Sinnaanta jirka ee diyaarad u janjeerta - adeegsiga dhibaatooyinka sharciga ugu horreeya ee Newton iyo xalalka

1. Baloog 2-kg ah ayaa ku yaal meel toosan oo u janjeerta xagal 37 o ah oo u jirta dhinaca toosan. Go'aami baaxadda xoogga dibadda ee lagu sameeyay baloogga, si balooggu uusan hoos ugu simbirixan diyaaradda. (sin 37 o = 0.6, cos 37 o = 0.8, g = 10 ms -2 , µ k = 0.2)

Sinnaanta jirka ee diyaaradda u janjeerta - adeegsiga dhibaatooyinka sharciga ugu horreeya ee Newton iyo xalalka 1La yaqaan:

Cufnaanta (m) = 2 kg

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s 2

Miisaanka baloogga (w) = mg = (2)(10) = 20 Newtons

Dem 37 o = 0.6

Kos 37 o = 0.8

Isku-darka is -jiidjiidka dhaqdhaqaaqak ) = 0.2

Qaybta y ee miisaanka (w y ) = w cos 37 o = (20)(0.8) = 16 Newtons

Qaybta x ee miisaanka (w x ) = w sin θ = (20)(dembi 37) = (20)(0.6) = 12 Newtons

xoogga caadiga ah (N) = w y = 16 Newtons

La Doonayo : Xoogga dibadda (F)

Xalka :

Sinnaanta jirka ee diyaaradda u janjeerta - adeegsiga dhibaatooyinka sharciga ugu horreeya ee Newton iyo xalalka 2wx = 12 Newton

Xoogga is-jiidjiidka dhaqdhaqaaqa (f k ) = µ k N = (0.1)(16) = 1.6 Newtons

Baaxadda xoogga dibadda F ee ku dhacay baloogga :

F + f k – w x = 0

F = w x – f k

F = 12 – 1.6

F = 10.4 Newton

Xoogga dibadda F wuxuu ka weyn yahay 10.4 Newtons.

Arag sidoo kale  Xoogga codka - dhibaatooyinka iyo xalalka

2. Cufka baloogga = 2 kg, isku-darka is-jiidjiidka taagan µ s = 0.4 iyo θ = 45 o . Go'aami baaxadda xoogga F si baloogga uu u bilaabo inuu kor u simbirixdo.

Sinnaanta jirka ee diyaaradda u janjeerta - adeegsiga dhibaatooyinka sharciga ugu horreeya ee Newton iyo xalalka 3La yaqaan:

Isugeynta is-jiidjiidka aan joogtada ahayn (µ s ) = 0.4

Xagasha (θ) = 45 o

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s 2

Cufka baloogga (m) = 2 kiilo garaam

Miisaanka baloogga (w) = mg = (2 kg)(10 m/s 2 ) = 20 kg m/s 2 = 20 Newtons

Qaybta x ee miisaanka (w x ) = w sin θ = (20)(dembi 45) = (20)(0.5√2) = 10√2 Newtons

Qaybta y ee miisaanka (w y ) = w cos θ = (20)(cos 45) = (20)(0.5√2) = 10√2 Newtons

La Doonayo : Baaxadda xoogga F

Xalka:

Sinnaanta jirka ee diyaaradda u janjeerta - adeegsiga dhibaatooyinka sharciga ugu horreeya ee Newton iyo xalalka 4Balooggu wuxuu bilaabaa inuu kor u simbirixdo, haddii Fwx + fs.

Qaybta x ee miisaanka:

w x = 10√2 Newton

qaybta y ee miisaanka :

w y = 10√2 Newton

Xoogga caadiga ah :

N = w y = 10√2 Newton

Xoogga is-jiidjiid la'aanta :

f s = µ s N = (0,4) (10√2) = 4√2

Baaxadda xoogga F si balooggu u bilaabo inuu kor u simbirixdo :

Fw x + f s

F ≥ 10√2 + 4 √2

F ≥ 14√2 Newton

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  1. Walxaha isku dheelitirka hal-cabbir ah
  2. Walxaha dheelitirka laba-geesoodka ah
  3. Sinnaanta jirka oo ay ku xiran yihiin xadhkaha iyo boolalku
  4. Sinnaanta jirka ee diyaaradda u janjeerta

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