Isibonelo Sokunyakaza Okuzungezayo

Izibonelo ezimbili zemibuzo yokunyakaza okujikelezayo

1. Into eyisilinda engenalutho (I = mR)²) ukugoqa ngaphandle kokushelela phezulu endizeni ethambekele emangelengeleni ngesivinini sokuqala esingu-10 m/s. Indizeni ethambekele ine-engeli yokuphakama engu-θ ene-tan θ = 0,75. Uma ukusheshisa ngenxa yamandla adonsela phansi g = 10 m/s^-2 futhi ijubane lento lehla laya ku-5 ms^-1 bese ibanga elihanjwa endizeni ethambekele yinto liyi….
A. 12,5 m
B. 10 m
C. 7,5 m
D. 5 m
E. 2,5 m
Ingxoxo
Kuyaziwa ukuthi:
Isikhathi sokungabi namandla kwesilinda esingenalutho (I) = m R²
I-engeli yokuphakama kwendiza ethambekele = θ , lapho i-tangent θ = 0,75 = 75/100 = ngaphambili / phansi
Isono θ = ngaphambili / etshekile = 75/125 = 3/5 = 0,6
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²
Ijubane lokuqala (v)_o) = 10 m/s
Ijubane lokugcina (v)_t) = 5 m/s
Kubuziwe: Ibanga elihanjwe yinto!
Impendulo:
Bala ukuphakama okufinyelelwe yi-cylinder usebenzisa ifomula yomthetho wokulondolozwa kwamandla omshini:

Ukuphakama kokuqala (h)_o) = 0 amamitha
Ijubane lokuqala (v)_o) = 10 m/s
Ijubane lokugcina (v)_t) = 5 m/s
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Isilinda sikhuphukela ukuphakama okungamamitha angu-7,5. Ibanga elihanjwa yisilinda yileli:

Ibanga elihanjwa yi-cylinder lingamamitha ayi-12,5.
Impendulo efanele ngu-A.

Incazelo yefomula:
o = isiqalo, t = okokugcina, EM = amandla omshini, EP = amandla angase abe khona, EK = amandla e-kinetic, m = isisindo, g = ukusheshisa ngenxa yamandla adonsela phansi, h = ukuphakama, v = ijubane eliqondile, ω = ijubane le-angular, I = umzuzu we-inertia, R = irediyasi yesilinda

2. Isilinda esiqinile (I = ½ mR²) enesisindo esingamakhilogremu ama-3 sigingqika ngaphandle kokushelela phezulu indiza ethambekele emangelengeleni enokuphakama okungu-θ kanye ne-sin θ = 0,6. Uma ukusheshisa ngenxa yamandla adonsela phansi g = 10 m/s^-2 futhi ijubane lokuqala lento lingu-10 m/s, bese ubude bendlela ethambekele ehamba ngayo into ngaphambi kokuma bungu....
A. amamitha angu-9,5
B. 10,5 amamitha
C. amamitha ayi-11,5
D. amamitha ayi-12,5
E. amamitha angu-13,5
Ingxoxo
Kuyaziwa ukuthi:
Isikhathi sokungabi namandla kwesilinda esiqinile (I) = ½ m R²
Isisindo sesilinda = 3 kg
Ijubane lokuqala (v)_o) = 10 m/s
Ijubane lokugcina (v)_t) = 0 m/s (ukuyeka kwezinto)
I-engeli yokuphakama kwendiza ethambekele (θ) = θ, lapho i-sin θ = 0,6 = 6/10 = ngaphambili/ekuthambekeni
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²
Kubuziwe: Ubude bendlela ehanjwe yinto ngaphambi kokuma!
Impendulo:
Bala ukuphakama okufinyelelwe yi-cylinder usebenzisa ifomula yomthetho wokulondolozwa kwamandla omshini:

Ukuphakama kokuqala (h)_o) = 0 amamitha
Ijubane lokuqala (v)_o) = 10 m/s
Ijubane lokugcina (v)_t) = 0 m/s (ukuyeka kwezinto)
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²

Isilinda sikhuphukela ukuphakama okungamamitha angu-7,5.

Ibanga elihanjwa yi-cylinder:

Ibanga elihanjwa yi-cylinder lingamamitha ayi-12,5.
Impendulo efanele ngu-D.

Umthombo wombuzo:

Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi