Melao ea Kirchhoff - mathata le litharollo
1. Motlakase oa terminal oa betri potolohong e ka tlase ke ofe?
tharollo
emf = matla a motlakase = phapang e ka bang teng pakeng tsa li-terminal ha ho se na hajwale phallo ho ea potolohong e kantle.
Motlakase oa terminal (V) = phapang e ka bang teng lipakeng tsa li-terminal ha motlakase o phalla ho tsoa betring.
Haeba ho se na motlakase o huloang betring, motlakase oa terminal o lekana le emf.
Tse tsejoang:
Mohanyetsi 1 (R)1) = 2 Ω
Mohanyetsi 2 (R)2) = 4 Ω
Mohanyetsi 3 (R)3= 4 Ω
emf 1 (E)1) = Li-volt tse 20
emf 2 (E)2) = Li-volt tse 15
Ho batloa: Motlakase oa terminal (V)
Tharollo 1:
Motlakase oa terminal:
V = E 1 – E 2 = 20 – 15 = 5 Volts
Tharollo 2:
Bala phallo ea hona joale potolohong (I)
First, Khetha tsela eo motlakase o mong le o mong o tsamaeang ka eona. Tsela eo motlakase o tsamaeang ka eona e ka khethoa ka mokhoa o sa reroang: haeba motlakase o le ka lehlakoreng le fapaneng, o tla tsoa ka letšoao la ho tlosa tharollong.
Ebe, ho qala ka nako efe kapa efe potolohong, re inahanela re potoloha selika-likoe, re eketsa li-emf le mantsoe a IR ha re ntse re li fihlela.
ea bobeli, Ha re tsamaea mohloling ho tloha ho – ho ea ho+, emf e nkoa e le ntle; ha re tsamaea ho tloha ho + ho ea ho –, emf e nkoa e le mpe.
Ntlha ea boraro, Ha re tsamaya ka hara resistor ka lehlakoreng le le leng le hakantsweng ha jwale, lentswe la IR ke le lebe hobane jwale le ya ka lehlakoreng la bokgoni bo fokotsehang. Ha re tsamaya ka hara resistor ka lehlakoreng le fapaneng le hakantsweng ha jwale, lentswe la IR ke le letle hobane sena se emela keketseho ya bokgoni.
Tsela eo motlakase o tsamaisoang ka eona e khethoa ka tsela e tšoanang le eo o e sebelisang ka oache:
E 1 – IR 1 – IR 2 – IR 3 – E 2 = 0
20 – Ke(2) – Ke(4) – Ke(4) – 15 = 0
20 – 15 – Ke (2) – Ke (4) – Ke (4) = 0
5 – 10 I = 0
5 = 10 I
Ke = 5/10
I = 0.5 Ampere
Motlakase o phallang potolohong ke 0.5 Ampere. Motlakase o saennweng o bolela hore tataiso ea motlakase ke ho tšoana le ka lehlakoreng le shebileng oache.
Bala resistor e lekanang (R):
Mohanyetsi 1 (R1), resistor 2 (R2) 'me khanyetso ea 3 (R)3) li hokahane ka letoto. Mohanyetsi o lekanang:
R = R1 + R2 + R3 = 2 Ω + 4 Ω + 4 Ω = 10 Ω
Motlakase oa terminal ka har'a resistor R (V)
V = IR = (0.5)(10) = 5 Volt
2. Potolohong jwalo ka ha ho bontshitswe setshwantshong se ka tlase, fumana matla a qhalakantsweng ho ea Sehanyetsi sa 3-Ω.
Tharollo:
Tse tsejoang:
Mohanyetsi 1 (R1= 2 Ω 
Mohanyetsi 2 (R2= 3 Ω
Mohanyetsi 3 (R)3= 4 Ω
emf 1 (E)1) = Li-volt tse 8
emf 2 (E2) = Li-volt tse 10
Oa Batla: Matla a ile a fela ka hare ho ea Mohanyetsi oa 3-Ω
Tharollo:
The matla e qhalakantsoe ka hare ho ea Mohanyetsi oa 3-Ωr:
P = VI
P= matla, V = ea matla a matlaho pholletsa ea Mohanyetsi oa 3-Ω, ke = motlakase o feta ka hara Mohanyetsi oa 3-Ω
Bala motlakase oa motlakase (Ke) feta ea Mohanyetsi oa 3-Ω
Tsela eo motlakase o tsamaisoang ka eona e khethoa ka tsela e tšoanang le eo o e sebelisang ka oache:
E 1 – IR 1 – IR 2 – IR 3 + E 2 = 0
8 – Ke(2) – Ke(3) – Ke(4) + 10 = 0
18 – 9 I = 0
18 = 9 I
Ke = 18 / 9
I = 2 Ampere
Motlakase o phallang potolohong ke 2 Ampere. Motlakase o saennweng o bolela hore tataiso ya motlakase ke ho tšoana le ka lehlakoreng le shebileng oache.
Dipotoloho di hokahantswe ka tatellano e le hore motlakase o phallang potolohong = motlakase o fetang ka hara 3-Ω sehanyetsi = Li-ampere tse 2.
