Intshukumo ejikelezayo engalinganiyo - iingxaki kunye nezisombululo

1. Ivili eliyimitha e-1 kwiradiyumu likhawuleza ngokulinganayo kwi-2 rad/s2. Misela i ukukhawulezisa iiangular kwaye i isantya se-angular yevili, emva kwemizuzwana emi-2.

Yaziwa:

Irediyasi (r) = 1 imitha

Ukukhawulezisa kwe-angular (α)) = 2 rad/s2

Ufuna: ukukhawulezisa kwe-angular kunye nesantya se-angular emva kwemizuzwana emi-2.

Isisombululo:

(a) Ukukhawulezisa kwe-angular kwimizuzwana emi-2

Ukukhawulezisa kwe-angular kuhlala kuhleli, ngoko ke emva kwemizuzwana emi-2, ukukhawulezisa kwe-angular kwevili yi-2 rad/s2.

(B) Isantya se-angular kwimizuzwana emi-2

Ukukhawulezisa kwe-angular 2 rad/s2 kuthetha ukuba isantya se-angular sonyusa iiradians ezi-2/isekhondi rhoqo emva kwesekhondi e-1. Emva kwesekhondi e-1, isantya se-angular = iiradians ezi-2/isekhondi. Emva kwemizuzwana emi-2, isantya se-angular = iiradians ezi-4/isekhondi.

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2. Isuntswana likhawuleza ngokulinganayo ukusuka ekuphumleni ukuya kwi-60 rpm kwimizuzwana eli-10. Chonga ubungakanani bokukhawulezisa kwe-angular!

Yaziwa:

Isantya sokuqala se-angular (ωo= 0

Isantya sokugqibela se-angular (ωt) = 60 rpm = iirevolutions ezingama-60 / imizuzwana engama-60 = ujikelezo olu-1 / isekhondi = iiradians eziyi-6,28/isekhondi

Ixesha eliphakathi (t) = imizuzwana eli-10

Ifunwa: Ukukhawulezisa kwe-angular (α)

Isisombululo:

Iintshukumo ezijikelezayo ezingalinganiyo - iingxaki kunye nezisombululo 1

ωo = isantya sokuqala se-angular, ωt = isantya sokugqibela se-angular, α = ukukhawulezisa kwe-angular, t = ixesha eliphakathi, θ = i-engile.

ωt = ωo + α t

6.28 = 0 + α (10)

6.28 = 10 α

α = 6.28/10

α = 0.628 rad/s2

Ubukhulu bokukhawuleziswa kwe-angular = 0.628 rad/s2

3. Into iyancipha ukusuka kwi-20 rad/s ukuya kwi-10 rad/s kwimizuzwana emi-4. Fumana ubungakanani bokukhawuleziswa kwe-angular!

Yaziwa:

Ixesha eliphakathi (t) = imizuzwana eli-4

Isantya sokuqala se-angular (ωo ) = 20 rad/s

Isantya sokugqibela se-angular (ωt) = 10 rad/s

wayefuna : ubukhulu bokukhawulezisa kwe-angular (α)

Isisombululo:

ωt = ωo + α t

10 = 20 + α (4)

10 - 20 = 4 α

-10 = 4 α

α = -10 / 4

α = – 2.5 rad/s2

Ubukhulu bokukhawuleziswa kwe-angular yi--2.5 rad/s2Uphawu olunegative luthetha ukuba into iyacotha. Ukukhawulezisa = isantya se-angular siyanda, ukucotha = isantya se-angular siyancipha.

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4. Into ikhawuleziswa imizuzwana emi-2 ukusuka kwi-10 rad/s ukuya kwi-2 rad/s2Chonga i-engile ejikelezwe yinto!

Yaziwa:

isantya sokuqala se-angular (ωo ) = 10 rad/s

ukukhawuleziswa kwe-angular (α) = 2 rad/s2

ixesha eliphakathi (t) = imizuzwana emi-2

Ifunwa: i-engile (θ)

Isisombululo:

θ = ωo + ½ α t2

θ = (10)(2) + ½ (2)(22)

θ = 20 + (1)(4) = 20 + 4

θ = iirediyani ezingama-24

5. Ivili lemoto liyehla ukusuka kwi-20 rad/s ukuya kuthi ga emva kwee-radians ezijikeleze i-20. Fumana ubungakanani bokukhawuleziswa kwevili nge-angular!

Yaziwa:

isantya sokuqala se-angular (ωo) = 20 rad/s

isantya sokugqibela se-angular (ωt= 0

Iengile (θ) = iiradiyani ezingama-20

Ifunwa: ubukhulu bokukhawuleziswa kwe-angular (α)

Isisombululo:

ωt2 = ωo2 + 2 α θ

0 = 202 + 2 α (20)

0 = 400 + 40 α

400 = – 40 α

α = – 400 / 40

α = – 10 rad/s2

6. I-rod PQ enobude obuyi-60 cm ijikeleza malunga nenqaku Q njenge-axis yokujikeleza kunye ne-PQ njenge-radius yesangqa. I-rod PQ ikhawuleza ukusuka ekuphumleni ukuya kwi-0.3 rad/s2Ithini isantya esithe ngqo senqaku P kwi-t = imizuzwana eli-10, ukuba indawo yokuqala ye-angular yi-0.

