1. A 2-kg block lies on a rough inclined plane at an angle 37o to the horizontal. Determine the magnitude of the external force exerted on the block, so the block is not slides down the plane. (sin 37o = 0.6, cos 37o = 0.8, g = 10 m.s-2, µk = 0.2)
I njohur:
Masë (m) = 2 kg
Përshpejtimi për shkak të gravitetit (g) = 10 m/s2
Block’s peshë (w) = mg = (2)(10) = 20 Njuton
Mëkati 37o = 0.6
Kosto 37o = 0.8
Coefficient of the fërkim kinetik (µk) = 0.2
The y-component of the weight (wy) = w cos 37o = (20)(0.8) = 16 Njuton
The x-component of the weight (wx) = w sin θ = (20)(sin 37) = (20)(0.6) = 12 Newton
the normal force (N) = wy = 16 Njuton
Shtepi : The external force (F)
Zgjidhje :
wx = 12 Njuton
The force of the kinetic friction (fk) = µk N = (0.1)(16) = 1.6 Njuton
The magnitude of the external force F exerted on the block :
F + fk - wx = 0
F = wx - fk
F = 12 – 1.6
F = 10.4 Njuton
The external force F greater than 10.4 Newton.
2. Mass of a block = 2 kg, coefficient of static friction µs = 0.4 and θ = 45o. Determine the magnitude of the force F so the block start to slides up.
I njohur:
The coefficient of the static friction (µs) = 0.4
Këndi (θ) = 45o
Përshpejtimi për shkak të gravitetit (g) = 10 m/s2
Block’s mass (m) = 2 kilogram
Block’s weight (w) = m g = (2 kg)(10 m/s2) = 20 kg m/s2 = 20 Njuton
The x-component of the weight (wx) = w sin θ = (20)(sin 45) = (20)(0.5√2) = 10√2 Newton
The y-component of the weight (wy) = w cos θ = (20)(cos 45) = (20)(0.5√2) = 10√2 Newton
Shtepi : The magnitude of the force F
zgjidhje:
Block starts to slide up, if F ≥ wx + fs.
The x-component of the weight :
wx = 10√2 Njuton
the y-component of the weight :
wy = 10√2 Njuton
Forca normale :
N = wy = 10√2 Njuton
The force of the static friction :
fs = µs N = (0,4)(10√2) = 4√2
The magnitude of the force F so that the block starts to slide up :
F ≥ wx + fs
F ≥ 10√2 + 42
F ≥ 14√2 Newton
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- Particles in one-dimensional equilibrium
- Particles in two-dimensional equilibrium
- Equilibrium of bodies connected by cord and pulley
- Equilibrium of bodies on the inclined plane