Mehlala e 14 ea Lipotso tsa Matla a Likaroloana
1. Boloko A e nang le boima ba 5 kg e beoa holim'a sebaka se bataletseng se boreleli, boloko B e nang le boima ba 3 kg e fanyehoa ka thapo 'me e hokahantsoe le boloko A ka pulley, haeba g = 10 m/s 2 e fumana lebelo la boloko!
A. 3,50 m/s2
B. 3,75 m/s 2
C. 4,00 m/s 2
D. 5,00 m/s 2
E. 5,25 m/s 2
Puisano
Hoa tsebahala hore:
Boreledi bo bataletseng.
Boima ba boloko A (m A ) = 5 kg
Boima ba boloko B (m B ) = 3 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Boima ba boloko B (w B ) = m B g = (3)(10) = 30 Newton
Potso: Ho potlaka ha boloko (a)
Karabo:
Bokaholimo bo bataletseng bo boreleli kahoo ha ho na matla a khohlano a thibelang motsamao oa boloko A. Matla a tsamaisang sistimi ea boloko ke boima ba boloko B.
ΣF = ma
w B = (m A + m B ) a
30 = (5 + 3) a
30 = 8 a
a = 30/8
a = 3,75 m/s 2
Karabo e nepahetseng ke B.
2. Ho latela setšoantšo, hoa tsebahala hore:
(1) ho potlaka ha ntho ho hang
(2) lintho tse tsamaeang ka mola o otlolohileng ka lebelo le sa fetoheng
(3) lintho tse boemong ba phomolo
(4) ntho e tla sisinyeha haeba boima ba ntho bo le ka tlase ho matla a ho hula
Polelo e nepahetseng ke….
A. (1) le (2) feela
B. (1) le (3) feela
C. (1) le (4)
D. (1), (2) le (3) feela
E. (1), (2), (3) le (4)
Puisano
(1) ho potlaka ha ntho ho hang
Ho potlaka ha ntho ke lefela haeba matla a hlahang a lekana le lefela.
∑F = ma 
ho potlaka (a) = 0
∑ F = 0
F 1 + F 2 – F 3 = 12 + 24 – 36 = 36 – 36 = 0 N
(2) lintho tse tsamaeang ka mola o otlolohileng ka lebelo le sa fetoheng
Ho se potlakise ntho ho hang ho ka bolela hore ntho e phomotse kapa ntho e tsamaya ka mola o otlolohileng ka lebelo le sa fetoheng (ntho e tsamaya ka lebelo le sa fetoheng).
(3) lintho tse boemong ba phomolo
Matla a hlahang a lefela a ka bolela hore ntho e phomotse.
(4) ntho e tla sisinyeha haeba boima ba ntho bo le ka tlase ho matla a ho hula
Boima ba ntho bo sebetsa ka ho otloloha, ha matla a ho hula a sebetsa ka ho otloloha. Hobane ntho e tsamaya ka ho otloloha, ke matla a ho otloloha feela a amang ntho eo.
Karabo e nepahetseng ke D.
3. Sheba setšoantšo se ka thoko!
Haeba coefficient ea kinetic friction pakeng tsa block A le tafole e le 0,1 'me lebelo le bakoang ke matla a khoheli e le 10 m/s-2 ebe matla a lokelang ho sebelisoa ho A e le hore sistimi e tsamaee ka letsohong le letšehali ka ho potlakisa
n 2 ms-2 ke ….
A. 70 N
B. 90 N
C. 150 N
D. 250 N
E. 330 N
Puisano
Hoa tsebahala hore:
Boima ba boloko A (m A ) = 30 kg
Boima ba boloko A (w A ) = (30 kg)(10 m/s 2 ) = 300 kg m/s 2 kapa 300 Newton
Boima ba boloko B (m B ) = 20 kg
Boima ba boloko B (w B ) = (20 kg)(10 m/s 2 ) = 200 kg m/s2 kapa 200 Newtons
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Khokahano ea kinetic ea khohlano (
= 0,1
Ho potlaka ha sistimi (a) = 2 m/s 2 (tsela ea ho potlaka ka letsohong le letšehali)
Matla a khohlano ea kinetic (f)k) = N= wA = (0,1)(300) = 30 Newton
Potso: Boholo ba matla F ke bofe?
Karabo:
Molao oa Bobeli oa Newton:
Σ F = ma
Sistimi e fallela ka letsohong le letšehali
F – f k – w B = (m A + m B ) a
F – 30 – 200 = (30 + 20)(2)
F – 230 = (50)(2)
F – 230 = 100
F = 230 + 100
F = 330 Newton
Karabo e nepahetseng ke E.
4. Lintho tse peli A le B, ka ho latellana tse nang le boima ba 2 kg le 6 kg, li tlangwa ka thapo ka pulley e boreleli joalo ka ha ho bontšitsoe setšoantšong. Ntho ea pele B e tšoaroa ebe e lokolloa. Haeba g = 10 ms -2 joale ho potlaka ha ntho B ke...
A. 8,0 ms-2
B. 7,5 ms -2
C. 6,0 ms -2
D. 5,0 ms -2
E. 4,0 ms -2
Puisano
Hoa tsebahala hore:
m A = 2 kg, m B = 6 kg, g = 10 m/s 2
w A = (m A )(g) = (2)(10) = 20 N
w B = (m B )(g) = (6)(10) = 60 N
Potso: ho potlaka ha ntho B kapa ho potlaka ha sistimi?
Karabo:
w B > w A ka hona ntho B e theohela tlase, ntho A e nyolohela hodimo (tsamaiso e tsamaya ka ho leba ka watjhe).
Σ F = ma
w B – w A = (m A + m B ) a
60 – 20 = (2 + 6) a
40 = (8) a
a = 5 m/s 2
Karabo e nepahetseng ke D.
5. Ntho e nang le boima e hokahantsoe ka thapo e fetang ka har'a pulley e boreleli joalo ka ha ho bontšitsoe setšoantšong. Haeba m 1 = 1 kg, m 2 = 2 kg, le g = 10 ms -2 , joale khatello ea T ke ….
A. 10,2 N 
B. 13,3 N
C. 15,5 N
D. 18,3 N
E. 20,0 N
Puisano
Hoa tsebahala hore:
m 1 = 1 kg, m 2 = 2 kg, g = 10 m/s 2
w 1 = m 1 g = (1 kg)(10 m/s 2 ) = 10 kg m/s 2 kapa 10 Li-Newton
w 2 = m 2 g = (2 kg)(10 m/s 2 ) = 20 kg m/s 2 kapa 20 Li-Newton
Potso: Matla a kgatello ya thapo (T) ke afe?
Karabo:
Ho potlakisa sistimi
w 2 > w 1 ka hona sistimi e tsamaya ka ho leba ho ya ka watjhe (m 2 e theohela tlase, m 1 e nyolohela hodimo).
Molao oa Bobeli oa Newton:
Σ F = ma
w 2 – w 1 = (m 1 + m 2 ) a
20 – 10 = (1 + 2) a
10 = (3) a
a = 3,3 m/s 2
Ho potlaka ha sistimi ke 3,3 m/s 2.
Khatello ea likhoele?
m2 e theohela tlase
w 2 – T 2 = m 2 a
20 – T 2 = (2)(3,33)
20 – T 2 = 6,66
T 2 = 20 – 6,66
T 2 = 13,3 Newton
m 1 e nyolohela holimo
T 1 – w 1 = m 1 a
T 1 – 10 = (1)(3,3)
T 1 – 10 = 3,33
T 1 = 10 + 3,33
T 1 = 13,3 Newton
Kgatelelo ya thapo (T) = 13,3 Newtons.
Karabo e nepahetseng ke B.
6. Sheba setshwantsho ka thoko! Boima ba diboloko ke m 1 = 6 kg mme m 2 = 4 kg, mme boima ba pulley bo hlokomolohuwa. Haeba bokahodimo ba sefofane bo boreleli mme g = 10 ms −2 , jwale ho potlaka ha sistimi ke….
A. 0,5 ms-2
B. 2,0 ms −2
C. 2,5 ms −2
D. 4,0 ms −2
E. 5,0 ms −2
Puisano
Hoa tsebahala hore:
m 1 = 6 kg, m 2 = 4 kg, g = 10 m/s 2
w 1 = m 1 g = (6 kg)(10 m/s 2 ) = 60 kg m/s 2 kapa 60 Li-Newton
w 2 = m 2 g = (4 kg)(10 m/s 2 ) = 40 kg m/s 2 kapa 40 Li-Newton
E botsitsweng: ho potlakisa sistimi (a)?
Karabo:
m 1 e holim'a bokaholimo bo boreleli, bo se nang khohlano e le hore sistimi e tsamaisoe ke matla a khoheli a block 2.
Sebelisa molao oa bobeli oa Newton:
∑ F = ma
w 2 = (m 1 + m 2 ) a
40 N = (6 kg + 4 kg) a
40 N = (10 kg) a
a = 40 N / 10 kg
a = 4 m/s 2
Karabo e nepahetseng ke D.
7. Liboloko tse peli, e 'ngoe le e 'ngoe e nang le boima ba 2 kg, li hokahantsoe ka thapo le pulley joalo ka ha ho bontšitsoe setšoantšong. Bokaholimo le pulley li boreleli. Haeba boloko B bo huloa ka matla a rapameng a 40 N, lebelo la boloko ke… (g = 10 m/s 2 )
A. 5 m/s2
B. 7,5 m/s 2
C. 10 m/s 2
D. 12,5 m/s 2
E. 15 m/s 2
Puisano:
Hoa tsebahala hore:
m A = m B = 2 kg, g = 10 m/s 2 , F = 40 N
w A = mg = (2)(10) = 20 N
Potso: ho potlaka ha block (a)?
Karabo:
Bokaholimo ba boloko bo boreleli, ka hona matla a amang motsamao oa boloko ke matla a F feela le boima ba boloko A.
Sebelisa molao oa bobeli oa Newton:
∑ F = ma
F – w A = (m A + m B ) a
40 – 20 = (2 + 2) a
20 = (4) a
a = 20/4
a = 5 m/s 2
Karabo e nepahetseng ke A.
8. Ho tsoa setšoantšong se latelang, boloko A bo na le boima ba 2 kg mme boloko B = 1 kg. Boloko B qalong bo eme mme bo theohela tlase ho fihlela bo ama fatshe. Haeba g = 10 ms -2 , boleng ba kgatello thapong T ke...
A. 20,0 Newton
B. 10,0 Newton
C. 6,7 Newton
D. 3,3 Newton
E. 1,7 Li-Newton
Puisano
Hoa tsebahala hore :
Boima ba boloko A (m A ) = 2 kg
Boima ba boloko B (m B ) = 1 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Boima ba boloko B (w B ) = m B g = (1)(10) = 10 Newton
Potso : Boleng ba kgatello ya thapo (T)
Karabo :
Potsong ha ho na tlhahisoleseding mabapi le khohlano, kahoo hlokomoloha khohlano.
Potlakiso ea sistimi (a)
Taba ea pele, bala ho potlaka ha sistimi u sebelisa molao oa bobeli oa Newton. Block B e emisitsoe e le hore ho be le matla a khoheli a block B a tsamaisang block B tlase. Block B le block A li hokahantsoe ka thapo e le hore block B e hule block A ho fihlela li tsamaea hammoho. Phapang ke hore block B e theohela tlase 'me block A e ea ka ho le letona. Ho na le matla a le mong feela a bapileng le motsamao oa li-block ka bobeli, e leng matla a khoheli a block B (wB). Matla a khoheli a block A a shebane le tataiso ea motsamao oa block A kahoo ha a nahaneloe ho rarolla bothata. Matla a khatello ea thapo a na le boholo bo lekanang thapong le mahlakoreng a fapaneng hoo li hlakolanang.
∑ F = ma
w B = (m A + m B ) a
10 = (2 + 1) a
10 = 3 a
a = 10/3
Khatello ea thapo (T)
Kgatelelo e ka hara thapo e balwa ka ho nahana ka boloko ka bong ka thoko.
Khatello thapong e bolokong A
∑ F = ma
T = m A a = (2)(10/3) = 20/3 = 6,7 Li-Newton
Khatello thapong e bolokong B
∑ F = ma
w B – T = m B a
10 – T = (1)(10/3)
10 – T = 3,3
T = 10 – 3,3 = 6,7 Newton
Matla a kgatello ya thapo (T) = 6,7 Newton
Karabo e nepahetseng ke C.
9. Ho tsoa setšoantšong se latelang, boloko A bo na le boima ba 2 kg mme boloko B = 1 kg. Haeba matla a khohlano pakeng tsa ntho A le sefofane e le 2,5 Newton, ha matla a khohlano pakeng tsa thapo le pulley a hlokomolohuoa, joale ho potlaka ha lintho tse peli ke...
A. 20,0 ms-2
B. 10,0 ms -2
C. 6,7 ms -2
D. 3,3 ms -2
E. 2,5 ms -2
Puisano
Hoa tsebahala hore :
Boima ba boloko A (m A ) = 2 kg
Boima ba boloko B (m B ) = 1 kg
Matla a khohlano pakeng tsa boloko A le bokaholimo bo bataletseng (f ges A ) = 2,5 Newton
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Boima ba boloko B (w B ) = m B g = (1)(10) = 10 Newton
Potso : Ho potlakisa dintho ka bobedi (a)
Karabo :
Ho potlaka ha lintho ka bobeli ho baloa ho sebelisoa mokhoa oa molao oa bobeli oa Newton.
∑ F = ma
w B – f ges = (m A + m B ) a
10 – 2,5 = (2 + 1) a
7,5 = 3 a
a = 7,5 / 3 = 2,5 m/s 2
Karabo e nepahetseng ke E.
10. Sheba setšoantšo! Boloko A bo boima ba 30 kg bo phomotseng fatše bo boreleli bo hokahantsoe le boloko B bo boima ba 10 kg ka pulley. Boloko B bo tshwarwa qalong ebe bo lokollwa hore bo theohe. Potlakiso ya sistimi ke… (g = 10 ms -2 )
A. 2,5 ms-2
B. 10 ms -2
C. 12 ms -2
D. 15 ms -2
E. 18 ms -2
Puisano
Hoa tsebahala hore :
Boima ba boloko A (m A ) = 30 kg
Boima ba boloko B (m B ) = 10 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Boima ba boloko B (w B ) = m B g = (10)(10) = 100 Newton
Potso : Ho potlakisa sistimi (a)
Karabo :
∑ F = ma
w B = (m A + m B ) a
100 = (30 + 10) a
100 = 40 a
a = 100/40
a = 2,5 m/s 2
Karabo e nepahetseng ke A.
11. Liboloko A le B, e 'ngoe le e 'ngoe e nang le boima ba 8 kg le 12 kg, li behiloe tafoleng joalokaha ho bontšitsoe setšoantšong. Khokahano ea khohlano pakeng tsa boloko A le tafole ke 0,3. Boloko C, e nang le boima ba 4 kg, e beoa holim'a boloko A. Ke efe ea lipolelo tse latelang e nepahetseng?
A. Kgatelelo ya thapo e kgolo ho feta pele, lebelo le lenyenyane ho feta pele
B. Kgatelelo thapong le ho potlaka ha sistimi ha di fetohe.
C. Kgatelelo ya thapo e nyane ho feta pele, lebelo le leholo ho feta pele.
D. Kgatelelo thapong e kgolo ho feta pele, lebelo le dula le tsitsitse.
E. Kgatelelo thapong e dula e tsitsitse ha lebelo le le lenyenyane ho feta pele.
Puisano
Hoa tsebahala hore:
Boima ba boloko A (m A ) = 8 kg
Boima ba boloko B (m B ) = 12 kg
Boima ba boloko C (mC ) = 4 kg
Koefficient ea khohlano pakeng tsa boloko A le tafole ( μ k ) = 0,3
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Boima ba boloko A (w A ) = m A g = (8 kg)(10 m/s 2 ) = 80 kg m/s 2
Boima ba boloko B (w B ) = m B g = (12 kg)(10 m/s 2 ) = 120 kg m/s 2
Matla a khohlano pakeng tsa boloko A le tafole (f k ) = μ k N A = μ k w A = (0,3)(80) = 24 N
Karabo:
Ho potlakisa sistimi:
Σ F = ma
w B – f k = (m A + m B ) a
120 – 24 = ( 8 + 12 ) a
96 = ( 20 ) a
a = 96/20
a = 4,8 m/s 2
Khatello ea thapo:
Nahana ka e 'ngoe ea lintho, mohlala, B.
Σ F = ma
w B – T = (m B ) a
120 – T = ( 12 ) 4,8
120 – T = 57,6
T = 120 – 57,6
T = 62,4 Newton
Bloko C e boima ba 4 kg e bewa hodima bloko A.
Ho potlakisa sistimi:
Σ F = ma
w B – f k = (m A + m B + m C ) a
120 – 24 = ( 8 + 12 + 4 ) a
96 = ( 24 ) a
a = 96/24
a = 4 m/s 2
Khatello ea thapo:
Nahana ka e 'ngoe ea lintho, mohlala, B.
Σ F = ma
w B – T = (m B ) a
120 – T = ( 12 ) 4
120 – T = 48
T = 120 – 48
T = 72 Newton
Karabo e nepahetseng ke A.
12. Ho tsoa setšoantšong se latelang, boloko A bo na le boima ba 2 kg mme boloko B = 1 kg. Boloko B qalong bo eme mme bo theohela tlase ho fihlela bo ama fatshe. Haeba g = 10 ms -2 , boleng ba kgatello thapong T ke...
