Fumana bophahamo bo phahameng ka ho fetisisa ba motsamao oa projectile

Mathata a rarollotsoeng motsamaong oa projectile - fumana bophahamo bo phahameng ka ho fetisisa

1. Bolo ea maoto e rahiloeng e tloha fatše ka sekhutlo sa θ = 60 ^o 'me lebelo la pele la ho rapama ke 10 m/s. Bala bophahamo bo phahameng ka ho fetisisa! Ho potlaka ha matla a khoheli ke 10 m/s ².

Tse tsejoang:

Sekhutlo (θ) = 60 ^o

Lebelo la pele (vo _o ) = 10 m/s

Ho batloa: Bolelele bo phahameng ka ho fetisisa (h)

Tharollo:

Karolo e otlolohileng ea lebelo la pele:

sebe 60 ^o = v _oy / v _o

v _oy = v _o sebe 60 ^o = (10)(sebe 60 ^o ) = (10)(0.5 √ 3 ) = 5 √ 3 m/s

Khetha tsela e yang hodimo e le e ntle le e theohelang e le e mpe.

Tse tsejoang:

Ho potlaka ha matla a khoheli (g) = -10 m/s ² (e mpe ho ea tlase)

Karolo e otlolohileng ea lebelo la pele (v _oy ) = + 5 √ 3 m/s (e ntle ho ea holimo)

Lebelo la ho qetela bophahamong bo phahameng ka ho fetisisa (v _ty ) = 0

Ho batloa: Bolelele bo phahameng ka ho fetisisa (h)

Tharollo:

v _t ² = v _o ² + 2 gh

0 ² = ( 5 √ 3) ² + 2 (-10) h

0 = 2 5 ( 3) – lihora tse 20

0 = 75 – 20 dihora

75 = lihora tse 20

h = 75 / 20

h = limithara tse 3.75

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 3.75.

[irp]

2. 'Mele o phahamisetsoa holimo ka sekhutlo sa 30 ^{o, 'me bophahamo ba oona bo rapameng ho tloha mohahong bo fihla ho limithara tse 20. Lebelo la oona la pele ke 4 m/s. Bala bophahamo bo phahameng ka ho fetisisa! Ho potlaka ha matla a khoheli ke 10} m/s.

Tse tsejoang:

Sekhutlo (θ) = 30 ^o

Bophahamo ba pele (h) = limithara tse 20

Lebelo la pele (vo _o ) = 4 m/s

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: Bophahamo bo phahameng ka ho fetisisa (h)

Tharollo:

Karolo e otlolohileng ea lebelo la pele:

sebe 30 ^o = v _oy / v _o

v _oy = v _o sebe 30 ^o = (4)(sebe 30 ^o ) = (4)(0.5) = 2 m/s

Khetha tsela e yang hodimo e le e ntle le e theohelang e le e mpe.

Tse tsejoang:

Ho potlaka ha matla a khoheli (g) = -10 m/s ² (e mpe ho ea tlase)

Karolo e otlolohileng ea lebelo la pele (v _oy ) = +2 m/s (e ntle ho ea holimo)

Lebelo la ho qetela bophahamong bo phahameng ka ho fetisisa (v _ty ) = 0

Ho batloa: Bolelele bo phahameng ka ho fetisisa

Tharollo:

Bophahamo bo phahameng ka ho fetisisa:

v _t ² = v _o ² + 2 gh

0 ² = 2 ² + 2 (-10) h

0 = 4 – 20 dihora

4 = lihora tse 20

h = 4 / 20

h = limithara tse 0.2

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 0.2 + limithara tse 20 = limithara tse 20.2.

[irp]

[ID ea sephutheloana sa wpdm='528′]

[ID ea sephutheloana sa wpdm='536′]

1. Rarolla lebelo la pele likarolong tse otlolohileng le tse otlolohileng
2. Fumana sebaka se rapameng
3. Fumana bophahamo bo phahameng ka ho fetisisa
4. Fumana nako ea karohano
5. Fumana boemo ba lintho
6. Fumana lebelo la ho qetela