Lipotso tsa Mohlala oa Matla a Coulomb

Mehlala e 9 ea Lipotso tsa Coulomb Force

1. Mejaro e meraro e hlophisitsoe joalo ka setšoantšong se ka tlase. Matla a Coulomb a fumanwang ke tjhaja B ke …. (k = 9 x 109 Nm2C-2, 1 μC = 10-6 C)
Mohlala oa Coulomb Force Potso ea 1

A. 09 x 10 1 N ho tjhaja C

B. 09 x 10 1 N ho tjhaja A

C. 18 x 10 1 N ho tjhaja C

D. 18 x 10 1 N ho tjhaja A

E. 36 x 10 1 N ho tjhaja C

Puisano

Hoa tsebahala hore :

q A = 10 µC = 10 x 10 -6 C = 10 -5 Coulombs

q B = 10 µC = 10 x 10 -6 = 10 -5 Li-Coulomb

q C = 20 µC = 20 x 10 -6 = 2 x 10 -5 Coulombs

r AB = limithara tse 0,1 = limithara tse 10 -1

r BC = limithara tse 0,1 = limithara tse 10 -1

k = 9 x 10 9 Nm 2 C −2

E botsitsoe : Sesole sa Coulomb se nang le phihlelo ka lebaka la qoso B

Karabo :

Ho na le mabotho a mabeli a Coulomb kapa matla a motlakase a sebetsang ka tjhaja B, e leng matla a Coulomb pakeng tsa litefiso A le B (F AB ) le matla a Coulomb pakeng tsa litefiso B le C (F BC ). Matla a Coulomb a fumanoang ka tjhaja B a bakoa ke F AB le F BC.

Matla a Coulomb pakeng tsa litefiso A le B:

Mohlala oa Coulomb Force Potso ea 2

Tefiso A ke e ntle mme tefiso B ke e ntle e le hore F AB e ye ho tefiso C.

Matla a Coulomb pakeng tsa litefiso B le C:

Mohlala oa Coulomb Force Potso ea 3

Tefiso B ke e ntle mme tefiso C ke e ntle e le hore F BC e ye ho tefiso A.

Matla a Coulomb a fumanoang ke tjhaja B:

F B = F BC – F AB = 180-90 = 90 N

Boholo ba matla a Coulomb a fumanwang ke tjhaja B (F B ) ke 90 Newtons. Tsela ya F B e tshwana le tsela ya F BC , e leng ho ya ho tjhaja A.

Karabo e nepahetseng ke B.

2. Boholo le tataiso ea matla a Coulomb a tjhajang B ke... ( k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)

Mohlala oa Coulomb Force Potso ea 4

A. 2,5 k Q 2 r -2 ka letsohong le letšehali

B. 2,5 k Q 2 r -2 ka ho le letona

C. 2 k Q 2 r -2 ka letsohong le letšehali

D. 2 k Q 2 r -2 ka ho le letona

E. 1 k Q 2 r -2 ka letsohong le letšehali

Puisano

Hoa tsebahala hore :

Tefiso A (q A ) = +Q

Tefiso B (q B ) = -2Q

Tefiso C (q C ) = -Q

Sebaka se pakeng tsa litefiso A le B (r AB ) = r

Sebaka se pakeng tsa litefiso B le C (r BC ) = 2r

k = 9 x 10 9 Nm 2 C −2

Ho batloa : boholo le tataiso ea lebotho la Coulomb le qosang B

Karabo :

Matla a Coulomb pakeng tsa tjhaja A le tjhaja B:

Mohlala oa Coulomb Force Potso ea 5

Tefiso A ke e ntle mme tefiso B ke e mpe e le hore tsela ya F AB e lebelle ho tefiso A

Matla a Coulomb pakeng tsa tjhaja B le tjhaja C:

Mohlala oa Coulomb Force Potso ea 6

Tefiso B ke e mpe 'me tefiso C ke e mpe kahoo tsela eo F BC e shebaneng le tefiso A ka eona

Matla a hlahang a sebetsang ho qoso ea B:

F = F AB + F BC = 2 k Q 2 /r 2 + 0,5 k Q 2 /r 2 = 2,5 k Q 2 /r 2 = 2,5 k Q 2 r -2

Tsela eo lebotho la Coulomb le shebileng ka yona e lebile ho tjhaja A kapa ka letsohong le letshehadi.

Karabo e nepahetseng ke A.

3. Litefiso tse peli tsa motlakase li behiloe ka thoko joalo ka ha ho bontšitsoe setšoantšong. Tefiso ho A ke 8 µC 'me matla a khahlang a sebetsang liqosong ka bobeli ke 45 N. Haeba tefiso A e fetisetsoa ka ho le letona ka 1 cm le k = 9.10 9 Nm 2 .C -2 , joale matla a khahlang a sebetsang liqosong ka bobeli ke…

A. 45 NMohlala oa Coulomb Force Potso ea 7

B. 60 N

C. 80 N

D. 90 N

E. 120 N

Puisano

Hoa tsebahala hore :

Tefiso ea motlakase ho A (q A ) = 8 µC = 8 x 10 -6 Coulombs

Matla a motlakase pakeng tsa litefiso tse peli (F) = 45 Newton

Sebaka se pakeng tsa litefiso tse peli (r AB ) = 4 cm = 0,04 metres = 4 x 10 -2 metres

E sa fetoheng (k) = 9 x 10 9 Nm 2 .C -2

Potso : Matla a motlakase pakeng tsa litefiso tse peli haeba tjhaja A e fetisetsoa ka ho le letona ka 1 cm kapa 0,01 metres

Karabo :

Qala ka ho bala tjhaja ya motlakase ho B, ebe o bala matla a motlakase pakeng tsa tjhaja tse pedi tsa motlakase, haeba tjhaja ya motlakase ho A e fetiseditswe ka ho le letona ka 1 cm.

Tefiso ea motlakase ho B :

Foromo Molao oa Coulomb :

F = k (q A )(q B ) / r 2

Fr 2 = k (q A )(q B )

q B = F r 2 / k (q A )

Tefiso ea motlakase ho B :

q B = (45)(4 x 10 -2 ) 2 / (9 x 10 9 )(8 x 10 -6 )

q B = (45)(16 x 10 -4 ) / 72 x 10 3

q B = (720 x 10 -4 ) / (72 x 10 3 )

q B = 10 x 10 -7 Coulombs

Matla a motlakase pakeng tsa litefiso tsa motlakase A le B :

Haeba tefiso ho A e fetisetsoa ka ho le letona ka 1 cm, sebaka se pakeng tsa tefiso tse peli e ba 3 cm = 0,03 metres = 3 x 10 -2 metres

F = k (q A )(q B ) / r 2

F = (9 x 10 9 )(8 x 10 -6 )(10 x 10 -7 ) / (3 x 10 -2 ) 2

F = (9 x 10 9 )(80 x 10 -13 ) / (9 x 10 -4 )

F = (1 x 10 9 )(80 x 10 -13 ) / (1 x 10 -4 )

F = (80 x 10 -4 ) / (1 x 10 -4 )

F = 80 Newton

Karabo e nepahetseng ke C.

4. Lichaja tse peli tsa motlakase P le Q tse arohaneng ka 10 cm li na le matla a hohelang a 8 N. Haeba tjhaja Q e fetisetsoa 5 cm ho ea ho tjhaja P (1 µC = 10 -6 C le k = 9 x 10 9 Nm 2 .C -2 ), joale matla a motlakase a hlahang ke...