Bala motlakase (V) Ho pholletsa le eona 3-Ω sehanyetsi
V = IR 2 = (2 A) (3 Ω) = 6 Volts
Matla a ile a fela ka hare ho ea Sehanyetsi sa 3-Ω:
P = VI = (6 Volt)(2 Ampere) = 12 Volt Ampere = 12 Watt
3. Ho latela potoloho joalo ka ha ho bontšitsoe setšoantšong se ka tlase, phapang e ka bang teng lipakeng tsa lintlha tsa A le B ke efe.
Tse tsejoang:
Mohanyetsi 1 (R)1= 2 Ω 
Mohanyetsi 2 (R)2= 3 Ω
Mohanyetsi 3 (R)3= 4 Ω
emf 1 (E)1) = Li-volt tse 8
emf 2 (E2) = Li-volt tse 10
Ho batloa: Phapang e ka bang teng (V) pakeng tsa ntlha A le B
Tharollo:
Bala motlakase oa motlakase (Ke) e phallang ka har'a 3-Ω sehanyetsi
Tsela eo motlakase o tsamaisoang ka eona e khethoa ka tsela e tšoanang le eo o e sebelisang ka oache:
– E 1 – IR 1 – IR 2 – E 2 – IR 3 = 0
– 8 – Ke (2) – Ke (3) – 10 – Ke (4) = 0
– 18 – 9 I = 0
– 18 = 9 I
Ke = -18 / 9
I = – Li-ampere tse 2
Motlakase o phallang potolohong ke 2 Ampere. Motlakase o saennoe mpe e bolela tataiso ea motlakase statstsela e yang ka watjhe.
Dipotoloho di hokahantswe ka tatellano e le hore motlakase o phallang potolohong = motlakase o fetang ka hara 3-Ω sehanyetsi = Li-ampere tse 2.
Bala phapang e ka bang teng (V) ho pholletsa le 3-Ω sehanyetsi:
V = IR 2 = (2 A) (3 Ω) = 6 Volts
4. Ho latela potoloho joalo ka ha ho bontšitsoe setšoantšong se ka tlase, phapang e ka bang teng ke efe ho pholletsa le R3 sehanyetsi.
Tse tsejoang:
Mohanyetsi 1 (R)1= 2 Ω 
Mohanyetsi 2 (R)2= 4 Ω
Mohanyetsi 3 (R)3= 3 Ω
emf 1 (E)1) = Li-volt tse 6
emf 2 (E)2) = Li-volt tse 9
Ho batloa: Phapang e ka bang teng ho pholletsa le R3 sehanyetsi
Tharollo:
Bala motlakase oa motlakase (Ke) e feta ka har'a R3 sehanyetsi
Tsela eo motlakase o tsamaisoang ka eona e khethoa ka tsela e tšoanang le eo o e sebelisang ka oache:
E 1 – IR 1 – E 2 – IR 2 – IR 3 = 0
6 – 2I – 9 – 4I – 3I = 0
6 – 9 – 2I – 4I – 3I = 0
-3 – 9I = 0
-3 = 9I
Ke = -3/9
Ke = -1/3
Motlakase o phallang potolohong ke 1/3 Ampere. Motlakase o saennoe mpe e bolela tataiso ea motlakase statstsela e yang ka watjhe.
Dipotoloho di hokahantswe ka tatellano e le hore motlakase o phallang potolohong = motlakase o fetang ka hara R3 sehanyetsi = 1/3 Ampere.
Bala phapang e ka bang teng (V) Ho pholletsa le eona R3 sehanyetsi
V = IR 3 = (1/3)(3) = 1 Volt
5. Motlakase o ka bang teng pakeng tsa lintlha tsa C le D = 4 Volts, fumana R!
Tse tsejoang:
Mohanyetsi 1 (R)1= 2 Ω 
Mohanyetsi 2 (R)2= 2 Ω
Mohanyetsi 3 (R)3) = R
emf 1 (E1) = Li-volt tse 8
emf 2 (E2) = Li-volt tse 4
Phapang e ka bang teng pakeng tsa C 'me D (V)CD) = Li-volt tse 4
Ho batloa: R
Tharollo:
CD ea V = IR
4 = IR
R = 4 / I
...............
Bala motlakase oa motlakase (Ke) e feta ka har'a resistor ea R
Tsela eo motlakase o tsamaisoang ka eona e khethoa ka tsela e tšoanang le eo o e sebelisang ka oache:
- E1 – 2I + E2 – 2I – IR = 0
– 8 – 2I + 4 – 2I – Ke (4/I) = 0
– 8 – 2I + 4 – 2I – 4 = 0
– 8 + 4 – 4 – 2I – 2I = 0
– 8 – 4I = 0
– 8 = 4I
Ke = -8 / 4
I = -2 Ampere
Motlakase o phallang potolohong ke 2 Ampere. Motlakase o saennoe mpe e bolela tataiso ea motlakase statstsela e yang ka watjhe.
Dipotoloho di hokahantswe ka tatellano e le hore motlakase o phallang potolohong = motlakase o fetang ka hara R sehanyetsi = 2 Ampere.
R:
R = 4 / Ke = 4 / 2 = 2 Ohm