Mehlala ea lipotso tse buang ka Litekanyetso tsa Trigonometric

Mehlala ea Lipotso tse Buisanang ka Litekanyetso tsa Trigonometric

Trigonometry ke lekala la lipalo le ithutang likamano pakeng tsa mahlakore le likhutlo tsa khutlotharo. Karolo e 'ngoe ea bohlokoa ea trigonometry ke ho utloisisa likarohano tsa trigonometric, ho kenyeletsoa sine (sin), cosine (cos), le tangent (tan). Sehlooho sena se tla tšohla mehlala e 'maloa ea likarohano tsa trigonometric le litlhaloso tsa tsona tse qaqileng ho nolofatsa kutloisiso e tebileng ea likhopolo tsa motheo tsa trigonometric.

Mohlala oa Potso ea 1: Ho Bala Litekanyetso tsa Sebe, Cos, le Tan

Potso:
Seithuti se kopuoa ho fumana boleng ba sin, cos, le tan ea angle \( \theta \) ka khutlotharo e nepahetseng, haeba bolelele ba lehlakore le fapaneng (angle e fapaneng \(\theta \)) e le 3 cm, bolelele ba lehlakore le haufi (botlaase) ke 4 cm, 'me bolelele ba hypotenuse (hypotenuse) e le 5 cm.

Puisano:
Mohato oa pele ke ho khetholla lehlakore ka leng le amanang le sekhutlo se fanoeng. Joalokaha ho tsejoa, ka khutlotharo e nepahetseng e nang le mahlakore a triple ea khale ea Pythagorean (3, 4, 5), re ka sebelisa mekhoa ea motheo ea trigonometric ka ho toba.

– Sine (sebe) ke karolelano pakeng tsa bolelele ba lehlakore le fapaneng le hypotenuse.
\[
\sin(\theta) = \frac{\text{obverse side}}{\text{hypotenuse}} = \frac{3}{5}
\]

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– Cosine (cos) ke karolelano pakeng tsa bolelele ba lehlakore le haufi le hypotenuse.
\[
\cos(\theta) = \frac{\text{adjacent side}}{\text{hypotenuse}} = \frac{4}{5}
\]

– Tangent (botsho) ke karolelano pakeng tsa bolelele ba lehlakore le ka pele le lehlakore.
\[
\tan(\theta) = \frac{\text{front side}}{\text{side side}} = \frac{3}{4}
\]

Kahoo, boleng ba dikarolelano tsa trigonometric bakeng sa angle \(\theta\) ke:
\[
\sin(\theta) = \frac{3}{5}, \quad \cos(\theta) = \frac{4}{5}, \quad \tan(\theta) = \frac{3}{4}
\]

Mohlala oa Potso ea 2: Ho Fumana Mahlakore a Khutlotharo ho Sebelisa Litekanyetso tsa Trigonometric

Potso:
Fana ka khutlotharo e nepahetseng e nang le sekhutlo \( \alpha = 30^\circ \). Haeba bolelele ba lehlakore le fapaneng la sekhutlo \( \alpha \) e le 4 cm, fumana bolelele ba lehlakore le leng.

Puisano:
Ho sebelisa boleng ba karolelano ea trigonometric bakeng sa angle \( 30^\circ \):

– \(\sin(30^\circ) = \frac{1}{2} \)
\[
\sin(30^\circ) = \frac{\text{front side}}{\text{hypotenuse}} = \frac{4}{\text{hypotenuse}}
\]
\[
\text{Hypotenuse} = \frac{4}{\sin(30^\circ)} = \frac{4}{\frac{1}{2}} = 8 \text{ cm}
\]

– \(\cos(30^\circ) = \frac{\sqrt{3}}{2} \)
\[
\cos(30^\circ) = \frac{\text{adjacent side}}{\text{hypotenuse}} = \frac{\text{adjacent side}}{8}
\]
\[
\text{Side side} = 8 \cos(30^\circ) = 8 \times \frac{\sqrt{3}}{2} = 4\sqrt{3} \text{cm}
\]

Kahoo, bolelele ba lehlakore le leng ke \(4\sqrt{3}\) cm mme hypotenuse ke 8 cm.

