Fumana ho falla ho rapameng ha motsamao oa projectile

Mathata a rarollotsoeng motsamaong oa projectile - fumana sebaka se otlolohileng

1. Bolo ea maoto e rahiloeng e tloha fatše ka sekhutlo sa θ = 60 ^o 'me lebelo la pele la 16 m/s le tla nka nako e kae pele bolo e otla fatše?

Tse tsejoang:

Sekhutlo ( θ ) = 60 ^o

Lebelo la pele (vo _o ) = 16 m/s

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: Ho falla ho otlolohileng (x)

Tharollo:

Karolo e otlolohileng ea lebelo la pele:

v _ox = v _o cos θ = (16 m/s)(cos 60 ^o ) = (16 m/s) (0.5) = 8 m/s

Karolo e otlolohileng ea lebelo la pele:

v _oy = v _o sebe θ = (16 m/s)(sebe 60 ^o ) = (16 m/s)(0.5 √ 3 ) = 8 √ 3 m/s

Motsamao o rotohileng o ka utlwisiswa ka ho sekaseka dikarolo tse otlolohileng le tse otlolohileng tsa motsamao ka thoko. Motsamao wa x o etsahala ka lebelo le sa fetoheng mme motsamao wa y o etsahala ka ho potlaka ha matla a khoheli kamehla.

Nako moeeng

Nako eo e dulang moeeng e laolwa ke motsamao wa y. Re qala ka ho fumana nako re sebedisa motsamao wa y ebe re sebedisa boleng bona ba nako ho di-equation tsa x ( equation ya lebelo le sa fetoheng ).

Khetha tsela e yang hodimo e le e ntle le e theohelang e le e mpe.

Tse tsejoang:

Lebelo la pele (v _o ) = 8 √ 3 m/s (v _o ho ya hodimo)

Ho potlaka ha matla a khoheli (g) = -10 m/s ² (g ho ea tlase)

Bolelele (h) = 0 (bolo e kgutletse boemong bo le bong)

Ho Batloa: Nako Moeeng

Tharollo:

h = vot ₊ 1/2 gt ^{​​​​2}

0 = ( 8 √ 3) t + 1/2 (-10) t ²

0 = 8 √ 3 t – 5 t ²

8 √ 3 t = 5 t ²

8 (1.7) = 5 t

14 = 5 t

t = 14 / 5 = metsotsoana e 2.8

Ho falla ho otlolohileng

Tse tsejoang:

Lebelo (v) = 8 m/s

Nako ea ho arohana (t) = metsotsoana e 2.8

Ho Batloa: Ho falla

Tharollo:

x = vt = (8 m/s)(2.8 s) = limithara tse 22.4

Sebaka se otlolohileng sa ho falla ke limithara tse 22.4.

2. 'Mele o phahamisetsoa holimo ka sekhutlo sa 60 ^{o, 'me bophahamo ba oona bo tloha mohahong bo fihla ho limithara tse 50. Lebelo la oona la pele ke 30 m/s. Bala ho falla ho rapameng! Ho potlaka ha matla a khoheli ke 10} m/s.

Tse tsejoang:

Sekhutlo ( θ ) = 60 ^o

Bolelele (h) = 15 m

Lebelo la pele (v _o ) = 30 m/s

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: x

Tharollo:

Karolo e otlolohileng ea lebelo la pele ::

v _ox = v _o cos θ = (30 m/s)(cos 60 ^o ) = (30 m/s) (0.5) = 15 m/s

Karolo e otlolohileng ea lebelo la pele:

v _oy = v _o sebe θ = (30 m/s)(sebe 60 ^o ) = (30 m/s)(0.5 √ 3 ) = 15 √ 3 m/s

Nako moeeng

Re qala ka ho fumana nako re sebelisa motsamao oa y ebe re sebelisa boleng bona ba nako ho li-equation tsa x (equation ea lebelo le sa fetoheng). Khetha ho ea holimo e le ntle le ho ea tlase e le mpe.

Tse tsejoang:

Lebelo la pele (v _o ) = 15 √ 3 m/s (ho ea holimo ho ea holimo)

Ho potlaka ha matla a khoheli (g) = -10 m/s ² (e mpe ho ea tlase)

Holimo (h) = -50 (Botlaaseng ba limithara tse 50 ka tlase ho sebaka sa pele)

Ho batloa: t

Tharollo:

h = vot ₊ 1/2 gt ^{​​​​2}

-50 = ( 15 √ 3 ) t + 1/2 (-10) t ²

-50 = 15 √ 3 t – 5 t ²

5 t ² – 15 √ 3 t – 50 = 0

Bala nako u sebelisa foromo ena:

a = 5, b = – 15 √ 3, c = – 50

Nako moeeng ke metsotsoana e 6.7.

Ho falla ho otlolohileng:

Tse tsejoang:

Lebelo (v) = 15 m/s

Nako ea ho arohana (t) = metsotsoana e 6.7

Ho batloa: ho falla

Tharollo:

s = vt = (15 m/s)(6.7 s) = limithara tse 100.5

Sebaka se otlolohileng sa ho falla ke limithara tse 100.5.

3. Bolo e nyane e shebiloe ka ho rapama ka lebelo la pele v _o = 10 m/s ho tloha mohahong o bophahamo ba limithara tse 10. Bala ho falla ho rapameng ! Ho potlaka ha matla a khoheli ke 10 m/s ²

Tse tsejoang:

Bolelele (h) = 10 m

Lebelo la pele (vo _o ) = 10 m/s

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: x

Tharollo:

Karolo e otlolohileng ea lebelo la pele = lebelo la pele = 10 m/s.

Nako moeeng

Nako moeeng e baloa ho sebelisoa equation ea motsamao oa ho oa mahala.

Tse tsejoang:

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Bophahamo (h) = limithara tse 10

Ho batloa: t

Tharollo:

h = 1/2 gt ^{​​​​2}

10 = 1/2 (10) t ²

10 = 5 t ²

t ² = 10 / 5 = 2

t = √2 = metsotsoana e 1.4

Ho falla ho otlolohileng

Ho falla ho rapameng ho balwa ho sebediswa equation ya motsamao ka lebelo le sa fetoheng.

Tse tsejoang:

Lebelo (v) = 10 m/s

Nako ea ho arohana (t) = metsotsoana e 1.4

Ho batloa: x

Tharollo:

s = vt = (10 m/s)(1.4 s) = limithara tse 14

Sebaka se otlolohileng sa ho falla ke limithara tse 14.

[ID ea sephutheloana sa wpdm='526′]

[ID ea sephutheloana sa wpdm='536′]

1. Rarolla lebelo la pele likarolong tse otlolohileng le tse otlolohileng
2. Fumana sebaka se rapameng
3. Fumana bophahamo bo phahameng ka ho fetisisa
4. Fumana nako ea karohano
5. Fumana boemo ba lintho
6. Fumana lebelo la ho qetela