Sehlooho se buang ka Resistors letotong
Haeba di-resistor di hokahantswe jwalo ka ha ho bontshitswe setshwantshong, di-resistor di hlophisitswe ka tatellano. Resistor kapa khanyetso ya motlakase e amehang e ka ba ka sebopeho sa dikarolo tsa resistor, mabone, kapa khanyetso e nngwe ya motlakase.
Tefiso ea motlakase e tsamaea ka har'a khanyetso 1 (R)1) = ea tefiso ea motlakase e tsamaea ka har'a khanyetso ea 2 (R)2) = tjhaja ya motlakase e tsamaya kganyetsong ya 3 (R)3). Motlakase (I) ke tjhaja ya motlakase e phallang nakong e itseng ya nako (I = Q / t), kahoo motlakase o phalla ka kganyetso ya 1 (I1) = motlakase o fetang kganyetsong 2 (I2) = motlakase o fetang kganyetsong 3 (I3Ho ya ka dipalo, motlakase o felletseng (I) = I1 = KE2 = KE3.
Conversely, the electric voltage (V) decreases when the electric charge moves through each resistor. Electricity voltage also called an electric potential difference, is an electric potential energy per unit of electric charge. Electricity voltage is reduced because electricity is used in each electrical resistance. So, the total electrical voltage (V) is equal to the amount of electricity in each resistor. Mathematically, the total electric voltage (V) = V1 +V2 +V3. V = I R so the equation of the electric voltage is V = I R1 + IR2 + IR3. The electric current flowing on each resistor is equal so that this equation changes to V = I (R1 + R2 + R3).
Based on the above equation, it can be concluded that the total electrical resistance (R) or the equivalent resistance of the electrical resistance
which is connected in series is equal to the sum of each electrical resistance, mathematically R = R1 + R2 + R3. If there are only two resistors in series, the equivalent resistor (R) = R1 + R2. If there are four resistors in series, the equivalent resistor (R) = R1 + R2 + R3 + R4. Likewise, if there are five or more five resistors that are connected in series.
Sample problem 1:
If known, R1 = 2 Ω, R2 = 3 Ω le R3 = 4 Ω. All three resistors are connected in series. What is the value of the equivalent resistor? (Ω = Ahm).
tharollo:
R = R1 + R2 + R3 = 2 + 3 + 4 = 9 Ω.
This result indicates that the equivalent resistance is greater than the value of the resistors connected in series.
Sample problem 2:
Two resistors R1 = 50 Ω and 50 Ω are connected in series and connected to a 12 Volt battery. Determine
(a) The equivalent resistance
(b) Electric current through each resistor
tharollo:
(a) R = R1 + R2 = 50 Ω + 50 Ω = 100 Ω.
(b) I = V / R = 12 Volt / 100 Ω = 0.12 A