A. 8 NMohlala oa Coulomb Force Potso ea 8

B. 16 N

C. 32 N

D. 40 N

E. 56 N

Puisano

Hoa tsebahala hore :

Sebaka se pakeng tsa litefiso P le Q (r PQ ) = 10 cm = 0,1 m = 1 x 10 -1 m

Matla a motlakase pakeng tsa litefiso P le Q (F) = 8 N

Tefiso ea motlakase Q (q Q ) = 40 µC = 40 x 10 -6 C

E sa fetoheng (k) = 9 x 10 9 Nm 2 .C -2

Potso : Matla a motlakase pakeng tsa litefiso P le Q haeba tefo Q e fetisetsoa 5 cm ho ea ho tefo P

Karabo :

Qala ka ho bala tjhaja ya motlakase P, ka mora moo bala matla a motlakase pakeng tsa tjhaja tse pedi tsa motlakase, haeba tjhaja ya motlakase Q e fetiseditswe ho 5 cm ho ya tjhaja P.

Tefiso ea motlakase P :

q P = F r 2 / k (q Q )

q P = (8)(1 x 10 -1 ) 2 / (9 x 10 9 )(40 x 10 -6 )

q P = (8)(1 x 10 -2 ) / 360 x 10 3

q P = (8 x 10 -2 ) / (36 x 10 4 )

q P = (1 x 10 -2 ) / (4,5 x 10 4 )

q P = (1/4,5) x 10 -6 Coulomb

Matla a motlakase pakeng tsa litefiso tsa motlakase P le Q :

Haeba tefiso ho Q e fetisetsoa ka letsohong le letšehali ka 5 cm, sebaka se pakeng tsa tefiso tse peli e ba 5 cm = 0,05 metres = 5 x 10 -2 metres

F = k (q P )(q Q ) / r 2

F = (9 x 10 9 )((1/4,5) x 10 -6 )(40 x 10 -6 ) / (5 x 10 -2 ) 2

F = (2 x 10 3 )(40 x 10 -6 ) / (25 x 10 -4 )

F = (80 x 10 -3 ) / (25 x 10 -4 )

F = 3,2 x 10 1

F = 32 Newton

Karabo e nepahetseng ke C.

5. Sheba setšoantšo se latelang sa litefiso tsa motlakase. Matla a motlakase a fumanoang ke tjhaja q B ke 8 N (1 µC = 10 -6 C) le (k = 9.10 9 Nm 2 .C -2 ). Haeba tjhaja q B e fetisetsoa ho 4 cm ho tloha ho A, joale matla a motlakase a fumanoang ke q B joale ke…

A. 2 NMohlala oa Coulomb Force Potso ea 9

B. 4 N

C. 6 N

D. 8 N

E. 10 N

Puisano

Hoa tsebahala hore :

Sebaka se pakeng tsa litefiso A le B (r AB ) = 2 cm = 0,02 m = 2 x 10 -2 m

Matla a motlakase pakeng tsa litefiso A le B (F) = 8 N

Tefiso ea motlakase A (q A ) = 2 µC = 2 x 10 -6 C

E sa fetoheng (k) = 9 x 10 9 Nm 2 .C -2

Potso : Matla a motlakase pakeng tsa litefiso A le B haeba sebaka se pakeng tsa litefiso tse peli e le 4 cm

Karabo :

Qala ka ho bala tjhaja ya motlakase B, ka mora moo bala matla a motlakase pakeng tsa tjhaja tse pedi tsa motlakase haeba sebaka se pakeng tsa tjhaja tse pedi tsa motlakase e le 4 cm = 0,04 metres = 4 x 10 -2 metres.

Tefiso ea motlakase B :

q B = F r 2 / k (q A )

q B = (8)(2 x 10 -2 ) 2 / (9 x 10 9 )(2 x 10 -6 )

q B = (8)(4 x 10 -4 ) / (18 x 10 3 )

q B = (32 x 10 -4 ) / (18 x 10 3 )

q B = (32/18) x 10 -7

q B = (16/9) x 10 -7 Coulombs

Matla a motlakase pakeng tsa litefiso A le B :

F = k (q A )(q B ) / r 2

F = (9 x 10 9 )(2 x 10 -6 )((16/9) x 10 -7 ) / (4 x 10 -2 ) 2

F = (18 x 10 3 )((16/9) x 10 -7 ) / (16 x 10 -4 )

F = (2 x 10 3 )(16 x 10 -7 ) / (16 x 10 -4 )

F = (2 x 10 3 )(1 x 10 -7 ) / (1 x 10 -4 )

F = (2 x 10 -4 ) / (1 x 10 -4 )

F = 2 Newton

Karabo e nepahetseng ke A.

