Korontada taagan - dhibaatooyinka iyo xalalka
Xoogga korontada
1. Barta A ee goobta korantada . Cabbirka goobta korontada ee barta A = 0.5 NC -1 . Haddii dallac 0.25-C la dhigo barta A, markaa waa maxay xoogga korontada ee lagu shubay dallacaadda.
La yaqaan:
Goobta korontada ee barta A = 0.5 NC -1
Dareeraha korontada ee barta A = 0.25 C
La Raadinayo: Koronto
Xalka:
F = q E
F = (0.25 C)(0.5 NC -1 )
F = 0.125N
2. Laba dallacaad oo 5 C iyo 4 C ah ayaa kala fogaada masaafada 3 mitir. Haddii joogtada Coulomb ay tahay 9 × 109 Nm2 C-2, waa maxay baaxadda xoogga korontada ee ay la kulmaan laba dallacaad?
La yaqaan:
Kharash 1 (q1) = 5 C
Kharash 2 (q2) = 4 C
Masaafada u dhaxaysa charge 1 iyo charge 2 (r) = 3 mitir
Joogtada ah ee Coulomb (k) = 9 × 109 Nm2 C-2
La doonayo: Baaxadda xoogga korontada (F)
Xalka:
3. Koronto + q1 = 10 μC; +q2 = 20 μC; iyo q3 waa la kala soocay, sida ku cad sawirka hoose. Xoogga korontada ee lagu shubay kharashka q2 = 0, markaa waa maxay qiimaha q3.
La yaqaan:
Dalac 1 (q 1 ) = 10 μC = 10 x 10 -6 C
Dalac 2 (q 2 ) = 20 μC = 20 x 10 -6 C
La doonayo: Waa maxay qiimaha q3
Xalka:
Waxaa jira laba awoodood oo ku shaqeeya + q2.
Xoogga koowaad waa xoogga iska caabiya ee u dhexeeya kharashka + q1 iyo dallac + q2 taasi waa F12, dhanka midig.
Xoogga korontada saafiga ah wuxuu ku shaqeeyaa q2 = 0 ka dibna q3 waa inay noqotaa mid taban.
Xoogga labaad waa xoogga soo jiidashada leh ee u dhexeeya kharashka + q2 iyo -q3 taasi waa F23, bidix u jeeda.
Labadan awoodoodba waxay ku dhaqmaan q2, waxay leeyihiin cabbir isku mid ah laakiin jihada ka soo horjeeda.
Xoogga saafiga ah wuxuu ku shaqeeyaa + q2 = 0.
4. Saddex dacwadood q1, q, iyo q2 waxay ku jiraan xariiq. Haddii q = 5.0 μC iyo d = 30 cm, markaa waa maxay baaxadda iyo jihada xoogga korontadu ku shaqeyso dallacaadda q.
La yaqaan:
Kharash 1 (q1) = 30 μC = 30 x 10-6 C
Kharash 2 (q2) = 60 μC = 60 x 10-6 C
Dalac 3 (q) = 5 μC = 5 x 10-6 C
Masaafada u dhaxaysa q1 iyo q = d
Masaafada u dhaxaysa q2 iyo q = 2d
d = 30 cm = 0.3 mitir
d 2 = (0.3) 2 = 0.09
Joogtada ah ee Coulomb (k) = 9 x 109 N m2 C-2
La doonayo: Cabbirka iyo jihada xoogga korontadu waxay ku dhacdaa kharashka korantada
Xalka:
Waxaa jira laba awoodood oo ku shaqeeya q oo ah F1 dhanka midig (q iyo q)1 waa kuwo togan sidaa darteed F1 ka fog q iyo q1) iyo F2 bidix u jeeda (q iyo q2 waa kuwo togan sidaa darteed F2 ka fog q iyo q2) Markii ugu horreysay ee la xisaabiyay F1 iyo F2.
Xoogga saafiga ah waa 7.5 Newtons. Jihada xoogga saafiga ah = jihada F1, dhibicda midig ee loo socdo si loo dallaco q2.
Goobta korantada
5. Dhexdhexaad naadir waa lacag q waa barta P ee goobta korantada soo saaray iyadoo loo marayo kharashka (+) si uu u dareemo xoog dhan 0.05 N jihada uu u socdo kharashka. qiimaha elektaroonigga ah field at dhibicda P waa 2 x 10-2 NC-1, ka dibna waxa baaxadda iyo nooca kharashka keena korontada beerta.
La yaqaan:
Xoogga korontada (F) = 0.05 N
Goobta korontada (E) = 2 x 10 -2 NC -1 = 0.02 NC -1
SE buska: Cabbirka iyo nooca dallacaadda korantada
Xalka:
Kharashka korantada waxaa lagu xisaabiyaa iyadoo la adeegsanayo qaacido muujinaysa xiriirka ka dhexeeya xoogga korontada (F), goobta korontada (E) iyo kharashka korontada (q):
F = q E
q = F / E = 0.05 N / 0.02 NC –1 = 2.5 Coulombs
Kharashku q wuxuu la kulmaa xoog koronto oo u jeeda inuu dallaco (+) kaas oo soo saara goob koronto, sidaas darteed kharashku q waa taban.
