1.
Tukuyin ang kuryente sa sirkito (1 µF = 10-6 F)
Kilala:
risistor (R) = 12 Ohm
Inductor (L) = 0.075 H
Kapasitor (C) = 500 µF = 500 x 10-6 F = 5 x 10-4 Farad
Voltage (V) = Vo sin ωt = vo sin 2πft = 26 sin 200t
Hinahanap: Electric kasalukuyang
solusyon:
Impedance (Z) :
The inductive reactance (XL) = ωL = (200)(0,075) = 15 Ohm
The capacitive reactance (XC) = 1 / ωC = 1 / (200)(5 x 10-4) = 1 / (1000 x 10-4) = 1 / 10-1 = 101 = 10 Ohm
Resistor (R) = 12 Ohm
Electric current (I) :
I = V / Z = 26 Boltahe / 13 Ohms
I = 2 Boltahe/Ohm
I = 2 Amp
2. If the impedance of the circuit is 250 Ω, determine the resistance of resistor R.
Kilala:
The impedance of the circuit (Z) = 250 Ω
Capacitor (C) = 8 m F = 8 x 10-6 F
Inductor (L) = 0.8 H
Voltage (V) = 200 Volt
w = 500 rad / s
Hinahanap: Resistance of resistor (R)
solusyon:
3. Determine the potential difference of both edge of the inductor.
Kilala:
R = 40 W
XL = 150 W
XC= 120 W
V = 100 Boltahe
Wanted: the potential difference
solusyon:
The total impedance Z of the circuit :
The potential difference of both edge of the inductor :
