Izibonelo Ezi-6 Zemibuzo Yamandla Emishini
Ithiyori yomsebenzi-wamandla wemishini
1. Naka isithombe ukufuduka vimba kanje! Cabanga ukuthi g = 10 m/s2Uma i-coefficient yokungqubuzana kwe-kinetic phakathi kwebhulokhi kanye nephansi μk = 0,5, khona-ke inani lokufuduka kwento lingu- ….
A. 5,00 m
B. 4,25 m
C. 3,00 m
D. 2,50 m
E. 2,00 m
Ingxoxo
I-Diketahui :
I-coefficient yokungqubuzana kwe-kinetic (μk) = 0,5
Isisindo sebhulokhi (m) = 4 kg
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s2
Isisindo sebhulokhi (w) = mg = (4)(10) = 40 Newton
Uma ibhloko lisesicaba, khona-ke amandla avamile (N) = isisindo (w) = amaNewton angu-40.
Ijubane lokuqala (v)1) = 5 m/s
Ijubane lokugcina (v)2) = 0 m/s
Kubuziwe : ukufuduka kwezinto (izinto)?
Jawab :
Ithiyori yamandla okusebenza-okusebenza ithi umsebenzi (W) owenziwa amandla angewona awokugcina ulingana noshintsho emandleni okusebenza ento noma emandleni okugcina okusebenza (EM).2) – amandla okuqala omshini (EM)1). Ukungqubuzana kwe-kinetic kungamandla angewona awokugcina futhi amandla angewona awokugcina asebenza ebhulokini ukungqubuzana kwe-kinetic.
W= ΔEM
fk s = EM2 – I-EM1
Umsebenzi owenziwe nge-kinetic friction:
W = fk s = (μk)(N)(s) = (0,5)(40)(s) = 20 s
Izinguquko emandleni omshini:
ΔI-EM = I-EM2 – I-EM1 = (EK + EP)2 – (EK + EP)1
Izinto zihamba endaweni eyisicaba futhi aziboni izinguquko ekuphakameni (Δh = 0) ngakho-ke akukho ushintsho emandleni adonsela phansi (ΔI-EP = I-EP2 – EP1 = 0). Ngakho-ke ushintsho lwamandla omshini luhilela kuphela ushintsho lwamandla okunyakaza.
ΔEM = EK2 – EK1 = ½ mv22 – ½ mv12 = ½ m (v22 - v12)
ΔI-EM = ½ (4)(02 - 52) = (2)(25) = 50
Ukufuduka kwebhulokhi yilokhu:
W= ΔEM
Amasekhondi angu-20 = 50
s = 50 / 20 = amamitha angu-2,5
Impendulo efanele ngu-D.
Umthetho wokulondolozwa kwamandla emishini
2. Izinto u-A no-B zinesisindo esifanayo. Into u-A iwela kusuka ekuphakameni kwamamitha angu-h kanti u-B uwela kusuka kumamitha angu-2. Uma u-A eshaya phansi ngesivinini se-vm/s, khona-ke into u-B izoshaya phansi ngamandla e-kinetic angu….
A. 2 mv2
B. mv2
C. 3/4 mv2
D. 1/2 mv2
E. 1/4 mv2
Ingxoxo
Isivinini sokugcina sento B esiwela ngokukhululeka sisuka ekuphakameni kwamahora ama-2 yilesi:
v2 = 2 g (amahora ama-2) = 4 gh
Amandla e-kinetic ento B yilawa:
EKB = ½ mv2 = ½ m (4 gh) = 2 mgh —– Isibalo 1
Amandla okuqala omshini ento B amandla adonsela phansi = mg h. Amandla okugcina omshini ento B amandla omshini = ½ mv2.
Umthetho wokulondolozwa kwamandla emishini :
mgh = ½ mv2.
UKarena mgh = ½ mv2 bese singashintsha i-mgh ku-equation 1 nge-½ mv2.
