Mehlala ea lipotso mabapi le matla le maemo a matla a molumo

Mehlala e 11 ea Matla a Molumo le Maemo a Molumo

1. Molumo o na le matla a 1 x 10^-9 W / limithara²Boemo ba matla a di-decibel (dB) ke bofe?
Puisano
Hoa tsebahala hore:
Ke = 1 x 10^-9 W / limithara²
I_o = 1x10^-12 W / limithara²
Potso: Boemo ba Matla (dB)?
Karabo:

2. Boemo ba matla a molumo ka phapusing ke 100 dB. Matla a molumo ka phapusing ke afe?
Puisano
Hoa tsebahala hore:
TI = 100 dB
I_o = 1x10^-12 W / limithara²
Potso: Matla a modumo (I) ka phapusing?
Karabo:

3. Maqhubu a mabeli a molumo a na le matla a 1 x 10^-5 W / limithara² le 1 x 10^-4 W / limithara²Phapang maemong a matla ho dB ke…
Puisano
Hoa tsebahala hore:
I₁ = 10^-5 W / limithara²
I₂ = 10^-4 W / limithara²
I_o = 10^-12 W / limithara²
Potso: Phapang boemong ba matla (TI) ho dB?
Karabo:
Phapang maemong a matla?
TI₁ – IT₂ = 80 dB -70 dB = 10 dB

4. Fumana karolelano ea matla a melumo e 'meli eo maemo a matla a eona e leng 10 dB le 40 dB.
Puisano
Hoa tsebahala hore:
TI₁ = 10dB
TI₂ = 40dB
I_o = 10^-12 W / limithara²
E botsitsweng: Papiso ya matla a medumo e mmedi (I₁ : Ke₂)?
Karabo:

Papiso ea matla a mehloli e 'meli ea molumo:
I₁ : Ke₂
10^-11 : 10^-8

5. Boemo ba matla a modumo ba dipiloto tse sekete tse tshwanang tse letswang mmoho ke 60 dB. Haeba dipiloto tse 10 tse tshwanang di letswa mmoho, boemo ba matla bo fetoha….

1. 40 dB
2. 50 dB
3. 60 dB
4. 70 dB
5. 90 dB

Puisano

Hoa tsebahala hore:
Lipiloto tsa TI 1000 = 60 dB
O botsitse: Melumo ea boemo ba 10 ea matla
Karabo:

Boemo ba matla a mololi o le mong:
TI 1000 meloli = TI meloli e le 'ngoe + 10 log x
60 = TI + 10 log 1000
60 = TI + 10 log 10³
60 = TI + (3)(10)(log 10)
60 = TI + (3)(10)(1)
60 = TI + 30
TI = 60 - 30
TI = 30 dB
Boemo ba matla ba mololi o le mong ke 30 dB.

Boemo ba matla a mololi o le mong:
TI 10 meloli = TI meloli e le 'ngoe + 10 log x
TI 10 meloli = 30 + 10 log 10
TI 10 meloli = 30 + 10 log 10¹
TI 10 meloli = 30 + (1)(10)(log 10)
TI 10 meloli = 30 + (1)(10)(1)
TI 10 meloli = 30 + 10
Lipiloto tsa TI 10 = 40 dB
Boemo ba matla a melumo e 10 ke 40 dB.
Karabo e nepahetseng ke A.

6. Boemo ba matla a molumo ba mechini e le 100 e tšoanang fekthering ea masela e sebetsang ka nako e le 'ngoe ke 80 dB. Haeba boemo ba matla a molumo ba mechini e meng e mengata e tšoanang e le 90 dB, joale palo ea mechini e sebelisoang ka nako eo ke….

1. 1.000 likotoana
2. 500 likotoana
3. 100 likotoana
4. 50 likotoana
5. 10 likotoana

Puisano
Hoa tsebahala hore:
Mochini oa TI 100 = 80 dB
O botsitse: palo ea mechini e nang le boemo ba matla ba 90 dB
Karabo:
Boemo ba matla a mochini o le mong:
Mechini ea TI 100 = TI mochini o le mong + 10 log x
80 = TI + 10 log 100
80 = TI + 10 log 10²
80 = TI + (2)(10)(log 10)
80 = TI + (2)(10)(1)
80 = TI + 20
TI = 80 - 20
TI = 60 dB
Boemo ba matla a mochini o le mong ke 60 dB.

Palo ea mechini e nang le boemo ba matla ba 90 dB:
TI x mochini = TI mochini o le mong + 10 log x
90 = 60 + 10 log x
90 – 60 = 10 log x
30 = 10 log x
30 / 10 = log x
3 = logong x
3 = logong 1000

kena 1000 = log 10³ = (3)(log 10) = (3)(1) = 3.

Palo ea mechini e nang le matla a 90 dB ke 1000.
Karabo e nepahetseng ke A.

7. Matla a modumo ntlheng ya P e leng dimithara tse 3 ho tloha mohloding wa modumo ke dimithara tse 10^-4 watts/m²Ntlha ea R e bohōle ba limithara tse 300 ho tloha mohloling oa molumo. Haeba moeli oa matla I₀ = 10^-12 watts/m², ebe papiso ea maemo a matla lintlheng tsa P le R ke…

K. 1: 2
B. 2: 1
C. 2: 3
D. 2: 4
E. 3: 4

Puisano
Hoa tsebahala :
Matla a molumo ntlheng ea P (I)_P= 10^-4 W / limithara²
Sebaka sa ntlha P ho tloha mohloling oa molumo (r_P) = limithara tse 3
Sebaka sa ntlha R ho tloha mohloling oa molumo (r_R) = limithara tse 300
Matla a monyako (I)_o= 10^-12 Watt/m²
E botsitsoe Papiso ea maemo a matla lintlheng tsa P le R (TI)_P : IT_R)
Jawab :

Foromo ea kamano pakeng tsa matla le sebaka :
I_p r_p² = KE_R r_R²
Matla a molumo ho R :
(10^-4(3)²) = (Ke_R(300)²)
(10^-4)(9) = (Ke_R)(90000)
9: x 10^-4 = (Ke_R)(9 x 10⁴)
I_R = 9x10^-4 : 9 x 10^-4
I_R = 10^-8
Matla a molumo ntlheng ea R ke 10^-8 W / limithara².
Boemo ba matla ho P :
Boemo ba matla ho R :
Papiso ea TI lintlheng tsa P le R :
80 dB: 40 dB
2: 1
Karabo e nepahetseng ke B.

8. Matla a modumo ntlheng ya A e leng mithara e le 1 ho tloha mohloding wa modumo ke 10^-7 W / limithara²Ntlha ea B e bohōle ba limithara tse 100 ho tloha mohloling oa molumo. Haeba matla a moeli a le 10^-12 W / limithara², papiso ea maemo a matla ho A le B ke…

K. 5: 3
B. 5: 1
C. 4: 5
D. 4: 3
E. 3: 1

Puisano
Hoa tsebahala :
Matla a molumo ntlheng ea A (I)_A= 10^-7 W / limithara²
Sebaka sa ntlha A ho tloha mohloling oa molumo (r)_A) = limithara tse 1
Sebaka sa ntlha B ho tloha mohloling oa molumo (r)_R) = limithara tse 100
Matla a monyako (I)_o= 10^-12 Watt/m²
E botsitsoe Papiso ea maemo a matla lintlheng tsa A le B_A : IT_B)
Jawab :
Foromo ea kamano pakeng tsa matla le sebaka :
I_A r_A² = KE_B r_B²
Matla a molumo ntlheng ea B :
(10^-7(1)²) = (Ke_B(100)²)
(10^-7)(1) = (Ke_B)(10.000)
1: x 10^-7 = (Ke_B)(1 x 10⁴)
I_B = 10^-7 : 10⁴
I_B = 10^-11
Matla a molumo ntlheng ea R ke 10^-11 W / limithara².
Boemo ba matla ntlheng ea A :
Boemo ba matla ntlheng ea B :
Papiso ea IT lintlheng tsa A le B :
50 dB: 10 dB
5: 1
Karabo e nepahetseng ke B.

9. Lintlha tsa A le B li na le sebaka sa 800 m le 400 m ka ho latellana ho tloha mohloling oa molumo. Haeba sebakeng sa A u utloa molumo o matla a 10^-3 W / limithara², joale papiso ea maemo a matla a lintlha A le B ke… (log 2 = 0,3 le I_o = 10^-12 W / limithara²)
K. 11: 15
B. 15: 11
C. 15: 16
D. 16: 11
E. 16: 15
Puisano
Hoa tsebahala :
Matla a molumo ntlheng ea A (I)_A= 10^-3 W / limithara²
Sebaka sa ntlha A ho tloha mohloling oa molumo (r)_A) = limithara tse 800
Sebaka sa ntlha B ho tloha mohloling oa molumo (r)_B) = limithara tse 400
Matla a monyako (I)_o= 10^-12 Watt/m²
Log 2 = 0,3
E botsitsoe Papiso ea maemo a matla lintlheng tsa A le B (TI)_A : IT_B)
Jawab :
Foromo ea kamano pakeng tsa matla le sebaka :
I_A r_A² = KE_B r_B²
Matla a molumo ntlheng ea B :
(10^-3(800)²) = (Ke_B(400)²)
(10^-3)(640.000) = (Ke_B)(160.000)
(10^-3)(64) = (Ke_B)(16)
(10^-3)(4) = (Ke_B)(1)
I_B = 4x10^-3 : 1
I_B = 4x10^-3
Matla a molumo ntlheng ea B ke 4 x 10^-3 W / limithara².
Boemo ba matla ntlheng ea A :
Boemo ba matla ntlheng ea B :
Karolelano ea TI lintlheng tsa P le R ke:
90 dB: 96 dB
15: 16
Karabo e nepahetseng ke C.

 10. Lintlha tsa A le B li bolelele ba limithara tse 3 le limithara tse 8 ho tloha mohloling oa molumo. Haeba ke_A 'me 'na_B e 'ngoe le e 'ngoe ke matla a molumo ntlheng ea A le ntlha ea B, ebe I_A : Ke_B ke …
K. 3: 2
B. 4: 9
C. 9: 4
D. 16: 81
E. 64: 9
Puisano:
Hoa tsebahala :
r_A = 3 m, r_B = 8 limithara
E botsitsoe :
I_A : Ke_B ?
Jawab :
Matla a modumo a lekana ka tsela e fapaneng le sekwere sa sebaka sa ntlha ho tloha mohloding wa modumo:
Karabo e nepahetseng ke E.

11. Sebaka ho tloha A ho ea mohloling oa molumo ke makhetlo a 3/4 ho feta sebaka ho tloha B ho ea mohloling oa molumo. Haeba matla a molumo o utluoang ke A e le I_o, joale matla a utlwileng ke B ke...
A. 1/3 Io
B. 2/3 Io
C. 3/4 Io
D. 9/4 Io
E. 9/16 Io
Puisano:
Hoa tsebahala :
r_A = 3/4r, r_B = r, I_A = KE_o
E botsitsoe :
I_B = ?
Jawab :

Karabo e nepahetseng ke E.

Lipotso mabapi le matla le maemo a matla a molumo

1. Bolo e lahlelwa fatshe ka ho otloloha ho tloha mohahong o nang le mekato e mengata ka lebelo la pele la 4 m/s mme e fihla fatshe kamora metsotswana e 3. Lebelo la bolo ke lefe ha e otla fatshe?
Karabo:
v_t = 30 m/s
2. Lejoe le lahleloa ka hara seliba ka lebelo la pele la 12 m/s mme le otla hodima metsi a seliba ka mora metsotswana e 3. Seliba se tebile hakae?
Karabo:
h = limithara tse 55
3. Ho tloha mohahong o bolelele ba limithara tse 100, sephutheloana se lahleloa ka ho otloloha tlase ka lebelo la 5 m/s. Fumana (a) nako eo sephutheloana se fihlang fatše ka eona (b) Lebelo la sephutheloana ha se fihla fatše
Karabo:
(a) t = metsotsoana e 4 (b) v_t = 45 m/s