1. Haeba R 1 = 2 Ω, R 2 = 4 Ω, R 3 = 6 Ω, fumana phallo ea motlakase potolohong e ka tlase.
Tse tsejoang:
Mohanyetsi 1 (R)1) = 2 Ω 
Mohanyetsi 2 (R2 ) = 4 Ω
Mohanyetsi 3 (R 3 ) = 6 Ω
Mohlodi wa emf 1 (E 1 ) = 9 V
Mohlodi wa emf 2 (E 2 ) = 3 V
Ho batloa: Motlakase (I)
Tharollo:
Potso ena e amana le molao oa Kirchhoff . Mokhoa oa ho rarolla bothata bona:
Sa pele , kgetha tsela eo motlakase o tsamayang ka yona. O ka kgetha tsela e fapaneng kapa tsela e tsamayang ka lehlakoreng le leng la oache.
Ea bobeli , ha motlakase o fetang ka resistor (R) o fokotseha hoo V = IR e saenneng ka nepo. Ea boraro , haeba motlakase o tloha ho motlakase o tlase ho ea ho o phahameng (- ho ea ho +) joale mohloli oa emf (E) o saenneng ka nepo ka lebaka la ho tjhaja matla mohloling oa emf. Haeba motlakase o tloha ho motlakase o phahameng ho ea ho o tlase (+ ho ea ho -) joale mohloli oa emf (E) o saenneng ka nepo ka lebaka la ho felloa ke matla mohloling oa emf.
Tharollong ena, tataiso ea hona joale e tšoana le tataiso ea potoloho ea oache.
– IR 1 + E 1 – IR 2 – IR 3 – E 2 = 0
– 2 Ke + 9 – 4 Ke – 6 Ke – 3 = 0
– 12 I + 6 = 0
– 12 I = – 6
Ke = -6 / -12
Ke = 0.5
Phallo ea motlakase potolohong ke 0.5 A. Motlakase o saennoeng hantle o bolela hore tataiso ea motlakase e tšoana le tataiso ea potoloho ea oache. Haeba motlakase o le mpe, joale motlakase o fapane le tataiso ea oache.
2. Fumana motlakase o phallang potolohong jwalo ka ha ho bontshitswe setshwantshong se ka tlase.
Tharollo:
Tharollong ena, tataiso ea hona joale e tšoana le tataiso ea potoloho ea oache.
-20 – 5I -5I – 12 – 10I = 0
-32 – 20I = 0
-32 = 20I
Ke = -32 / 20
Ke = -1.6 A
Kaha motlakase o le tlase, tataiso ea motlakase e fapane le tataiso ea oache. Tsela eo motlakase o lebang ka eona ha e tšoane le e hakantsoeng.
3. Fumana motlakase o phallang potolohong jwalo ka ha ho bontshitswe setshwantshong se ka tlase.
Tharollo:
Tharollong ena, tataiso ea hona joale e tšoana le tataiso ea potoloho ea oache.
– Ke – 6I + 12 – 2I + 12 = 0
-9I + 24 = 0
-9I = -24
Ke = 24 / 9
Ke = 8 / 3 A
4. Potoloho ea motlakase e na le li-resistor tse 'ne, R 1 = 12 Ohm, R 2 = 12 Ohm, R 3 = 3 Ohm le R 4 = 6 Ohm, li hokahane le mohloli oa emf E 1 = 6 Volt, E 2 = 12 Volt. Fumana phallo ea motlakase potolohong joalo ka ha ho bontšitsoe setšoantšong se ka tlase.
Tse tsejoang:
Mohanyetsi 1 (R 1 ) = 12 Ω
Mohanyetsi 2 (R 2 ) = 12 Ω
Mohanyetsi 3 (R 3 ) = 3 Ω
Mohanyetsi 4 (R 4 ) = 6 Ω
Mohloli oa emf 1 (E 1 ) = 6 Volts
Mohloli oa emf 2 (E 2 ) = 12 Volts
Ho batloa: Motlakase o phalla potolohong (I)
Tharollo:
Resistor 1 ( R1 ) le resistor 2 ( R2 ) li hokahane ka ho lekana. Resistor e lekanang:
1/R 12 = 1/R 1 + 1/R 2 = 1/12 + 1/12 = 2/12
R 12 = 12/2 = 6 Ω
Tharollong ena, tataiso ea hona joale e tšoana le tataiso ea potoloho ea oache.
– IR 12 – E 1 – IR 3 – IR 4 + E 2 = 0
– 6 I – 6 – 3I – 6I + 12 = 0
– 6I – 3I – 6I = 6 -12
– 15I = – 6
Ke = -6/-15
Ke = 2/5 A
5. Fumana motlakase o phallang ka potoloho joalo ka ha ho bontšitsoe setšoantšong se ka tlase.
Tse tsejoang:
Mohanyetsi 1 (R 1 ) = 10 Ω
Mohanyetsi 2 (R 2 ) = 6 Ω
Mohanyetsi 3 (R 3 ) = 5 Ω
Mohanyetsi 4 (R 4 ) = 20 Ω
Mohloli oa emf 1 (E 1 ) = 8 Volts
Mohloli oa emf 2 (E 2 ) = 12 Volts
Ho batloa: Motlakase o phallang potolohong
Tharollo:
Resistor 3 ( R3 ) le resistor 4 ( R4 ) li hokahane ka ho lekana. Resistor e lekanang:
1/R 34 = 1/R 3 + 1/R 4 = 1/5 + 1/20 = 4/20 + 1/20 = 5/20
R 34 = 20/5 = 4 Ω
Tharollong ena, tataiso ea hona joale e tšoana le tataiso ea potoloho ea oache.
– IR 1 – IR 2 – E 1 – IR 34 + E 2 = 0
– 10I – 6I – 8 – 4I + 12 = 0
– 10I – 6I – 4I = 8 – 12
– 20 I = – 4
Ke = -4/-20
Ke = 1/5 A
Ke = 0.2 A
6. Fumana motlakase o phallang ka potoloho joalo ka ha ho bontšitsoe setšoantšong se ka tlase.
Tse tsejoang:
Mohanyetsi 1 (R 1 ) = 1 Ω
Mohanyetsi 2 (R 2 ) = 6 Ω
Mohanyetsi 3 (R 3 ) = 6 Ω
Mohanyetsi 4 (R 4 ) = 4 Ω
Mohloli oa emf 1 (E 1 ) = 12 Volts
Mohloli oa emf 2 (E 2 ) = 6 Volts
Ho batloa: Motlakase o phallang potolohong
Tharollo:
Resistor 1 ( R1 ) le resistor 2 ( R2 ) li hokahane ka ho lekana. Resistor e lekanang:
1/R 12 = 1/R 1 + 1/R 2 = 1/1 + 1/6 = 6/6 + 1/6 = 7/6
R 12 = 6/7 Ω
Tsela eo motlakase o potolohang ka yona e tshwana le tsela eo motlakase o potolohang ka yona ka watjhe.
E 1 – I R 12 – E 2 – I R 4 – IR 3 = 0
12 – (6/7)I – 6 – 4I – 6I = 0
12 – 6 – (6/7)I – 4I – 6I = 0
6 – (6/7)I – 10I = 0
6 = (6/7)I + 10I
6 = (6/7)I + (70/7)I
6 = (76/7)I
(6)(7) = 76I
42 = 76I
Ke = 42/76
Ke = 0.5 A
