Parallel rezistor muammolariga misol

Parallel rezistor muammolarining 4 ta misoli

Shuningdek, materialni o'rganing Parallel rezistorlar dan Ketma-ket rezistorli muammolarga misol, Elektr qarshiligi bo'yicha savollarga misol

1. Ma'lumki, R.₁ = 2 Ω va R₂ = 4 Ω parallel ulangan. O'rinbosar rezistorning qiymati qancha? (Ω = Oh).

Munozara

1/R = 1/R₁ + 1/R₂ = 1/2 + 1/4 = 2/4 + 1/4 = 3/4

R = 4/3 Ω

O'zgartirish qarshiligining qiymati ketma-ket ulangan har bir rezistorning qiymatidan katta.

2. R.₁ = 1 Ω, R₂ = 2 Ω, R₃ = 3 Ω. O'zgartirish rezistorining qiymati…..

Munozara

1/R = 1/R₁ + 1/R₂ + 1/R₃ = 1/1 + 1/2 + 1/3 = 6/6 + 3/6 + 2/6 = 11/6

R = 6/11 Ω.

3. R.₁ = 4 Ω, R₂ = 2 Ω, V = 12 Volts. (a) almashtirish rezistorining qiymatini aniqlang (b) Elektr toki zanjirda oqayotgan elektr toki (c) R rezistordan o'tayotgan₁ dan R₂

Munozara

(a) O'zgartirish rezistori

1/R = 1/R₁ + 1/R₂ = 1/4 + 1/2 = 1/4 + 2/4 = 3/4

R = 4/3 Ω.

(b) Zanjirdagi elektr toki

I = V / R = 12: 4/3 = 12 x 3/4 = 9 Amper

(c) Rezistor orqali o'tadigan elektr toki R₁ va R₂

R ning ikkala uchidagi potentsiallar farqi₁ = R ning ikkala uchidagi potensiallar farqi₂ = 12 Volt.

I₁ = V / R₁ = 12 / 4 = 3 Amper

I₂ = V / R₂ = 12 / 2 = 6 Amper

Bu natija mos keladi Kirxgoffning birinchi qonuni :

Men = Men₁ + I₂

9 A = 3 A + 6 A

4. R₁ = 2 Ω, R₂ = 4 Ω, R₃ = 6 Ω, R₄ = 8 Ω, V = 12 Volts. Aniqlang (a) O'zgartirish rezistorining qiymati (b) Zanjirda oqayotgan elektr toki (c) R rezistoridan o'tayotgan elektr toki₂ (d) R rezistorining ikkala uchidagi elektr kuchlanishi₄.

Munozara

(a) O'zgartirish rezistori

1/R = 1/R₁ + 1 /R₂ + 1/R₃ + 1/R₄ = 1/2 + 1/4 + 1/6 + 1/8 = 12/24 + 6/24 + 4/24 + 3/24 = 25/24

R = 24/25 Ω

(b) Zanjirdan o'tadigan elektr toki

I = V / R = 12 : 24/25 = 12 x 25/24 = 1 x 25/2 = 12,5 Aimperator

(c) R rezistordan o'tadigan elektr toki_1, R₂, R₃, R₄

R ning ikkala uchidagi potentsiallar farqi₁ = R ning ikkala uchidagi potensiallar farqi₂ = R ning ikkala uchidagi potensiallar farqi₃ = R ning ikkala uchidagi potensiallar farqi₄ = 12 Volt.

I₁ = V / R₁ = 12 / 2 = 6 Amper

I₂ = V / R₂ = 12 / 4 = 3 Amper

I₃ = V / R₃ = 12 / 6 = 2 Amper

I₄ = V / R₄ = 12 / 8 = 1,5 Amper

Bu natija Kirxgoffning birinchi qonuniga mos keladi:

Men = Men₁ + I₂

12,5 A = 6 A + 3 A + 2 A + 1,5 A

(D)

R ning ikkala uchidagi potentsiallar farqi₁ = R ning ikkala uchidagi potensiallar farqi₂ = R ning ikkala uchidagi potensiallar farqi₃ = R ning ikkala uchidagi potensiallar farqi₄ = 12 Volt.