Amandla e-kinetic ento B = 2 mgh = 2(½ mv)2) = mv2
Impendulo efanele ingu-B.
3. Bheka isithombe esingezansi! Into iwela ngokukhululeka isuka ekuphakameni okungamamitha angu-20. Uma ukusheshisa okubangelwa amandla adonsela phansi kungu-10 m/s, khona-ke ijubane lento uma ingaphezu komhlabathi ngamamitha angu-15 li….
A. 2 m/s
B. 5 m/s
C. 10 m/s
D. 15 m/s
E. 20 m/s
Ingxoxo
Amandla okugcina omshini = amandla okuqala omshini
Amandla e-kinetic ento ephuzwini lesi-2 = ukwehla kwamandla adonsela phansi ngamamitha ama-5
½ mv2 = mgh
½ v2 = (10)(20-15)
½ v2 = (10)(5)
½ v2 = 50
v2 = (2)(50)
v2 = 100
v = 10 m/s
Impendulo efanele ngu-C.
4. Ibhulokhi libanjwe phezulu kwendiza ethambekele njengoba kuboniswe esithombeni. Uma likhishwa, ibhulokhi lishelela ngaphandle kokushayisana eduze kokwenyuka. Isivinini sebhulokhi uma sifika phansi kokwenyuka…
B. 8 ms-1
C. 10 ms-1
D. 12 ms-1
E. 16 ms-1
Ingxoxo
Amandla okuqala omshini = amandla adonsela phansi = mgh = m (10)(5) = 50 m
Amandla okugcina omshini = amandla e-kinetic = 1/2 mv2
Umthetho wokulondolozwa kwamandla omshini uthi amandla okuqala omshini = amandla okugcina omshini.
EMo = I-EMt
50 m = 1/2 mv2
50 = 1/2 v2
100 = v2
v = 10 m/s
Impendulo efanele ngu-C.
5. Ibhulokhi enesisindo esingu-m kg ikhishwa ekuphakameni kwamamitha angu-h ngaphezu komhlabathi njengoba kuboniswe esithombeni. Isilinganiso samandla angase abe khona (EP) kanye namandla e-kinetic (EK) uma sisephuzwini elingu-M….
A. 1: 3 
B. 1: 2
C. 2: 1
D. 2: 5
Isahluko 3: 7
Ingxoxo
Amandla adonsela phansi endaweni M:
EPM = mg (amahora angu-0,3)
Amandla e-kinetic endaweni ethi M = ukwehla kwamandla adonsela phansi ngo-h-0,3h = 0,7h
EKM = EP = mg (amahora angu-0,7)
Isilinganiso samandla adonsela phansi kanye namandla e-kinetic endaweni ethi M yilesi:
EPM : EKM
mg (0,3 h): mg (0,7 h)
0,3: 0,7
3: 7
Impendulo efanele ngu-E.
6. Bheka isithombe sento A iwela ngokukhululeka kusuka endaweni P ngezansi!
Uma i-EPQ kanye ne-EKQ ngalinye liyi-potential energy kanye ne-kinetic energy endaweni ethi Q (g = 10 m/s2), bese kuba yi-EPQ : EKQ kuyinto….
A. 16: 9
B. 9: 16
C. 3: 2
D. 2: 3
Isahluko 2: 1
Ingxoxo
Amandla adonsela phansi endaweni ethi Q:
EPQ = mgh = (m)(10)(1,8) = 18 m
Amandla e-kinetic endaweni ethi Q = ukwehla kwamandla adonsela phansi ngo-5-1,8 = amamitha angu-3,2
EKQ = EP = mgh = m (10)(3,2) = 32 m
Isilinganiso samandla adonsela phansi kanye namandla e-kinetic endaweni ethi Q yilesi:
EPQ : EKQ
18 m : 32 m
18: 32
9: 16
Umthombo wombuzo:
Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi