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Mohlala oa 3: Ho Sebelisa Trigonometry ho Cartesian Coordinates

Potso:
Fumana boleng ba sin, cos, le tan bakeng sa ntlha \( P(3, 4) \) ho li-coordinate tsa Cartesian haeba ntlha e etsa sekhutlo \(\theta\) ka x-axis e ntle ho quadrant I.

Puisano:
Taba ea pele, bala sebaka sa ntlha \(P(3, 4)\) ho tloha tšimolohong (O), e leng hypotenuse ea khutlotharo e entsoeng.

– Hypotenuse (\(r\)) e ka balwa ho sebediswa theorem ya Pythagorean:
\[
r = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5
\]

Ebe, trigonometry ea ntlha P e ka baloa ka tsela e latelang:

– Sine (sin) ke karolelano pakeng tsa ordinate (y) le hypotenuse (r):
\[
\sin(\theta) = \frac{y}{r} = \frac{4}{5}
\]

– Cosine (cos) ke karolelano pakeng tsa abscissa (x) le hypotenuse (r):
\[
\cos(\theta) = \frac{x}{r} = \frac{3}{5}
\]

– Tangent (tan) ke karolelano pakeng tsa ordinate (y) le abscissa (x):
\[
\tan(\theta) = \frac{y}{x} = \frac{4}{3}
\]

Kahoo, boleng ba trigonometric bakeng sa ntlha P ke:
\[
\sin(\theta) = \frac{4}{5}, \quad \cos(\theta) = \frac{3}{5}, \quad \tan(\theta) = \frac{4}{3}
\]

Mohlala oa Potso ea 4: Ho Sebelisa Boitsebiso ba Trigonometric

Potso:
Haeba \( \sin(\theta) = \frac{3}{5} \), fumana boleng ba \( \cos(\theta) \) o sebedisa boitsebiso ba trigonometric \( \sin^2(\theta) + \cos^2(\theta) = 1 \).

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Puisano:
Re qala ka boitsebiso ba motheo ba trigonometric:
\[
\sin^2(\theta) + \cos^2(\theta) = 1
\]

Ha ho fanoe ka \( \sin(\theta) = \frac{3}{5} \), ebe:
\[
\sin^2(\theta) = \left(\frac{3}{5}\right)^2 = \frac{9}{25}
\]
\[
\sin^2(\theta) + \cos^2(\theta) = 1
\]
\[
\frac{9}{25} + \cos^2(\theta) = 1
\]
\[
\cos^2(\theta) = 1 – \frac{9}{25} = \frac{25}{25} – \frac{9}{25} = \frac{16}{25}
\]
\[
\cos(\theta) = \pm \sqrt{\frac{16}{25}} = \pm \frac{4}{5}
\]

Boleng ba \( \cos(\theta) \) e ka ba bo botle kapa bo bobe ho latela quadrant eo angle \(\theta\) e leng ho yona. Empa bakeng sa bothata bona ntle le tlhaloso e hlakileng ya quadrant, re sebedisa \(\cos(\theta) = \frac{4}{5}\) bakeng sa quadrant I kapa \( -\frac{4}{5}\) bakeng sa quadrants II, III, kapa IV.

Qetello

Ho utloisisa dikarolelano tsa trigonometric ho bohlokoa bakeng sa ho rarolla mathata a fapaneng a kenyeletsang dikhutlo le bolelele dikhutlotharong. Ka ho itloaetsa ho rarolla mathata a kang a ka hodimo, o ka ntlafatsa bokgoni ba hao ba ho bala le ho utlwisisa dikamano pakeng tsa mahlakore le dikhutlo dikhutlotharong. Trigonometry ha e sebediswe feela dipalong tse hlwekileng empa hape le mafapheng a fapaneng a saense jwalo ka fisiks, boenjiniere le bolepi ba dinaledi. Ho thabile ho itloaetsa!

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