Llogaritja e konsumit të energjisë elektrike nga mjetet elektrike - problemet dhe zgjidhjet
1. In a house, there are 5 lamps 25 Watt used 14 hours per day, a 200 Watt refrigerator used 24 hours per day, and a 125 Watt water pump used 8 hours per day. How much energji elektrike used for a month (30 days)?
I njohur:
Power of lamp = 5(25) = 125 Watt and time of use = 14 hours x 30 = 420 hours
Fuqia e frigorifer = 200 Watt and time of use = 24 hours x 30 = 720 hours
Power of water pump = 125 Watt and time of use = 8 hours x 30 = 240 hours
Kërkohet: Electrical energy used for a month
zgjidhje:
Electric energy = energji elektrike x time interval
Energy (lamp) = (125 Watt)(420 hours) = 52,500 Watt jam = 52,5 kilo Watt hours
Energy (refrigerator) = (200 Watt)(720 hours) = 144,000 Watt jam = 144 kilo Watt hours
Energy (water pump) = (125 Watt)(240 hours) = 30,000 Watt jam = 30 kilo Watt hours
Electrical energy used for a month = 52,5 + 144 + 30 = 226,5 kilo Watt hour = 226,5 kilo Watt hour = 226,5 kWh.
2. A house using electrical tools as listed in the following table.
How much electrical energy is used for 1 month (30 days)?
I njohur:
Power of lamp = 4 x 10 Watt = 40 Watt and time of use = 10 hours x 30 = 300 hours
Power of TV = 1 x 100 Watt = 100 Watt and time of use = 10 hours x 30 = 300 hours
Power of iron = 1 x 300 Watt = 300 Watt and time of use = 2 hours x 30 = 60 hours
Kërkohet: Electrical energy is used for 1 month
zgjidhje:
Electric energy = electric power x time
Energy used by lamp = (40 Watt)(300 hours) = 12,000 Watt hours = 12 kilo Watt hours = 12 kWh
Energy used by TV = (100 Watt)(300 hours) = 30,000 Watt hours = 30 kilo Watt hours = 30 kWh
Energy used by iron = (300 Watt)(60 hours) = 18,000 Watt hours = 18 kilo Watt hours = 18 kWh
Total energy = 12 kWh + 30 kWh + 18 kWh = 60 kWh.
3.
The electrical energy used by the above three electrical tools is…
A. 158,400 Xhaul
B. 950,400 Xhaul
Rreth 5,860,800 xhaul
D. 9,504,000 Xhaul
Zgjidhje
Electric power of TV :
P = VI = (220 volt) (0.3 amper) = 66 volt amper = 66 vat = 66 xhaul/sekondë
Electric power of computer :
P = VI = (220 volt) (0.4 amper) = 88 volt amper = 88 vat = 88 xhaul/sekondë
Electric power of water pump :
P = VI = (220 volt) (0.5 amper) = 110 volt amper = 110 vat = 110 xhaul/sekondë
Time interval :
10 hours = 10 x 3600 seconds = 36,000 seconds
6 hours = 6 x 3600 seconds = 21600 seconds
4 hours = 4 x 3600 seconds = 14400 seconds
Electric energy = electric power x time
Electric energy used by TV = 66 Joule/second x Sekonda 36,000 = 2,376,000 Xhaul
Electric energy used by computer = 88 Joule/second x Sekonda 21,600 = 1,900,800 Xhaul
Electric energy used by water pump = 110 Joule/seconds x Sekonda 14,400 = 1,584,000 Xhaul
Total electric energy :
2,376,000 Xhulë + 1,900,800 Xhulë + 1,584,000 Xhulë = 5,860,800 Xhulë
4. A family uses electrical energy for a month (30 days) for tools as in the following table!
Electric power of washing machine, TV and AC are…
zgjidhje:
Electric energy of washing machine = 12 kWh = 12,000 Watt hour, time of use = 2 hours x 30 = 60 hours
Electric energy of TV = 19.2 kWh = 19,200 Watt hour, time of use = 8 hours x 30 = 240 hours
Electric energy of AC = 72 kWh = 72,000 Watt hour, time of use = 6 hours x 30 = 180 hours
Electric power = electric energy / time
Electric power of washing machine = 12,000 Watt hour / 60 hours = 200 Watt
Electric power TV = 19,200 Watt hour / 240 hours = 80 Watt
Electric power AC = 72,000 Watt hour / 180 hours = 400 Watt
