1. Haddii R 1 = 2 Ω, R 2 = 4 Ω, R 3 = 6 Ω, go'aami socodka korantada ee wareegga hoose.
La yaqaan:
Resistor 1 (R1) = 2 Ω 
Iska caabbinta 2 (R 2 ) = 4 Ω
Iska caabbinta 3 (R 3 ) = 6 Ω
Isha emf 1 (E 1 ) = 9 V
Isha emf 2 (E 2 ) = 3 V
La Raadinayo: Koronto koronto (I)
Xalka:
Su'aashani waxay la xiriirtaa sharciga Kirchhoff . Sida loo xalliyo dhibaatadan:
Marka hore , dooro jihada hadda socota. Waxaad go'aansan kartaa jihada ka soo horjeeda ee hadda socota ama jihada saacadda u socota.
Marka labaad , marka uu hadda dhex maro iska caabinta (R) waxaa jira hoos u dhac suurtagal ah si V = IR uu u saxiixo taban. Saddexaad , haddii hadda uu ka dhaqaaqo danab hoose una gudbo danab sare (- ilaa +) markaas isha emf (E) waxay u saxiixday togan sababtoo ah dallacaadda tamarta ee isha emf. Haddii hadda uu ka dhaqaaqo danab sare una gudbo danab hoose (+ ilaa -) markaas isha emf (E) waxaa loo saxiixay taban sababtoo ah faaruqinta tamarta ee isha emf.
Xalkan, jihada hadda jirta waxay la mid tahay jihada wareegga saacadda.
- IR 1 + E 1 - IR 2 - IR 3 - E 2 = 0
– 2 I + 9 – 4 I – 6 I – 3 = 0
– 12 I + 6 = 0
– 12 I = – 6
I = -6 / -12
I = 0.5
Qulqulka korantada ee wareegga waa 0.5 A. Qulqulka korontada ee calaamadaysan ee togan wuxuu ka dhigan yahay in jihada qulqulka korontada ay la mid tahay jihada wareegga saacadda. Haddii qulqulka korontadu uu taban yahay, markaa qulqulka korontadu wuxuu ka soo horjeedaa jihada saacadda.
2. Go'aami qulqulka korantada ee ku socda wareegga sida ku cad sawirka hoose.
Xalka:
Xalkan, jihada hadda jirta waxay la mid tahay jihada wareegga saacadda.
-20 – 5I -5I – 12 – 10I = 0
-32 – 20I = 0
-32 = 20I
I = -32 / 20
I = -1.6 A
Maadaama korontada ay tahay mid taban, jihada korontada waxay dhab ahaantii ka soo horjeeddaa jihada saacadda u socota. Jihada korontada ma aha mid la mid ah tii la qiyaasay.
3. Go'aami qulqulka korantada ee ku socda wareegga sida ku cad sawirka hoose.
Xalka:
Xalkan, jihada hadda jirta waxay la mid tahay jihada wareegga saacadda u socda.
– I – 6I + 12 – 2I + 12 = 0
-9I + 24 = 0
-9I = -24
I = 24/9
I = 8/3 A
4. Wareeg koronto wuxuu ka kooban yahay afar iska caabin ah, R 1 = 12 Ohm, R 2 = 12 Ohm, R 3 = 3 Ohm iyo R 4 = 6 Ohm, waxay ku xiran yihiin isha emf E 1 = 6 Volt, E 2 = 12 Volt. Go'aami socodka korantada ee wareegga sida ku cad jaantuska hoose.
La yaqaan:
Iska caabbinta 1 (R 1 ) = 12 Ω
Iska caabbinta 2 (R 2 ) = 12 Ω
Iska caabbiye 3 (R 3 ) = 3 Ω
Iska caabbiye 4 (R 4 ) = 6 Ω
Isha emf 1 (E 1 ) = 6 Volts
Isha emf 2 (E 2 ) = 12 Volts
La Doonayo: Korontada ayaa ku socota wareegga (I)
Xalka:
Iska caabbinta 1 ( R 1 ) iyo iska caabbinta 2 ( R 2 ) waxay ku xiran yihiin is barbar socda. Iska caabbinta u dhiganta:
1/R 12 = 1/R 1 + 1/R 2 = 1/12 + 1/12 = 2/12
R 12 = 12/2 = 6 Ω
Xalkan, jihada hadda jirta waxay la mid tahay jihada wareegga saacadda u socda.
- IR 12 - E 1 - IR 3 - IR 4 + E 2 = 0
– 6 I – 6 – 3I – 6I + 12 = 0
– 6I – 3I – 6I = 6 -12
– 15I = – 6
I = -6/-15
I = 2/5 A
5. Go'aami qulqulka korantada ee ku socda wareegga sida ku cad sawirka hoose.
La yaqaan:
Iska caabbinta 1 (R 1 ) = 10 Ω
Iska caabbinta 2 (R 2 ) = 6 Ω
Iska caabbiye 3 (R 3 ) = 5 Ω
Iska caabbiye 4 (R 4 ) = 20 Ω
Isha emf 1 (E 1 ) = 8 Volts
Isha emf 2 (E 2 ) = 12 Volts
La Doonayo: Korontada ku socota wareegga
Xalka:
Iska caabbinta 3 ( R 3 ) iyo iska caabbinta 4 ( R 4 ) waxay ku xiran yihiin is barbar socda. Iska caabbinta u dhiganta:
1/R 34 = 1/R 3 + 1/R 4 = 1/5 + 1/20 = 4/20 + 1/20 = 5/20
R 34 = 20/5 = 4 Ω
Xalkan, jihada hadda jirta waxay la mid tahay jihada wareegga saacadda u socda.
- IR 1 - IR 2 - E 1 - IR 34 + E 2 = 0
– 10I – 6I – 8 – 4I + 12 = 0
– 10I – 6I – 4I = 8 – 12
– 20 I = – 4
I = -4/-20
I = 1/5 A
I = 0.2 A
6. Go'aami qulqulka korantada ee ku socda wareegga sida ku cad sawirka hoose.
La yaqaan:
Iska caabbinta 1 (R 1 ) = 1 Ω
Iska caabbinta 2 (R 2 ) = 6 Ω
Iska caabbiye 3 (R 3 ) = 6 Ω
Iska caabbiye 4 (R 4 ) = 4 Ω
Isha emf 1 (E 1 ) = 12 Volts
Isha emf 2 (E 2 ) = 6 Volts
La Doonayo: Korontada ku socota wareegga
Xalka:
Iska caabbinta 1 ( R 1 ) iyo iska caabbinta 2 ( R 2 ) waxay ku xiran yihiin is barbar socda. Iska caabbinta u dhiganta:
1/R 12 = 1/R 1 + 1/R 2 = 1/1 + 1/6 = 6/6 + 1/6 = 7/6
R 12 = 6/7 Ω
Jihada hadda jirta waxay la mid tahay jihada wareegga saacadda u jeeda.
E 1 – I R 12 – E 2 – I R 4 – IR 3 = 0
12 – (6/7)I – 6 – 4I – 6I = 0
12 – 6 – (6/7)I – 4I – 6I = 0
6 – (6/7)I – 10I = 0
6 = (6/7) Aniga + 10I
6 = (6/7)I + (70/7)I
6 = (76/7)I
(6)(7) = 76I
42 = 76I
I = 42/76
I = 0.5 A
