m/s2)
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Ibhloko lizohamba ngqo uma ubukhulu bamandla okudonsa = ubukhulu bamandla aphezulu okungqubuzana okungaguquki. Ukungqubuzana okungaguquki kusebenza entweni (kuvimbela ukunyakaza kwento) lapho into idonswa kodwa into ayikakashukumi. Ukungqubuzana okungaguquki kunenani eliphezulu lapho into isizohamba (into ayikashukumi, into icishe ihambe). Ngokuphambene nalokho, ukungqubuzana okungaguquki kusebenza entweni (kuvimbela ukunyakaza kwento) lapho into isivele ihamba.
Kuyaziwa ukuthi:
Umbuzo: Amandla aphezulu okungqubuzana okungaguquki (f)s)?
Impendulo:
Uma into isendaweni eyisicaba njengoba kusesithombeni, ubukhulu bamandla avamile = isisindo sento.
Amandla ajwayelekile (N) = amandla adonsela phansi (w) = amaNewton ayi-100
Ifomula yamandla okungqubuzana okuqinile ephezulu:
I-coefficient ye-kinetic friction ayisetshenziswa ekubalweni.
11. Amabhulokhi amabili axhunywe ngentambo elula edonswa ngamandla avundlile F = 20 N (bheka umfanekiso). Uma g = 10 ms-2 futhi i-coefficient yokungqubuzana kwe-kinetic phakathi kwebhulokhi kanye nobuso ingu-0,1, nquma ubukhulu bokusheshisa kwebhulokhi...
Ingxoxo
Kuyaziwa ukuthi:
Kubuziwe: ukusheshisa (a) kwebhulokhi?
Impendulo:
12. Ibhulokhi A enesisindo esingu-2 kg kanye no-B enesisindo esingu-4 kg zihlelwe njengoba kuboniswe esithombeni. Uma i-coefficient of friction yephansi iphindwe kathathu kune-coefficient of friction yebhulokhi B, ibhulokhi A izohamba ngokusheshisa okungu-5 m/s.-2Ngakho-ke isilinganiso samandla okungqubuzana phakathi kwebhulokhi A kanye nephansi kumabhulokhi A kanye no-B singu… g = 10 m/s2
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Kuyaziwa ukuthi:
Kubuziwe:
Ukuqhathaniswa kwamandla okungqubuzana kwebhulokhi A kanye nephansi (fs A) ngamandla okungqubuzana kwamabhulokhi A no-B (fs B)?
Impendulo:
13. Bheka isithombe ohlangothini! Isisindo sebhulokhi ngayinye singu-m.1 = 2 kg kanye m2 = 3 kg futhi isisindo se-pulley asinakwa. Uma ubuso bendiza bubushelelezi futhi g = 10 ms-2, khona-ke ukusheshisa kohlelo ku ....
A. 0,5 ms-2
B. 2,0 ms-2
C. 2,5 ms-2
D. 4,0 ms-2
E. 6,0 ms-2
Ingxoxo
Kuyaziwa ukuthi:
m1 = 2 kg, m2 = 3 kg, g = 10 ms-2
w2 = m2 g = (3)(10) = 30 kg m/s2 noma amaNewton angu-30
Umbuzo: Ukusheshisa uhlelo (a)?
Impendulo:
14. Into enobunzima ixhunywe ngentambo edlula epulangweni elibushelelezi njengoba kuboniswe esithombeni. Uma u-m1 = 2 kg, m2 = 3 kg kanye no-g = 10 ms-2, khona-ke ubukhulu bamandla okucindezela entambo u-T…
A. 10,2 N
B. 13,3 N
C. 15,5 N
D. 18,3 N
E. 24,0 N
Ingxoxo
Kuyaziwa ukuthi:
m1 = 2 kg, m2 = 3 kg, g = 10 ms-2
w1 = (2)(10) = 20 Newton
w2 = (3)(10) = 30 Newton
Umbuzo: Ubukhulu bamandla okucindezela entanjeni (T) buyini?
