Mohlala oa potso ea puisano mabapi le tharollo ea stoichiometry

Mohlala oa Potso ea Puisano mabapi le Stoichiometry ea Tharollo

Stoichiometry ke lekala la k'hemistri le ithutang kamano ea bongata pakeng tsa li-reactants le lihlahisoa karabelong ea lik'hemik'hale. Stoichiometry ea tharollo e totobetse haholoanyane, kaha e shebane le liketso tsa lik'hemik'hale tse hlahang ka har'a solvent, hangata metsing. Sehloohong sena, re tla tšohla mehlala ea mathata a amanang le stoichiometry ea tharollo ho utloisisa mohopolo ona hamolemo.

Mehopolo ea Motheo ea Tharollo Stoichiometry

Pele re kena lipotsong tsa mohlala, ho na le likhopolo tse ling tsa motheo tseo re hlokang ho li utloisisa:

1. Molarity (M): Khatello ea tharollo e hlahisoa ka molarity. Molarity ke palo ea li-moles tsa solute ka litara ea tharollo (mol/L).
2. Mol: Yuniti ya bongata ba ntho eo ho yona ho nang le dikarolwana tsa Avogadro (6.022 x 10²³).
3. Bophahamo ba Tharollo: Hangata e lekanngoa ka lilithara (L).

Ka kutloisiso ena ea motheo, re se re loketse ho fetela mathateng le litharollong tsa mohlala.

Mohlala oa Potso ea 1: Ho Bala Molarity oa Tharollo

Potso:
Kaha digrama tse 5 tsa NaCl (Sodium Chloride) di qhibilihiswa ka hara 250 mL ya metsi, molarity ya tharollo ya NaCl ke efe?

Tharollo:

1. Bala palo ea li-moles tsa NaCl:
– Boima ba limolek'hule (BM) ba NaCl: Na (23) + Cl (35.5) = 58.5 g/mol
– Palo ea li-moles = Boima / BM
``
Palo ea li-moles tsa NaCl = 5 g / 58.5 g/mol ≈ 0.0855 mol
``
2. Fetola bophahamo ba tharollo ho tloha ho mL ho ea ho L:
``
Bophahamo ba tharollo = 250 mL = 0.250 L
``
3. Bala molarity (M):
``
Molarity (M) = Palo ea li-moles / Bophahamo ba tharollo
= 0.0855 mol / 0.250 L
≈ 0.342 M
``
Kahoo, molarity ea tharollo ea NaCl ke 0.342 M.

Mohlala oa Potso ea 2: Karabelo ea ho se nke lehlakore

Potso:
Ke bolumo bofe ba tharollo ea 0.5 M HCl bo hlokahalang ho kokobetsa 50 mL ea tharollo ea 0.1 M NaOH?

Tharollo:
Likarabelo tse hlahang:
``
HCl + NaOH → NaCl + H₂O
``
Karabelo ena e etsahala ka karolelano ea 1: 1.

1. Bala palo ea li-moles tsa NaOH:
``
Palo ea li-moles tsa NaOH = Molarity x Volume
= 0.1 M x 0.050 L
= 0.005 mol
``
2. Hobane karolelano ea karabelo ke 1:1, palo ea li-moles tsa HCl = palo ea li-moles tsa NaOH = 0.005 mol.

3. Bala bophahamo ba tharollo ea HCl e hlokahalang:
``
Moqolo oa HCl = Palo ea li-moles / Molarity
= 0.005 mol / 0.5 M
= 0.01 L (kapa 10 mL)
``
Kahoo, bophahamo ba tharollo ea 0.5 M HCl ke 10 mL.

Mohlala oa Potso ea 3: Titration ea Asiti-Base

Potso:
Tharollo ea 25 mL ea CH₃COOH (acetic acid) e kenngoa ka tharollo ea 0.1 M NaOH ho ea ntlheng ea tekano. 30 mL ea tharollo ea NaOH ea hlokahala ho fihlela ntlha ea tekano. Bala molarity oa tharollo ea CH₃COOH.

Tharollo:
Likarabelo tse hlahang:
``
CH₃COOH + NaOH → CH₃COONA + H₂O
``
Karabelo ena e boetse e etsahala ka karolelano ea 1: 1.

1. Bala palo ea li-moles tsa NaOH tse sebelisitsoeng:
``
Palo ea li-moles tsa NaOH = Molarity x Volume
= 0.1 M x 0.030 L
= 0.003 mol
``
2. Palo ea li-moles tsa CH₃COOH e tšoana le palo ea li-moles tsa NaOH tse arabelitsoeng (karolelano ea 1:1):
``
Palo ea li-moles tsa CH₃COOH = 0.003 mol
``
3. Bala molarity oa CH₃COOH:
``
Molarity (M) = Palo ea li-moles / Bolumo
= 0.003 mol / 0.025 L
= 0.12 M
``
Kahoo, molarity ea tharollo ea CH₃COOH ke 0.12 M.

Mohlala oa Potso ea 4: Ho Hlapolloa ha Tharollo

Potso:
Ke bophahamo bofe ba metsi bo lokelang ho eketsoa ho qhibilihisa 100 mL ea tharollo ea 1 M H₂SO₄ e le hore mahloriso a eona a be 0.25 M?

Tharollo:

1. Sebelisa foromo ea ho hlapolla (M₁V₁ = M₂V₂):
– M₁ = 1 M
– V₁ = 100 mL
– M₂ = 0.25 M

2. Bala V₂:
``
M₁V₁ = M₂V₂
1 M x 100 mL = 0.25 M x V₂
V₂ = (1 x 100) / 0.25
= 400 mL
``
3. Bala bophahamo ba metsi a lokelang ho eketsoa:
``
Bophahamo ba metsi bo ekelitsoeng = V₂ – V₁
= 400 mL – 100 mL
= 300 mL
``
Kahoo, ho hlokahala ho eketsa 300 mL ea metsi ho hlapolla tharollo ea H₂SO₄ ho tloha ho 1 M ho isa ho 0.25 M.

Mohlala oa Potso ea 5: Karabelo ea Pula

Potso:
Ke digrama tse kae tsa AgCl precipitate tse bopilweng ha 100 mL ya tharollo ya 0.1 M AgNO₃ e kopantswe le 100 mL ya tharollo ya 0.1 M NaCl?

Tharollo:
Likarabelo tse hlahang:
``
AgNO₃ + NaCl → AgCl (pula) + NaNO₃
``
Karabelo ena e etsahala ka karolelano ea 1: 1.

1. Bala palo ea li-moles tsa AgNO₃ le NaCl:
``
Palo ea li-moles tsa AgNO₃ = Molarity x Volume
= 0.1 M x 0.100 L
= 0.01 mol
Palo ea li-moles tsa NaCl = Molarity x Volume
= 0.1 M x 0.100 L
= 0.01 mol
``

2. Hobane karolelano ea karabelo ke 1:1, palo ea li-moles tsa AgCl tse entsoeng = Palo ea li-moles tsa AgNO₃ kapa NaCl:
``
Palo ea li-moles tsa AgCl = 0.01 mol
``

3. Bala boima ba AgCl:
– Boima ba limolek'hule ba AgCl = Ag (107.87) + Cl (35.45) = 143.32 g/mol
``
Boima ba AgCl = Palo ea li-moles x BM
= 0.01 mol x 143.32 g/mol
= 1.4332 g
``
Kahoo, boima ba AgCl precipitate bo entsoeng ke ligrama tse 1.4332.

Qetello

Sengoloa sena se buile ka mehlala e 'maloa ea mathata le litharollo mabapi le stoichiometry ea tharollo, ho kenyeletsoa ho bala molarity, karabelo ea neutralization, titrations ea acid-base, dilution, le ho thehoa ha precipitate. Ka ho utloisisa mehlala ena, re ka utloisisa hamolemo hore na mohopolo oa stoichiometry ea tharollo o sebelisoa joang maemong a sebele. Stoichiometry ea tharollo ha e bohlokoa feela thutong ea k'hemistri empa hape e na le lits'ebetso tse pharaletseng masimong a fapaneng joalo ka khemistri, biochemistry le indasteri ea lik'hemik'hale.

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