Physics

9 Miisaanka heerkulka ee beddelaya (Miisaanka Celsius miisaanka Fahrenheit miisaanka Kelvin)

1. 50 ^oC = …… ^oF?

Solution

Jawiga caadiga ah cadaadiska, barta barafowga biyaha waa 0 ^oC oo ku yaal Miisaanka Celsius iyo 32 ^oF oo ku saabsan cabbirka Fahrenheit. Cadaadiska jawiga caadiga ah, barta karkaraya ee biyuhu waa 100 ^oC oo ku saabsan cabbirka Celsius iyo 212 ^oF oo ku jirta cabbirka Fahrenheit.

0 ^oC = 32 ^oF iyo 100 ^oC = 212 ^oF. Isbeddel 5 C ah^o = isbeddel 9 F ah^o.

Miisaanka Celsius, masaafada u dhaxaysa 0 ^oC iyo 100 ^oC waxaa loo qaybiyaa 100 isku-meelood oo isku mid ah. Cabbirka Fahrenheit, masaafada u dhaxaysa 0 ^oC iyo 100 ^oC waxaa loo qaybiyay 180 isku mar.

T^oF = (180/100) T^oC+32

T^oF = (9/5) T^oC+32

T^oF = (9/5) 50 + 32

T^oF = (9) 10 + 32

T^oF=90 + 32

T^oF=122

50 ^oC = 122 ^oF

2. 86 ^oF = …… ^oC?

Solution

T^oC = (100/180)(T)^oF – 32)

T^oC = (5/9)(T)^oF – 32)

T^oC = (5/9)(86 – 32)

T^oC = (5/9)(54)

T^oC = (5)(6)

T^oC = 30

86 ^oF=30 ^oC

3. 50^oC = ….. K?

Solution

T = T ^oC+273

T = 50 + 273

T = 323

50 ^oC= 323 K

4. 212^oF = ….. K?

Solution

T^oC = (100/180)(T)^oF – 32)

T^oC = (5/9)(T)^oF – 32)

T^oC = (5/9)(212 – 32)

T^oC = (5/9)(180)

T^oC = (5)(20)

T^oC = 100

212 ^oF=100 ^oC+273

212 ^oF=373 K

 

5. x ^oC = x ^oF

x = …..?

Solution

1: Beddelidda miisaanka Celsius una beddel cabbirka Fahrenheit

2: Beddelidda miisaanka Fahrenheit una beddel cabbirka Celsius

6. 122°F = ….. Celsius

Solution

Beddelka u dhexeeya labada miisaan ee heerkulka waxaa lagu qori karaa:

T_C = 5/9 (T_F - 32)

T_C = Heerkulka Celsius, T_F = heerkulka Fahrenheit

Heerkulka Celsius:

T_C = 5/9 (122 – 32) = T_C = 5/9 (90) = 5 (10)

T_C = 50 ^oC

7. Shaxda hoose waxay muujineysaa cabbirka heerkulka a dareere leh heerkulbeegga cabbirka Fahrenheit! Haddii heerkulka dareeraha lagu cabbiro heerkulbeegga cabbirka Celsius, markaa waxa heerkulka dareeraha ahe.

La yaqaan:

Fahrenheit miisaanka (T_F= 95^oF

La doonayo: Miisaanka Celsius

Xalka:

Cadaadis dhan 1 atm, barta barafowga biyaha is 0 °C halka miisaanka Fahrenheit uu yahay 32 ^oF. Taas beddelkeeda, tbarta karkaraya biyaha ee CElsius miisaanku waa 100 ^oC halka miisaanka Fahrenheit uu yahay is 212 ^oF.

Cabbirka Celsius, inta u dhaxaysa 0 °C iyo 100 °C waxaa jira 100 ° halka cabbirka Fahrenheit uu yahay 32 °F ilaa 212 °F waxaa jira 180 °.

T_C = 100/180 (T_F - 32)

T_C = 5/9 (T_F - 32)

T_C = 5/9 (95 - 32)

T_C = 5/9 (63)

T_C = 315 / 9

T_C = 35^oC

8. Iyada oo ku saleysan sawirka hoose, go'aami theerkulka P ee heerkulbeegga Celsius.

Solution

T_C = 100/180 (T_F - 32)

T_C = 5/9 (T_F - 32)

T_C = 5/9 (104 – 32)

T_C = 5/9 (72)

T_C = 360 / 9

T_C = 40 ^oC

9. Haddii heerkulka cabbirka Celsius uu yahay sida ku cad sawirka hoose, go'aami heerkulka cabbirka Fahrenheit sida ku cad sawirka hoose.

Xalka:

T^oF = (180/100) T^oC+32

T^oF = (9/5) T^oC+32

T^oF = (9/5) 60 + 32

T^oF = (9) 12 + 32

T^oF=108 + 32

T^oF=140

1. Beddelidda miisaanka heerkulka
2. Balaadhinta toosan
3. Ballaarinta aagga
4. Ballaarinta mugga
5. Heat
6. U dhigma farsamo ee kulaylka
7. Awood gaar ah oo kul iyo kulayl ah
8. Kulayl qarsoon, kulayl isku-dhafan, kulayl uumi-baxa
9. Ilaalinta tamarta ee wareejinta kulaylka

Akhri wax dheeraad ah

1. Garaafka xoogga (F) iyo fidinta (x)) oo lagu muujiyey sawirka hoose. Soo hel joogtada guga!

Solution

Sharciga Hooke formula

k = F/x

F = ciidan (Newton)

k = joogto ah guga (Newton/mitir)

x = isbeddelka dhererka (mitir)

Joogtada guga:

k = 10 / 0.02 = 20 / 0.04

k = 500 N/m

2. Go'aanso guga joogto ah.

Solution

Joogtada guga:

k = F/x

k = 5 / 0.01 = 10 / 0.02 = 15 / 0.03 = 20 / 0.04

k = 500 N/m

3. Guga A wuxuu leeyahay dhererkii asalka ahaa ee 60 cm halka guga B uu leeyahay dhererkii asalka ahaa ee 90 cm. Guga A wuxuu leeyahay joogto ah 100 N/m, guga B wuxuu leeyahay joogto ah 200 N/m. Saamiga isbeddelka dhererka guga A iyo isbeddelka dhererka gu'ga B waa…

La yaqaan:

Joogtada guga A (k)_A) = 100 N/m

Joogtada guga B (k)_B) = 200 N/m

Xoogga guga A (F)_A) = F

Xoogga guga B (F)_B) = F

SE buska: Δl_A : Δl_B

Xalka:

Qaacidada sharciga Hooke:

Δl = F / k

Δl = isbeddelka dhererka, F = xoog, k = joogto ah

Isbeddelka dhererka gu'ga A:

Δl_A =F_A / k_A = F / 100

Isbeddelka dhererka guga B:

Δl_B =F_B / k_B = F / 200

Saamiga isbeddelka dhererka guga A iyo isbeddelka dhererka guga B:

Δl_A : Δl_B

F/100: F/200

1 / 100: 1 / 200

1 / 1: 1 / 2

2: 1

4. Xarig nayloon ah oo dhererkiisu yahay 20 cm, waxaa jiidaya xoog dhan 10 N. Isbeddelka dhererka xariggu waa 2 cm. Go'aami baaxadda xoogga haddii isbeddelka dhererku yahay 6 cm.

La yaqaan:

Xoogga (F) = 10 N

Isbeddelka dhererka (Δl) = 2 cm = 0.02 m

La doonayo: baaxadda xoogga (F) haddii Δl = 0.06 m.

Xalka:

Joogto ah:

k = F / Δl

k = 10 / 0.02 = 500 N/m

Baaxadda xoogga (F) haddii Δl = 0.06 m:

F = kx

F = (500)(0.06)

F = 30N

[wpdm_package id='689′]

1. Sharciga Hooke
2. Cadaadis, cadaadis, Modulus-ka Young

Akhri wax dheeraad ah

Modulus-ka Dhibaatada Walbahaarka ee Dhalinyarada - Dhibaatooyinka iyo Xalalka

1. Xadhig nayloon ah wuxuu leeyahay dhexroor dhan 2 mm, oo uu jiido xoog dhan 100 N. Go'aami cadaadiska!

La yaqaan:

Force (F) = 100 N

Dhexroorka (d) = 2 mm = 0.002 m

Gacanka (r) = 1 mm = 0.001 m

La doonayo: Cadaadiska

Xalka:

Aagga:

A = π r²

A = (3.14)(0.001 m)² = 0.00000314 m²

A = 3.14 x 10^-6 m²

Walwalka:

2. Xadhig dhererkiisu yahay 100 cm ayaa xoog lagu jiidaa. Isbeddelka dhererka xadhiggu waa 2 mm. Go'aami culayska!

La yaqaan:

Dhererka asalka ah (l)₀) = 100 cm = 1 m

Isbeddelka dhererka (Δl) = 2 mm = 0.002 m

La doonayo: Caloosha

Xalka:

Stareen:

3. Xadhig 4 mm dhexroor ah wuxuu leeyahay dherer asal ah 2 m. Xariga waxaa jiidaya xoog dhan 200 N. Haddii dhererka ugu dambeeya ee gu'gu uu yahay 2.02 m, go'aami: (a) cadaadis (b) cadaadis (c) Modulus-ka Young

La yaqaan:

Dhexroorka (d) = 4 mm = 0.004 m

Gacanka (r) = 2 mm = 0.002 m

Aagga (A) = π r² = (3.14)(0.002 m)²

Bedka (A) = 0.00001256 m² = 12.56x10^-6 m²

Xoogga (F) = 200 N

Dhererka asalka ah ee guga (l)₀) = 2 m

Isbeddelka dhererka (Δl) = 2.02 – 2 = 0.02 m

La doonayo: (a) Cadaadiska (b) Cadaadiska c) Modulus-ka Young

Xalka:

(a) ssheyga

(b) Cadaadiska

(C) Qeybinta dhalinyarada

4. Xariggu wuxuu leeyahay dhexroor 1 cm ah dhererkiisuna waa 2 m. Xariggu wuxuu jiidayaa xoog dhan 200 N. Go'aami isbeddelka dhererka xarigga! Modulus-ka Young ee xarigga = 5 x 10⁹ N / m²

La yaqaan:

Modulus-ka Young (E) = 5 x 10⁹ N / m²

Dhererka asalka ah (l)₀) = 2 m

Xoogga (F) = 200 N

Dhexroorka (d) = 1 cm = 0.01 m

Gacanka (r) = 0.5 cm = 0.005 m = 5 x 10^-3 m

Aagga (A) = π r² = (3.14)(5 x 10^-3 m)² = (3.14)(25 x 10^-6 m²)

Bedka (A) = 78.5 x 10^-6 m² = 7.85x10^-5 m²

rabay Isbeddelka dhererka (Δl)

Xalka:

Qaacidada moodulka Young:

Isbeddelka dhererka :

5. Sibidhku wuxuu leeyahay dherer dhan 5 mitir wuxuuna leeyahay bedka halbeegga oo ah 3 mitir³ taageertaa a mass oo ah 30,000 kg. Go'aami (a) Cadaadiska (b) Cadaadiska (c) Isbeddelka dhererka! Dardargelinta cufjiidka awgeed (g) = 10 m/s²Qaab-dhismeedka shubka ee Young = 20 x 10⁹ N / m²

La yaqaan:

Qaab-dhismeedka shubka ee Young = 20 x 10⁹ N / m²

Dhererka bilowga ah (l)₀) = 5 mitir

Bedka cutubka (A) = 3 m²

Miisaanka (w) = mg = (30,000)(10) = 300,000 N

La doonayo: (a) Cadaadiska (b) Cadaadiska (c) Isbeddelka dhererka!

Xalka:

(a) Walbahaarka

(b) Cadaadiska

(c) Isbeddelka dhererka

1. Sharciga Hooke
2. Cadaadis, cadaadis, Modulus-ka Young

Akhri wax dheeraad ah

1. Kubbad, oo ku xiran dhammaadka xarig jiif ah, ayaa lagu wareejinayaa goobaabo gacan ah oo 20 cm ah. Kubbadu waxay ku wareegsan tahay 360^o Ilbiriqsi kasta. Go'aami baaxadda dardargelinta bartamaha!

La yaqaan:

Xawaaraha xagasha (ω)= 360^o/ilbiriqsi = 1 kacaan/ilbiriqsi = 6.28 raadiya/ilbiriqsi

Gacanka (r) = 20 cm = 0.2 m

La doonayo: Dardargelinta bartamaha dhexe (a)_r)

Xalka:

a_r =v² /r —> v = r ω

a_r = (r ω)² / r = r² ω² /r

a_r =r ω²

a_s = dardargelinta bartamaha, v = xawaaraha toosan, r = gacanka, ω = xawaaraha xagasha

Baaxadda xawaaraha dhexe ee dhexe :

a_r =r ω² a_r = (0,2 m)(6.28 rad/s)

a_r = 1.256m/s²

2. Taayir 30 cm ah oo gacan ah ayaa wareegaya xawaare dhan 180 rpm. Go'aami xawaaraha dhexe ee barta ku taal geeska giraangiraha!

La yaqaan:

Gacanka (r) = 30 cm = 0.3 m

Xawaaraha xagasha (ω) = 180 kacaan / 60 ilbiriqsi = 3 kacaan / ilbiriqsi = (3)(6.28 kacaan) / ilbiriqsi = 18.84 kacaan/ilbiriqsi

La doonayo: dardargelinta bartamaha dhexe (a_r) ee r = 0.3 m

Xalka:

Baaxadda xawaaraha dhexe ee centripetal-ka:

a_r =r ω²

a_r = (0.3 m)(18.84) rad / s)

a_r = 5.65m/s²

3. Gaariga tartanka wuxuu ku socdaa waddo wareeg ah oo 50 mitir ah. Haddii xawaaraha gaarigu yahay 72 km/saacaddii, go'aami baaxadda xawaaraha dhexe!

La yaqaan:

Gacanka (r) = 50 mitir

Xawaaraha (v) = 72 km/saacaddii = (72)(1000 mitir) / 3600 ilbiriqsi = 20 mitir/ilbiriqsi

rabay : baaxadda dardargelinta bartamaha dhexe (a_r)

Xalka:

a_r =v² / r = 20² / 50 = 400 / 50 = 8 m/s²

4. Gaadhigu wuxuu leeyahay xawaaraha ugu badan ee centripetal-ka ah ee 10 m/s², si gaarigu u leexan karo isagoon ka simbiriirixan waddo qaloocan. Haddii gaarigu uu ku socdo xawaare joogto ah 108 km/saacaddii, waa maxay gacanka qalooca aan bannayn?

La yaqaan:

Dardargelinta bartamaha (a_r) = 10 m/s²

Xawaaraha gaariga (v) = 108 km/h = (108)(1000) / 3600 = 30 mitirs/second

La doonayo: radius (r)

Xalka:

r =v² / at_r

r = 30² / 10 = 900 / 10 = 90 mitirs

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Gaari saddex-taayir leh0 cm oo gacan ah ayaa si joogto ah u wareegaysa 5 rad/s²Waa maxay baaxadda Dardargelinta toosan bar ku taal (a) 10 cm u jirta bartamaha (b) 20 cm u jirta bartamaha (c) ee geeska giraangiraha?

La yaqaan:

Gacanka (r) = 30 cm = 0.3 m

Dardargelinta xagasha (α) = 5 rad/s²

La doonayo: Dardargelinta toosan (a) r = 0.1 m (b) r = 0.2 m (c) r = 0.3 m

Xalka:

Xiriirka ka dhexeeya dardargelinta toosan (a) iyo dardargelinta xagasha:

a = r α

(A) Dardargelinta toosan, r = 0.1 m

a = (0.1 m)(5 rad/s²) = 0.5 m/s²

(B) Dardargelinta toosan, r = 0.2 m

a = (0.2 m)(5 rad/s²) = 1 m/s²

(C) Dardargelinta toosan, r = 0.3 m

a = (0.3 m)(5 rad/s²) = 1.5 m/s²

2. Barkin 50 cm ah oo gacan ah. Haddii xawaaraha toosan ee barta ku taal geeska barkinta uu yahay 2 m/s², go'aami xawaaraha xagasha ee boolalka!

La yaqaan:

Gacanka (r) = 50 cm = 0,5 m

Dardargelinta toosan (a) = 2 m/s²

La doonayo: dardargelinta xagasha

Xalka:

α = a / r = 2 / 0.5 = 4 rad/s²

3. Daabyada ku jira blender 20 cm oo gacan ah, marka hore marka la nasto. 2 ilbiriqsi ka dib, daabyadu waxay wareegaan 10 rad/s. Go'aami baaxadda dardargelinta toosan (a) dhibic ku taal 10 cm bartamaha (b) dhibic ku taal geeska daabyada.

La yaqaan:

Gacanka (r) = 20 cm = 0.2 m

Xawaaraha xagasha bilowga ah (ω_o) = 0

Xawaaraha ugu dambeeya ee xagasha (ω_t) = 10 gacan/ilbiriqsi

Muddada (t) = 2 ilbiriqsi

La doonayo: xawaaraha toosantirinta dhibic ku taal (a) r = 0.1 m (b) r = 0.2 m

Xalka:

ω_t = ω_o + α t

10 = 0 + α (2)

10 = 2 α

α = 10/2

 α = 5 rad/s

(A) Dardargelinta toosan ee r = 0.1 m

a = r α = (0.1 m)(5 rad/s²) = 0.5 m/s²

(B) Dardargelinta toosan ee r = 0.2 m

a =r α = (0.2 m)(5 rad/s²) = 1 m/s²

4. Taayir 20 cm ah oo gacan ah ayaa la dedejinayaa 2 ilbiriqsi laga bilaabo 20 rad/s si loo nasto. Go'aami baaxadda dardargelinta toosan (a) dhibic ku taal 10 cm oo ka fog bartamaha (b) dhibic ku taal 10 cm oo ka fog bartamaha.

La yaqaan:

Gacanka (r) = 20 cm = 0.2 m

Xawaaraha xagasha bilowga ah (ω_o) = 20 rad/s

Xawaaraha ugu dambeeya ee xagasha (ω_t= 0

Muddada (t) = 2 ilbiriqsi

La doonayo: Dardargelinta toosan (a) r = 0.1 m (b) r = 0.2 m

Xalka:

ω_t = ω_o + α t

0 = 20 + α (2)

-20 = 2 α

α = -20 / 2

 α = -10 rad/s

Calaamadda taban macnaheedu waa xawaaraha xagal ayaa hoos u dhacaysa.

(A) Dardargelinta toosan ee r = 0.1 m

 a =r α = (0.1 m)(-10 rad/s²) = -1 m/s²

(B) Dardargelinta toosan ee r = 0.2 m

a = r α = (0.2 m)(-10 rad/s²) = -2 m/s²

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Kubbad dhammaadka xarig ah ayaa si isku mid ah ugu wareegaysa goob siman oo gacan ah 2 mitir xawaare xagal joogto ah 10 rad/s. Go'aami baaxadda xawaaraha toosan ee barta ku taal:

(a) 0.5 mitir u jirta bartamaha

(b) 1 mitir u jirta bartamaha

(c) 2 mitir u jirta bartamaha

La yaqaan:

gacan (r) = 0.5 meters, 1 mitir, 3 mitir

Xawaaraha xagasha = 10 radians/sexaalad

La doonayo: The xawaaraha toosan

Xalka:

v = r ω

v= xawaaraha toosan, r = radius, ω = xawaaraha xagasha

(A) Xawaaraha toosan (v) ee dhibic ku taal r = 0.5 mitir

v = r ω = (0.5 mitir)s)(10 rad/s) = 5 mitirs/sexaalad

(B) Xawaaraha toosan (V) dhibic ku taal r = 1 mitir

v = r ω = (1 mitir)(10 rad/s) = 10 mitirs/sexaalad

(C) Xawaaraha toosan (V) dhibic ku taal r = 2 mitirs

v = r ω = (2 mitir)s)(10 rad/s) = 20 mitirs/sexaalad

2. Daabyada ku jira blender-ka waxay ku wareegaan xawaare dhan 5000 rpm. Go'aami baaxadda xawaaraha toosan:

(A) dhibic ku taal bartamaha 5 cm

(B) dhibic ku taal bartamaha 10 cm

La yaqaan:

gacan (r) = 5 cm iyo 10 cm

Xawaaraha xagasha (ω) = 5000 kacdoonada / 60 ilbiriqsidhamaado = 83.3 kacdoonada / sexaalad = (83.3)(6.28 radiyaan) / sexaalad = 523.3 radians / sexaalad

La doonayo: Baaxadda xawaaraha toosan

Xalka:

(A) Cabbirka xawaaraha toosan ee barta ku taal 0.05 m bartamaha

v = r ω = (0.05 m) (523.3 rad/s) = 26 m/s

(B) Cabbirka xawaaraha toosan ee barta ku taal 0,1 m bartamaha

v = r ω = (0.1 m) (523.3 rad/s) = 52 m/s

3. Bar ku taal geeska giraangiraha 30 cm gacan, wareegsan wareeg xawaare joogto ah 10 mitir/ilbiriqsi.

Waa maxay baaxadda xawaaraha xagasha?

La yaqaan:

Gacanka (r) = 30 cm = 0.3 mitirs

Xawaaraha toosan (v) = 10 mitirs/sexaalad

La doonayo: xawaaraha xagasha

Xalka:

ω = v / r = 10 / 0.3 = 33 raadiyaans/sexaalad

4. Gaari leh taayiro dhexroorkoodu yahay 50 cm safarl10 mitir gudaha 1 labaad. Waa maxay xawaaraha xagasha?

La yaqaan:

gacan (r) = 0.25 mitir

Xawaaraha toosan ee a Barta geeska taayirka (v) = 10 mitirs/sexaalad

SE buska: Xawaaraha xagasha

Xalka:

ω = v / r = 10 / 0.25 = 40 raadiyaans/sexaalad

5. Xawaaraha xagasha ee giraangiraha 20 cm ee radians waa 120 rpm. Waa maxay masaafada haddii gaarigu socdo 10 ilbiriqsi gudahood.

La yaqaan:

gacan (r) = 20 cm = 0.2 mitirs

Xawaaraha xagasha = 120 rev / 60 sexaaladaha = 2 rev / sexaalad = (2)(6.28) raadiyaans / sexaalad = 12.56 radians / sexaalad

La doonayo: masaafada

Xalka:

xawaaraha geeska giraangiraha:

v = r ω = (0.2 mitir)s(12.56 radians/sexaalad) = 2.5 mitirs/sexaalad

Mitirka 2.5s / second macnaheedu waa bar ku taal geeska safarka giraangiraha Mitirka 2.5s 1 ilbiriqsi kasta. Ka dib markii ay 10xaaladaha, barta ayaa safreysa Mitirka 25s.

Markaa masaafada waa Mitirka 25s.

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

Beddelidda cutubyada xagasha (heerka, radian, kacaanka)

1. ¼ rev = ….. ^o (shahaadada)?

Solution

1 rev = 360^o

½ rev = 180^o

¼ rev = 90^o

2. ½ rev = …….. rad ?

Solution

1 rev = 2π rad = 2(3.14) rad = 6.28 rad

½ rev = pi rad = 3.14 rad

3. 180^o = ….. dib-u-eegis?

Solution

360^o = 1 rev

180^o = ½ rev

4. 90^o = ….. rad?

Solution

360^o = 2π rad = 2(3.14) rad = 6.28 radd

180^o = π rad = 3.14 rad

90^o = ½ π rad = ½ (3.14) = 1.57

5. 60 rad = ….. rev ?

Solution

6.28 rad = 1 rev

60 rad/6.28 = 9.55 rev

6. 40 rad= ….. ^o ?

Solution

6.28 rad = 360^o

40 rad/6.28 = (6.37)(360)^o= 2292.99^o

Barakaca xagasha iyo barokaca toosan

1. Taayir baaskiil oo dhexroorkiisu yahay 60 cm ayaa wareegaya 10 radian. Waa maxay barokac toosan dhibic ku taal geeska giraangiraha?

La yaqaan:

Gacanka (r) = 30 cm = 0.3 m

Xagasha (θ)) = 10 radiyaan

La doonayo: barokac toosan (l)

Xalka:

l = r θ

l = (0.3 m)(10 rad)

l = 3 mitir

2. Taayir 50 cm ah oo gacan ah ayaa wareegaya 360^oWaa maxay kala-guurka toosan ee barta ku taal geeska giraangiraha?

La yaqaan:

Gacanka (r) = 50 cm = 0.5 mitir

Xagasha (θ= 360^o = 6.28 radiyaan

La doonayo: barokac toosan (l)

Xalka:

l = r θ

l = (0.5 m)(6.28 rad)

l = 3.14 mitir

3. Taayir 50 cm ah oo gacan ah ayaa wareegaya 2 wareeg. Waa maxay kala-guurka toosan ee barta ku taal geeska giraangiraha?

La yaqaan:

Gacanka (r) = 50 cm = 0,5 m

Xagasha (θ) = 2 kacaan = (2)(6.28 gacan) = 12.56 gacan

La doonayo: barokaca toosan (l)?

Xalka:

l = r θ

l = (0.5 m)(12.56 rad)

l = 6.28 m

4. Bar ku taal cidhifka giraangiraha 2 mitir oo gacan ah, waxay u socotaa 100 mitir. Go'aami meesha ay ka soo baxayso xagasha.

La yaqaan:

Gacanka (r) = ½ (dhexroor) = ½ (2 mitir) = 1 mitir

Barakaca toosan (l) = 100 mitir

Xalka:

(a) Barakaca xagasha (ee raadiyaanka)

θ = s / r = 100 / 1 = 100 radiyaan

(b) Barakaca xagasha (heerar)

1 gacan = 360^o

100 raadiyaanka = 100(360)^o) = 36,000 radiyaan

(c) Barakac xagal ah (kacaankii)

6.28 raadiyaanka = 1 kacaan

36,000 / 6.28 = 5732,484 kacaan

5. Walax ayaa wareeg ku wareegsan 10 mitir waxayna wareegtaa 180^oWaa maxay gacanka?

La yaqaan:

Barakaca toosan (l) = 10 mitir

Xagasha (θ= 180^o = 3.14 radiyaan

La doonayo: gacan (r)

Xalka:

r = l / θ = 10 / 3.14 = 3.18 mitir

1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Taayir 1 mitir ah oo gacan ah ayaa si isku mid ah u dardargeliya 2 rad/s²Go'aami dardargelinta xagal iyo xawaaraha xagal giraangiraha, 2 ilbiriqsi ka dib.

La yaqaan:

Gacanka (r) = 1 mitir

Dardargelinta xagasha (α)) = 2 rad/s²

SE buska: dardargelinta xagasha iyo xawaaraha xagasha 2 ilbiriqsi ka dib.

Xalka:

(A) Dardargelinta xagasha 2 ilbiriqsi gudahood

Dardargelinta xagasha waa mid joogto ah, sidaas darteed 2 ilbiriqsi ka dib, dardargelinta xagasha giraangiraha waa 2 rad/s².

(B) Xawaaraha xagasha 2 ilbiriqsi gudahood

Dardargelinta xagasha 2 rad/s² macnaheedu waa xawaaraha xagasha wuxuu kordhiyaa 2 radian/ilbiriqsi 1 ilbiriqsi kasta. Ka dib 1 ilbiriqsi, xawaaraha xagasha = 2 radian/ilbiriqsi. Ka dib 2 ilbiriqsi, xawaaraha xagasha = 4 radian/ilbiriqsi.

2. Walax ayaa si isku mid ah u dardargelisa laga bilaabo nasashada ilaa 60 rpm 10 ilbiriqsi gudahood. Go'aami baaxadda dardargelinta xagasha!

La yaqaan:

Xawaaraha xagasha bilowga ah (ω)_o= 0

Xawaaraha ugu dambeeya ee xagasha (ω_t) = 60 rpm = 60 kacaan / 60 ilbiriqsi = 1 kacaan / ilbiriqsi = 6,28 rpm/ilbiriqsi

Muddada (t) = 10 ilbiriqsi

La doonayo: Dardargelinta xagasha (α)

Xalka:

ω_o = xawaaraha xagasha bilowga ah, ω_t = xawaaraha ugu dambeeya ee xagasha, α = dardargelinta xagasha, t = kala-goynta waqtiga, θ = xagal.

ω_t = ω_o + α t

6.28 = 0 + α (10)

= 6.28 10 α

α = 6.28/10

α = 0.628 rad/s²

Baaxadda xawaaraha xagasha = 0.628 rad/s²

3. Shay ayaa hoos u dhacaya laga bilaabo 20 rad/s ilaa 10 rad/s 4 ilbiriqsi gudahood. Go'aami baaxadda dardargelinta xagasha!

La yaqaan:

Muddada (t) = 4 ilbiriqsi

Xawaaraha xagasha bilowga ah (ω_o ) = 20 rad/s

Xawaaraha ugu dambeeya ee xagasha (ω_t) = 10 rad/s

rabay : baaxadda xawaaraha xagasha (α))

Xalka:

ω_t = ω_o + α t

10 = 20 + α (4)

10 - 20 = 4 α

-10 = 4 α

α = -10 / 4

α = – 2.5 rad/s²

Baaxadda xawaaraha xagasha waa -2.5 rad/s²Calaamad taban macnaheedu waa shaygu wuu yaraanayaa. Dardargelin = xawaaraha xagasha ayaa kordha, hoos u dhac = xawaaraha xagasha ayaa yaraada.

4. Shay ayaa la dedejinayaa 2 ilbiriqsi laga bilaabo 10 rad/s ilaa 2 rad/s²Go'aami xagasha lagu wareegsan yahay shayga!

La yaqaan:

xawaaraha xagasha bilowga ah (ω_o ) = 10 rad/s

dardargelinta xagasha (α)) = 2 rad/s²

waqtiga u dhexeeya (t) = 2 ilbiriqsi

La doonayo: xagal (θ)

Xalka:

θ = ω_o + ½ α t²

θ = (10)(2) + ½ (2)(2)²)

θ = 20 + (1)(4) = 20 + 4

θ = 24 raadiyaan

5. Taayirada gaadhigu waxay hoos uga dhacdaa 20 rad/s si ay u nasato ka dib wareega 20 radians. Go'aami baaxadda xawaaraha xagasha ee taayirada!

La yaqaan:

xawaaraha xagasha bilowga ah (ω_o) = 20 rad/s

xawaaraha xagasha ugu dambeeya (ω_t= 0

Xagasha (θ) = 20 radiyaan

La doonayo: baaxadda xawaaraha xagasha (α))

Xalka:

ω_t² = ω_o² + 2 α θ

= 0 20² + 2 α (20)

0 = 400 + 40 α

400 = – 40 α

α = – 400 / 40

α = – 10 rad/s²

6. Ul PQ oo dhererkeedu yahay 60 cm ayaa ku wareegaysa barta Q sida dhidibka wareegga iyo PQ oo ah radius-ka wareegga. Ul PQ ayaa ka soo degdegtay nasashada ilaa 0.3 rad/s²Waa maxay xawaaraha toosan ee barta P ee t = 10 ilbiriqsi, haddii booska bilowga xagasha uu yahay 0.

La yaqaan:

Dhererka usha PQ = gacanka goobada (r) = 60 cm = 60/100 m = 0.60 m

Xawaaraha xagasha bilowga ah (ω_o) = 0 rad/s

Dardargelinta xagasha (α) = 0.3 rad s^-2

Booska xagasha bilowga ah (θ)_o= 0

La doonayo: Xawaaraha toosan (v) ee dhibicda P ee t = 10 ilbiriqsi

Xalka:

Xawaaraha xagasha ugu dambeeya 10 ilbiriqsi ka dib:

ω_t = ω_o + α t = 0 rad/s + (0.3 rad s^-2)(10 ilbiriqsi) = 3 rad/s

Xawaaraha ugu dambeeya ee toosan 10 ilbiriqsi ka dib:

v = r ω = (0.6 m)(3 rad/s) = 1.8 m/s

7. Shay ayaa wareegaya xawaaraha bilowga ah ee 4 rad/s, dardargelinta xagashana waa 0.5 rad/s²Waa maxay xawaaraha shayga 4 ilbiriqsi ka dib.

La yaqaan:

Xawaaraha xagasha bilowga ah (ω_o) = 4 rad/s

Dardargelinta xagasha (α) = 0.5 rad/s²

Muddada (t) = 4 ilbiriqsi

La doonayo: Xawaaraha shayga 4 ilbiriqsi ka dib (ω)_t)

Xalka:

ω_t = ω_o + α t

ω_t = 4 + (0.5)(4)

ω_t = 4 + 2

ω_t = 6 rad/s

8. A Saacad derbi ah oo dhexroorkeedu yahay 10 cm waxay leedahay saddex irbadood, mid walbana wuxuu muujinayaa saacadaha, daqiiqadaha iyo ilbiriqsiyada. Isbarbardhigga tirada wareegyada irbadda saacadda: irbadda daqiiqadda: irbadda labaad.

