1.
Gẹ́gẹ́ bí a ṣe rí i lórí tábìlì tó wà lókè yìí, wá R àti P.
ojutu
Ìbáṣepọ̀ Transformer:
Vs Np = Ns Vp ati Vp Ip = Vs Is
Vs = secondary voltage, Vp = primary folitejiNs = secondary loops, Np = primary loops, Ip = primary lọwọlọwọ, Mos = secondary current
Fóltéèjì àkọ́kọ́ (V)p)
Vp Ip = Vs Is
Vp (4) = (10)(80)
Vp = 800/4
Vp = R = 200 Volt
Àwọn ìlù kejì (N)s)
Vs Np = Ns Vp
(10)(600) = Ns (200)
6000 = 200 Ns
Ns = 6000/200
Ns = P = 30 loops
2.
Based on the above table, find K and L.
Ojutu:
Secondary current (Is) of transformer 1 :
Vp Ip = Vs Is
(200)(3) = (300)(Is)
Is = 600/300
Is = K = 2 A
Fóltéèjì kejì (V)s) ti Amunawa 2:
Vp Ip = Vs Is
(40)(0,75) = Vs (1)
Vs = L = 30 Volt
3.
Based on the table above, find P and Q.
Ojutu:
Fóltéèjì àkọ́kọ́ (V)p)
Vs Np = Ns Vp
(220)(300) = (600) Vp
(220)(3) = (6) Vp
660 = 6 Vp
Vp = 660/6
Vp = P = 110 Volt
Primary current (Ip)
Vp Ip = Vs Is
(110)(Ip) = (220)(2)
(110)(Ip) = 440
Ip = 440/110
Ip = Q = 4 A
