Matla a hlahisoang karabelong ea ho kopanya - mathata le litharollo

1. Ho latela equation e latelang ea karabelo ea ho kopanya , fumana matla a hlahisoang karabelong ea ho kopanya!

Matla a hlahisoang karabelong ea ho kopanya - mathata le litharollo 1

tharollo

Boima ba reactant le sehlahisoa:

Boima ba reactant (m reactant ) = 1.0078 amu + 1.0078 amu = 2.0156 amu

Boima ba sehlahisoa (m sehlahisoa ) = 2.01410 amu + 0.00055 amu = 2.01465 amu

Tahlehelo ea boima karabelong:

Δm = m di-reactant – m dihlahiswa

Δm = 2.01560 amu - 2.01465 amu

Δm = 0.00095 amu

Tahlehelo ea boima karabelong ke 0.00095 amu.

1 amu = 931 MeV. 0.00095 amu = 0.00095 x 931 MeV = 0.88445 MeV.

amu = yuniti ea boima ba athomo

MeV = megaelectron-volt (yuniti ea matla)

2. Ho latela equation e latelang ea karabelo ea ho kopanya, fumana matla a hlahisoang karabelong ea ho kopanya!

Matla a hlahisoang karabelong ea ho kopanya - mathata le litharollo 2

Tharollo:

Boima ba reactant le sehlahisoa:

Boima ba reactant (m reactant ) = 2.014 amu + 3.016 amu = 5.03 amu

Boima ba sehlahisoa (m sehlahisoa ) = 4.0026 amu + 1.0084 amu = 5.011 amu

Tahlehelo ea boima karabelong:

Δm = m di-reactant – m dihlahiswa

Δm = 5.03 amu - 5.011 amu

Δm = 0.019 amu

Tahlehelo ea boima karabelong ke 0.019 amu.

1 amu = 931 MeV. 0.019 amu = 0.019 x 931 MeV = 17.689 MeV = 17.69 MeV.

3. Ho latela equation e latelang ea karabelo ea ho kopanya, fumana matla a hlahisoang karabelong ea ho kopanya!

Matla a hlahisoang karabelong ea ho kopanya - mathata le litharollo 3

Tharollo:

Boima ba reactant le sehlahisoa:

Boima ba reactant (m reactant ) = 13.0033 amu + 2.0141 amu = 15.0174 amu

Boima ba sehlahisoa (m sehlahisoa ) = 14.0030 amu + 1.0078 amu = 15.0108 amu

Tahlehelo ea boima karabelong:

Δm = m di-reactant – m dihlahiswa

Δm = 15.0174 amu - 15.0108 amu

Δm = 0.0066 amu

Tahlehelo ea boima karabelong ke 0.0066 amu.

1 amu = 931 MeV. 0.0066 amu = 0.0066 x 931 MeV = 6.1446 MeV.

4. Ho latela equation e latelang ea karabelo ea ho kopanya, fumana matla a hlahisoang karabelong ea ho kopanya.

Matla a hlahisoang karabelong ea ho kopanya - mathata le litharollo 4

Tharollo:

Boima ba reactant le sehlahisoa:

Boima ba reactant (m reactant ) = 4 ( 1.0078 amu ) = 4.0312 amu

Boima ba sehlahisoa (m sehlahisoa ) = 4.0026 amu + 0.0005 amu = 4.0031 amu

Tahlehelo ea boima karabelong:

Δm = m di-reactant – m dihlahiswa

Δm = 4.0312 amu - 4.0031 amu

Δm = 0.0281 amu

Tahlehelo ea boima karabelong ke 0.0281 amu.

1 amu = 931 MeV. 0.0281 amu = 0.0281 x 931 MeV = 26.1611 MeV.

Leave a Comment