Yaziwa:

Ubude bentonga ye-PQ = irediyasi yesangqa (r) = 60 cm = 60/100 m = 0.60 m

Isantya sokuqala se-angular (ωo) = 0 rad/s

Ukukhawulezisa kwe-angular (α) = 0.3 rad s-2

Indawo yokuqala ye-angular (θo= 0

Ifunwa: Isantya esithe ngqo (v) senqaku P kwi-t = imizuzwana eli-10

Isisombululo:

Isantya sokugqibela se-angular emva kwemizuzwana eli-10:

ωt = ωo + α t = 0 rad/s + (0.3 rad s-2)(10 s) = 3 rad/s

Isantya sokugqibela esithe ngqo emva kwemizuzwana eli-10:

v = r ω = (0.6 m)(3 rad/s) = 1.8 m/s

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7. Into ijikeleza ngesantya sokuqala se-4 rad/s kwaye i-angular acceleration yi-0.5 rad/s2Ingakanani isantya sento emva kwemizuzwana emi-4?

Yaziwa:

Isantya sokuqala se-angular (ωo) = 4 rad/s

Ukukhawulezisa kwe-angular (α) = 0.5 rad/s2

Ixesha eliphakathi (t) = imizuzwana eli-4

Ifunwa: Isantya sento emva kwemizuzwana emi-4 (ωt)

Isisombululo:

ωt = ωo + α t

ωt = 4 + (0.5)(4)

ωt = 4 + 2

ωt = 6 rad/s

8. A Iwotshi yodonga enobubanzi obuyi-10 cm ineenaliti ezintathu, nganye ibonisa iiyure, imizuzu kunye nemizuzwana. Uthelekiso lwenani leemijikelo zenaliti yeyure: inaliti yomzuzu: inaliti yesibini.

A. 1: 3: 180

B. 1: 12: 720

C. 4 : 12 : 180

D. 4 : 12 : 720

Yaziwa:

Iyure e-1 = imizuzu engama-60

Iiyure ezili-12 = (12)(imizuzu engama-60) = imizuzu engama-720

Isantya se-angular senaliti yeyure = umjikelo o-1 / iiyure ezili-12 = umjikelo o-1 / imizuzu engama-720

Isantya se-angular senaliti yemizuzu = ukujikeleza oku-1 / iyure e-1 = ukujikeleza oku-1 / imizuzu engama-60

Isantya se-angular senaliti yesibini = ukujikeleza oku-1 / umzuzu o-1

Ufuna: Uthelekiso lwenani leemijikelo zenaliti yeyure: inaliti yomzuzu: inaliti yesibini

Isisombululo:

I-equation yentshukumo ejikelezayo:

Isantya se-angular = inani leenguqu / ixesha eliphakathi

Inani leenguqu = isantya se-angular x ixesha eliphakathi

Kwixesha elifanayo, umzekelo, umzuzu o-1, zingaphi iinguqu zenaliti yeyure, inaliti yemizuzu, kunye nenaliti yesibini.

Inani leenguqu zenaliti yeyure = isantya se-angular x ixesha eliphakathi = (umjikelo o-1 / imizuzu engama-720) (umzuzu o-1) = iinguqu eziyi-1/720

Inani leenguqu zenaliti yemizuzu = isantya se-angular x ixesha eliphakathi = (umjikelo o-1 / imizuzu engama-60) (umzuzu o-1) = iinguqu eziyi-1/60

Inani leenguqu zenaliti yesibini = isantya se-angular x ixesha eliphakathi = (umjikelo o-1 / umzuzu o-1)(umzuzu o-1) = umjikelo o-1/1

Uthelekiso lweenguqu ezininzi:

Inani leenguqu zenaliti yeyure: inani leenguqu zenaliti yemizuzu: inani leenguqu zenaliti yesibini.

1/720: 1/60: 1/1

1/720: 12/720: 720/720

1: 12: 720

Impendulo echanekileyo ngu-B.

9. Ibhola ebotshelelwe ngentambo. Ibhola iyajikeleziswa ukuze ihambe ngendlela ejikelezayo ehambelana nomphezulu womhlaba. Kule ntshukumo, ibhola iyakhawuleza kuba…..

A. Ukuqulunqa yomoya

B. ubunzima yebhola

C. Amandla oxinzelelo

D. Amandla womxhuzulane

Isisombululo:

Umthetho wesibini wesindululo sikaNewton ithi into ikhawuleziswa ukuba kukho amandla avelayo. Ibhola iqhagamshelwe kwintambo kwaye xa intambo ijikeleza, nebhola iyajikeleza. Xa ibhola ijikeleza (ibhola ihamba ngesangqa), ibhola idlula kwi-centripetal acceleration. Zonke izinto ezihambayo ziyi-circular centripetal acceleration. Ukukhawulezisa okuphakathi kubangelwa amandla asecentripetalAmandla asembindini kweli tyala ngamandla oxinzelelo.

Impendulo echanekileyo nguC.

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  1. Iingxaki zesampulu zokuguqula iiyunithi ze-engile ngezisombululo
  2. Iingxaki zesampulu zokufuduka kwe-angular kunye nesampulu yokufuduka ethe tye kunye nezisombululo
  3. Iingxaki zesampuli zesantya se-angular kunye nesantya esithe ngqo kunye nezisombululo
  4. Iingxaki zesampulu zokukhawulezisa ze-angular kunye nesampulu yokukhawulezisa ethe tye enezisombululo
  5. Iingxaki zesampuli zeentshukumo ezijikelezayo ezifanayo kunye nezisombululo
  6. Iingxaki zesampulu yokukhawulezisa iCentripetal kunye nezisombululo
  7. Iingxaki zesampuli zeentshukumo ezijikelezayo ezingalinganiyo kunye nezisombululo

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