3 su'aalood oo ku saabsan isle'egta kala duwanaanshaha suurtagalka ah
1. Dalac koronto ayaa lagu dhaqaajiyaa goob koronto oo isku mid ah oo leh xoog 2√3 N masaafad 20 cm ah. Haddii jihada xooggu ay tahay xagal 30 o ah oo ku wajahan kala-guurka dalac koronto, waa maxay faraqa u dhexeeya tamarta awoodda korantada ee boosaska bilowga iyo kan ugu dambeeya ee dalac koronto.
La yaqaan
Xoogga (F) = 2√3 N
Masaafada (yada) = 20 cm = 0.2 m
Xagasha (θ) = 30 o
La Doonayo: Farqiga Awoodda Korontada
Solution:
Shaqada wareejinta kharashka + q laga bilaabo a ilaa b waxay la mid tahay farqiga tamarta korontada ee dhibcaha a iyo b.
ΔEP = ΔW
Haddii jihada xoogga F ee la xiriirta jihada wareejinta dallacaadda + q uu xagal yahay θ, markaa shaqada wareejinta dallacaadda + q ee laga bilaabo a ilaa b waa:
ΔW = F Δs cos θ = ( 2 √ 3 ) (0,2) (cos 30) = (0,4 √ 3 ) (0,5 √ 3 ) = (0,2) (3) = 0,6 Joule
2. Haddii dallacaadda iyo awoodda kaabsataduhu ay yihiin 5 µC iyo 20 µF, siday u kala horreeyaan, go'aami farqiga suurtagalka ah ee kaabsataduhu.
La yaqaan
Dakhli koronto (q) = 5 µC = 5 x 10 -6 C
Awoodda kondhiyaha (C) = 20 µF = 20 x 10 -6 F
La Doonayo: Farqiga suurtagalka ah ee kondenser-ka (V)
Solution:
Qaacidada farqiga suurtagalka ah ee capacitor, awoodda capacitor iyo dallacaadda:
V = q / C = (5 x 10 -6 ) / 20 x 10 -6 = 5/20 = 0,25 Volts
3. Laba dalac oo QA = -4 µC iyo QB = 8 µC waxay u jiraan 16 cm. Go'aami awoodda korantada meel u dhaxaysa labada dalac oo kala bar ah.
La yaqaan
Dakhli koronto 1 (QA ) = 4 x 10 -6 C
Dakhli koronto 2 (Q B ) = 8 x 10 -6 C
Masaafada (r) = 8 cm = 0,08 m
Joogtada Coulomb (k) = 9 × 10 9 Nm 2 /C 2
La Doonayo: Awoodda korantada ee C ( VC )
Solution:
V A = k Q / r = (9 × 10 9 )(4 x 10 -6 ) / 0,08 = (36 × 10 3 ) / 0,08 = -450 Volts
V B = k Q / r = (9 × 10 9 )(8 x 10 -6 ) / 0,08 = (72 × 10 3 ) / 0,08 = 900 Volts
Awoodda korantada ee C (VC ) = 900 – 450 = 450 Volts
