fisiks

Lipotso tse 3 mabapi le equation ea phapang e ka bang teng

1. Tefiso ea motlakase e tsamaisoa tšimong ea motlakase e ts'oanang ka matla a 2√3 N sebaka sa 20 cm. Haeba tataiso ea matla e le ka lehlakoreng la 30^o ho ea ho ho falla ha tjhaja ea motlakase, phapang ke efe matla a motlakase a ka bang teng maemong a pele le a ho qetela a tjhaja ea motlakase.

Tse tsejoang:

Matla (F) = 2√3 N

Sebaka (libaka) = 20 cm = 0.2 m

Sekhutlo (θ) = 30^o

Oa Batla: Phapang ea bokhoni ba motlakase

tharollo:

Bala haholoanyane

Lipotso tse 3 mabapi le equation ea lebelo la Angular

1. Ntho e tsamayang tseleng e chitja e na le radius ya 0.5 m. Karoloana e kgona ho kwahela sekhutlo sa 60π rad ka metsotswana e 15. Fumana lebelo la angular la ntho eo.

Tse tsejoang:

Radius (r) = limithara tse 0.5

Sekhutlo (θ) = 60π rad

Nako ea ho arohana (t) = metsotsoana e 15

Oa Batla: Lebelo la Angular (ω)

tharollo:

Bala haholoanyane

Lipotso tse 3 mabapi le Tekanyo ea matla e hlahang

1. Koloi e boima ba lithane tse 5 e tloha phomolong ka metsotsoana e 50, e fihla lebelong la 72 km/hora. Matla koloing ke…

Tse tsejoang:

Boima (m) = lithane tse 5 = 5000 kg

Lebelo la pele (vo) = 0

Lebelo la ho qetela (vt) = 72 km/h = 20 m/s

Nako ea ho arohana (t) = metsotsoana e 50

Oa Batla: Matla (F)

tharollo:

Bala haholoanyane

Lipotso tse 3 mabapi le equation ea Impulse

1. Koloi e boima ba 250 kg e tsamaya ka lebelo la 72 km/hora, ebe e potlakiswa ka matla a sa fetoheng hoo ka metsotsoana e 5 lebelo la yona le fetohang 80 km/hora. Fumana hore na pululelo e tsamaya ka metsotsoana e 5.

Tse tsejoang:

Boima ba koloi (m) = 250 kg

Lebelo la pele (v)_o) = 72 km/h = 20 m/s

Lebelo la ho qetela (v)_t) = 80 km/h = 22 m/s

Nako ea ho arohana (t) = metsotsoana e 5

Oa Batla: Fumana tšusumetso (I)

tharollo:

Bala haholoanyane

Lipotso tse 3 mabapi le equation ea matla a khohlano

1. Boloko A 3 kg e beoa tafoleng ebe e tlangwa ka thapo e hoketsweng lejwe B = 2 kg ka pulley jwalo ka ha ho bontshitswe. Boima le kgohlano ya pulley di hlokomolohuwa. Ho potlaka ka lebaka la matla a kgoheli g = 10 m/s²Fumana hore na sistimi e potlakile hakae le hore na e tsitsitse hakae thapong haeba:

a) tafole e boreleli

b) tafole e sa tebang e nang le coefficient ea kinetic friction ea 0.4

Tse tsejoang:

Boima ba boloko A (m_A) = 3 kg

Boima ba lefika B (m_B) = 2 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Boima ba boloko A (w)_A) = mg = (3)(10) = 30 Newton

Boima ba lefika B (w)_B) = mg = (2)(10) = 20 Newton

Oa Batla: Ho potlaka ha sistimi (a) le kgatello thapong (T)

tharollo:

Bala haholoanyane

Lipotso tse 3 mabapi le equation ea matla a tloaelehileng

1. Boloko bo na le boima ba 5 kg. Haeba g = 10 m/s², etsa qeto:

a) boima ba boloko

b) matla a tloaelehileng haeba boloko bo behiloe sefofaneng se bataletseng

c) matla a tloaelehileng haeba boloko bo lutse sefofaneng se sekametseng se etsang sekhutlo sa 30^o ho ea ho rapameng

Tse tsejoang:

Boima ba boloko (m) = 5 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Oa Batla: w, N sefofaneng le N moeding

tharollo:

Bala haholoanyane

Lipotso tse 3 mabapi le equation ea khatello ea thapo

1. Setšoantšo se ka tlase se bontša liboloko tse tharo, e leng A, B le C tse fumanehang sebakeng se bataletseng se bataletseng. Haeba boima ba A = 1 kg, boima ba B = 2 kg le boima ba C = 2 kg le F = 10 N, joale fumana karolelano ea khatello thapong pakeng tsa A le B le khatello thapong pakeng tsa B le C.

Tse tsejoang:

Boima ba A (m_A) = 1 kg

Boima ba B (m_B) = 2 kg

Boima ba C (m_C) = 2 kg

Matla a ho tsikinyeha (F) = 10 N

Oa Batla: T_AB :T_BC

tharollo:

Bala haholoanyane

3 Mathata le litharollo mabapi le equation ea Moment of inertia

1. Silindara e tiileng e na le radius ea 8 cm le boima ba 2 kg. Ho sa le joalo, bolo e tiileng e na le radius ea 5 cm le boima ba 4 kg. Haeba lintho tse peli li potoloha ka axis bohareng ba tsona, fumana karolelano ea motsotso oa inertia oa silindara le bolo.

Tse tsejoang:

Radius e tiileng ea silindara (r) = 8 cm = 0.08 m

Boima ba silindara e tiileng (m) = 2 kg

Radiyo ya bolo e tiileng (r) = 5 cm = 0.05 m

Boima ba bolo e tiileng (m) = 4 kg

Oa Batla: Papiso ea motsotso oa inertia oa silindara le bolo

tharollo:

Bala haholoanyane

Mathata le litharollo tse 3 mabapi le equation ea Momentum

1. Haeba lebelo la ntho le fetoha lebelo la yona la pele ka makgetlo a mahlano, jwale lebelo la ntho le fetoha ... lebelo la yona la pele.

Tse tsejoang:

Lebelo la pele = v

Lebelo la ho qetela = 5v

Boima = 1

Oa Batla: Momentum

tharollo:

Bala haholoanyane

Mathata a 3 le litharollo mabapi le equation ea Speed

1. Koloi e tsamaea ho ea boroa ka limithara tse 100 ka motsotso o le mong ebe e retelehela bochabela ka limithara tse 120 ka metsotso e 0.5. Fumana lebelo le tloaelehileng la koloi.

Tse tsejoang:

Kakaretso ea sebaka = limithara tse 100 + limithara tse 120 = limithara tse 220

Kakaretso ea nako = motsotso o le 1 + metsotso e 0.5 = metsotso e 1.5 = metsotsoana e 90

Oa Batla: Karolelano ea lebelo

tharollo:

Bala haholoanyane