6. Dalacadaha A iyo B waxaa loo kala saaraa masaafo dhan 4 mitir. Dhibcaha C waxay u dhexeeyaan labada dalac, 1 mitir u jirta dhibicda A. Haddii QA = –300 μC, QB = 600 μC. 1/4 π ε0 = 9 × 109 N m2 C– 2, markaa waa maxay baaxadda goobta korantada ee barta C ee ay soo saaraan labada dallacaad.
La yaqaan:
Masaafada u dhaxaysa khidmadaha A iyo B (r)AB) = 4 mitir
Masaafada u dhaxaysa barta C iyo dallacaadda A (r)AC) = 1 mitir
Masaafada u dhaxaysa barta C iyo dallacaadda B (r)BC) = 3 mitir
Dalac A (q)A) = –300 μC = -300 x 10-6 C = -3 x 10-4 Coulomb
Dalac B (q)B) = 600 μC = 600 x 10-6 C = 6 x 10-4 Coulomb
Joogto ah (k) = 9 × 109 N m2 C-2
La doonayo: Goobta korantada ee barta C
Xalka:
Goobta korontada ee lagu soo saaro dallacaadda A barta C:
eedayn A waa taban si jihada goobta korontada ay u tilmaamto dallacaadda A iyo ka fog dallacaadda B (bidixda).
Goobta korantada ee ay soo saarto dallacaadda B barta C:
Dalac B waa togan si jihada goobta korontada ay uga fogaato dalac B oo ay u tilmaamto dalac A (bidix).
Natiijada garoonka korantada ee barta A:
E = E A + E B
E = (27 x 10 5 ) + (6 x 10 5 )
E = 33 x 10 5 N/C
Jihada goobta korontada waxay tilmaamaysaa in la dallaco A iyo in laga fogaado lacagta B (bidix).
7. Boodh 1-mg ah ayaa hawada ku dul sabaynaya. Haddii culayska boorku yahay 0.5 μC oo dardar-gelintu ay sabab u tahay cufisjiidadka uu yahay 10 m/s2, go'aami baaxadda goobta korontada ee taageerta boodhka.
La yaqaan:
Cufka boodhka (m) = 1 mg = 1 x 10-6 kg
Dareeraha boodhka (q) = 0.5 μC = 0.5 x 10-6 C
Dardargelinta cufisjiidadka awgeed (g) = 10 m/s 2
La doonayo: Goobta korantada
Xalka:
w = mg
w = miisaanka boodhka, m = cufnaanta boodhka, g = dardargelinta cufisjiidadka awgeed
Xoogga cufisjiidadka wuxuu ku shaqeeyaa boodhka:
w = mg = (1 x 10 -6 kg)(10 m/s 2 ) = 10 x 10 -6 kg m/s 2 = 10 x 10 -6 Newtons
Isle'egta goobta korantada:
E = F/q
E = goob koronto, F = xoog koronto, q = dallac koronto
Ku beddel F isle'egta goobta korantada oo leh w isle'egta miisaanka:
E = F/q = w/q
E = (10 x 10 -6 N) / (0.5 x 10 -6 C)
E = 10 N / 0,5 C
E = 20 N/C
8. Laba dacwadood q1 = 32 μC iyo q2 = -214 μC waxaa lagu kala saaraa masaafada x, sida ka muuqata sawirka hoose. Ma jiro goob koronto oo ku taal barta P oo ku taal 10 cm u jirta q.2Soo hel x.
La yaqaan:
Kharash 1 (Q)1) = 32 μC
Kharash 2 (Q)2) = -214 μC
Masaafada barta P laga bilaabo q1 = x + 10 cm
Masaafada barta P laga bilaabo q2 = 10cm
SE buska: x
Xalka:
E1 = garoon koronto oo ay soo saarto dallac Q1Jihada garoonka korontada ee ka fog Q1 sababtoo ah Q1 waa mid togan. E2 = garoon koronto oo ay soo saartay Q2Jihada garoonka korontada waxay tilmaamaysaa Q2 sababtoo ah Q2 waa taban.
Ma jiro xoog saafi ah oo ku yaal barta p oo ku taal 10 cm Q2
Isticmaal qaacidada labajibbaaran:
9. Barta la dallacay q waxay ku taal barta P ee goobta korantada soo saaray iyadoo loo marayo kharashka (+), sidaas darteedna leh awood dhan 0.05 N. Haddii kharashku yahay +5 × l0-6 Coulomb, markaa waa maxay baaxadda goobta korantada ee barta C.
La yaqaan:
Xoogga korontada (F) = 0.05 Newtons
Dakhli koronto (Q) = +5 × l0-6 Coulomb = 0.000005
La doonayo: Goobta korontada ee barta P
Xalka:
E = F / Q
E = 0.05 Newton / 0.000005 Coulomb
E = 5 Newton / 0.0005 Coulomb
E = 10,000 Newton/Coulomb
E = 10 4 N/C
E = 10 4 NC -1
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