6. Lichaja tse tharo tsa motlakase li behiloe likhutlong tsa khutlotharo ea ABC ka bolelele ba lehlakore AB = BC = 20 cm le boholo ba tjhaja bo tšoanang (q = 2µC) joalo ka setšoantšong se ka lehlakoreng (k = 9.10 9 Nm 2 .C -2 , 1 µ = 10 -6 ). Boholo ba matla a motlakase a sebetsang ntlheng ea B ke….

A. 0,9√3 NMohlala oa Coulomb Force Potso ea 10

B. 0,9√2 N

C. 0,9 N

D. 0,81 N

E. 0,4 N

Puisano

Hoa tsebahala hore:

Tefiso ntlheng ea A (q A ) = 2 µC = 2 x 10 -6 Coulomb

Tefiso ntlheng ea B (q B ) = 2 µC = 2 x 10 -6 Coulomb

Tefiso ntlheng ea C (q C ) = 2 µC = 2 x 10 -6 Coulomb

Sebaka sa B ho isa ho C (r BC ) = 20 cm = 0,2 metres = 2 x 10 -1 metres

Sebaka sa B ho ea ho A (r BA ) = 20 cm = 0,2 metres = 2 x 10 -1 metres

k = 9.10 9 Nm 2 .C -2

Potso: Boholo ba matla a motlakase a sebetsang ntlheng ea B

Karabo:

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le C:

F BC = k (q B )(q C ) / r BC 2

F BC = (9 x 10 9 )(2 x 10 -6 )(2 x 10 -6 ) / (2 x 10 -1 ) 2

F BC = (9 x 10 9 )(4 x 10 -12 ) / (4 x 10 -2 )

F BC = (36 x 10 -3 ) / (4 x 10 -2 )

F BC = 9 x 10 -1

F BC = 0,9 Newton

Tefiso ea motlakase lintlheng tsa B le C e ntle, ka hona tataiso ea matla a motlakase F BC e ka letsohong le letšehali, hole le ntlha ea C.

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le A:

F BA = k (q B )(q A ) / r BA 2

F BA = (9 x 10 9 )(2 x 10 -6 )(2 x 10 -6 ) / (2 x 10 -1 ) 2

F BA = (9 x 10 9 )(4 x 10 -12 ) / (4 x 10 -2 )

F BA = (36 x 10 -3 ) / (4 x 10 -2 )

F BA = 9 x 10 -1

F BA = 0,9 Newton

Tefiso ea motlakase lintlheng tsa B le A e ntle, ka hona tataiso ea matla a motlakase F BA e theohela tlase, hole le ntlha ea A.

Matla a mabeli a motlakase a etsa sekhutlo se nepahetseng, ka hona matla a motlakase a hlahang a sebetsang ntlheng ea B a baloa ho sebelisoa foromo ea Pythagorean.

Mohlala oa Coulomb Force Potso ea 11

Karabo e nepahetseng ke B.

7. Sheba setšoantšo se latelang!

Lichaja tse tharo Q 1 , Q 2 , le Q 3 li behiloe lintlheng tsa khutlotharo e ka letsohong le letona ABC. Bolelele ba AB = BC = 30 cm. Ha ho fanoe ka k = 9.10 9 Nm 2 .C -2 le 1 µ = 10 -6 joale matla a Coulomb a hlahang holim'a tjhaja Q 1 ke….

A. 1 NMohlala oa Coulomb Force Potso ea 12

B. 5 N

C. 7 N

D. 10 N

E. 12 N

Puisano

Hoa tsebahala hore:

Tefiso ntlheng ea A (q A ) = 3 µC = 3 x 10 -6 Coulomb

Tefiso ntlheng ea B (q B ) = -10 µC = -10 x 10 -6 Coulomb

Tefiso ntlheng ea C (q C ) = 4 µC = 4 x 10 -6 Coulomb

Sebaka sa B ho isa ho C (r BC ) = 30 cm = 0,3 metres = 3 x 10 -1 metres

Sebaka sa B ho ea ho A (r BA ) = 30 cm = 0,3 metres = 3 x 10 -1 metres

k = 9.10 9 Nm 2 .C -2

Potso: Matla a Coulomb a hlahang ntlheng ea B

Karabo:

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le C:

F BC = k (q B )(q C ) / r BC 2

F BC = (9 x 10 9 )(10 x 10 -6 )(4 x 10 -6 ) / (3 x 10 -1 ) 2

F BC = (9 x 10 9 )(40 x 10 -12 ) / (9 x 10 -2 )

F BC = (360 x 10 -3 ) / (9 x 10 -2 )

F BC = 40 x 10 -1

F BC = 4 Newton

Tefiso ea motlakase ntlheng ea B ke e mpe 'me tefiso ea motlakase ntlheng ea C ke e ntle, ka hona tsela ea matla a motlakase F BC e ka letsohong le letona ho ea ntlheng ea C.

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le A:

F BA = k (q B )(q A ) / r BA 2

F BA = (9 x 10 9 )(10 x 10 -6 )(3 x 10 -6 ) / (3 x 10 -1 ) 2

F BA = (9 x 10 9 )(30 x 10 -12 ) / (9 x 10 -2 )

F BA = (270 x 10 -3 ) / (9 x 10 -2 )

F BA = 30 x 10 -1

F BA = 3 Newton

Tefiso ea motlakase ntlheng ea B ke e mpe 'me tefiso ea motlakase ntlheng ea A ke e ntle, ka hona tataiso ea matla a motlakase F BA e ea holimo ho ea ntlheng ea A.

Matla a mabeli a motlakase a etsa sekhutlo se nepahetseng, ka hona matla a motlakase a hlahang a sebetsang ntlheng ea B a baloa ho sebelisoa foromo ea Pythagorean.

Mohlala oa Coulomb Force Potso ea 13

Karabo e nepahetseng ke B.

8. Litefiso tse tharo tsa motlakase li behiloe likhutlong tsa khutlotharo ABC ka bolelele ba lehlakore AB = BC = 20 cm le boholo bo tšoanang ba tefo (q = 2µC) joalo ka setšoantšong se ka lehlakoreng (k = 9.109 Nm2.C-2, 1 µ = 10-6Boholo ba matla a motlakase Mohlala oa Coulomb Force Potso ea 14ho sebetsa ntlheng ea B ke….

  1. 0,9√3 N
  2. 0,9√2 N
  3. 0,9 N
  4. 0,81 N
  5. 0,4 N

Puisano

Hoa tsebahala hore:
Tefiso ntlheng ea A (q)A) = 2 µC = 2 x 10-6 Coulomb
Tefiso ntlheng ea B (q)B) = 2 µC = 2 x 10-6 Coulomb
Tefiso ntlheng ea C (q)C) = 2 µC = 2 x 10-6 Coulomb
Sebaka ho tloha ho B ho ea ho C (r)BC) = 20 cm = 0,2 limithara = 2 x 10-1 mitha
Sebaka ho tloha ho B ho ea ho A (r)BA) = 20 cm = 0,2 limithara = 2 x 10-1 mitha
k =9.109 Nm2.C-2
O botsitse: Boholo ba matla a motlakase a sebetsang ntlheng ea B
Karabo:

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le C:
FBC = k (qB(q)(q)C) / rBC2
FBC = (9 x 109)(2 x 10-6)(2 x 10-6) / (2 x 10-1)2
FBC = (9 x 109)(4 x 10-12) / (4 x 10-2)
FBC = (36 x 10-3) / (4 x 10-2)
FBC = 9x10-1
FBC = 0,9 Newton
Tefiso ea motlakase lintlheng tsa B le C e ntle, ka hona tataiso ea matla a motlakase F keBC ka letsohong le letšehali, hole le ntlha ea C.

