Fumana boemo ba ntho e tsamaeang ka mokhoa o hlabang

Mathata a rarollotsoeng motsamaong o qotsitsoeng - fumana boemo ba ntho

1. 'Mele o phahamisetsoa holimo ka sekhutlo sa 60 ^o ho ea ho se bataletseng ka lebelo la pele la 12 m/s. Fumana boemo ba ntho ka mor'a ho tsamaea motsotsoana o le mong! Ho potlaka ha matla a khoheli ke 10 m/s ².

Tse tsejoang:

Sekhutlo ( θ ) = 60 ^o

Lebelo la pele (vo _o ) = 12 m/s

Nako ea nako (t) = motsotsoana o le mong

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: Sebaka sa ntho ka mora ho sisinyeha motsotsoana o le mong

Tharollo:

Karolo e otlolohileng ea lebelo la pele:

v _ox = v _o cos θ = (12 m/s)(cos 60 ^o ) = (12 m/s) (0.5) = 6 m/s

Karolo e otlolohileng ea lebelo la pele:

v _oy = v _o sebe θ = (12 m/s)(sebe 60 ^o ) = (12 m/s)(0.5 √ 3 ) = 6 √ 3 m/s

Sebaka sa ntho ka lehlakoreng le otlolohileng:

Tse tsejoang:

Karolo e otlolohileng ea lebelo (v _x ) = 6 m/s

Nako ea nako (t) = motsotsoana o le mong

Ho batloa: sebaka se bataletseng (x)

Tharollo:

Limithara tse 6 / motsotsoana li bolela hore bolo e tsamaea ho fihlela ho limithara tse 6 motsotsoana o mong le o mong. Sebaka sa bolo ka mor'a ho tsamaea motsotsoana o le mong ke limithara tse 6. Kahoo boemo ba bolo ka lehlakoreng le otlolohileng ke limithara tse 6.

Sebaka sa ntho ka lehlakoreng le otlolohileng:

Khetha tsela e yang hodimo e le e ntle le e theohelang e le e mpe.

Tse tsejoang:

Lebelo la pele (v _o ) = 6 √ 3 m/s (ho ea holimo ho ea holimo)

Nako ea nako (t) = motsotsoana o le mong

Ho potlaka ha matla a khoheli (g) = -10 m/s ² (e mpe ho ea tlase)

Ho batloa: bolelele ka mora ho sisinyeha motsotsoana o le mong

Tharollo:

h = v_o t + 1/2 gt² = (6√3(1) + 1/2 (-10)(1²) = 6√3 + (-5)(1) = 6√3 – 5 = 6(1.7) – 5 = 10.2 – 5 = 5.2 metres.

Sebaka sa ntho ka mora ho sisinyeha motsotsoana o le mong:

Ho falla ho otlolohileng (x) = limithara tse 6

Ho falla ho otlolohileng (y) = limithara tse 5.2

2. 'Mele o phahamisetsoa holimo ka sekhutlo sa 30 ^o ho ea ho se bataletseng ho tloha mohahong o bophahamo ba limithara tse 20. Lebelo la oona la pele ke 50 m/s. Bala ho falla ho otlolohileng ka mor'a hore 'mele o tsamaee motsotsoana o le mong! Ho potlaka ha matla a khoheli ke 10 m/s ².

Tse tsejoang:

Sekhutlo ( θ ) = 30 ^o

Bophahamo ba pele (h _o ) = limithara tse 20

Lebelo la pele (v _o ) = 50 m/s

Nako ea nako (t) = motsotsoana o le mong

Ho potlaka ha matla a khoheli (g) = 1 0 m/s ²

Ho batloa: Bolelele (h)

Tharollo:

Karolo e otlolohileng ea lebelo la pele:

v _oy = v _o sebe θ = (50 m/s)(sebe 30 ^o ) = (50 m/s)(0.5) = 25 m/s

Bophahamo:

Khetha tsela e yang hodimo e le e ntle le e theohelang e le e mpe.

Tse tsejoang:

Lebelo la pele (vo _o ) = 25 m/s (le holimo ho ea holimo)

Nako ea nako (t) = motsotsoana o le mong

Ho potlaka ha matla a khoheli (g) = -1 0 m/s ² (e mpe ho ya tlase)

Ho batloa: Bolelele (h)

Tharollo:

h = vo _o t + 1/2 gt ^{​​​​2} = (25)(1) + 1/2 (-10)(1 ² ) = 25 + (-5)(1) = 25 - 5 = limithara tse 20.

Bophahamo ba 'mele ka mor'a ho tsamaea motsotsoana o le mong ke limithara tse 20 ka holimo ho moo 'mele o hakantsoeng teng kapa limithara tse 40 ka holimo ho mobu.

3. Bolo e nyane e shebiloe ka ho rapama ka lebelo la pele v _o = 10 m/s ho tloha mohahong o bophahamo ba limithara tse 10. Bala ho falla ha bolo ka mor'a ho tsamaea motsotsoana o le mong ! Ho potlaka ha matla a khoheli ke 10 m/s ²

Tse tsejoang:

Bophahamo ba pele (h) = limithara tse 10

Lebelo la pele (vo _o ) = 10 m/s

Nako ea nako (t) = motsotsoana o le mong

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: Sebaka sa bolo ka mor'a ho tsamaea motsotsoana o le mong!

Tharollo:

Ho falla ho otlolohileng:

Tse tsejoang:

Karolo e otlolohileng ea lebelo (v _x ) = 10 m/s

Nako ea nako (t) = motsotsoana o le mong

Ho batloa: Sebaka sa ntho

Tharollo:

Limithara tse 10 ka motsotsoana li bolela hore ntho e tsamaea ho fihlela ho limithara tse 10 motsotsoana o mong le o mong. Ho falla ka mor'a ho falla motsotsoana o le mong ke limithara tse 10. Kahoo ho falla ka ho rapama ke limithara tse 10.

Ho falla ho otlolohileng:

E baloa e le motsamao oa ho oa o lokolohileng.

Tse tsejoang:

Nako ea nako (t) = motsotsoana o le mong

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: Bolelele ka mora ho sisinyeha motsotsoana o le mong (h)

Tharollo:

h = 1/2 gt ^{​​​​2} = 1/2 (10)(1 ² ) = (5)(1) = limithara tse 5.

Kamora motsotsoana o le mong, ntho e oela ho fihlela ho limithara tse 5. Bophahamo ka holim'a mobu = limithara tse 10 - limithara tse 5 = limithara tse 5.

Sebaka sa ntho ka mora ho tsamaya motsotsoana o le mong:

Sebaka sa ntho ka lehlakoreng le otlolohileng (x) = limithara tse 10

Sebaka sa ntho ka lehlakoreng le otlolohileng (y) = limithara tse 5

[ID ea sephutheloana sa wpdm='532′]

[ID ea sephutheloana sa wpdm='536′]

1. Rarolla lebelo la pele likarolong tse otlolohileng le tse otlolohileng
2. Fumana sebaka se rapameng
3. Fumana bophahamo bo phahameng ka ho fetisisa
4. Fumana nako ea karohano
5. Fumana boemo ba ntho
6. Fumana lebelo la ho qetela