Mathata le litharollo tsa motlakase oa motlakase

1. Fumana matla a motlakase ntlheng e fumanehang ho 1 cm ho tloha tefisong 5.0 μ C. Coulomb constant (k) = 9 x 10 ⁹ Nm ² C ⁻² , 1 μC = 10 ⁻⁶ C.

Tse tsejoang:

Sebaka ho tloha ho tjhaja (r) = 1 cm = 1/100 m = 0.01 m = 10 ^-2 m

Tefiso (q) = 5.0 μ C = 5.0 x 10 ^-6 C

Sephetho sa Coulomb (k) = 9 x 10 ⁹ Nm ² C ⁻²

Ho batloa: Bokhoni ba motlakase (V)

Tharollo:

Bokhoni ba motlakase:

Bokgoni ba motlakase ke 4.5 x 10 ⁶ Volts

2. lefisa Q₁ = 5.0 μC le tefello Q₂ = 6.0 μC. Kamehla ea Coulomb (k) = 9 x 10⁹ Nm²C^-2, 1 μC = 10^-6 C. Ntlha ea A e pakeng tsa liqoso. Fumana matla a motlakase ntlheng ea A.

Tse tsejoang:

Tefiso Q ₁ = -5.0 μ C = -5.0 x 10 ^-6 C

Sebaka sa ntlha A ho tloha ho Q ₁ = 10 cm = 0.1 m = 10 ^-1 m

Tefiso Q ₂ = 6.0 μ C = 6.0 x 10 ^-6 C

Sebaka sa ntlha a ho tloha Q ₂ = 10 cm = 0.1 m = 10 ^-1 m

Sephetho sa Coulomb (k) = 9 x 10 ⁹ Nm ² C ⁻²

Ho batloa: Matla a motlakase ntlheng ea A

Tharollo:

Bokhoni ba motlakase 1 :

Bokhoni ba motlakase 2 :

Bokhoni ba motlakase ntlheng ea A :

V = V ₂ – V ₁

V = (54 – 45) x 10 ⁴

V = 9 x 10 ⁴

3. lefisa q₁ = 5.0 μC le tefello q₂ = 6.0 μC. Kamehla ea Coulomb (k) = 9 x 10⁹ Nm²C^-2, 1 μC = 10^-6 C. Fumana matla a motlakase ntlheng ea A.

Tse tsejoang:

Tefiso Q ₁ = -5.0 μ C = -5.0 x 10 ^-6 C

Sebaka sa ntlha A ho tloha ho Q ₁ = 40 cm = 0.4 m = 4 x 10 ^-1 m

Tefiso Q ₂ = 6.0 μ C = 6.0 x 10 ^-6 C

Sebaka sa ntlha A ho tloha ho Q ₂ = 50 cm = 0.5 m = 5 x 10 ^-1 m

Sephetho sa Coulomb (k) = 9 x 10 ⁹ Nm ² C ⁻²

Ho batloa: Matla a motlakase ntlheng ea A

Tharollo:

Bokhoni ba motlakase 1 :

Bokhoni ba motlakase 2 :

Bokhoni ba motlakase ntlheng ea A :

V = V ₁ + V ₂

V = (-11.25 + 10.8) x 10 ⁴

V = -0.45 x 10 ⁴

V = -4.5 x 10 ³

Bokgoni ba motlakase ntlheng ya A ke -4.5 x 10 ³ Volts