Isibonelo samandla anwebekayo esiphethu

Izibonelo ezi-5 zemibuzo ngamandla anwebekayo eziphethu

1. Isipilingi sinikezwa umthwalo ongama-2 kg bese silenga siqonde phezulu esitendini. Uma isipilingi sikhula ngo-4 cm, khona-ke ushintsho ku- amandla angase abe khona Amandla okunwebeka entwasahlobo angu… g = 10 m/s²
Ingxoxo
I-Diketahui :
Isisindo somthwalo (m) = 2 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²
Isisindo somthwalo (w) = mg = (2)(10) = 20 Newton
Ukwanda kobude bentwasahlobo (x) = 4 cm = 0,04 amamitha
Kubuziwe : Amandla anamandla okunwebeka entwasahlobo
Jawab :
Ifomula Umthetho kaHooke yi-F = kx, lapho u-F = amandla, u-k = ukungaguquguquki kwentwasahlobo kanye no-x = ​​ukwanda kobude bentwasahlobo. Uma kuvunyelwana nale nkinga, ifomula yomthetho kaHooke ishintshwa ibe yi-w = kx, lapho u-w = amandla adonsela phansiUkuze ubale i-spring constant, shintsha ifomula yomthetho kaHooke ibe yi-k = w / x. Ngakho i-spring constant ingu-k = w / x = 20 / 0,04 = 500 Newton/meter.
Ushintsho emandleni okunwebeka kwentwasahlobo luyi:
I-EP = ½ kx² = ½ (500)(0,04)² = (250)(0,0016) = 0,4 amaJoules

Ushintsho emandleni anamandla okunwebeka esiphethwini lungabalwa kusetshenziswa ifomula eyodwa:
I-EP = ½ kx² = ½ (w / x) x² = ½ wx = ½ mgx
Incazelo: w = amandla esisindo somthwalo, m = isisindo somthwalo, x = ushintsho kubude besiphethu.
I-EP = ½ (2)(10)(0,04) = (10)(0,04) = 0,4 Ama-Joules.

2. Ukuze welule isiphethu esingu-10 cm, kudingeka amandla angu-50 N. Amandla anwebekayo adingekayo ukuze welule isiphethu esingu-12 cm…
Ingxoxo
I-Diketahui :
Ukwanda kobude bentwasahlobo (x) = 10 cm = 0,1 amamitha
Amandla (F) = 50 Newton
Kubuziwe : amandla anamandla okunwebeka entwasahlobo ukuze kwelulwe intwasahlobo kuze kufike ku-12 cm noma amamitha angu-0,12.
Jawab :
I-spring constant yile:
k = F / x = 50 / 0,1 = 500 Newtons/meter
Intwasahlobo esetshenzisiwe iyafana, ngakho-ke i-spring constant etholwe ekubalweni kwangaphambilini isetshenziselwa ukubala amandla anamandla okunwebeka entwasahlobo ukuze kwelulwe intwasahlobo ngamamitha angu-0,12.
I-EP = ½ kx² = ½ (500)(0,12)² = (250)(0,0144) = 3,6 amaJoules.

3. Igrafu engezansi ikhombisa ubudlelwano phakathi kwamandla (F) kanye nokwanda kobude bentwasahlobo (x). Uma intwasahlobo iphambukile ngo-10 cm, khona-ke amandla anamandla okunwebeka entwasahlobo…

Ingxoxo
I-Diketahui :
Amandla (F) = 5 Newton
Ukwanda kobude bentwasahlobo (x) = 2 cm = 0,02 amamitha
Kubuziwe : amandla angaba khona entwasahlobo uma intwasahlobo iphambukile ngamasentimitha ayi-10 noma amamitha angu-0,1.
Jawab :
I-constant yasentwasahlobo:
k = F / x = 5 / 0,02 = 250 Newtons/meter
Amandla angaba khona entwasahlobo uma intwasahlobo iphambukile ngamamitha angu-0,1:
I-EP = ½ kx² = ½ (250)(0,1)² = (125)(0,01) = 1,25 amaJoules.

Amandla Anganwebeka Anganwebeka
4. Isipilingi sinikezwa umthwalo ongama-2 kg njengoba kuboniswe esithombeni esilandelayo. Uma isipilingi sithola ukwanda kobude obungama-5 cm kanye ukusheshisa ngenxa yamandla adonsela phansi umhlaba 10 ms^-2, khona-ke amandla anamandla okunwebeka entwasahlobo...
A. 4,0 J
B. 3,0 J
C. 2,5 J
D. 1,0 J
E. 0,5 J
Ingxoxo
I-Diketahui :
Ukwanda kobude (Δx) = 5 cm = 0,05 amamitha
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s²
Isisindo somthwalo (m) = 2 kg
Isisindo somthwalo (w) = mg = (2)(10) = 20 Newton
Kubuziwe Amandla angaba khona erabha?
Jawab :
Okokuqala, bala i-elastic constant yesipringi usebenzisa ifomula yomthetho kaHooke:
k = w / Δx = 20 / 0,05 = 400 N/m
Amandla anamandla okunwebeka entwasahlobo yilawa:
I-EP = ½ k Δx² = ½ (400)(0,05)² = (200)(0,0025)
I-EP = ama-Joule ayi-0,5
Impendulo efanele ngu-E.

5. Ukuze welule isiphethu esingu-5 cm, kudingeka amandla angu-20 N. Amandla angaba khona esiphethu uma selulela ku-10 cm…
A. 2 Joule
B. 4 Joule
C. 20 Joule
D. 50 Joule
E. 100 AmaJoule
Ingxoxo
I-Diketahui :
Ukwanda kobude (Δx) = 5 cm = 0,05 amamitha
Amandla (F) = 20 Newton
Kubuziwe : I-EP yentwasahlobo lapho intwasahlobo inwebeka ngo-10 cm?
Jawab :
I-constant yasentwasahlobo:
k = F / Δx = 20 / 0,05 = 400 N/m
Amandla angaba khona entwasahlobo lapho i-Δx = 10 cm = 0,1 amamitha:
I-EP = ½ k Δx² = ½ (400)(0,1)² = (200)(0,01)
I-EP = ama-Joule ayi-2
Impendulo efanele ngu-A.