Impendulo:
w2 = AmaNewton angu-30 makhulu kuno-w1 = 20 amaNewton ngakho-ke m2 hamba phansi, m1 Hamba uyephezulu.
Ifomula yomthetho wesibili kaNewton:
Amandla okucindezela entambo?
Ngokusho kwesiqondiso sokunyakaza kwesistimu noma isiqondiso sokusheshisa kwesistimu, isiqondiso samandla adonsela phansi m2 phansi, isiqondiso samandla okucindezela intambo ku-m2 phezulu:
w2 - T2 = m2 a
30 - T2 = (3)(2)
30 - T2 = 6
T2 = 30 - 6
T2 = 24 uNewton
Isiqondiso samandla adonsela phansi m1 phansi, isiqondiso samandla okucindezela intambo ku-m1 phezulu:
T1 - w1 = (m1) (a)
T1 – 20 = (2)(2)
T1 - 20 = 4
T1 = 4 + 20
T1 = 24 uNewton
Amandla okucindezela intambo (T) = T1 =T2 = AmaNewton angu-24.
15. Amabhulokhi amabili, ngalinye linesisindo esingu-4 kg, axhunywe ngentambo kanye ne-pulley njengoba kuboniswe esithombeni. Ubuso kanye ne-pulley kubushelelezi. Uma ibhulokhi B lidonswa ngamandla avundlile angu-50 N, ukusheshisa kwebhulokhi kungu… (g = 10 m/s2)
A. 1,25 m/s2
B. 7,5 m/s2
C. 10 m/s2
D. 12,5 m/s2
E. 15 m/s2
Ingxoxo
Kuyaziwa ukuthi:
mA = 4 kg, mB = 4 kg, g = 10 m/s2
wA = (mA)(g) = 4)(10) = 40 Newton
F = 50 Newton
Kubuziwe: ukusheshisa uhlelo?
Impendulo:
Ifomula yomthetho wesibili kaNewton:
Ukusheshisa kwamabhulokhi womabili kungu-1,25 m/s2. Isiqondiso sokunyakaza kwamabhulokhi amabili = isiqondiso samandla okudonsa F.
16. Bheka isithombe ohlangothini! Ubuningi bamabhulokhi bungu-m 1 = 6 kg kanye no-m 2 = 4 kg, kanti ubunzima be-pulley abunakwa. Uma ubuso bendiza bubushelelezi futhi u-g = 10 ms −2 , khona-ke ukusheshisa kwesistimu….
A. 0,5 ms-2
B. 2,0 ms-2
C. 2,5 ms-2
D. 4,0 ms-2
E. 5,0 ms-2
Ingxoxo
Kuyaziwa ukuthi:
m1 = 6 kg, m2 = 4 kg, g = 10 m/s2
w1 = m1 g = (6 kg)(10 m/s2) = 60 kg m/s2 noma amaNewton angu-60
w2 = m2 g = (4 kg)(10 m/s2) = 40 kg m/s2 noma amaNewton angu-40
Kubuziwe: ukusheshisa kwesistimu (a)?
Impendulo:
m1isendaweni ebushelelezi, eyisicaba engenakho ukungqubuzana ukuze uhlelo luqhutshwe yi amandla adonsela phansi ibhlogo 2.
I-Terapkan Umthetho wesibili kaNewton :
∑F = ma
w2 = (m1 +m2) futhi
40 N = (6 kg + 4 kg) a
40 N = (10 kg) a
a = 40 N / 10 kg
a = 4 m/s2
Impendulo efanele ngu-D.
17. Amabhulokhi amabili, ngalinye linesisindo esingu-2 kg, axhunywe ngentambo kanye ne-pulley njengoba kuboniswe esithombeni. Ubuso kanye ne-pulley kubushelelezi. Uma ibhulokhi B lidonswa ngamandla avundlile angu-40 N, ukusheshisa kwebhulokhi kungu… (g = 10 m/s 2 )
A. 5 m/s2
B. 7,5 m/s2
C. 10 m/s2
D. 12,5 m/s2
E. 15 m/s2
Ingxoxo:
Kuyaziwa ukuthi:
mA = mB = 2 kg, g = 10 m/s2, F = 40 N
wA = mg = (2)(10) = 20 N
Umbuzo: ukusheshisa kwebhulokhi (a)?
Impendulo:
Ubuso bebhlokhi bubushelelezi, ngakho-ke amandla athinta ukunyakaza kwebhlokhi kuphela amandla F kanye nesisindo sebhulokhi A.
Sebenzisa umthetho wesibili kaNewton:
∑F = ma
F – wA = (mA +mB) futhi
40 – 20 = (2 + 2) a
20 = (4) a
a = 20/4
a = 5 m/s2
Impendulo efanele ngu-A.
Indiza ethambekele
18. Ibhulokhi enesisindo esingu-2 kg isendaweni ebushelelezi ethambekele nge-engeli yokuthambekela = 30o, ukuze ibhloko lihambe ngokusheshisa okuqhubekayo. Uma g = 10 ms-2, khona-ke ubukhulu bamandla ashukumisa ibhlogo...
A. 5 N
B. 6 N
C. 7 N
D. 8 N
E. 10 N
Ingxoxo
Kuyaziwa ukuthi:
m = 2 kg, g = 10 m/s2, i-theta = 30o
w = mg = (2)(10) = 20 kg m/s2 = 20 uN
Umbuzo: Yimaphi amandla ashukumisa ibhlogo?
Impendulo:
Amandla ashukumisa ibhlogo ngu-wx.
wx = w sin teta
wx = (20 N)(isono 30o)
wx = (20 N)(0,5)
wx = 10 N.
Amandla ashukumisa ibhlogo angamaNewton ayi-10.
Impendulo efanele ngu-E.
19. Amabhulokhi amabili axhunywe ngentambo elula edonswa ngamandla avundlile F = 24 N. g = 10 ms-2 futhi ubuso bephansi buyashelela. Ubukhulu bokusheshisa kwebhulokhi kusetshenziswa umthetho wesibili kaNewton wento ngayinye...
Ingxoxo
Kuyaziwa ukuthi:
m1 = 2 kg, m2 = 4 kg, F = 24 N
Umbuzo: Kuyini ukusheshisa kwebhulokhi (a)?
Impendulo:
Ubukhulu bokusheshisa kwebhulokhi buyi-4 m/s2.
20. Uma use-lifti engashintshi, isisindo sikaSandi singama-N angu-500. Ukusheshisa ngenxa yamandla adonsela phansi = 10 ms-2Uma ilifti ishesha, ukucindezeleka entanjeni kuba ngu-750 N. Ngakho-ke, ukusheshisa ilifti...
A. 5,0 ms-2
B. 7,5 ms-2
C. 10,0 ms-2
D. 12,5 ms-2
I-E. 15,0 ms-2
Ingxoxo
Kuyaziwa ukuthi:
w = 500 N, g = 10 m/s2, T = 750 N
Umbuzo: ukusheshisa i-lifti (a)?
Impendulo:
Isisindo sephasiwedi:
w = mg
500 = m (10)
m = 500/10
m = 50 kg
Isisindo se-lift asikaziwa ngakho-ke isisindo esiphelele se-lift kanye nokuqukethwe kwayo = isisindo sekhodi.
Ngokomthetho wokuqala kaNewton, uma ilifti isalokhu ikhona, amandla aphumela kuyo = 0.
Amandla okucindezela entambo (T) lapho i-lift imile = 500 N.
Uma ilifti ishesha, amandla okucindezela intambo (T) aba ngu-750 N noma anda ngo-250 N.
Ukusheshisa kwe-elevator kungu-5 m/s2 futhi isiqondiso sokusheshisa = isiqondiso sokunyakaza kwe-lifti siphezulu.
Umthombo wombuzo:
Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi