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le A:
FBA = k (qB(q)(q)A) / rBA2
FBA = (9 x 109)(2 x 10-6)(2 x 10-6) / (2 x 10-1)2
FBA = (9 x 109)(4 x 10-12) / (4 x 10-2)
FBA = (36 x 10-3) / (4 x 10-2)
FBA = 9x10-1
FBA = 0,9 Newton
Tefiso ea motlakase lintlheng tsa B le A e ntle, ka hona tataiso ea matla a motlakase F keBA tlase, hole le ntlha ya A.

Matla a mabeli a motlakase a etsa sekhutlo se nepahetseng, ka hona matla a motlakase a hlahang a sebetsang ntlheng ea B a baloa ho sebelisoa foromo ea Pythagorean.
Mohlala oa Coulomb Force Potso ea 15Karabo e nepahetseng ke B.

9. Sheba setšoantšo se latelang!
Litefiso tse tharo Q1,Q2, le Q3 e ntlheng ea khutlotharo e ka letsohong le letona ABC. Bolelele ba AB = BC = 30 cm. Hoa tsebahala hore Mohlala oa Coulomb Force Potso ea 16k =9.109 Nm2.C-2 le 1 µ = 10-6 ebe lebotho la Coulomb le hlahang le qosang Q1 ke….

  1. 1 N
  2. 5 N
  3. 7 N
  4. 10 N
  5. 12 N

Puisano
Hoa tsebahala hore:
Tefiso ntlheng ea A (q)A) = 3 µC = 3 x 10-6 Coulomb
Tefiso ntlheng ea B (q)B) = -10 µC = -10 x 10-6 Coulomb
Tefiso ntlheng ea C (q)C) = 4 µC = 4 x 10-6 Coulomb
Sebaka ho tloha ho B ho ea ho C (r)BC) = 30 cm = 0,3 limithara = 3 x 10-1 mitha
Sebaka ho tloha ho B ho ea ho A (r)BA) = 30 cm = 0,3 limithara = 3 x 10-1 mitha
k =9.109 Nm2.C-2
O botsitse: Matla a Coulomb a hlahang ntlheng ea B
Karabo:
Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le C:
FBC = k (qB(q)(q)C) / rBC2
FBC = (9 x 109)(10 x 10-6)(4 x 10-6) / (3 x 10-1)2
FBC = (9 x 109)(40 x 10-12) / (9 x 10-2)
FBC = (360 x 10-3) / (9 x 10-2)
FBC = 40x10-1
FBC = 4 Newton
Tefiso ea motlakase ntlheng ea B ke e mpe 'me tefiso ea motlakase ntlheng ea C ke e ntle, ka hona tataiso ea matla a motlakase F keBC ka letsohong le letona ho ya ntlheng ya C.

Matla a motlakase pakeng tsa litefiso tse libakeng tsa B le A:
FBA = k (qB(q)(q)A) / rBA2
FBA = (9 x 109)(10 x 10-6)(3 x 10-6) / (3 x 10-1)2
FBA = (9 x 109)(30 x 10-12) / (9 x 10-2)
FBA = (270 x 10-3) / (9 x 10-2)
FBA = 30x10-1
FBA = 3 Newton
Tefiso ea motlakase ntlheng ea B ke e mpe 'me tefiso ea motlakase ntlheng ea A ke e ntle, ka hona tataiso ea matla a motlakase F keBA ho ea fihla ntlheng ea A.
 
Matla a mabeli a motlakase a etsa sekhutlo se nepahetseng, ka hona matla a motlakase a hlahang a sebetsang ntlheng ea B a baloa ho sebelisoa foromo ea Pythagorean.
Mohlala oa Coulomb Force Potso ea 18Karabo e nepahetseng ke B.

Mohloli oa lipotso:

Lipotso tsa Fisiks tsa Tlhahlobo ea Naha bakeng sa Sekolo se Phahameng sa Thuto e Phahameng/Sekolo se Phahameng sa Mosebetsi

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