A. 20,0 Newton
B. 10,0 Newton
C. 6,7 Newton
D. 3,3 Newton
E. 1,7 Li-Newton
Puisano
Hoa tsebahala :
Boima ba boloko A (mA) = 2 kg
Boima ba boloko B (mB) = 1 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
Boima ba boloko B (wB) = mB g = (1)(10) = 10 Newton
E botsitsoe Boleng ba kgatello ya thapo (T)
Jawab :
Potsong ha ho na tlhahisoleseding mabapi le khohlano, kahoo hlokomoloha khohlano.
Potlakiso ea sistimi (a)
Palo ea pele ho potlaka sistimi ho sebelisa foromo Molao oa bobeli oa Newton. Tloko B e leketlile ka tsela eo ho nang le matla a khoheli a boloko B a tsamaisang boloko B tlase. Tloko B le boloko A di hokahantswe ka thapo e le hore boloko B e hule boloko A ho fihlela bobedi bo tsamaya mmoho. Phapang ke hore boloko B e theohela tlase mme boloko A e tsamaya ka ho le letona. Ho na le matla a le mong feela a bapileng le motsamao wa diboloko ka bobedi, e leng matla a khoheli a boloko B (wB). Matla a khoheli Boloko A bo shebane le tsela eo boloko A bo tsamayang ka yona kahoo ha bo nahannwe ha ho rarollwa bothata. Matla a kgatello thapong a na le boholo bo lekanang boleleleng ba thapo le ka mahlakoreng a fapaneng kahoo a a kgaohana.
∑F = ma
wB = (mA +mB) a
10 = (2 + 1) a
10 = 3 a
a = 10/3
Khatello ea thapo (T)
Kgatelelo e ka hara thapo e balwa ka ho nahana ka boloko ka bong ka thoko.
Khatello thapong e bolokong A
∑F = ma
T = mA a = (2)(10/3) = 20/3 = 6,7 Li-Newton
Khatello thapong e bolokong B
∑F = ma
wB – T = mB a
10 – T = (1)(10/3)
10 – T = 3,3
T = 10 – 3,3 = 6,7 Newton
Matla a kgatello ya thapo (T) = 6,7 Newton
Karabo e nepahetseng ke C.
13. Ho tsoa setšoantšong se latelang, boloko A bo na le boima ba 2 kg mme boloko B = 1 kg. Ha matla a khohlano pakeng tsa ntho A le sefofane sa Newton sa 2,5, ha matla a khohlano a thapo le pulley a hlokomolohuoa, joale ho potlaka ha lintho tse peli ho...
A. 20,0 ms-2
B. 10,0 ms-2
C. 6,7 ms-2
D. 3,3 ms-2
E. 2,5 ms-2
Puisano
Hoa tsebahala :
Boima ba boloko A (mA) = 2 kg
Boima ba boloko B (mB) = 1 kg
Matla a khohlano pakeng tsa boloko A le bokaholimo bo bataletseng (fges A) = 2,5 Newton
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
Boima ba boloko B (wB) = mB g = (1)(10) = 10 Newton
E botsitsoe Ho potlaka ha lintho ka bobeli (a)
Jawab :
Ho potlaka ha lintho ka bobeli ho baloa ho sebelisoa mokhoa oa molao oa bobeli oa Newton.
∑F = ma
wB - fges = (mA +mB) a
10 – 2,5 = (2 + 1) a
7,5 = 3 a
a = 7,5 / 3 = 2,5 m/s2
Karabo e nepahetseng ke E.
14. 
Sheba setšoantšo! Boloko A bo boima ba 30 kg bo phomotseng fatše bo boreleli bo hokahantsoe le boloko B bo boima ba 10 kg ka pulley. Boloko B bo tshwarwa qalong ebe bo lokollwa hore bo theohe. Potlakiso ya sistimi ke… (g = 10 m/s-2)
A. 2,5 ms-2
B. 10 ms-2
C. 12 ms-2
D. 15 ms-2
E. 18 ms-2
Puisano
Hoa tsebahala :
Boima ba boloko A (mA) = 30 kg
Boima ba boloko B (mB) = 10 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
Boima ba boloko B (wB) = mB g = (10)(10) = 100 Newton
E botsitsoe : Ho potlakisa sistimi (a)
Jawab :
∑F = ma
wB = (mA +mB) a
100 = (30 + 10) a
100 = 40 a
a = 100/40
a = 2,5 m/s2
Karabo e nepahetseng ke A.
Mohloli oa lipotso:
Lipotso tsa Fisiks tsa Tlhahlobo ea Naha bakeng sa Sekolo se Phahameng sa Thuto e Phahameng/Sekolo se Phahameng sa Mosebetsi
