Likaroloana tse leka-lekaneng la ntlha e le 'ngoe - ts'ebeliso ea mathata le litharollo tsa molao oa pele oa Newton

^{1. Boholo ea ntho, m = 10 kg, e tšehelitsoeng ke thapo. Fumana khatello ka har'a thapo!} g = 10 m/s²

Tse tsejoang:

Boima (m) = 10 kg

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s²

Ho batloa: Matla a khatello ea maikutlo (T)

Tharollo:

ΣF_y = 0

T – w = 0

T = w

T = mg

T = (10 kg)(10 m/s²) = 100 kg m/s²

T = 100 Newton

2. Boima ba ntho ke 10 kg. Fumana kgatello thapong….. Ho potlaka ka lebaka la matla a khoheli = 10 m/s².

tharollo

Tse tsejoang:

Boima (m) = 10 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s².

Ho batloa: Matla a khatello ea maikutlo (T)

Tharollo:

^{w = boima ba 'mele = mg = (10 kg)(10 m/s2}) = 100 kg m/s²

T₁ = matla a khatello ea maikutlo 1

_T1x = karolo ea x ea matla a khatello 1 = T₁ Cos 45^o = 0.7 T₁

_T1y = karolo ea y ea matla a khatello 2 = T₁ sebe 45^o = 0.7 T₁

T₂ = matla a khatello ea maikutlo 2

_T2x = karolo ea x ea matla a khatello 2 = T₂ Cos 45^o = 0.7 T₂

_T2y = karolo ea y ea matla a khatello 2 = T₂ sebe 45^o = 0.7 T₂

Boemo ba tekano ΣF = 0.

mothapo oa y:

ΣF_y = 0

T_1y +T_2y – w = 0

0.7T₁ + 0.7T₂ - 100 = 0

0.7T₁ + 0.7T₂ = 100 —– equation 1

mothapo oa x:

ΣF_x = 0

T_2x - T_1x = 0

0.7T₂ – 0.7T₁ = 0

0.7T₂ = 0.7T₁

T₂ = T₁ —– equation 2

Fumana boholo ba T₁ :

0.7T₁ + 0.7T₁ = 100

1.4T₁ = 100

T₁ = 100/1.4

T₁ = 71.4 Newton

T₁ = T₂ kahoo T₂ = 71.4 Newton

[ID ea sephutheloana sa wpdm='486′]

1. Likaroloana tse leka-lekaneng la ntlha e le 'ngoe
2. Likaroloana tse nang le tekano ea mahlakore a mabeli
3. Tekano ea 'mele e hokahaneng ka lithapo le li-pulley
4. Tekano ea 'mele e sekametseng