Izibonelo ezi-5 zemibuzo engaba khona yamandla
Amandla Adonsela Phansi
1. Ama-Joules angu-4.900 wamandla asetshenziswa ukuphakamisa into enesisindo esingu-50 kg iqonde phezulu. Into izophakama ifike kubude obungu-... (g = 9,8 m/s).-2 )
A. 0,1 m
B. 10 m
C. 98 m
D. 245 m
E. 960 m
Ingxoxo
Kuyaziwa ukuthi:
Ushintsho emandleni angase abe khona (ΔEP) = 4900 Joules
isisindo sento (m) = 50 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 9,8 m/s2
Kubuziwe: Into izophakama ifinyelele ukuphakama (Δh)
Impendulo:
ΔEP = mg Δh
4900 = (50)(9,8) Δh
Δh = amamitha ayi-10
Impendulo efanele ingu-B.
Amandla Angase Abe Sentwasahlobo
2. Igrafu elandelayo ikhombisa ubudlelwano phakathi kuka-F (amandla) no-x (ukwanda kobude) besiphethu. Uma isiphethu sihlanekezelwe ngo-8 cm, khona-ke amandla angase abe khona esiphethu...
A. 1,6 × 10-5 Joule
B. 6,4 × 10-4 Joule
C. 8 Joule
D. 16 Joule
E. 128 AmaJoule
Ingxoxo
Kuyaziwa ukuthi:
Amandla (F) = 2 Newton
Ukwanda kobude (x) = 1 cm = 1/100 imitha = 0,01 imitha
Ukuphambuka kwentwasahlobo = 8 cm = 8/100 amamitha = 0,08 amamitha
Kubuziwe: Amandla angase abe khona entwasahlobo
Impendulo:
Sebenzisa idatha ekugrafu ukuze ubale i-spring constant.
Amandla angaba khona entwasahlobo:
∆I-EP = 1/2 kx2
∆I-EP = 1/2 (200 N/m)(0,08 m)2
∆I-EP = (100 N/m)(0,0064 m2)
∆I-EP = 0,64 Nm
3. Phakathi kwezimo ezilandelayo:
(1) Irabha yeslingshot enwetshiwe
(2) I-pendulum ephambukile
(3) Insimbi eshisayo
Izinto ezinamandla angase zibe nezinombolo...
A. (1)
B. (1) kanye no-(2)
C. (2)
D. (2) kanye (3)
E. (3)
Ingxoxo
(1) Irabha yeslingshot enwetshiwe
Uma iluliwe, irabha yeslingshot inamandla anwebekayo.
(2) I-pendulum ephambukile
Uma i-pendulum iphambukile, i-pendulum inamandla adonsela phansi.
Impendulo efanele ingu-B.
4. Ithebula elingezansi libonisa imiphumela yokuhlolwa okuhilela isipilingi esinomthwalo ofakwe ekugcineni. U-F umele isisindo somthwalo kanti u-ΔL umele ukwanda kobude. Bala umsebenzi odingekayo ukuze kwandiswe isipilingi ngo-10 cm.
A. 2,0 Joule
B. 2,5 Joule
C. 5,0 Joule
D. 7,6 Joule
E. 10 ama-joule
Ingxoxo
Kuyaziwa ukuthi:
Ukwanda kobude bentwasahlobo (∆L) = 10 cm = 0,1 amamitha
Kubuziwe: Umzamo wokwandisa intwasahlobo ngo-10 cm
Impendulo:
Sebenzisa idatha ethebulani ukuze ubale i-spring constant:
k = F / ∆x = 20 N / 0,04 m = 500 N/m
k = F / ∆x = 30 N / 0,06 m = 500 N/m
k = F / ∆x = 40 N / 0,08 m = 500 N/m
I-spring constant ingu-500 N/m
Umzamo wokwandisa intwasahlobo ngo-10 cm umi kanje:
W = 1/2 k ∆L2 = 1/2 (500 N/m)(0,1 m)2 = (250 N/m)(0,01 m2) = 2,5 amamitha amaNewton = 2,5 amaJoules.
Impendulo efanele ingu-B.
5. Igrafu (Fx) ikhombisa ubudlelwano phakathi kwamandla nokwanda kobude bentwasahlobo. Amandla angaba khona entwasahlobo asekelwe kugrafu engenhla…
A. Ama-joule angu-20
B. ama-joule ayi-16
C. 3,2 ama-joule
D. 1,6 ama-joule
E. 1,2 ama-joule
Ingxoxo
I-Diketahui :
F = 40 Newton
Δx = amamitha angu-0,08
Kubuziwe Amandla angaba khona entwasahlobo?
Jawab :
I-constant yasentwasahlobo:
k = F / Δx
Amandla angaba khona entwasahlobo:
I-EP = ½ k Δx2 = ½ (F/Δx) Δx2 = ½ F Δx
I-EP = ½ (40)(0,08) = (20)(0,08) = 1,6 Ama-Joules
Impendulo efanele ngu-D.
Umthombo wombuzo:
Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi
