Mathata a Rarollotsoeng Fisiks ea Motheo

1. Iho sebetsana le likhase ka har'a setshelo se koetsoeng qalong ba na le moqolo oa V le khatello P. Haeba kgatello ya ho qetela e le 4P mme modumo o dula o tsitsitse, ra ke eng?tio ea matla a pele a kinetic le ea ho qetela matla a kinetic.

Tse tsejoang:

Khatello ea pele (P₁) = P

Khatello ea ho qetela (P₂) = 4P

Molumo oa pele (V₁) = V

Molumo oa ho qetela (V₂) = V

Oa Batla: Karolelano ea matla a pele a kinetic ho matla a ho qetela a kinetic (KE₁ :KE₂)

Tharollo:

Kamano pakeng tsa khatello (P), bophahamo ba modumo (V) le matla a kinetic (KE) a likhase tse loketseng :

Karolelano ea matla a pele a kinetic ho matla a ho qetela a kinetic:

2. Ke bokae matla a kinetic a phetolelo a limolek'hule khaseng e loketseng ho 57^oC.

Tse tsejoang:

Thempereichara ea khase (T) = 57^oC + 273 = 330 Kelvin

Boltzmannkamehla (k) = 1.38 x 10^-23 Joule/Kelvin

Oa Batla: Matla a tloaelehileng a kinetic a phetolelo

Tharollo:

Kamano pakeng tsa kinetic energy (KE) le mocheso ea khase (T):

Matla a tloaelehileng a kinetic a phetolelo:

3. Khase ho 27^oC setshelong se koetsoeng. Haeba matla a kinetic a khase a eketseha ka makhetlo a mabeli ho feta matla a pele a kinetic, kahoo mocheso oa ho qetela oa khase ke…

Tse tsejoang:

Mocheso oa pele (T₁= 27^oC + 273 = 300 K

Matla a pele a kinetic = KE

Matla a ho qetela a kinetic = 4 KE

Oa Batla: Mocheso oa ho qetela (T₂)

Tharollo:

4. Khase e loketseng e ka setshelong se koetsoeng, e futhumatsoa e le hore e be ea ho qetela lebelo le tloaelehileng ea likaroloana tsa khase e eketseha ka makhetlo a 3 ho feta lebelo la karolelano la pele. Haeba mocheso oa pele oa khase o le 27^oC, ebe mocheso oa ho qetela oa khase e loketseng ke…

Tse tsejoang:

Mocheso oa pele = 27^oC + 273 = 300 Kelvin

Lebelo la pele = v

Lebelo la ho qetela = 2v

o ne a batla :Tmocheso oa ho qetela oa khase e loketseng

Tharollo:

Lebelo le tloaelehileng la ho qetela = 2 x lebelo la karolelano la pele

5. Li-mole tse tharo tsa khase li sebakeng sa bophahamo ba lilithara tse 36. Molek'hule e 'ngoe le e 'ngoe ea khase e na le matla a kinetic a 5 x 10^-21 Joule. Khase e sa fetoheng ka kakaretso = 8.315 J/mole.K le khase e sa fetoheng ka kakaretso ea Boltzmann = 1.38 x 10^-23 J/K. Kgatelelo ya kgase ka hara setshelo ke efe?

Tse tsejoang:

Palo ea li-moles (n) = li-moles tse 3

Bophahamo ba modumo = lilithara tse 36 = 36 dm³ = 36x10^-3 m³

Boltzmann's constant (k) = 1.38 x 10^-23 J/K

Matla a kinetic (KE) = 5 x 10^-21 Joule

Khase e sa fetoheng ea bokahohleng (R) = 8.315 J/mole.K

o ne a batla : Khatello ea khase (P)

Tharollo:

Bala mocheso o sebedisa equation ya kinetic eneji ya kgase.

Bala khatello ea khase u sebelisa equation ea molao o motle oa khase (ka palo ea li-moles, n):

PV = n RT

P (36 x 10)^-3) = (3)(8.315)(241.5)

P (36 x 10)^-3= 6024.22

Khatello ea khase ke 1.67 x 10⁵ Pascal kapa sepakapaka sa 1.67.

Bala haholoanyane

1 Keho sebetsana le likhase ka har'a setshelo se koetsoeng qalong ba na le moqolo oa V le mocheso P. Mocheso oa ho qetela ke 5/4T 'me oa ho qetela ke khatello ke 2P. Bophahamo ba ho qetela ba khase ke bofe?

Tse tsejoang:

Molumo oa pele (V)₁) = V

Mocheso oa pele (T)₁) = T

Mocheso oa ho qetela (T)₂) = 5/4 T

Khatello ea pele (P)₁) = P

Khatello ea ho qetela (P)₂) = 2P

Oa Batla: Moqolo oa ho qetela (V)₂)

Tharollo:

2. Fumana bophahamo ba 2.00 moles ea likhase (khase e loketseng) ho STP. STP = Mocheso le Khatello e Tloaelehileng.

Tse tsejoang:

Li-mole tsa khase (n) = 2 moles

Mocheso o tloaelehileng (T) = 0 ^oC = 0 + 273 = 273 Kelvin

Khatello e tloaelehileng (P) = 1 atm = 1.013 x 10⁵ Pa

Khase e sa fetoheng ea bokahohle (R) = 8.315 Joules/mole.Kelvin

o ne a batla : Bophahamo ba likhase (V)

Tharollo:

Tekanyo ea Molao o loketseng oa khase (palong ea li-moles, n)

Bophahamo ba limole tse 2 tsa likhase ke lilithara tse 44.8.

Bophahamo ba mole e le 'ngoe ea likhase ke lilithara tse 45.4 / 2 = lilithara tse 22.4.

Bophahamo ba mole e le 'ngoe ea khase efe kapa efe ke lilithara tse 22.4.

3. Lilithara tse 4 tsa khase ea oksijene li na le mocheso oa 27°C le khatello ea 2 atm (1 atm = 10⁵ Pa) ka setshelong se koetsoeng. Universal gas constant (R) = 8.314 J.mole^-1.K^-1 le nomoro ea Avogadro (N_A= 6.02 x 10²³ limolek'hule/mole. Limolek'hule tsa likhase tsa oksijene tse ka har'a setshelo ke life?

Tse tsejoang:

Bophahamo ba likhase (V) = lilithara tse 4 = 4 dm³ = 4x10^-3 m³

Mocheso oa likhase (T) = 27^oC = 27 + 273 = 300 Kelvin

Khatello ea likhase (P) = 2 atm = 2 x 10⁵ Pa

Khase e sa fetoheng ea bokahohle (R) = 8.314 J.mole^-1.K^-1

Nomoro ea Avogadro (N)_A) = 6.02 x 10²³

o ne a batla : Limolek'hule tsa likhase tsa oksijene tse ka har'a setshelo ke life (N)

Tharollo:

Ka mole e le 'ngoe ea khase ea oksijene, ho na le 1.93 x 10²³ limolek'hule tsa oksijene.

4. Setshelo se nang le khase ea neon (Ne, boima ba athomo = 20 u) mochesong le khatellong e tloaelehileng (STP).) e na le bophahamo ba limithara tse 2³Fumana boima ba khase ea neon!

Tse tsejoang:

Boima ba athomo ba neon = digrama tse 20/mole = 0,02 kg/mole

Mocheso o tloaelehileng (T) = 0^oC = 273 Kelvin

Khatello e tloaelehileng (P) = 1 atm = 1.013 x 10⁵ Pascal

Bophahamo (V) = 2 m³

o ne a batla : boima (M) ea khase ea neon

Tharollo:

Ka mocheso le khatello e tloaelehileng (STP), 1 mole ea likhase life kapa life, kenyeletsa khase ea neon, e na le bophahamo ba modumo 22.4 lithas = 22.4 dm³ = 0.0448 limithara³.

Ka bophahamo ba 2 m³, ho na le limole tse 44.6 tsa khase ea neon.

Boima ba athomo ba khase ea neon ke ligrama tse 20 ka mole.

Sena se bolela hore ka mole e le 'ngoe ho na le ligrama tse 20 kapa 0.02 kg ea khase ea neon. Hobane ka mole e le 'ngoe ho na le 0.02 kg ea khase ea neon joale ka mole e 44.6 ho na le limole tse 44.6 x 0.02 kg/mole = 0.892 kg = ligrama tse 892 tsa likhase tsa neon.

Bala haholoanyane

1. Ilikhase tsa tumellano qalong li na le khatello P le mocheso T. Khase e feta tlas'a ts'ebetso ea isochoric e le hore kgatello ya ho qetela e be kgatello ya pele ka makgetlo a mane. Mocheso wa ho qetela wa kgase ke ofe?

Tse tsejoang:

Khatello ea pele (P)₁) = P

Khatello ea ho qetela (P)₂) = 4P

Mocheso oa pele (T)₁) = T

Oa Batla: Mocheso oa ho qetela (T)₂)

Tharollo:

Foromo ea Molao oa Gay-Lussac :

Mocheso oa ho qetela o ba makhetlo a mane ho feta mocheso oa pele.

2. Ka setshelong se koetsoeng, likhase tse loketseng qalong li na le mocheso oa likhato tse 27^oC. Haeba Kgatelelo ya ho qetela e ba kgatelelo ya pele ka makgetlo a mabedi, mocheso wa ho qetela ke ofe?

Tse tsejoang:

Khatello ea pele (P)₁) = P

Khatello ea ho qetela (P)₂) = 2P

Mocheso oa pele (T)₁= 27^oC + 273 = 300 K

Oa Batla: Mocheso oa ho qetela (T)₂)

Tharollo:

3. Thaere e tlatswa ho fihlela kgatellong ya 2 atm ho 27°C. Kamora ho kganna, mocheso ka hare ho thaere o nyolohela ho 47°C. Kgatello ka hare ho thaere ke efe jwale?

Tse tsejoang:

Khatello ea sepakapaka = 1 atm = 1 x 10⁵ Pa

Khatello ea pele ea tekanyo = 2 atm = 2 x 10⁵ Pa

Kgatelelo e feletseng ya pele (P)₁) = 1 atm + 2 atm = 3 atm = 3 x 10⁵ Pa

Mocheso oa pele (T)₁= 27^oC + 273 = 300 K

Mocheso oa ho qetela (T)₁= 47^oC + 273 = 320 K

Ho batloa: Mocheso oa ho qetela oa tekanyo

Tharollo:

Kgatelelo ya ho qetela ya tekanyo = kgatelelo e feletseng ya ho qetela – kgatelelo ya sepakapaka

Khatello ea ho qetela ea tekanyo = 3.2 atm - 1 atm

Khatello ea ho qetela ea tekanyo = 2.2 atm

Bala haholoanyane

1. Ka setshelong se koetsoeng, khase e atoloha hoo bophahamo ba ho qetela bo bang makhetlo a mararo ho feta bophahamo ba pele (V = bophahamo ba pele, T = qalong mocheso). Mocheso oa ho qetela ke ofe?

Tse tsejoang:

Molumo oa pele (V)₁) = V

Moqolo oa ho qetela (V)₂) = 3V

Mocheso oa pele (T)₁) = T

Oa Batla: Mocheso oa ho qetela (T)₂)

Tharollo:

Foromo ea Molao oa Charles :

Thempereichara ea ho qetela ea likhase e ba makhetlo a mararo ho feta thempereichara ea pele.

2 Kelikhase tse sebetsanang le tsona qalong li na le bophahamo ba V le mocheso T. Haeba khase e feta ts'ebetso ea isobaric hoo mocheso o bang makgetlo a mabedi ho feta mocheso wa pele, ebe bophahamo ba ho qetela ba dikgase ke…

Tse tsejoang:

Molumo oa pele (V)₁) = V

Mocheso oa pele (T)₁) = T

Mocheso oa ho qetela (T)₂) = 2T

Oa Batla: moqolo oa ho qetela (V)₂)

Tharollo:

Bophahamo ba ho qetela ba likhase bo ba makhetlo a mabeli ho feta bophahamo ba pele.

3. Ka setshelong se koetsoeng, likhase tse loketseng qalong li na le bophahamo ba lilithara tse 2 le mocheso oa 27^oC. Haeba bophahamo ba ho qetela ba likhase bo fetoha lilithara tse 3 joale mocheso oa ho qetela ke…

Tse tsejoang:

Molumo oa pele (V)₁) = lilithara tse 2 = 2 dm³ = 2x10^-3 m³

Moqolo oa ho qetela (V)₂) = lilithara tse 3 = 3 dm³ = 3x10^-3 m³

Mocheso oa pele (T)₁= 27^oC + 273 = 300 K

Ho batloa: Mocheso oa ho qetela (T)₂)

Tharollo:

Mocheso oa ho qetela ke 177^oC kapa 177 + 273 = 450 Kelvin.

Bala haholoanyane

1. Likhase tse ling tse ntle qalong li na le khatello P le bophahamo ba V. Haeba khase e feta ts'ebetso ea isothermal hoo kgatello ya ho qetela e bang makgetlo a mane a kgatello ya pele, ebe modumo wa ho qetela wa kgase ke…

Tse tsejoang:

Khatello ea pele (P₁) = P

Khatello ea ho qetela (P₂) = 4P

Molumo oa pele (V₁) = V

Oa Batla: Molumo oa ho qetela (V₂)

Tharollo:

Foromo ea Molao oa Boyle :

PV = kamehla

P₁ V₁ = P.₂ V₂

(P)(V) = (4P)(V)₂)

V = 4 V₂

V₂ = V / 4 = ¼ V

Bophahamo ba ho qetela ba likhase ke ¼ makhetlo a bophahamo ba pele.

2. Ka setshelong se koetsoeng, khase e a atoloha hoo ho qetela bophahamo ba modumo e fetoha Metsotso e 'meli ea bophahamo ba pele (V = bophahamo ba pele, P = khatello ea pele). Kgatelelo ya ho qetela ya dikhase ke…

Tse tsejoang:

Khatello ea pele (P₁) = P

Molumo oa pele (V₁) = V

Molumo oa ho qetela (V₂) = 2V

o ne a batla : Khatello ea ho qetela (P₂)

Tharollo:

P₁ V₁ = P.₂ V₂

PV = P₂ (2V)

P= P₂ (2)

P₂ = P / 2 = ½ P

Khatello ea khase e ba makhetlo a halofo ho feta khatello ea pele.

3. Ka setshelong se koetsoeng, likhase tse nang le khatello ea 2 atm le bophahamo ba litara e le 1. Haeba khatello ea khase e fetoha 4 atm joale bophahamo ba khase bo fetoha...

Tse tsejoang:

Khatello ea pele (P₁) = 2 atm = 2 x 10⁵ Pa

Khatello ea ho qetela (P₂) = 4 atm = 4 x 10⁵ Pa

Molumo oa pele (V₁) = lilithara tse 1 = 1 dm³ = 1x10^-3 m³

o ne a batla : Molumo oa ho qetela (V₂)

Tharollo:

P₁ V₁ = P.₂ V₂

(2: x 10⁵)(1 x 10^-3) = (4 x 10⁵) V₂

(1)(1 x 10^-3) = (2) V₂

1: x 10^-3 = (2) V₂

V₂ = ½ x 10^-3

V₂ = 0.5x10^-3 m³ = 0.5 dm³ = 0.5 litaras

Bala haholoanyane

1. Li-capacitor tse tharo, C₁ = 2 μF, C₂ = 4 μF, C₃ = 4 μF, ke e hokahantsoe ka letoto le ka ho bapaFumana bokhoni ba capacitor e le 'ngoe bo tla ba le phello e tšoanang le motsoako.

Tse tsejoang:

Moqapi C₁ = 2 μF

Motlakase C₂ = 4 μF

Motlakase C₃ = 4 μF

Ho batloa: Bokgoni bo lekanang (C)

Tharollo:

Moqapi C₂ le C₃ e hokahantsoe ka ho bapa. Bokgoni bo lekanang:

C_P =C₂ + C.₃ 4 + 4 = 8 μF

Moqapi C₁ le C_p e hokahantsoe ka letoto. Bokgoni bo lekanang:

1/C = 1/C₁ + 1/C_P = 1/2 + 1/8 = 4/8 + 1/8 = 5/8

C = 8/5 μF

2. Tse hlano li-capacitor, C₁ = 2 μF, C₂ = 4 μF, C₃ = 6 μF, C₄ = 5 μF, C₅ = 10 μF, li hokahane ka tatellano le ka tsela e ts'oanang. Fumana bokhoni ba capacitor e le 'ngoe e tla ba le phello e tšoanang le motsoako.

Tse tsejoang:

Motlakase C₁ = 2 μF

Motlakase C₂ = 4 μF

Motlakase C₃ = 6 μF

Motlakase C₄ = 5 μF

Motlakase C₅ = 10 μF

Ho batloa: Capacitance e lekanang (C)

Tharollo:

Moqapi C₂ le C₃ li hokahane ka ho bapa. Capacitance e lekanang:

C_P =C₂ + C.₃

C_P = 4 + 6

C_P = 10 μF

Moqapi C₁, C_P, C₄ le C₅ li hokahane ka letoto. Bokgoni bo lekanang:

1/C = 1/C₁ + 1/C_P + 1/C₄ + 1/C₅

1/C = 1/2 + 1/10 + 1/5 + 1/10

1/C = 5/10 + 1/10 + 2/10 + 1/10

1/C = 9/10

C = 10/9 μF

3 C₁ = 3 μF, C₂ = 4 μF le C₃ = 3 μF, li hokahane ka tatellano le ka ho bapa. Fumana matla a motlakase ka lipotoloho.

Tse tsejoang:

Motlakase C₁ = 3 μF

Motlakase C₂ = 4 μF

Motlakase C₃ = 3 μF

Ho batloa: Capacitance e lekanang (C)

Tharollo:

Moqapi C₂ le C₃ li hokahane ka ho bapa. Capacitance e lekanang:

C_P =C₂ + C.₃

C_P = 4 + 3

C_P = 7 μF

Moqapi C₁ 'me C_P li hokahane ka letoto. Bokgoni bo lekanang:

1/C = 1/C₁ + 1/C_P

1/C = 1/3 + 1/7

1/C = 7/21 + 3/21

1/C = 10/21

C = 21/10

EA-2.1-C μF

C = 2.1 x 10^-6 F

Matla a motlakase lipotolohong:

E = ½ CV²

E = ½ (2.1: x 10^-6(12)²)

E = ½ (2.1 x 10)^-6)(144)

E = (2.1 x 10^-6)(72)

E = 151.2 x 10^-6 Joule

E = 1.5 x 10^-4 Joule

Bala haholoanyane

1. Li-capacitor tse 'ne, C₁ = 2 μF, C₂ = 1 μF, C₃ = 3 μF, C₄ = 4 μF, li hokahane ka letoto la lihlooho tseFumana bokhoni ba sesebelisoa se le seng bokgoni seo se tla ba le phello e tšoanang le motsoako.

Tse tsejoang:

Motlakase C₁ = 2 μF

Motlakase C₂ = 1 μF

Motlakase C₃ = 3 μF

Motlakase C₃ = 4 μF

Ho batloa: Capacitance e lekanang

Tharollo:

Bokgoni bo lekanang:

1/C = 1/C₁ + 1/C₂ + 1/C₃ + 1/C₄

1 / C = 1/2 + 1/1 + 1/3 + 1/4

1 / C = 6/12 + 12/12 + 4/12 + 3/12

1 / C = 25 / 12

C = 12 / 25

C = 0.48

Bokgoni bo lekanang ba motsoako oohle is 0.48 μF.

2. Fumana tefiso ho capacitor C₁ haeba e phapang e ka bang teng Pakeng tsa P 'me Q is 12 Volt…

Tse tsejoang:

Motlakase C₁ = 10 μF= 10: x 10^-6 F

Motlakase C₂ = 20 μF= 20: x 10^-6 F

Phapang e ka bang teng (V) = 12 Volt

Ho batloa: tjhaja ho capacitor C₁ (Q₁)

Tharollo:

Bokgoni bo lekanang:

1/C = 1/C₁ + 1/C₂

1/C = 1/10 + 1/20 = 2/20 + 1/20 = 3/20

C = 20/3 μF = (20/3) x 10^-6 F

Tefiso ea motlakase ho capacitor e lekanang:

Q = (C)(V) = (20/3)(12)(10^-6) = 80 x 10^-6 C

Q = 80 μC

Li-capacitor li hokahantsoe ka letoto e le hore tjhaja ya motlakase hodima di-capacitor tse lekanang = tjhaja ya motlakase hodima di-capacitor C₁ = tjhaja ya motlakase hodima capacitor C₂.

Tefiso ea motlakase ho capacitor C₁ ke 80 μC.

3. Li-capacitor tse peli, C₁ = 2 μF le C₂ = 4 μF, li hokahantsoe ka tatellano. Li-capacitor lia chajoa. Phapang e ka bang teng ho capacitor C₁ ke li-Volt tse 2. Tefiso ea motlakase ho capacitor C₂ ke ...

Tse tsejoang:

Cbokongcmoetapele C₁ = 2 μF = 2 x 10^-6 F

Cbokongcmoetapele C₂ = 4 μF = 4 x 10^-6 F

Phapang e ka bang teng ho capacitor C₁ (V₁) = Li-volt tse 2

o ne a batla : Tefiso ea motlakase ho capacitor C₂.

Tharollo:

Tefiso ea motlakase ho capacitor C₁ :

Q₁ =C₁ V₁ = (2 x 10^-6)(2) = 4 x 10^-6 C

Q₁ = 4 μC

Li-capacitor li hokahane ka tatellano e le hore tjhaja ea motlakase holim'a capacitor C₁ = tjhaja ya motlakase hodima capacitor C₂.

Tefiso ho capacitor C₂ is 4 μC.

Bala haholoanyane

1. Tse 'ne capacitors, C₁ = 2 μF, C₂ = 1 μF, C₃ = 3 μF, C₄ = 4 μF, di hokahantswe ka ho bapa. Fumana bokgoni ba capacitor e le nngwe e tla ba le phello e tshwanang le ya motswako.

Tse tsejoang:

Moqapi C₁ = 2 μF

Moqapi C₂ = 1 μF

Moqapi C₃ = 3 μF

Moqapi C₃ = 4 μF

Ho batloa: Capacitance e lekanang

Tharollo:

Bokgoni bo lekanang:

C =C₁ + C.₂ + C.₃

C = 4 μF+2 μF+3 μF=9 μF

Bokgoni bo lekanang ba motsoako oohle ke 9 μF.

2. Etsa qeto ea tefiso holim'a capacitor C₂ haeba e phapang e ka bang teng pakeng tsa ntlha A le B ke Li-volt tse 9…

Tse tsejoang:

Cbokongcmoetapele C₁ = 20 μF = 20 x 10^-6 F

Cbokongcmoetapele C₂ = 30 μF = 30 x 10^-6 F

Phapang e ka bang teng lipakeng tsa lintlha A 'me B (V)_AB) = Li-volt tse 9

o ne a batla : tefiso ho capacitor C₂ (Q₂)

Tharollo:

Phapang e ka bang teng:

Li-capacitor li hokahane ka nako e le 'ngoe e le hore phapang e ka bang teng pakeng tsa A le B (V)_AB) = phapang e ka bang teng ho capacitor C₁ (V₁) = phapang e ka bang teng ho capacitor C₂ (V₂) = Li-volt tse 9.

Tefiso ea motlakase ho capacitor C₂ :

Q₂ =C₂ V₂ = (30 x 10^-6)(9) = 270 x 10^-6 C

Q₂ = 270 μC

Tefiso ea motlakase ho capacitor C₂ is 270 μC.

3. Three li-capacitor, C₁ = 4 μF, C₂ = 2 μF, C₃ = 3 μF, li hokahane ka ho lekana. Li-capacitor li tjhajwa. Phapang e ka bang teng ho capacitor C₂ ke li-Volt tse 4. Fumana

(a) Tefiso ea motlakase ho capacitor C₁, C₂ le C₃

(b) Tefiso ea motlakase holim'a capacitor e lekanang ea motsoako oohle

Tse tsejoang:

Cbokongcmoetapele C₁ = 4 μF = 4 x 10^-6 F

Ccapacitor C₂ = 2 μF = 2 x 10^-6 F

Ccapacitor C₃ = 3 μF = 3 x 10^-6 F

Phapang e ka bang teng ho capacitor C₂ (V₂) = Li-volt tse 4

o ne a batla : Tefiso ea motlakase ho capacitor C₃ (Q₃)

Tharollo:

(A) Tefiso ea motlakase ho capacitor C₃

Phapang e ka bang teng ho capacitor C₃ :

Li-capacitor li hokahantsoe ka nako e le 'ngoe e le hore phapang e ka bang teng ho capacitor C₃ (V₃) = phapang e ka bang teng ho capacitor C₂ (V₂) = phapang e ka bang teng ho capacitor C₁ (V₁) = phapang e ka bang teng ho capacitor e lekanang (V) = 4 Volt

Tefiso ea motlakase ho capacitor C₁ :

Q₁ =C₁ V₁ = (4 x 10^-6)(4) = 16 x 10^-6 C

Q₁ = 16 μC

Tefiso ea motlakase ho capacitor C₂ :

Q₂ =C₂ V₂ = (2 x 10^-6)(4) = 8 x 10^-6 C

Q₂ = 8 μC

Tefiso ea motlakase ho capacitor C₃ :

Q₃ =C₃ V₃ = (3 x 10^-6)(4) = 12 x 10^-6 C

Q₃ = 12 μC

(B) Tefiso ea motlakase holim'a capacitor e lekanang

P = P₁ +Q₂ +Q₃

Q = 16 μC + 8 μC + 12 μEA-36-C μC

Tharollo e 'ngoe:

Bokgoni bo lekanang:

C = C₁ + C.₂ + C.₃

EA-4-C μF+2 μF+3 μF=9 μF

C = 9 x 10^-6 F

Phapang e ka bang teng ho capacitor e lekanang:

V₁ =V₂ =V₃ = V = 4 Volt

Tefiso ea motlakase ho capacitor e lekanang:

Q = CV = (9 x 10)^-6)(4) = 36 x 10^-6 C

Q = 36 μC

Bala haholoanyane