3 su'aalood oo ku saabsan isle'egta cufisjiidadka
1. Saddex qaybood oo midkiiba miisaankoodu yahay 1 kg ayaa ku yaal geesaha saddexagal siman oo dhinacyadu ay dhererkoodu yahay 1 m. Waa immisa xoogga cufisjiidadka ee ay la kulmaan walax kasta oo dhibic ah (G)?
Solution
Cabbirka xoogga cufisjiidadka ee uu la kulmo mid ka mid ah walxaha.
F 12 = G (m 1 )(m 2 ) / r 2 = G (1)(1) / 1 2 = G/1 = G
F 13 = G (m 1 )(m 3 ) / r 2 = G (1)(1) / 1 2 = G/1 = G
Xoogga cufisjiidadka ee ka dhashay qodobka 1aad:
F 1 = √1 2 +1 2 = √1 +1 = √2 Newtons
2. Jaantuska hoose wuxuu muujinayaa saddex shay m 1 = 6 kg; m 2 = 3 kg iyo m 3 = 4 kg waxay ku yaalliin xariiq toosan. Go'aami baaxadda iyo jihada xoogga cufisjiidadka ee ka dhashay m2! (xaaladda G)
La yaqaan
m1 = 6kg
m2 = 3 kg
m3 = 4 kg
Joogto cufisjiidadka = G
r 21 = 4 m
r 23 = 2 m
La Doonayo: Cufisjiidadka F ee ay la kulmeen m 2
Solution:
Xoogga cufisjiidadka ee u dhexeeya m 2 iyo m 3 :
F = G (3)(4) / 2 2 = G 12 / 4 = 3G
Xoogga cufisjiidadka ee u dhexeeya m 2 iyo m 1 :
F = G (3)(6) / 4 2 = G 18 / 16 = 1,125G
3. Shayga A oo leh cuf dhan 1 kg iyo shayga B oo leh cuf dhan 2 kg ayaa kala fog 2 m midba midka kale. Barta P waa 2 m shayga A iyo 2 m shayga B. Sidee ayuu u xooggan yahay goobta cufisjiidadka ee barta P?
La yaqaan
m A = 1 kg
m B = 2 kg
r PA = 2 m
r PB = 2 m
Joogtada cuf-isjiidadka = G
La Doonayo: Cufisjiidadka E ee barta P
Solution:
E PA = G (m A ) / r 2 = G (1) / 2 2 = G/4 = 0,25G
E PB = G (m B ) / r 2 = G (2) / 2 2 = 2G/4 = 0,5G
Xoogga goobta cufisjiidadka ee ka dhalatay barta P:
E = √0,25G 2 +0,5G 2 = √0,0625G 2 +0,25G 2 = √0,3125G 2 = 0,56G N/kg