A. 1: 3: 180

B. 1: 12: 720

C. 4: 12: 180

D. 4: 12: 720

La yaqaan:

1 saac = 60 daqiiqo

12 saacadood = (12)(60 daqiiqo) = 720 daqiiqo

Xawaaraha xagasha ee irbadda saacadda = 1 kacaan / 12 saacadood = 1 kacaan / 720 daqiiqo

Xawaaraha xagal ee irbadda daqiiqadaha = 1 kacaan / 1 saac = 1 kacaan / 60 daqiiqo

Xawaaraha xagal ee irbadda labaad = 1 wareeg / 1 daqiiqo

SE buska: Isbarbardhigga tirada wareegyada irbadda saacadda: irbadda daqiiqadda: irbadda labaad

Xalka:

Isle'egta dhaqdhaqaaqa wareegga:

Xawaaraha xagasha = tirada wareegyada / waqtiga u dhexeeya

Tirada wareegyada = xawaaraha xagasha x waqtiga u dhexeeya

Isla waqtigaas, tusaale ahaan, 1 daqiiqo, inta wareeg ee irbadda saacadda ah, irbadda daqiiqadda ah, iyo irbadda labaad.

Tirada wareegyada irbadda saacadda = xawaaraha xagasha x waqtiga u dhexeeya = (1 kacaanka / 720 daqiiqo)(1 daqiiqo) = 1/720 wareeg

Tirada wareegyada irbadda daqiiqadda = xawaaraha xagasha x waqtiga u dhexeeya = (1 kacaanka / 60 daqiiqo)(1 daqiiqo) = 1/60 wareeg

Tirada wareegyada irbadda labaad = xawaaraha xagal x waqtiga u dhexeeya = (1 kacaanka / 1 daqiiqo)(1 daqiiqo) = 1/1 kacaanka

Isbarbardhigga tiro kacaanno ah:

Tirada wareegyada irbadda saacadda: tirada wareegyada irbadda daqiiqadda: tirada wareegyada irbadda labaad.

1/720: 1/60: 1/1

1/720: 12/720: 720/720

1: 12: 720

Jawaabta saxda ah waa B.

9. Kubbad lagu xidhay xarig. Kubbadu waxay u wareegaysaa si ay ugu dhaqaaqdo meel wareegsan oo barbar socota dusha sare ee dhulka. Dhaqdhaqaaqan, kubbaddu way degdegaysaa sababtoo ah…..

A. Khilaaf ee hawada

B. Miisaanka kubadda

C. Xoogga xiisadda

D. Xoogga cufisjiidka

Xalka:

Sharciga labaad ee dhaqdhaqaaqa Newton waxay sheegaysaa in shay la dedejiyo haddii uu jiro xoog natiijo leh. Kubaddu waxay ku xiran tahay xarigga marka xariggu wareego, kubbaddu sidoo kale way wareegtaa. Marka kubbadu wareegto (kubaddu waxay ku dhaqaaqdaa goobaabin), kubbaddu waxay martaa dardargelinta dhexe. Dhammaan walxaha dhaqaaqaya waa dardargelinta dhexe ee wareegsan. Dardargelinta bartamaha waxaa sababay xoogga centripetalXoogga dhexe ee kiiskan waa xoogga xiisadda.

Jawaabta saxda ah waa C.

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[wpdm_package id='439′]

1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Shay ayaa ku wareegaya goobaabin iyadoo xawaaraha xagasha ee joogtada ah uu yahay 10 rad/s. Go'aami (a) Xawaaraha xagasha 10 ilbiriqsi ka dib (b) Barakaca xagasha 10 ilbiriqsi kadib.

La yaqaan:

Xawaaraha xagasha (ω) = 10 rad/s

La doonayo:

(a) Xawaaraha xagasha (ω) 10 ilbiriqsi ka dib.

(b) Xagasha (θ) 10 ilbiriqsi ka dib

Xalka:

(A) Xawaaraha xagasha (ω) 10 ilbiriqsi ka dib

Shayga ku jira dhaqdhaqaaq wareeg ah oo siman si xawaaraha xagalku uu u noqdo mid joogto ah, 10 rad/s.

(b) Barakaca xagasha (θ)

Xawaaraha xagasha joogtada ah 10 radian/ilbiriqsi macnaheedu waa shayga qiyaastii 10 radian ilbiriqsikiiba. 10 ilbiriqsi ka dib, shayga qiyaastii 10 x 10 radian = 100 radian.

2. Walax ayaa ku socota goobaabin xawaare joogto ah oo ah 10 m/s. Radius-ka goobada = 1 mitir. Go'aami (a) Xawaaraha Walxaha ka dib 5 ilbiriqsi (b) Walxaha barakac 5 ilbiriqsi ka dib (c) Dardargelinta bartamaha.

La yaqaan:

Gacanka goobada (r) = 1 mitir

Xawaaraha walxaha (v) = 10 m/s

Xalka:

(A) Xawaaraha walxaha 5 ilbiriqsi ka dib

Dhaqdhaqaaqa shaygu wuxuu ku jiraa dhaqdhaqaaq wareeg ah oo isku mid ah si xawaaruhu u noqdo mid joogto ah, 10 m/s.

(B) Bararka walxaha 5 ilbiriqsi ka dib

10 mitir/ilbiriqsi macnaheedu waa 1 ilbiriqsi kasta, barokaca walxaha = 10 mitir. 5 ilbiriqsi ka dib, barokaca walxaha = 5 x 10 mitir = 50 mitir.

(C) Dardargelinta bartamaha dhexe (a)_r)

a_r =v² / r = 10² / 1 = 100 / 1 = 100 m/s²

3. Kubad ku xiran hal dhinac oo xarig ah, waxaa lagu wareejinayaa goobaabin leh gacan 2 mitir ah oo leh xawaare joogto ah oo ah 60 rpm. Go'aami (a) baaxadda xawaaraha xagasha ka dib 2 ilbiriqsi (b) barokaca xagasha ka dib 1 daqiiqo.

La yaqaan:

Gacanka goobada (r) = 2 mitir

Xawaaraha xagasha (ω) = 60 rpm = 60 wareeg / 1 daqiiqo

= 60 kacaan / 60 ilbiriqsi = 1 kacaan / ilbiriqsi = 2π raadiyaan / ilbiriqsi

= 2(3.14) raadiyaan / ilbiriqsi = 6.28 raadiyaan / ilbiriqsi

Xalka:

(A) Xawaaraha xagasha (ω) 2 ilbiriqsi ka dib

Xawaaraha xagasha waa mid joogto ah markaa 2 ilbiriqsi ka dib, xawaaraha xagasha (ω) = 6.28 radians / ilbiriqsi

(B) Barakaca xagasha (θ)

Xawaaraha xagasha = 1 kacaan/ilbiriqsi macnaheedu waa 1 ilbiriqsi kasta, kubaddu waxay la kulantaa 1 kacaan. 60 ilbiriqsi ka dib, kubbaddu waxay dhaqaaqdaa 60 kacaan.

Xawaaraha xagasha = 6.28 radians/ilbiriqsi macnaheedu waa 1 ilbiriqsi kasta, kubaddu waxay ku socotaa xagal dhan 6.28 radians. 60 ilbiriqsi ka dib, kubbaddu waxay dhaqaaqdaa 376.8 radians.

4. Taayir baaskiil wuxuu wareegaa 120 wareeg 60 ilbiriqsi gudahood. Waa maxay xawaaraha xagasha?

Xalka:

(a) wareegyada daqiiqaddii (rpm)

120 wareeg / 60 ilbiriqsi = 120 wareeg / 1 daqiiqo = 120 wareeg / daqiiqo = 120 wareeg

(B) darajo ilbiriqsikiiba (^o/ s)

1 kacaan = 360^o, 120 kacaan = 43200^o

120 wareeg / 60 ilbiriqsi = (120)(360)^o) / 60 ilbiriqsi = 43200^o / 60 ilbiriqsi = 720^o/labaad

(C) raadiyaan ilbiriqsigiiba (rad/s)

1 kacaan = 6.28 radiyaan

120 wareeg / 60 ilbiriqsi = (120)(6.28) raadiyaan / 60 ilbiriqsi = 753.6 raadiyaan / 60 ilbiriqsi = 12.56 raadiyaan/ilbiriqsi.

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. A 0.1Kubbad -kg ah, oo ku xiran dhammaadka xarig jiifa, ayaa lagu wareejiyaa goobaabin ah 50 cm iyo kubbadaha xawaaraha xagal is 4 rad s^-1Waa maxay baaxadda bartamaha xoog?

La yaqaan:

Mass (m) = 100 garaam = 100/1000 kg = 1/10 kg = 0.1 kg

Xawaaraha xagasha (ω) = 4 radiyaan/sq.xaalad

Radius (r) = 50 cm = 50/100 m = 0.5 m

La doonayo: Xoogga dhexe

Xalka:

Xoogga dhexe (centripetal force) waa xoog saafi ah oo soo saara dardargelinta bartamaha :

ΣF = ma_r

ΣF = mv²/r = m ω² r

ΣF = xoog saafi ah = xoog dhexe, m = mass, v = xawaaraha, ω = xawaaraha xagal, r = radius

ΣF = m ω² r = (0.1)(4)² (0.5) = (0.1)(16)(0,5) = 0.8 Newtons

2. Kubbadu si siman ayay ugu wareegaysaa goobaabin jiif ah. Haddii xawaaruhu isu beddelo afar jibaar qiimaha bilowga ah, waa maxay baaxadda xoogga dhexe…..

La yaqaan:

Mass = m

Speed =v

Xawaaraha bilowga ah = v_o

Radius (r) =r

SE buska: Baaxadda xoogga dhexe ee dhexe

Xalka:

3. Qallooc wareegsan oo radius R ah ayaa loogu talagalay in gaarigu ku socdo xawaare dhan 12 ms.^-1 si ammaan ah ayuu u gorgortami karaa leexashada. khilaaf aan joogto ahayn inta u dhaxaysa baabuurka iyo wadada = 0.4. Waa maxay gacanka R. Dardargelinta cufjiidka awgeed (g) = 10 ms^-2.

La yaqaan:

Speed (v) = 12 m/s

Isku-darka is-jiidjiid aan joogto ahayn (μ_s) = 0.4

Dardargelinta cufjiidka awgeed (g) = 10 m/s²

SE buska: Gacanka (R)

Xalka:

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1. Cufka iyo miisaanka
2. xoog caadi ah
3. Sharciga labaad ee dhaqdhaqaaqa Newton
4. Xoogga is-qabqabsiga
5. Dhaqdhaqaaq dusha sare oo siman oo aan lahayn xoog is jiidjiid ah
6. Dhaqdhaqaaqa laba jidh oo leh xawaare isku mid ah oo ku yaal dusha sare ee toosan ee qallafsan oo leh xoogga is-jiidjiidka
7. Dhaqdhaqaaqa diyaaradda u janjeerta iyada oo aan lahayn xoog is jiidjiid ah
8. Dhaqdhaqaaqa diyaaradda qallafsan ee u janjeerta oo leh xoogga is jiidjiidka
9. Dhaqdhaqaaqa wiishka
10. Dhaqdhaqaaqa jirka waxaa isku xira fiilooyin iyo boolal
11. Laba jir oo leh xawaare isku mid ah
12. Wareegidda qalooc fidsan - dhaqdhaqaaqa dhaqdhaqaaqa wareegsan
13. Soo koobidda qalooca bangi - dhaqdhaqaaqa dhaqdhaqaaqa wareegsan
14. Dhaqdhaqaaq siman oo goobo jiif ah
15. Xoogga dhexe ee dhaqdhaqaaqa wareegsan ee isku midka ah

Akhri wax dheeraad ah