1. Elektaroonku wuxuu ka soo kacaa nasashada iyadoo loo marayo farqi suurtagal ah oo ah 12 V. Waa maxay isbeddelka tamarta awoodda korantada ee elektaroonku?
La yaqaan:
Xaraashka elektaroonada (e) = -1.60 x 10 -19 Coulomb
Awoodda korantada = danab (V) = 12 Volts
La Doonayo: Isbeddelka tamarta korontada ee elektarooniga (ΔPE)
Xalka:
ΔPE = q V = (-1.60 x 10 -19 C)(12 V) = -19.2 x 10 -19 Joules
Calaamadda laga jaray waxay muujinaysaa in tamarta suurtagalka ah ay hoos u dhacayso.
2. Laba saxan oo is barbar socda ayaa la dallacayaa. Kala-soocidda u dhaxaysa saxannada waa 2 cm, baaxadda goobta korontada ee u dhaxaysa saxannadana waa 500 Volt/mitir. Waa maxay isbeddelka tamarta suurtagalka ah ee proton-ka marka laga dardargeliyo saxanka togan ee loo dallacsiiyay saxanka taban.
La yaqaan:
Cabbirka garoonka korantada ee u dhexeeya taarikada (E) = 500 Volt/mitir
Masaafada u dhaxaysa saxanadaha (yada) = 2 cm = 0,02 m
Kharashka ku jira proton = +1.60 x 10 -19 Coulombs
La Doonayo: Isbeddelka tamarta korontada ee suurtogalka ah (ΔPE)
Xalka:
Awoodda korontada:
V = E s
V = (500 Volt/m)(0.02 m)
V = 10 Volt
Isbeddelka ku yimaada tamarta korontada ku shaqaysa:
ΔPE = q V
ΔPE = (1,60 x 10 -19 C)(10 V)
ΔPE = 16 x 10 -19 Joule
ΔPE = 1.6 x 10 -1 8 Joule
3. Laba dalac oo dhibic ah ayaa kala fogaada masaafada 10 cm. Dalac oo dhibicda A = +9 μC ah iyo dalac oo dhibicda B = -4 μC ah. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C. Waa maxay isbeddelka tamarta korontada ee awoodda dallacaadda ee dhibicda B haddii loo dedejiyo dhibicda A?
La yaqaan:
Dalac A (q 1 ) = +9 μC = +9 x 10 −6 C
Dalacaadda B (q 1 ) = -4 μC = -4 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Masaafada u dhaxaysa khidmadaha A iyo B (r) = 10 cm = 0.1 m = 10 -1 m
La Doonayo: Isbeddelka tamarta korontada ee suurtogalka ah (ΔEP)
Xalka:
